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Answerrrrrrrrr

Answer:

H₂ + O₂ → H₂O

Now, check that oxygen has two atoms on the left and one on the right

so, you put 2 on the right side

H₂ + O₂ → 2H₂O

oxygen is balanced so, add 2 on H₂ to balance out hydrogen

THE FINAL BALANCED EQUATION:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

1 mole of [tex] \sf{ COCl_2} [/tex] has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of [tex] \sf{COCl_2} [/tex] will have ~

[tex]\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \approx4.7 \times 10 {}^{23} \: \: \: molecules[/tex]

1.3 x 10¹⁵ : 1.2 x 10⁹ = 1.083 x 10⁶

Answer:

1.3x 10 15 gallons of water / 1.2x 10 9 gallons/day=

1.1x 10 6 gallons/day

Explanation:

The reactants are Option C , dilute hydrochloric acid and magnesium which turns methyl orange from red to orange .

Indicators are substances that change colour when they are added to acidic or alkaline solutions.

Litmus, phenolphthalein, and methyl orange are all indicators that are commonly used in the laboratory.

Methyl orange in an acidic medium turns Red or orange , Yellow in neutral medium and Yellow in akaline medium .

Phenolphthalein in an acidic medium turns Colourless , Colourless in neutral medium and Pink in akaline medium .  

Magnesium reacts with hydrochloric acid to produce hydrogen gas

Mg (s) + 2 HCl (aq) → MgCl₂ (aq) + H₂ (g)

In this reaction, the magnesium and acid are gradually used up. However the acid is in excess, so it is mainly the loss of magnesium.

So the solution is acidic and therefore when methyl orange are added to a reaction mixture methyl orange turns from red to orange

Therefore the The reactants are Option C , dilute hydrochloric acid and magnesium which turns methyl orange from red to orange and H₂ gas is produced .

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CH₂O = C + 2.H + O

= 12.01 + 2 x 1.008 + 16

= 30.026 amu = 30.026 g/mol

The answers of every subquestion is given below:

Percent yield of the reaction is the percent ratio of actual yield to the theoretical yield.It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%.

The theoretical yield is the amount predicted by a stiochiometric calculation based on the number of moles of all reactants present.

This calculation assumes that only one reaction occurs and that the limiting reactant reacts completely.

The actual yield is the quantity of a product that is obtained from a chemical reaction.

          2 C₆H₁₀ + 17 O₂ ⇒ 12 CO₂ + 10 H₂O

1. When you do this calculation for 35 grams of C₆H₁₀, you find that 113 grams of CO2 will be formed.

When you do the calculation for 45 grams of oxygen,You find that 43.7 grams of CO2 will be formed.Because 43.7 grams is the smaller number forming 43.7 grams of product.

2. Oxygen is the limiting reagent

3. 21.4 grams of C₆H₁₀ will be left over.

4.  80.1%

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Answer:

D

Explanation:

While evaluating you will notice if it works or not

Answer:

The Clean Water Act and the Endangered Species Act.

Explanation:

mining operations must follow these regulations or else they will not be able to use the land

Answer:

Answer: (b) F

Explanation:

Sodium has 1, magnesium has 2 and Aluminium has 3 electrons in its outermost shell whereas Fluorine has 7 electrons in its outermost shell hence Fluorine does not lose electrons easily.

The electronic configuration of fluorine is 2,7.

Fluorine is the ninth element with a total of 9 electrons.

The first two electrons will go in the 1s orbital.

The next 2 electrons for F go in the 2s orbital.

The remaining five electrons will go in the 2p orbital. Therefore the F electron configuration will be 1s22s22p5.

The value of concentration of H₃O⁺ of the polyprotic acid solution 0.140M H₃C₆H₅O₇ is 2.1×10⁻⁴M.

Ka is the acid dissociation constant which shows its value in the equilibrium condition.

Given chemical reaction with ICE table is:

                          H₃C₆H₅O₇   →   C₆H₅O₆⁻   +   H₃O⁺

Initial:                    0.140                 0                  0

Change:                    -x                   +x                 +x

Equilibrium:         0.140-x                x                   x

Ka for the acid = (x)(x) / (0.140-x)

For the H₃C₆H₅O₇ acid value of Ka = 3.2 × 10⁻⁷

We can neglect the value of x from the term 0.140-x, as x is vey small as compared to 0.140 so that equation becomes,

3.2 × 10⁻⁷ = x² / 0.140

x = 2.1×10⁻⁴M

Hence the concentration of H₃O⁺ is 2.1×10⁻⁴M.

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A factor which helped to first drive plants to live on land is: A. greater access to sunlight on land.

In Science, photosynthesis is a light-dependent process and it is typically represented by the following chemical reaction:

Carbon dioxide + water + light energy ⇒ sugar + oxygen

Based on the chemical reaction above, we can infer and logically deduce that light energy (sunlight) obtained from the Sun is a very important factor for photosynthesis.

Consequently, greater access to sunlight on land became a factor which helped to first drive plants to live on land.

