Answer:
x = A sin (wt + theta) where w = angular frequency - basic SHM equation
w = 8 pi = 2 pi f
f = 4 basic frequency
N = 8 number of times thru origin
Each cycle the particle will pass thru the origin +x and -x twice
Two forces are acting on a body. One acts east, the other at 35° north of east. If the
two forces are equal in magnitude of 50 N, find the resultant using the Law of Sines
and the Law of Cosines. Please answer with full solution. Thanks
A=B=50NAngle=theta=35°
We know
[tex]\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\Theta}}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{50^2+50^2+2(50)(50)cos35}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{2500+2500+2(2500)\times (-0.9)}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{5000+5000(-0.9)}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{5000+(-4500)}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{5000-4500}[/tex]
[tex]\\ \sf\longmapsto R=\sqrt{-500}[/tex]
[tex]\\ \sf\longmapsto R=22.4i[/tex]
Resultant using the Law of Sines and the Law of Cosines will be R=95 N
What is force?Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.
The Magnitude of two forces =50 N
Angle between the forces = 35
By using the resultant formula
[tex]\rm R=\sqrt{A^2+B^2+2ABCos\theta}[/tex]
[tex]\rm R=\sqrt{50^2+50^2+2(50)(50)Cos35}[/tex]
[tex]\rm R=\sqrt{5000+5000(0.81)}[/tex]
[tex]\rm R=\sqrt{5000+4500}[/tex]
[tex]\rm R=95\ N[/tex]
Hence the Resultant using the Law of Sines and the Law of Cosines will be R=95 N
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Which of the following exhibit the Tyndall Effect?
A flashlight beam through air in a room.
A laser beam through salt water.
Car headlights on a foggy night.
A laser beam through a soda drink.
Answer:
Probably all but (a)
The Tyndall Effect is caused by dispersion of the incident light by the individual molecules in the liquid.
Salt water and a foggy night will cause dispersion of the incident light.
A soda drink may also cause this dispersion, but and not sure.
Help again! Thank you all xoxo
Answer:
Amount of charge
Explanation:
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A magnifying glass produces a maximum angular magnification of 5.4 when used by a young person with a near point of 20 cm. What is the maximum angular magnification obtained by an older person with a near point of 65 cm
We do not use water instead of mercury in a barometer
Answer:
Because
1)Water is relatively less dense. Mercury is 13.6 times more dense than water. SO, If you use water, you have to have the length of barometer of length (or height) 13.534 times the length of mercury barometer, which may be more than 11 meter in length.
2)Also mercury as compared to water, has comparatively less specific heat and good conductor of heat, could come to the same temperature of the atmosphere more quickly.
Answer:
The atmospheric pressure at sea level 76 cm of Hg=1.013× 10⁵ pascal .
Explanation:
That is if water is used in barometer tube instead of mercury the length of the tube must be greater than 10.326 cm.so we cannot replace mercury by water in the barometer.
A very long straight wire carries a 12 A current eastward and a second very long straight wire carries a 14 A current westward. The wires are parallel to each other and are 42 cm apart. Calculate the force on a 6.4 m length of one of the wires.
Answer: 5.12x10∧-4N
Explanation:
Force = I B L
L = 6.4m
Let Current (I) I₁ = I₂= 14A
Distance of the wire = 42cm = 0.42m
BUT
B = μ₀I / 2πr
=(2X10∧-7 X 12) / 0.42
B =5.714×10∧-6T
Force = I B L
Force = 14x [5.714×10-6]×6.4
Force = 5.12x10∧-4N
The image shows a facility that converts the energy of moving water into
electrical energy. What is one advantage of using this technology in place of a
coal-burning power plant?
A. It is fueled by a nonrenewable resource.
B. It causes no harm to ecosystems.
оооо
C. It produces more water pollution.
D. It does not emit greenhouse gases.
Answer:
D. It does not emit greenhouse gases.
Explanation:
D. It does not emit greenhouse gases.
a dentist used a light have wavelength 450nm what is the energy of the light
Answer:
≈ 4.41 x 10^-19
Explanation:
The formula for the energy of light is...
E = hc / λ
where 'h' is Planck's constant: 6.626 x 10^-34 Js
'c' is the speed of light: 2.998 x 10^8 ms
& 'λ' is the wavelength (in this case): 450 nm
1 nanometer (nm) = 1 x 10^-9m
E = (6.626 x 10^-34 Js)(2.998 x 10^8 ms) / (450nm)(1 m / 10^-9 nm)
E ≈ 4.41 x 10^-19 J
I think that's the answer and I hope it helps!
Someone help me with these questions please!
Answer:
a 25 and b 25
2. 26
60n
An electron is moving at speed of 6.3 x 10^4 m/s in a circular path of radius of 1.7 cm inside a solenoid the magnetic field of the solenoid is perpendicular to the plane of the electron's path. Find its relevatn motion.
