Answer:
2:3 is equal to 8:12
Step-by-step explanation:
2:3
To get the first number to 8
8/2 = 4
Multiply by all terms 4
2*3 : 3*4
8:12
2:3 is equal to 8:12
8:12 = 8/12
= 2/3
= 2:3
Therefore 2:3 and 8:12 are equalent to each other.
Answered by Gauthmath must click thanks and mark brainliest
Find the measures of angles 1 and 2. If necessary, round to the tenths place.
Hint: Do not assume that Point D is the center of the circle.
A. m<1 = 20 m<2= 20
B. m<1 =40 m<2 = 140
C. m<1 = 82.5 m<2 = 97.5
D. m<1 =97.5 m<2= 82.5
Answer:
Option C
Step-by-step explanation:
From the picture attached,
m∠ABC = 40° [Given]
Since, measure of the intercepted arc is double of the measure of the inscribed angle.
Therefore, m(arc AC) = 2(m∠ABC)
m(arc AC) = 2(40°)
= 80°
m(arc FB) = 115° [Given]
By applying theorem of the angles formed by the chords inside a circle,
m∠2 = [tex]\frac{1}{2}(\text{arc}AC+\text{arc}FB)[/tex]
= [tex]\frac{1}{2}(80^{\circ}+115^{\circ})[/tex]
= 97.5°
m∠1 + m∠2 = 180° [Linear pair of angles are supplementary]
m∠1 + 97.5° = 180°
m∠1 = 180° - 97.5°
= 82.5°
Option C is the answer.
Which quadrilateral has equal diagonals
Select one:
a. trapezoid
b. rectangle
c. parallelogram
d. rhombus
Answer:
Option b: Rectangle
Explanation:
Give branliest pls ;)
Ryanair provides cheap flights in Europe but prides itself on their on-time record. Ryanair quotes a flight time of 2 hours, 5 minutes. Suppose we believe that actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes.
What is the expected flight time in minutes?
Answer:
The expected flight time is 2 hours 10 minutes
Step-by-step explanation:
Given
[tex]a = 2\ hours[/tex]
[tex]b = 2\ hours\ 20\ mins[/tex]
Required
The expected flight time
To do this, we simply calculate the mean using:
[tex]Mean = \frac{a + b}{2}[/tex]
So, we have:
[tex]Mean = \frac{2\ hours + 2\ hours\ 20\ mins}{2}[/tex]
[tex]Mean = \frac{4\ hours\ 20\ mins}{2}[/tex]
[tex]Mean = 2\ hours\ 10\ mins[/tex]
What is the length of the arc of a circle of diameter 8 meters subtended by a central angle of
3pi/4 radians?
Answer:
9.42 meters
Step-by-step explanation:
diameter = 8 m
radius = 4 m
Length of arc = radius * central angle in radians
= 4 * 3[tex]\pi[/tex] / 4
= 12[tex]\pi[/tex] / 4
= 3[tex]\pi[/tex]
= 66 / 7
= 9.42 m
The length of the arc of a circle of diameter 8 meters subtended by a central angle of 3pi/4 radians is 9.42 meters.
What is the arc of the circle?The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.
expalination:
⇒angle= arc/radius
= 3pi/4 radians
diameter = 8 m
radius = 4 m
Length of arc = radius * central angle in radians
⇒4 * 3 / 4
⇒12 / 4 = 3
⇒66 / 7
⇒9.42 m
Hence the arc of a circle is 9.42 m.
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I need help please can not figure out this problem
Shortern this expression pls
Answer:
[tex]c =\frac{8}{3}[/tex]
Step-by-step explanation:
Given
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]
Required
Shorten
We have:
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]
Rationalize
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}[/tex]
Expand
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}[/tex]
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}[/tex]
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}[/tex]
Take positive square roots
[tex]c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}[/tex]
Take LCM
[tex]c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}[/tex]
Collect like terms
[tex]c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}[/tex]
[tex]c =\frac{8}{3}[/tex]
 In one of the examples he is working on, he knows that the two coordinates (0,6) and
(8, 10) are on the function that he is deriving. Using the information from these two
coordinates, determine the slope and y-intercept of the function Mike is looking for, and
then write out the correct function.
