Anybody know how to do the last 2. Pls its due in the morning!

Answer:

f = 1, w = 4

Step-by-step explanation:

Given the 2 equations

5w = 23 - 3f → (1)

4f = 12 - 2w (add 2w to both sides )

2w + 4f = 12 ( subtract 4f from both sides )

2w = 12 - 4f → (2)

Multiplying (1) by 4 and (2) by - 3 and adding the result will eliminate f

20w = 92 - 12f → (3)

- 6w = - 36 + 12f → (4)

Add (3) and (4) term by term to eliminate f

14w = 56 ( divide both sides by 14 )

w = 4

Substitute w = 4 into either of the 2 equations and solve for f

Substituting into (1)

5(4) = 23 - 3f

20 = 23 - 3f ( subtract 23 from both sides )

- 3 = 3f ( divide both sides by - 3 )

1 = f

Answer:

Step-by-step explanation:

Answer:

.

Step-by-step explanation:

2: 5, 10, 261.8, 785.4, 0.33

3: 7, 20, 1,026.3, 3,078.8, 0.33

4: 8, 6, 402.1, 1,206.4, 0.33

5: 12, 11, 1,658.8, 4,976.3, 0.33

Answer:

The equation has two zeros because the discriminant is greater than 0.

Step-by-step explanation:

3x^2 – 7x + 4

a=3   b = -7   c=4

The discriminant is

b^2 -4ac

(-7)^2 - 4(3)(4)

49 - 48

1

Since the discriminant is greater than zero, there are two real solutions

Answer:

The equation has two zeros because the discriminant is greater than 0.

Step-by-step explanation:

Answer:

or, -4a - 2a -7 = 11

or, -4a -2a =11 +7

or, - 6a = 18

or, a= 18÷ -6

a= -3

Answer:

[tex]q^{-30}[/tex]

Step-by-step explanation:

[tex](p^{2}q^{5})^{-4}\cdot(p^{-4}q^{5})^{-2}\\=p^{-8}q^{-20}\cdot p^{8}q^{-10}\\=p^{-8+8}\cdot q^{-20+-10}\\=q^{-30}\\[/tex]

Answer:

102

Step-by-step explanation:

x= 12

y= 30

z= 60

Hope u got it

Answer:

Hello,

a) -6

b) -39

c) 102

Step-by-step explanation:

I suppose this are sequence arithemical or geometrical

[tex]a)\\u_1=-14\\u_2=x\\u_3=-6\\u_4=y\\u_5=2\\u_6=z\\u_7=10\\\\We\ see\ that\ :\\u_3-u_1=-6-(-14)=-6+14=8\\u_5-u_3=2-(-6)=2+6=8\\u_7-u_5=10-2=8\\\\We\ may \imagine\ that\ the\ difference\ bethween\ 2\ terms\ is\ =8/2=4\\\\so\ x=-10, y=-2, z=6 \ and\ x+y+z=-10+(-2)+6=-6\\[/tex]

[tex]b)\\u_1=x\\u_2=-2\\u_3=4\\u_4=y\\u_5=16\\u_6=z\\u_7=64\\\\We\ see\ that\ :\\\\\dfrac{u_5}{u_3}=\dfrac{16}{4} =4\\\dfrac{u_8}{u_6}=\dfrac{64}{16} =4\\\dfrac{u_3}{u_2}=\dfrac{4}{-2} =-2\\\\The\ common\ factor\ is\ -2\\\\u_1=x=\dfrac{u_2}{-2} =1\\\\u_4=y=\dfrac{u_5}{-2} =-8\\\\u_6=z=\dfrac{u_7}{-2} =-32\\x+y+z=1+(-8)+(-32)=-39\\[/tex]

c)

All those numbers are divisor of 3*4*5=60

x=12, y=30, z=60

x+y+z=12+30+60=102

Answer:

-8 5/20 , 4/25 , 9/20

Step-by-step explanation:

If there are negative numbers, those are the least. Let's say the number was -2 and -1. With a positive integer, 2 would be greater, but since it's negative, it's the least. SO -8 and 5/20 would be the least. Then putting the other two fractions into decimal form, or you can find the greatest common denominator, you'll find that 9/20 is greater than 4/25.

C

since the graph is almost symmetrical then the mode,median and mean are approximately equal

7n-16

Step-by-step explanation:

Sry can u give me the picture

Answer: C . 147π / 4 mi²

Concept:

The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.

A = (θ / 360) πr²

θ = angle of the sector

π = constant

r = radius

Solve:

Given variable

θ = 270°

r = 7 mi

Given formula

A = (θ / 360) πr²

Substitute values into the formula

A = (270 / 360) π (7)²

Simplify exponents

A = (270 / 360) π 49

Simplify by multiplication

A = (147 / 4) π

A = 147π / 4

Hope this helps!! :)

Please let me know if you have any questions

Answer:

50

Step-by-step explanation:

= 3^3 + (2 x 2 x 3) + 2^2 + ( 3 + 2)^5

= 3^3 + (12) + 2^2 + (3 + 2)^5

= 3^3 + 12 + 2^2 + (5)^5

= 9 + 12 + 2^2 + 5^5

= 9 + 12 + 4 + 5^5

= 9 + 12 + 4 + 25

= 50

[tex]\\ \rm\Rrightarrow (5x+1)(5x-1)[/tex]

[tex]\\ \rm\Rrightarrow (5x)^2-(1)^2[/tex]

[tex]\\ \rm\Rrightarrow 25x^2-1[/tex]

Answer: 25x²-1

i have attached a graph of it if you need it :)

Step-by-step explanation:

the area of a triangle is baseline×height/2

in case of such a right-angled triangle we can use the sides that enclose the 90 degree angle as baseline and height.

so,

B = 8×6/2 = 8×3 = 24 yd²

the height h is 8 yd (as the picture clearly shows).

the perimeter of the base is the sum of all three sides

P = 8 + 6 + 10 = 24 yd

Step-by-step explanation:

look it is very easy.

use formula of simple interest

Answer:

this is even math bro

Step-by-step explanation:  

Answer:

16 packs

Step-by-step explanation:

Take the number of children and divide by the number of pens in a pack

125/8

15.625

We need to round up to get the number of packs

16 packs

Answer:

125 pens and 16 packs.

