An object is thrown with a horizontal velocity of 49mt/sec and a vertical velocity of 18.8 mt/sec. How long will the object take to return to earth. Please help asap

Answers

Answer 1

Answer:

The object takes 3.84 seconds to return to earth.

Explanation:

Projectile Motion

It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.

The initial velocity has two components, given by:

[tex]v_x=vo_x[/tex]

[tex]v_y=vo_y-gt[/tex]

Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.

The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:

[tex]vo_y-gt=0[/tex]

[tex]\displaystyle t_m=\frac{vo_y}{g}[/tex]

The initial vertical component of the velocity is 18.8 m/s, thus:

[tex]\displaystyle t_m=\frac{18.8}{9.8}=1.92~s[/tex]

The total time is double that time:

[tex]t_t=2*1.92~s=3.84~s[/tex]

The object takes 3.84 seconds to return to earth.


Related Questions

A car travels with a constant acceleration of 2.4 m/s2. Find the mass of the car if an 1850 N net force is required to produce this acceleration.

Answers

Answer:

770.83 kg

Explanation:

The mass of the car can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{1850}{2.4} \\ = 770.83333...[/tex]

We have the final answer as

770.83 kg

Hope this helps you

Starting at (0,0) an object travels 36 meters north and then it covers 20 meters east. What is
the magnitude and direction of its displacement? (

Answers

Answer:

Explanation:

Using the pythagoras theorem, the displacement is expressed as;

d² = x²+y²

y = 36m (north)

x = 20m east

Substitute;

d² = 36²+20²

d² = 1296+400

d² = 1696

d = √1696

d = 41.18m

For the direction;

theta = tan^-1(y/x)

theta = tan^-1(36/20)

theta = tan^-1(1.8)

theta = 60.95°

Hence the magnitude is 41.18m and the direction is 60.95°

Which best describes most covalent compounds? resilient brittle cold warm

Answers

Answer:

B) brittle

Explanation:

This describes most covalent compounds.

Answer:

B.)

Explanation:

The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.

A roller coaster car is traveling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is traveling 36 m/s. What is the average acceleration?

Answers

Answer:

Explanation:

F

Consider a cylindrical pipe with both ends open and fundamental resonance frequency 150 Hz. If this particular pipe has a length of L, what the wavelengths of three lowest modes produced by this pipe? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. L,2L, 3L b. 2L, L, 2L/3 с. 2L/3, L, 2L d. L, L/2, L/3 e. 4L, 24, 4L/3 f. 4L, 4L/3, 4L/5 g. Neither of above.

Answers

Answer:

answers, the correct one is b

Explanation:

For this problem we use the fact that since the ends are open at these points we have a maximum,

fundamental L =λ/2 λ = 2L

second harmonic L = λ λ = 2L / 2

third harmonic L = 3 λ/2 λ = 2L / 3

n harmonic lam = 2L / n

 with n an integer

therefore the length of the first three harmonics are: 2L, L, 2L / 3

when examining the different answers, the correct one is b

A 25 kg of bananas is being pushed across the floor with a force of 37.5 N. What is the acceleration of the crate?

Answers

the acceleration should be 1.5 because 37.5 divided by 25 is 1.5

mark me brainliest

What is the relationship between the focal length of a cylindrical mirror and its radius of curvature?

Answers

Answer:

Explanation:

Focal length (f) can be defined as the distance from the focal point to the centre of the surface of the mirror.

While radius of curvature (r) is the radius of the sphere of which the mirror forms a part.

Hence the relationship between the two is that the focal length is half of the length of the radius of curvature.

Mathematically,

F = r/2

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