Answer:
Here, m=9×10
−31
kg,
q=1.6×10
−19
C,v=3×10
7
ms
−1
,
b=6×10
−4
T
r=
qB
mv
=
(1.6×10
−19
)(6×10
−4
)
(9×10
−31
)×(3×10
7
)
=0.28m
v=
2πr
v
=
2πm
Bq
=
2×(22/7)×9×10
−31
(6×10
−4
)×(1.6×10
−19
)
=1.7×10
7
Hz
Ek=
2
1
mv
2
=
2
1
×(9×10
−31
)×(3×10
7
)
2
J
=40.5×10
−17
J=
1.6×10
−16
40.5×10
−17
keV
=2.53keV
a bullet is dropped from the same height when another bullet is fired horizontally. they will hit the ground
Answer:
it will drop simultaneously
What is not one of the main uses of springs?
A. Car suspension
B. Bike suspension
C. The seasons
D. Clock making
As a skydiver accelerates downward, what force increases? A. Gravity B. Thrust C. Air resistance D. Centripetal
Answer:
(A) Gravity is you're answer.
Explanation:
When an object or human is falling at an increased rate, The force of gravity is taking place.
A rubber ball and a steel ball are dropped from the same height onto a concrete floor. They have the same mass, and lets assume that they both rebound to the same height after hitting the ground. How would the average forces experienced by the balls compare. Group of answer choices The steel ball would experience the greater average force The average forces would be the same The rubber ball would experience the greater average force
Answer:
The average forces would be the same
Explanation:
Both have the same velocity on impact as they fell from the same height.
Both have the same velocity after the bounce because they reach the same height.
Both have the same mass
Both will thus experience the same impulse because both have the same change in momentum.
Therefore both experience the same average force.
when 999mm is added to 100m ______ is the result
Answer:
what, 100.999m
Explanation:
convert 999 mm into meters, which is 0.999m and add that to a 100 m and that will make the total 100.999 m
The result of the addition of the two values is equal to 100.999 meters.
Given the following data:
Value 1 = 999 millimetersValue 2 = 100 metersTo determine the result of the addition of the two values:
First of all, we would convert the value in millimeter (mm) to meter (m) as follows:
Conversion:
1 millimeter = 0.001 meter
999 millimeter = X meter
Cross-multiplying, we have:
[tex]X = 0.001 \times 999[/tex]
X = 0.999 meter.
For the result:
[tex]Result = 0.999 +100[/tex]
Result = 100.999 meters.
Read more on measurements here: https://brainly.com/question/24842282
A roller coaster has a total track length of 500 yards. A complete ride on the roller coaster is considered two times around the track. The start and stop places for the ride are virtually the same. What are the distance and displacement for a ride on the roller coaster? Explain your answers.
Answer:
Explanation:
its 1000 yards if its going around the track 2 times and that if one whole around the track is 500 its 500 x 2
A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this tim
moves a distance of
meters.
Answer:
400m
Explanation:
[tex]x = v_{0}t + \frac{at^{2} }{2} \\x = 20*10+\frac{4*10x^{2} }{2} = 400m[/tex]Two resistors connected in series have an equivalent resistance of 690 Ohms. When they are connected in parallel, their equivalent resistance is 118 Ohms. Find the resistance of each resistor.
Explanation:
Let [tex]R_1[/tex] and [tex]R_2[/tex] be the the resistances of the resistors. We are given that
[tex]R_1 + R_2 = 690\:Ω\:\:\:\:\:\:\:(1)[/tex]
and
[tex]\dfrac{1}{R_1} + \dfrac{1}{R_2} = \dfrac{1}{118\:Ω}\:\:\:\:\:(2)[/tex]
From Eqn(1), we can write
[tex]R_2 = 690\:Ω - R_1[/tex]
and then plug this into Eqn(2):
[tex]\dfrac{1}{R_1} + \dfrac{1}{690\:Ω - R_1} = \dfrac{1}{118\:Ω}[/tex]
or
[tex]\dfrac{690\:Ω}{(690\:Ω)R_1 - R_1^2}= \dfrac{1}{118\:Ω}[/tex]
[tex]\Rightarrow R_1^2 - (690\:Ω)R_1 + (690\:Ω)(118\:Ω)= 0[/tex]
or
[tex]R_1^2 - 690R_1 + 81420 = 0[/tex]
Using the quadratic formula, we find that the above equation has two roots:
[tex]R_1 = 151.1\:Ω,\:\:538.9\:Ω[/tex]
This means that if you choose one root value for [tex]R_1[/tex], the other root will be the value for [tex]R_2[/tex].