Step-by-step explanation:

Given:

Each child gets 1 pen, so there needs to be 125 pens.

Since there are 8 pens in a pack, there will need to be:

125 / 8 = 15.62

Estimate:

16 packs

There needs to be 16 packs for the 125 children.

Please explain in english

Answer:

Đáp án: 180km

Step-by-step explanation:

Giải thích các bước giải:

Gọi quãng đường AB là x (km)

            (x > 0)

Thời gian ô tô đi từ A -> B là x/60 (h)

Thời gian ô tô đi từ B -> A là x/45 (h)

Vì thời gian cả đi và về hết 7h

=> x/60 + x/45 = 7

=> x = 180 (TM)

Vậy quãng đường AB là 180 km

Answer:

C

Step-by-step explanation:

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Let the adding value be x

ATQ

[tex]\\ \sf\longmapsto \dfrac{2+x}{5+x}=\dfrac{5}{6}[/tex]

[tex]\\ \sf\longmapsto 6(2+x)=5(5+x)[/tex]

[tex]\\ \sf\longmapsto 12+6x=25+5x[/tex]

[tex]\\ \sf\longmapsto 6x-5x=25-12[/tex]

[tex]\\ \sf\longmapsto x=13[/tex]

Answer:

a=35,b=49,c=-14

Step-by-step explanation:

[tex]\frac{a}{-5} =\frac{b}{-7} =\frac{c}{2} =r(say)\\a=-5r,b=-7r,c=2r\\a-b+c=-5r+7r+2r=4r=-28\\r=\frac{-28}{4}=-7\\a=-5 \times -7=35\\b=-7 \times -7=49\\c=2 \times -7=-14[/tex]

Answer:

Step-by-step explanation:

Answer:

11x+6

Step-by-step explanation:

9x + 4 + 2x + 2

Combine like terms

9x+2x   + 4 +2

11x     +6

on a horizontal number line . numbers to the left are less than numbers to the right .. numbers to the right are less than numbers to the left

Step-by-step explanation:

what is the condition of loss ?1)sp>mp 2)CP>sp 3) sp>CP 4)mp>sp

Answer:

a^2 +4ab+4b^2

Step-by-step explanation:

(a+2b)^2

(a+2b)(a+2b)

FOIL

first: a*a = a^2

outer:  a*2b = 2ab

inner: 2b*a = 2ab

last: 2b*2b = 4b^2

Add them together

a^2 +2ab+2ab+4b^2

Combine like terms

a^2 +4ab+4b^2

Answer:

Solution given:

(a+2b)²

we have

by using formula

(a+b)²=a²+2ab+b²

so

we get

a²+2*a*2b+(2b)²

=a²+4ab+4b²

Answer:

The value of this number is 31.

Step-by-step explanation:

To solve this you could set up an equation and solve for x.

Sum means add, so you are going to add 2n and 13 to get 75.

2n + 13 = 75

Subtract 13 from both sides.

2n = 62

To get n alone, divide by 2 on both sides.

n = 31

The value of this number is 31.

Have a nice day, please mark brainliest if possible! :)

Answer:

D

Step-by-step explanation:

A. Sin 42=0.669

Cos=52=0.617

B. Sin 90=1

cos 90=0

C. cos30=0.866

sin 70=0.940

D. sin80=0.985

cos 10=0.985

Answer:

[tex]x=20[/tex]

Step-by-step explanation:

Refer to the diagram below for letter names of points.

Using the theorem provided on the second image, we can conclude that [tex]m\angle AOC=2*m\angle ABC=2*100\textdegree = 200\textdegree[/tex]. Keep in mind that this is the reflex [tex]\angle AOC[/tex].

Because [tex]O \in DC[/tex], we know that [tex]DC[/tex] is a diameter by definition, which makes [tex]m\angle DOC = 180\textdegree[/tex].

Using the Angle Addition Postulate, we can write the following equation:

[tex]m\angle AOD+m\angle DOC=m\angle AOC[/tex]

Substituting the measures of each angle into the equation gives us:

[tex]x\textdegree + 180\textdegree = 200\textdegree[/tex]

Solving the equation for [tex]x[/tex] gives us:

[tex]x\textdegree + 180\textdegree = 200\textdegree[/tex]

[tex]x\textdegree + 180\textdegree - 180\textdegree = 200\textdegree - 180\textdegree[/tex] (Subtract [tex]180\textdegree[/tex] from both sides of the equation to isolate [tex]x[/tex])

[tex]x\textdegree = 20\textdegree \rightarrow \bf x=20[/tex] (Simplify)

Remember that [tex]x=20[/tex], not [tex]20\textdegree[/tex] because the degree symbol was already given in the original expression. Hope this helps!