9514 1404 393
Answer:
y = 1/2x + 6
Step-by-step explanation:
The slope m is given by the formula ...
m = (y2 -y1)/(x2 -x1)
m = (10 -6)/(8 -0) = 4/8 = 1/2
The y-intercept is given by the formula ...
b = y -mx
b = 6 -(1/2)(0) = 6
Then the slope-intercept equation is ...
y = mx +b
y = 1/2x +6
What is the area of a trapezoid.. base 14in and 7in height is 5in?
if the formula is [tex]\frac{(B+b)}{2} .h[/tex] we just need to plug in the values
21/2 = 10.5 x 5 = 52.5
hope it helps :)
Answer:
A = 52.5 in^2
Step-by-step explanation:
The area of a trapezoid is
A = 1/2 (b1+b2)h
where b1 and b2 are the bases and h is the height
A = 1/2 ( 14+7)*5
A = 105/2
A = 52.5 in^2
find the product of 8×53×(-125) by using suitable property
Answer:
-53,000
Step-by-step explanation:
Now to find this answer you use the PEMDAS rule now that stands for:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Now the first thing that you do is look for the parenthesis now there is but there is no equation in that so we go to the next one exponents and there are no exponents. So we go to the multiplication and we multiply everything and that is how you get that answer.
Hope it helped!
The Online Exam from Applied Statistics consists of 6 questions. Statistics show that there is a 75% chance that the student will answer to any one of Exam problems correctly. If the number of attempts for each question is unlimited, find the following probabilities
a. The student will correctly answer the first question after the 4th attempt.
b. The student will correctly answer three questions after 10 total attempts.
c. What is the average number and SD of attempts up to when the student answers all the questions correctly?
Solution :
a). The probability that the student will [tex]\text{correctly answer}[/tex] the 1st question after the 4th attempt.
P (correct in the 4th attempt)
= [tex]$(1-0.75)^3 \times 0.75$[/tex]
= 0.01171875
b). The probability that the student will [tex]\text{correctly answer}[/tex] 3 questions after 10 total attempts.
P( X = 3) for X = B in (n = 10, p = 0.75)
= [tex]$C(10,30) \times 0.75^3 \times 0.25^7$[/tex]
= 0.0031
c). The mean and the standard deviation for the number of attempts up to when the students gets all the questions correct is :
There are = 6 success, p = 0.75.
Therefore, this is a case of a negative binomial distribution.
[tex]$E(X)=\frac{k}{p}$[/tex]
[tex]$=\frac{6}{0.75}$[/tex]
= 8
So, [tex]$\sigma = \frac{\sqrt{k(1-p)}}{p}$[/tex]
[tex]$\sigma = \frac{\sqrt{6(1-0.75)}}{0.75}$[/tex]
= 1.6330
Find the length of AB
Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.
Remember: SOH-CAH-TOA
Looking from the given angle, we know the opposite side and want to know the hypotenuse. Therefore, we should use the sine function.
sin(54) = 16/AB
AB = 16/sin(54)
AB = 19.78 units
Hope this helps!
Subtract the complex numbers: (–2 + 12i) – (–1 – 9i)
Question 18 options:
A)
–3 + 21i
B)
–1 + 21i
C)
–1 + 3i
D)
–3 + 3i
Answer:
B
Step-by-step explanation:
hope it is well understood
Armando planted a 9-inch tall magical beanstalk. The height of the beanstalk increases by 13% each day. Write a function f that determines the height of the beanstalk in inches in terms of the number of days t since Armando planted the beanstalk.
Answer:
F(t) = 9(1 + 0.13)^t
Step-by-step explanation:
Given :
Height of beanstalk = initial height = 9 inches
Percentage increase in height per day = 13%
This plant exhibits an exponential increase in growth per day, hence, the function will be modeled using an exponential function.
Using an exponential function :
F(t) = initial height(1 + percentage increase)^t
Where, t = number of days since tree was planted.
The function is :
F(t) = 9(1 + 0.13)^t
a bus carry 53 passengar on a trif. how many passenger can 9 such carry if each dose 2 trif
Answer:
954 passengers
Step-by-step explanation:
(Assuming I read the question correctly)
1 bus can carry in 1 trip = 53 passengers
1 bus can carry in 2 trips : 106 passsengers
9 busses can carry in 2 trips = 106 x 9 = 954
Answred by Gauthmath
find the area of the semi circle plss
Answer:
Step-by-step explanation:
Which equation has a graph that is a parabola with a vertex at (-2, 0)?
y= -2x^2
y = (x + 2)^2
y= (x – 2)^2
y= x^2 – 2
X+y=11
Graphing which function
Answer:
Step-by-step explanation:
slopee -1
y-intercept (0,11)
x y
0 11
1 10
95% confident that the true mean difference in mean crying time after being given a vitamin K shot between infants using conventional methods and infants held by their mothers is between ____________and ___________________. In other words, the mean crying time of infants given vitamin K shot using conventional methods is anywhere from ______________ less than to _______________more than the mean crying time of infants given vitamin K shot using new methods.
Solution :
Two sample T-test and CI : Conventional methods, New methods
Two sample T for conventional method Vs new method
N Mean StDev Se Mean
Conventional mean 30 35.3 20.8 3.8
New methods 30 35.1 22.3 4.1
Difference = μ (conventional method) - μ (new method)
Estimate for difference : 0.17
95% CI for difference : (-10.976, 11.309)
T-Test of difference = 0(vs <): T-value = 0.03 P-value =0.5119 DF = 57
95% confident that the true mean difference in mean crying time after being given a vitamin K shot between infants using conventional methods and infants held by their mothers is between -10.976 and 11.309. In other words, the mean crying time of infants given vitamin K shot using conventional methods is anywhere from -10.976 less than to 11.309 more than the mean crying time of infants given vitamin K shot using new methods.
WORTH 15 POINTSSSSSSSSS
Answer:
15
Step-by-step explanation:
Difference in distances = 75-60 = 15 miles
So Car A travels 15 miles more than Car A in an hour
Answered by Gauthmath
The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
A graph titled daily text messaging has number of text on the x-axis, going from 8 to 248 in increments of 30. Data is distributed normally. The highest point of the curve is at 128.
What percentage of young adults send between 68 and 158 text messages per day?
34%
47.5%
81.5%
95%
This value is approximate.
====================================================
Explanation:
We have a normal distribution with these parameters
mu = 128 = population meansigma = 30 = population standard deviationThe goal is to find the area under the curve from x = 68 to x = 158, where x is the number of text messages sent per day. So effectively, we want to find P(68 < x < 158).
Let's convert the score x = 68 to its corresponding z score
z = (x-mu)/sigma
z = (68-128)/30
z = -60/30
z = -2
This tells us that the score x = 68 is exactly two standard deviations below the mean mu = 128.
Repeat for x = 158
z = (x-mu)/sigma
z = (158-128)/30
z = 30/30
z = 1
This value is exactly one standard deviation above the mean
-------------------------------------------
The problem of finding P(68 < x < 158) can be rephrased into P(-2 < z < 1)
We do this because we can then use the Empirical rule as shown in the diagram below.
We'll focus on the regions between z = -2 and z = 1. This consists of the blue 13.5% on the left, and the two pink 34% portions. So we will say 13.5% + 34% + 34% = 81.5%
Approximately 81.5% of the the population sends between 68 and 158 text messages per day. This value is approximate because the percentages listed in the Empirical rule below are approximate.
Answer:
C. 81.5%
Step-by-step explanation:
PLEASEEEE HELP
In the diagram, AABC-ADEC What is the value of x?
Similar triangles are proportional, meaning one will be a factor larger or smaller than the other. This factor will be the same for all of the sides. So, we can say that one corresponding pair of sides is equal to another corresponding pair of sides.
BA / ED = AC / CD
42 / 6 = (64 - x) / (x)
6(64 - x) = 42(x)
384 - 6x = 42x
384 = 48x
x = 8
Hope this helps!
A number increased by 100% and decreased by 20% is x. what is the number ? NEEDED TODAY
Answer:
Let's assume the number be 100.
According to the problem , 100 is increased by 100%.
So, new number will be 100+100=200
Now 200 will decreased by 20%.
So, 20% of 200= 0.20*200= 40.
So, again the number has been changed into 200+40=240.
So, x=240
Step-by-step explanation:
9514 1404 393
Answer:
x/1.6
Step-by-step explanation:
Let n represent the number. When n is increased by 100%, its new value is ...
n(1 +100%) = n(1 +1) = 2n
When this value is decreased by 20%, its new value is ...
(2n)(1 -20%) = (2n)(0.8) = 1.6n
This value is x, so the number is ...
1.6n = x
n = x/1.6 . . . . . . . divide both sides by 1.6
Find the measure of the incanted angle to the nearest degree
Answer:
15.5⁰ or approximately 16⁰
Step-by-step explanation:
let unknown side be x
cos x= 53/55
cos x= 0.9636
x=cos inverse of 0.9636
x=15.5⁰
Answer:
[tex]cosx = \frac{53}{55} \\ x = {cos}^{ - 1} ( \frac{53}{55} ) \\ x = 15.4987[/tex]
Which choice correctly shows the solution(s) of the equation x2 = 1442
A)
x= √144
B)
x=V12
X=-
-V144
D)
x = 1V144
Answer:
Step-by-step explanation:
If the 2s are exponents, you need to indicate this with "^":
x^2 = 144^2 means x² = 144²
x = ±√144² = ±144
Answer:
Step-by-step explanation:
f the 2s are exponents, you need to indicate this with "^":
x^2 = 144^2 means x² = 144²
x = ±√144² = ±144
For a 13-person team, how does the actual weekly labor cost compare to the targeted labor cost?
