An expression is shown below: \sqrt(50)+\sqrt(2) is it irrational or rational

Answer:

C.

0.5; 13.5; 1093.5

Step-by-step explanation:

Answer:

[tex]Max\ z = 1[/tex]

[tex]Min\ z = -9[/tex]

Step-by-step explanation:

Given

[tex]z = 4x + 5y[/tex]

[tex]x \ge -1[/tex]

[tex]y \le 2x +3[/tex]

[tex]y \le -1[/tex]

Required

The maximum and minimum of z

To do this, we make use of the graphical method

See attachment for graphs of

[tex]x \ge -1[/tex]

[tex]y \le 2x +3[/tex]

[tex]y \le -1[/tex]

The corner points of the function are:

[tex](x,y) = (-1,1)[/tex]

[tex](x,y) = (-1,0)[/tex]

[tex](x,y) = (-1,-1)[/tex]

We have:

[tex]z = 4x + 5y[/tex]

Calculate z with  the above values

[tex]z = 4(-1) + 5(1) = 1[/tex]

[tex]z = 4(-1) + 5(0) = -4[/tex]

[tex]z = 4(-1) + 5(-1) = -9[/tex]

So, we have:

[tex]Max\ z = 1[/tex]

[tex]Min\ z = -9[/tex]

You can model the ellipse with the equation

(x/6)² + (y/5)² = 1

If you're comfortable with calculus, read on.

Let x = 6 cos(t ) and y = 5 sin(t ), with 0 ≤ t ≤ π/2. Then the curve C parameterized by (x(t), y(t)) traces out one quarter of the ellipse. The arc length of this curve is given by the integral,

[tex]\displaystyle\int_C\mathrm ds = \int_0^{\pi/2}\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt \\\\ = \int_0^{\pi/2}\sqrt{36\sin^2(t)+25\cos^2(t)}\,\mathrm dt \\\\ = \int_0^{\pi/2}\sqrt{25+11\sin^2(t)}\,\mathrm dt \\\\ = 5\int_0^{\pi/2}\sqrt{1+\frac{11}{25}\sin^2(t)}\,\mathrm dt[/tex]

Unfortunately, you cannot find the exact value of this integral. (Well, you can, but it involves introducing a special kind of function; I'll link it in a comment.)

But you can approximate it, and the integral above comes out to about 8.657.

I'm not sure if there's a simpler, purely geometric way to estimate the arc length. But since the semiaxes (5 ft and 6 ft) are fairly close, you could try a circle with a radius somewhere in between. The arc length would range between 7.854 ft and 9.425 ft. If the material isn't too expensive, you can always overshoot and trim off the excess or repurpose it.

Answer:

g/c =m

Step-by-step explanation:

g=4cm-3cm

Combine like terms

g = 1cm

g =cm

Divide by c

g/c = cm/c

g/c =m

Answer:

y=-11

Step-by-step explanation:

A line can be represented by a linear equation of

[tex]y = mx + b[/tex]

where m is the slope and y is the y intercept.

The slope is 0 so this function will be

[tex]y = b[/tex]

Which is also called a constant function. The y intercept is -11. So the answer is

[tex]y = - 11[/tex]

Answer:

2

y = 3x-15

y=5x-35

x1=5

x2=7

distance between = 7-5 = 2

Step-by-step explanation:

Answer:

2769.25Secound...........

Answer:

-9xy+16x

Step-by-step explanation:

x(y-2)+3x(6-y)-7xy

xy-2x+18x-3xy-7xy

xy-3xy-7xy-2x+18x

-9xy+16x

Answer:

a) 4 packages

b) 7000 g or 7 kg

Step-by-step explanation:

x is the number of 250g packages and y is the number of 750g packages.