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Answer:

it is A step by step

Explanation:

Answer:

recycle and dispose of trash properly

minimize use of fertilizer

use environmentally friendly modes of transportation

scientists say creating marine refuges where fishing, mining, and recreating are off limits, make the reefs healthier, and so more resilient

Answer:          gugygy

Explanation:

When aqueous sodium phosphate reacts with aqueous copper(ii) sulfate then the formation of Cu₃(PO₄)₂ precipitate and aqueous solution of sodium sulfate takes place.

Double displacement reactions are those reactions in which two elements are displaced within the reaction.

Given chemical reaction is:

Na₃PO₄(aq) + CuSO₄(aq) → Cu₃(PO₄)₂(s) + Na₂SO₄(aq)

In the above reaction sodium and copper ions are displaced between each other by which Cu₃(PO₄)₂ precipitate and aqueous solution of sodium sulfate is formed.

Hence in the above reaction precipitate of Cu₃(PO₄)₂ is formed.

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Answer:

2.00 Cups

Explanation:

This question isn't really possible without the density of the sugar, you can pack it tighter like if you have sugar cubes for example, but a quick search gives a density of 1.59 g/mL, so that what I will use.

Let's get the number of grams of sucrose (molar mass 342.3 g/mol) we have by taking 342.3 g/mol * 0.880 mol. Moles cancel and we get 301.224 grams of sucrose.

Now we just need to take the density, there is one mL for every 1.59 grams of sucrose, so we will take (301.224 g)/(1.59 g/mL). grams cancel and we are left with 478.94616 mL.

The question asked for cups (I'm assuming US cups) though, so let's convert by dividing by 240 to give us 1.995609 cups. Or when we round to sig figs we get 2.00 cups.

Answer:

See below

Explanation:

goes down....turns more acidic   as HCl is added to water

Answer:

Decrease

Explanation:

There will be a decrease in the pH of the water solution.

Answer:

C20

Explanation:

Element is a pure substance which is composed of atoms of similar elements. It can not be decomposed into simpler constituents using chemical reactions. Example: Carbon

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass. It can be decomposed into simpler constituents using chemical reactions.

Example: Carbon monoxide.

Thus chemical symbol represents an element is C20

Pretty sure this is what you're looking for.

The molality of a solid solution containing 867 g of aluminum and 14.9 g of copper is 0.27 mol/kg.

The molality of a solution is a way to express the concentration of the solute in a given mass of solvent.

Molality of solution is given by the formula given below:

In the given solid solution, aluminium is the solvent while copper is the solute.

Mass of solvent = 867 g = 0.867 Kg

Moles of solute = mass/molar mass

molar mass of copper = 64.0 g

moles of solute = 14.9/64 = 0.233 moles

Molality of solution = 0.233 mol/0.867 kg = 0.27 mol/kg.

Therefore, the molality of a solid solution containing 867 g of aluminum and 14.9 g of copper is 0.27 mol/kg.

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Coefficient A: 2 must be added to the product to balance the equation.

 The mass of the reactant side is always equal to the mass of the reactant side.

To balance the chemical equation coefficient is added to make the number of atoms equal on both sides.

                La₂O₃+ 3H₂O => 2La(OH)₃

Left-hand side of atoms is equal to right-hand side La=2            

                                                                                     O=6

                                                                                     H =6

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Answer:

Keep the pace of 5 C up until you get to about 60 C. Than Measure the totl amount of heat added to the factor of these numbers.

Explanation:

Answer:

3 g

Explanation:

new mass = (1/2)^n * original mass

where n = number of half lives

(1/2) ^2 * 12

= 3 g

The symbol of the radioactive nuclide given the data is superscript 40 subscript 19 upper K (⁴⁰₁₉K)

An atom is composed of sub-particles which include

The symbol of an atom showing its atomic number and molar mass can be represented as follow

ⁿₓA

Where

ⁿₓA => ⁴⁰₁₉K

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Answer:

c

Explanation:

edge

The pOH of pure water at 40 degree C is 6.8, then the hydronium ion concentration in pure water at this temperature is 6.3 × 10⁻⁸M.

Relation between the pH and pOH will be represented by the following equation:

pH + pOH = 14

Given that, pOH of water = 6.8

Then pH will be pH = 14 - 6.8 = 7.2

We know that, pH = -log[H⁺]

[H⁺] = [tex]10^{-pH}[/tex]

[H⁺] = [tex]10^{-7.2}[/tex] = 6.3 × 10⁻⁸M

Hence concentration of hydronium ion at that temperature is 6.3 × 10⁻⁸M.

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Answer: +5

Explanation:

The oxidation number of potassium is +1, and the oxidation number of oxygen is -2. So, for the compound to have a charge of 0, the oxidation number of chlorine must be +5.

The rate of formation of water and the decomposition of hydrogen peroxide is double as compared to rate of formation of oxygen.

The chemical reaction is given as the reaction of the reactants in the process to form the new compound.

The chemical reaction with the decomposition of hydrogen peroxide is:

[tex]\rm 2\;H_2O_2\;\rightarrow 2\;H_2O\;+\;O_2[/tex]

The rate of formation of water is given to be double the rate of formation of oxygen as 2 moles of water formed with 1 mole of oxygen.

The rate of disappearance of hydrogen peroxide is double with formation of oxygen as for decomposition of 2 moles of hydrogen peroxide, 1 mole of oxygen is formed.

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