The actual labor cost is $600 over the targeted labor cost.
Given that,
Work done by each person per week = 40 hours
Required labor hours per week = 600 hours
No. of workers in the team = 13
To find,
Actual weekly labor cost = ?
Procedure:
Actual weekly labor cost = No. of workers * no. of hours performed by them
[tex]= 13 * 40[/tex]
[tex]= 520 hours[/tex]
Given that,
[tex]Regular rate = $ 15.00 per hour[/tex]
[tex]Overtime rate = $ 22.50 per hour[/tex]
Thus,
Actual labor cost = (regular hours worked * regular rate) + (overtime * overtime rate)
[tex]= (520 * 15) + ([600 - 520] * 22.50)[/tex]
[tex]= $ 7,800 + $ 1,800[/tex]
[tex]= $ 9600[/tex]
Targeted Labor cost = $ 9,000 per week
Thus, option C i.e. the actual labor cost is $ 600 over the targeted labor cost.
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Can anyone help with this math equation please?
In a random sample of 7 residents of the state of Maine, the mean waste recycled per person per day was 1.4 pounds with a standard deviation of 0.23 pounds.
a. Determine the 95% confidence interval for the mean waste recycled per person per day for the population of Maine. Assume the population is approximately normal.
b. Find the critical value that should be used in constructing the confidence interval.
Answer:
a) The 95% confidence interval for the mean waste recycled per person per day for the population of Maine is between 1.19 and 1.61 pounds.
b) [tex]T_c = 2.4469[/tex]
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 7 - 1 = 6
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.4469, and the answer to question b is [tex]T_c = 2.4469[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.4469\frac{0.23}{\sqrt{7}} = 0.21[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.4 - 0.21 = 1.19 pounds.
The upper end of the interval is the sample mean added to M. So it is 1.4 + 0.21 = 1.61 pounds.
The 95% confidence interval for the mean waste recycled per person per day for the population of Maine is between 1.19 and 1.61 pounds.
33. The population of Canada, y (in millions), can be approximated by the relation y=
0.146x + 31, where x represents the number of years since 2000.
a. Approximate the population of Canada in the year 2006.
b. In what year did the population of Canada reach approximately 32,752,000?
Answer:x=6573/500,x=13(73/500
Step-by-step explanation:
It will takes 12 years to reach approximately 32,752,000.
What is Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given:
y = 0.146x + 31
where x represents the number of years since 2000.
a) The population of Canada in the year 2006
x= 6
y= 0.146 x 6 + 31
y = 31.876
b) The population of Canada reach approximately 32,752,000 in
y = 32.752
0.146x + 31= 32.752
0.146x = 1.752
x= 1.752/0.146
x= 12
Hence, it will takes 12 years to reach approximately 32,752,000.
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write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
VW ≈ 4.0
Step-by-step explanation:
Using the sine ratio in the right triangle
sin35° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{VW}{VX}[/tex] = [tex]\frac{VW}{7}[/tex] ( multiply both sides by 7 )
7 × sin35° = VW , then
VW ≈ 4.0 ( to the nearest tenth )
Please show work will mark you brainliest!
QUESTION:- An artist uses 200 tiles to create a tessellation design that covers a rectangle with dimensions 2 ft by 3 ft. He will cover a wall with dimensions 10 ft by 15 ft using the same design and tiles of the same size. How many tiles will he need to cover the entire wall?
ANSWER:-
CASE 1 :- NUMBER OF TILES USED -> 200AREA WHICH IS TO BE COVERED-> 2×3 ft² (given-> rectangle)CASE 2:-
AREA WHICH IS TO BE COVERED-> 10×15 ft² (given-> rectangle)NUMBER OF TILES:- TO FINDIT IS GIVEN THAT DESIGN AND SIZE OF TILES R SAME SO WE CAN CONSIDER THAT SAME NUMBER OF TILES WILL COVER SAME AREA IN BOTH CASE.
WE CAN USE UNITARY METHOD FOR SOLVING THIS:-
[tex]6ft² \: is \: covered \: using \: 200 \: tiles \\ 1ft² \: is \: covered \: using \: \frac{200}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times 150}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times \cancel{150}^{ \: \: 25} }{ \cancel6 {}^{ \: 1} } \: tiles \\ 150ft² \: is \: covered \: using \: 200 \times 25 \: tiles \\ 150ft² \: is \: covered \: using \: 5000 \: tiles[/tex]