If the horizontal range and the max height of a body projected at an angle titre to the horizontal is K and Q respectively. Show that the muzzle velocity Vo is given by: Vo=√[2gQ + K²/8Q]
Explanation:
Recall that
[tex]K = \dfrac{v_0^2\sin2\theta}{g}\:\:\:\:\:\:\:\:\:(1)[/tex]
and
[tex]Q = \dfrac{v_0^2\sin^2\theta}{2g}\:\:\:\:\:\:\:\:\:(2)[/tex]
From Eqn(2), we can write
[tex]\sin\theta = \sqrt{\dfrac{2gQ}{v_0^2}}\:\:\:\:\:\:\:\:\:(3)[/tex]
Using the identity [tex]\sin\theta = 2\sin\theta \cos\theta[/tex], we can rewrite Eqn(1) as
[tex]\dfrac{gK}{2v_0^2} = \sin\theta \cos\theta[/tex]
Squaring the above equation, we get
[tex]\dfrac{g^2K^2}{4v_0^4} = \sin^2\theta \cos^2\theta[/tex]
[tex]\:\:\:\:\:\:\:\:\:=\sin^2\theta(1 - \sin^2\theta)\:\:\:\:\:\:\:(4)[/tex]
Use Eqn(3) on Eqn(4) and we will get the following:
[tex]\dfrac{g^2K^2}{4v_0^4} = \dfrac{2gQ}{v_0^2}(1 - \dfrac{2gQ}{v_0^2})[/tex]
This simplifies to
[tex]\dfrac{gK^2}{8v_0^2Q} = 1 - \dfrac{2gQ}{v_0^2}[/tex]
Rearranging this further, we get
[tex]1 = \dfrac{2gQ}{v_0^2} + \dfrac{gK^2}{8v_0^2Q}[/tex]
Putting [tex]v_0^2[/tex] to the left side, we get
[tex]v_0^2 = 2qQ + \dfrac{gK^2}{8Q}[/tex]
Finally, taking the square root of the equation above, we get the expression for the muzzle velocity [tex]v_0[/tex] as
[tex]v_0 = \sqrt{2gQ + \dfrac{gK^2}{8Q}}[/tex]
b) Calculate the equivalent capacitance of the network shown below between the points A nd 'B', Given: C1 = C2 = 12uF.C3 = 7uF, CA = C5 = C6 =151F C6 =15uF
As No diagram attached I am taking all are connected in series
We know
[tex]\boxed{\sf C_{eq}=C_1+C_2\dots}[/tex]
[tex]\\ \sf \longmapsto C_{eq}=12+12+7+15+15+15[/tex]
[tex]\\ \sf \longmapsto C_{eq}=24+7+45[/tex]
[tex]\\ \sf \longmapsto C_{eq}=76\mu F[/tex]
which sources of associated with the line emission spectrum?
1) electric fire
2) neon street sign
3) red traffic light
4) sun
Answer:
Answer if this question neon street sign
Explanation:
may this answer is helpful for you
Two long straight wires are suspended vertically. The wires are connected in series, and a current from a battery is maintained in them. What happens to the wires? What happens if the battery is replaced by an a-c source?
Answer:
(i) When a battery is connected inseries to two long parallel wires, the currents in the two wires will be in opposite directions. Due to which a force of repulsion will be acting between them and they are moving further apart.
(ii) When a battery is connected in parallel to two long parallel wires, the currents in the two wires will be in same direction. Due to it, a force of attraction will be acting between them and they are coming closer to each other.
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Explanation:
Hope it will helps you lot!
Which of the units of the following physical quantities are derived
Answer:
where is the attachment
Explanation:
What is the final velocity if you have an initial velocity of 5 m/s with an acceleration of 3 m/s2 over a 4 second interval?
Answer: 17 m/s
Explanation:
Using the formula Vf=Vi+at
Vf=5m/s+3m/s^2(4s)
Vf= 17m/s
how is the area of a circle measured
Answer:
Area of circle is measured using formula πr² which means π×radius×radius and π could be 22/7 or 3.14
Explanation:
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Light of wavelength 600 nm illuminates a diffraction grating. The second-order maximum is at angle 39.2. How many lines per millimeter does this grating have?
Answer:
Diffraction equation applies in this case:
d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2
Substituting;
d* Sin 39.5 = 2*600*10^-9
d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m
In 1 mm (or 0.001 m), the number of lines is given as;
Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines
Open the sash half way up, take the beaker containing the dry ice / water out of the hood, and slowly move it from right in front of the hood all the way down to the floor. At what point do the fumes stop getting sucked up by the fume hood?
Answer:
The fumes stop getting sucked up by the fume hood once the beaker is pulled out of the hood.
For example, we can take Water
In (A) Water has same mass and great volume
In (B) Water has same mass and lower volume
Will there be any change in its density then?
Answer:
yes there will be change in its density
If you jump off a 5 m diving platform how long will take you hit the water
Answer:
t = 1.0s
Explanation:
^d = v_0*t + (1/2)*a*t²
(5m-0m) = 0m/s*t + (.5)(9.81m/s²)*(t)²
5m = (4.905m/s²)*t²
t² = 1.01937s²
t = √1.01937s²
t = 1.0s
5. An electron is moving north in a region where
the magnetic field is south. The magnetic force
exerted on the electron is:
A.Zero
B. up
C. down
D. east
E. west
Answer:
eastlove india