2x = y

3(x + 2 x (750 : 250)) = 5(y - 2)

3(x + 6) = 5(y - 2)

3(x + 6) = 5(2x - 2)

3(x + 6) = 5(2(x - 1))

3(x + 6) = 5 * 2 * (x - 1)

3(x + 6) = 10(x - 1)

3x + 18 = 10x - 10

(3x + 18) + 10 = (10x - 10) + 10

3x + 28 = 10x

28 = 10x - 3x

28 = 7x

x = 28/7

x = 4

y = 2 * 4 = 8

(250 * 4) + (750 * 8) = 7000 g

Answer:

4x-7=-5x²

or, 5x²+4x-7=0

so the standard form of the equation is,

5x²+4x-7=0

or, f(x) = 5x²+4x-7

Answered by GAUTHMATH

Complete question is;

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t². How long after launch does the projectile return to the ground?

Answer:

2 seconds

Step-by-step explanation:

We are told that the height function is given by;

h = 32t – 16t²

Now, the velocity will be the derivative of the height equation.

Thus;

v(t) = dh/dt = 32 - 32t

Now, for projectiles, at max height, v = 0.

Thus;

32 - 32t = 0

32t = 32

t = 32/32

t = 1 s

It will take the same time it took to get to Max height as it will to get to ground from that height.

Thus, total height = 1 + 1 = 2 seconds

Answer:

Is this a trick question ???

Why would the ratio of salt to pepper change if you doubled the recipe?

The amount of salt and pepper would double, but not the ratio...

the answer should be 2:3

Step-by-step explanation:

Answer:

C. 7 units

Step-by-step explanation:

The given parameters are;

The length of the chord of the circle, [tex]\overline{AC}[/tex] = 14 units

The orientation of the radius and the chord = The radius is perpendicular to the chord

We have in ΔAOC, [tex]\overline{AO}[/tex] = [tex]\overline{OC}[/tex] = The radius of the circle

[tex]\overline{OB}[/tex] ≅ [tex]\overline{OB}[/tex]  by reflexive property

The angle at point B = 90° by angle formed by the radius which is perpendiclar to the chord [tex]\overline{AC}[/tex]

ΔAOB and ΔCOB are right triangles (triangles having one 90° angle)

[tex]\overline{AO}[/tex] and [tex]\overline{OC}[/tex] are hypotenuse sides of ΔAOB and ΔCOB respectively and [tex]\overline{OB}[/tex] is a leg to ΔAOB and ΔCOB

Therefore;

ΔAOB ≅ ΔCOB, by Hypotenuse Leg rule of congruency

Therefore;

[tex]\overline{AB}[/tex] ≅ [tex]\overline{BC}[/tex] by Congruent Parts of Congruent Triangles are Congruent, CPCTC

[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex] by definition of congruency

[tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] by segment addition postulate

∴ [tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] =  [tex]\overline{AB}[/tex] + [tex]\overline{AB}[/tex] = 2 ×  [tex]\overline{AB}[/tex]

∴  [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex]/2

[tex]\overline{AB}[/tex] = 14/2 = 7

[tex]\overline{AB}[/tex] = 7 units.

Answer:

7 units

Step-by-step explanation:

Answer:

750kmph

Step-by-step explanation:

Average is sum of all parts divided by the number of parts.

Let Stot be average speed for total trip (800kmph).

Let S1 be speed for first quarter of trip (950kmph).

Let S2, S3, and S4 be the speeds of each of the remaining quarters respectively.

Let Sans be the average speed for the remaining three quarters of the trip (a.k.a. The Answer!).

Stot = (S1 + S2 + S3 + S4) / 4

800kmph = (950kmph + S2 + S3 + S4) / 4

3200kmph = 950kmph + S2 + S3 + S4

3200kmph - 950kmph = 2250kmph = S2 + S3 + S4

Divide both sides by 3.

2250kmph / 3 = (S2 + S3 + S4) / 3 = Sans

Sans = 750kmph

Answer:

[tex]16\pi\:\mathrm{units^2}\text{ or }50.24\:\mathrm{ units^2}[/tex]

Step-by-step explanation:

The area of a circle with radius [tex]r[/tex] is given as [tex]A=r^2\pi[/tex].

In the question, we're given [tex]r=4[/tex] and asked to solve for [tex]A[/tex].

Substituting [tex]r=4[/tex] into [tex]A=r^2\pi[/tex], we get:

[tex]A=4^2\pi,\\A=\boxed{16\pi\:\mathrm{units^2}}[/tex]

If we use [tex]\pi=3.14[/tex] as mentioned in the question, we would have:

[tex]A=16\pi=16\cdot 3.14=\boxed{50.24\:\mathrm{units^2}}[/tex]

Answer:

The width of the confidence interval based on the 784 women would be narrower than the  confidence interval based on the 327 women.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

From this, we have that the margin of error, and also the width, is inversely proportional to the sample size, that is, a larger sample size leads to a smaller margin of error and a narrower interval.

How would the width of the new confidence interval compare to the width of the  confidence interval based on the 327 women in the armed forces?

New interval: 784

Old interval: 327

Sample size increased, so the new interval will be narrower, and the correct answer is:

The width of the confidence interval based on the 784 women would be narrower than the  confidence interval based on the 327 women.

The slope is -1.

You have to find the two closest points where the line directly hits a number. For that, we have -3 in the first quadrant and -3 in the third quadrant. With this info, the line goes down 3 times and to the right 3 times,  The ratio would look like this: [tex]\frac{-3}{3}[/tex]. Divide both and you get -1. Hope that helped!

Answer:

Mike had 72 stamps

Ken had 120 stamps

Step-by-step explanation:

Given

[tex]M \to Mike[/tex]

[tex]K \to Ken[/tex]

[tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]

[tex]K + 24 = 3 * ( M - 24)[/tex]

Required

Find K and M

Make K the subject in: [tex]K + 24 = 3 * ( M - 24)[/tex]

[tex]K = 3 * ( M - 24) - 24[/tex]

Substitute [tex]K = 3 * ( M - 24) - 24[/tex] in [tex]\frac{1}{5} * K = \frac{1}{3} * M[/tex]

[tex]\frac{1}{5} * [3 * ( M - 24) - 24] = \frac{1}{3} * M[/tex]

Open brackets

[tex]\frac{1}{5} * [3M - 72 - 24] = \frac{1}{3} * M[/tex]

[tex]\frac{1}{5} * [3M -96] = \frac{1}{3} * M[/tex]

Multiply both sides by 15

[tex]3* [3M -96] = 5 * M[/tex]

[tex]9M -288 = 5M[/tex]

Collect like terms

[tex]9M -5M= 288[/tex]

[tex]4M= 288[/tex]

Divide both sides by 4

[tex]M= 72[/tex]

Substitute [tex]M= 72[/tex] in [tex]K = 3 * ( M - 24) - 24[/tex]

[tex]K = 3 * (72 - 24) - 24[/tex]

[tex]K = 3 * 48 - 24[/tex]

[tex]K = 120[/tex]

Answer:

1) 0.7104 = 71%

2) 0.6615 = 66%

3) 0.8944 = 89%

Step-by-step explanation:

1)

Z(low)=-2.333 0.009815329

Z(upper)=0.583 0.720165536

2)

Z(low)=0.333 0.63055866

Z(upper)=8322.908 1

3)

Z(low)=-10.417 0

Z(upper)=1.25 0.894350226

Answer:

the answer is a and ik because I just had the test

Answer:

the answer is option 1

Step-by-step explanation:

the negative angle => a quarter round angle (clockwise) = ¼ x ( -360°) = -90°

and

the positive angle => a full round angle + 270° = (360°)+270°

= 630°

Answer:

correct answer is -90 and 630

Step-by-step explanation:

Answer:

2020³-1/4041

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

x÷3 dư 1-->x=3a+1

y÷3 dư 2-->y=3b+2

x×y=(3a+1)×(3b+2)

=9ab+6a+3b+2

Mà 9ab, 6a, 3b chia hết cho 3, 2 chia 3 dư 1

==>x×y chia 3 dư 2

Step-by-step explanation:

LCM of 7 and 5 is 35

now will make the denominator equal,

10+7/35

So, Ram's work = 10/35

Shyam's work = 7/35

so

Ram > Shyam

hope it helps

Answer:

The conic section for the equation 5x^2 - y = 12 is parabola

Answer:

Step-by-step explanation: