Aaron uses 18% of the paper in a printer paper package when she print a report for social studies class this is 90 sheets of paper how many sheets of paper are there in the printer paper in a package?
Answer:
percentage of paper used= 18%
Number of papers printed= 90
Total number of papers in the paper package= 'y'
total number of papers
= [tex]\frac{18}{100}[/tex] × y =90
transpose to the other side,
y= 90 ×[tex]\frac{100}{18}[/tex]
y=10 x100
y=1000
hence total number of papers in the package is 1000
Hope this helps
Please mark me as brainliest
Consider the value of t such that 0.01 of the area under the curve is to the right of t. Assuming the degrees of freedom equals 27, determine the t value. Round your answer to three decimal places.
The t-value that satisfies the condition is t = 2.797 (rounded to three decimal places).
To determine the t-value such that 0.01 of the area under the curve is to the right of it, we need to use a t-distribution table or a statistical software.
The t-distribution is characterized by its degrees of freedom, which in this case is given as 27.
To find the t-value corresponding to an upper tail probability of 0.01, we need to locate the critical value in the t-distribution table.
Since we're looking for the right tail, we want to find the t-value that corresponds to a cumulative probability of 1 - 0.01 = 0.99.
Let's denote this critical value as t(critical).
Using the t-distribution table or a statistical software, we find that the t-value for a cumulative probability of 0.99 with 27 degrees of freedom is approximately 2.797.
Therefore, the t-value that satisfies the condition is t = 2.797 (rounded to three decimal places).
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Given: ABCD is a trapezoid,
AB= 13, CD = 14,
BC = 5, and AD= 20.
Find: A
ABCD
Answer:
A=13×13
=169sqr.units
look at the image below
Answer:
SA = 153.9m^2
Step-by-step explanation:
SA = 4[tex]\pi[/tex][tex]r^{2}[/tex]
r = 3.5
SA = 4[tex]\pi[/tex][tex](3.5)^{2}[/tex]
SA = 4[tex]\pi[/tex](12.25)
SA = 49[tex]\pi[/tex]
SA = 153.9m^2
At a retail store they needed to do surveys of 32 stores which equals 40% of all their stores.How many stores does the owner have in total?
Answer:
=32÷40%
=32÷0.4
=80
the owner have total 80 stores
Step-by-step explanation:
th
Answer:
80.
Step-by-step explanation:
40 % = 32 stores, so:
10% = 32/4 = 8 stores, and
100% = 8*10 = 80 stores.
The organic garden at a restaurant is rectangular in shape and has a perimeter of 84 feet. If the length of the garden is 24 ft longer than the width of the garden what is the area of the garden in sq ft
Answer:
297 square feet
Step-by-step explanation:
Let w represent the width of the garden.
Since the length is 24 ft longer than the width, it can be represented by w + 24.
Use the perimeter formula, p = 2l + 2w. Plug in the perimeter and w + 24 as l, then solve for w:
p = 2l + 2w
84 = 2(w + 24) + 2w
84 = 2w + 48 + 2w
84 = 4w + 48
36 = 4w
9 = w
So, the width is 9 ft. Add 24 to this to find the length:
24 + 9 = 33
So, the length is 33 ft.
Find the area of the garden with the formula A = lw:
A = lw
A = (33)(9)
A = 297
The area of the garden is 297 square feet.
Complete the table using the equation w = m + 4
Answer:
5+4 = 9
6+4 = 10
7+4 =11
Step-by-step explanation:
Answer:
(5,9)
(6,10)
(7,11)
Step-by-step explanation:
w = m + 4
when m = 5,
w = 5 + 4 = 9
when m = 6
w = 6 + 4 = 10
when m = 7
w = 7 + 4 = 11
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of the experiment.
n=12, p=0.35, x=2
Answer:
0.1088 or 10.88%
Step-by-step explanation:
q = 1 - 0.35 = 0.65
P(X=2) = 12C2 × (0.35)² × (0.65)¹⁰
= 0.1088
can someone please help me?
Determine what type of model best fits the given situation: A 4% raise in salary each year.
the models aren't given..
Answer: no models given
Step-by-step explanation:
The sum of two consecutive even integers is 54. What are the two integers?
Answer:
26 and 2
Step-by-step explanation:
Given,
Sum of two even numbers = 54
let one number be x
another number be x +2
x + x +2 = 54
2x + 2 = 54
2x = 54 - 2
2x = 52
x = 52/2
x = 26
Therefore, the numbers are 26 and 26 + 2 = 28..
If 1/2 of a loaf of brown bread costs R6,how much will 2 halves cost
Answer:
wdym R6
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
6*2
The figure below is a rectangular prism.
Which edge is parallel to segment BD?
A. HK
B. BM
C. DK
D. AH
One time Maria took 27 minutes to walk 1.8km to school. She left home at 07:48 . Write down the time Maria arrived at school
Answer:
8:15
Step-by-step explanation:
Find the length of side
x to the nearest tenth.
find the sum 38+39+40+41...+114+115
It seems like you want to find the sum of 38 to 115:
[tex] \displaystyle \large{38 + 39 + 40 + 41 + ... + 114 + 115}[/tex]
If we notice, this is arithmetic series or the sum of arithmetic sequences.
To find the sum of the sequences, there are three types of formulas but I will demonstrate only one and the best for this problem.
[tex] \displaystyle \large{S_n = \frac{n(a_1+a_n) }{2} }[/tex]
This formula only applies to the sequences that have the common difference = 1.
Given that a1 = first term of sequence/series, n = number of terms and a_n = last term
We know the first term which is 38 and the last term is 115. The problem here is the number of sequences.
To find the n, you can use the following formula.
[tex] \displaystyle \large{n = (a_n - a_1) + 1}[/tex]
Substitute an = 115 and a1 = 38 in the formula of finding n.
[tex] \displaystyle \large{n = (115 - 38) + 1} \\ \displaystyle \large{n = (77) + 1} \\ \displaystyle \large{n = 78}[/tex]
Therefore the number of sequences is 78.
Then we substitute an = 115, a1 = 38 and n = 78 in the sum formula.
[tex] \displaystyle \large{S_{78} = \frac{78(38+115) }{2} } \\ \displaystyle \large{S_{78} = \frac{39(38+115) }{1} } \\ \displaystyle \large{S_{78} = 39(153) } \\ \displaystyle \large \boxed{S_{78} = 5967}[/tex]
Hence, the sum is 5967.
A triangular lamina has vertices (0, 0), (0, 1) and (c, 0) for some positive constant c. Assuming constant mass density, show that the y-coordinate of the center of mass of the lamina is independent of the constant c.
The equation of the line through (0, 1) and (c, 0) is
y - 0 = (0 - 1)/(c - 0) (x - c) ==> y = 1 - x/c
Let L denote the given lamina,
L = {(x, y) : 0 ≤ x ≤ c and 0 ≤ y ≤ 1 - x/c}
Then the center of mass of L is the point [tex](\bar x,\bar y)[/tex] with coordinates given by
[tex]\bar x = \dfrac{M_x}m \text{ and } \bar y = \dfrac{M_y}m[/tex]
where [tex]M_x[/tex] is the first moment of L about the x-axis, [tex]M_y[/tex] is the first moment about the y-axis, and m is the mass of L. We only care about the y-coordinate, of course.
Let ρ be the mass density of L. Then L has a mass of
[tex]\displaystyle m = \iint_L \rho \,\mathrm dA = \rho\int_0^c\int_0^{1-\frac xc}\mathrm dy\,\mathrm dx = \frac{\rho c}2[/tex]
Now we compute the first moment about the y-axis:
[tex]\displaystyle M_y = \iint_L x\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}x\,\mathrm dy\,\mathrm dx = \frac{\rho c^2}6[/tex]
Then
[tex]\bar y = \dfrac{M_y}m = \dfrac{\dfrac{\rho c^2}6}{\dfrac{\rho c}2} = \dfrac c3[/tex]
but this clearly isn't independent of c ...
Maybe the x-coordinate was intended? Because we would have had
[tex]\displaystyle M_x = \iint_L y\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}y\,\mathrm dy\,\mathrm dx = \frac{\rho c}6[/tex]
and we get
[tex]\bar x = \dfrac{M_x}m = \dfrac{\dfrac{\rho c}6}{\dfrac{\rho c}2} = \dfrac13[/tex]
The center of mass for a uniform triangular shape is on its centroid. The y-coordinate of the center of mass of the lamina is 1/3 (independent of c).
What is the center of mass for a triangular shape?If the surface is plane triangle approximately and mass is uniformally distributed, then its center of mass will lie on the centroid of that triangle.
What is centroid of a triangle and its coordinates?The point of intersection of a triangle's medians is its centroid (the lines joining each vertex with the midpoint of the opposite side).
If the triangle has its vertices as [tex](x_1, y_1), (x_2, y_2) , \: (x_3, y_3)[/tex], then the coordinates of the centroid of that triangle is given by:
[tex](x,y) = \left( \dfrac{x_1 + x_2 + x_3}{3} + \dfrac{y_1 + y_2 + y_3}{3} \right)[/tex]
For this case, the triangular lamina has vertices (0, 0), (0, 1) and (c, 0)
Assuming its mass is spread regularly, the coordinates of its center of mass would be:
[tex](x,y) = \left( \dfrac{x_1 + x_2 + x_3}{3} + \dfrac{y_1 + y_2 + y_3}{3} \right)\\\\(x,y) = \left( \dfrac{0+0+c}{3} + \dfrac{0+1+0}{3} \right) = (c/3, 1/3)[/tex]
Thus, the y-coordinate of the center of mass of the lamina is 1/3 (independent of c).
Learn more about centroid here:
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To draw a graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of ___, a second point by going over 3 and up ___, and then draw a line through the points
For drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.
How to know if a point lies in the graph of a function?All the points (and only those points) which lie on the graph of the function satisfy its equation.
Thus, if a point lies on the graph of a function, then it must also satisfy the function.
For this case, the equation given to us is:
[tex]y = \dfrac{3}{4}x + 7[/tex]
Any equation of the form [tex]y = mx + c[/tex] where m and c are constants and x and y are variables is the equation of a straight line.
For a straight line to be characterized, only two points are sufficient.
For x = 0, the y-coordinate would be such that it would satisfy the equation [tex]y = \dfrac{3}{4}x + 7[/tex]
Putting x = 0, we get:
[tex]y = \dfrac{3}{4} \times 0 + 7 = 7[/tex]
Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 7. Thus, (0,7) is one of the point's coordinate on the considered line.
Putting x = 3, we get:
[tex]y = \dfrac{3}{4} \times 3 + 7 = 9.25[/tex]
Thus, y-coordinate of the point on this line whose x-coordinate is 0 is 9.25 . Thus, (0,9.25) is another of the point's coordinate on the considered line.
Thus, for drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.
Learn more about points lying on graph of a function here:
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Solve the following system of equations for x: xy = 6
3y = x - 3
Answer:
B
Step-by-step explanation:
xy=6
y=6/x (1)
substitute (1) into 3y=x-3 and solve
describe the effect of the transformation (x,y) --> (x,y+4)
First correct gets brainliest!
A) Vertical stretch without reflection
B) Vertical stretch with reflection
C) Horizontal translation of 4 units
D) Vertical translation of 4 units
Answer:
D. Vertical translation of 4 units.
Step-by-step explanation:
This transformation keeps x the same but shifts y up 4 units (adding 4 to it). This is a vertical shift up 4, which we can also call a vertical "translation."
What is the height of a room which is 8m long, 6m wide and contains 144 meters cube of air?
f(x) = 3x + 2
What is f(5)?
Answer:
17
Step-by-step explanation:
f(x) = 3x + 2
f(5) = 3(5) + 2
f(5) = 15 + 2
f(5) = 17
Answer:
17
Step-by-step explanation:
f(x) = 3x + 2
Plug in:
3(5) + 2
15 + 2 = 17
Hope this helped.
How many different 4 card hands can be drawn from a set of 30 cards
Answer:
[tex]27,\!405[/tex] if:
The cards are drawn without replacement, All cards in this set are distinct from one another, andThe ordering of the four chosen cards does not matter.Step-by-step explanation:
[tex]\displaystyle \genfrac{(}{)}{0}{}{30}{4} = \frac{30 \times 29 \times 28 \times 27}{4 \times 3 \times 2 \times 1} = 27,\!405[/tex].
Assume for now that the ordering of the four cards does matter. Hands like [tex]\verb!A!\, \verb!B!\, \verb!C!\, \verb!D![/tex] and [tex]\verb!A!\, \verb!B!\, \verb!D!\, \verb!C![/tex] would then be considered different from one another.
There would [tex]30[/tex] choices for the first card. Since the first card was not returned to the pile, there would be only [tex]29[/tex] choices for the second card. Likewise, there would be [tex]28[/tex] choices for the third card and [tex]27[/tex] for the fourth.
By this reasoning, there would be [tex]30 \times 29 \times 28 \times 27 = 657,\!720[/tex] different ways to draw a hand of four cards from this set when the ordering of these four cards do matter.
However, in many card games, once a hand of cards is drawn, the ordering of cards within that hand does not matter. In other words, hands like [tex]\verb!A!\, \verb!B!\, \verb!C!\, \verb!D![/tex] and [tex]\verb!A!\, \verb!B!\, \verb!D!\, \verb!C![/tex] would not be considered as distinct from one another.
In that case, the [tex]30 \times 29 \times 28 \times 27 = 657,\!720[/tex] ways of drawing cards would include a large number of duplicates.
There are be [tex]4 \times 3 \times 2 \times 1 = 24[/tex] ways to arrange a hand of four cards when the order matter. Hence, when the ordering within a hand no longer matters, each hand of four cards would have been counted [tex]24[/tex] times among those [tex]30 \times 29 \times 28 \times 27 = 657,\!720[/tex] ways.
Therefore, when the ordering of cards within a set does not matter, [tex]\displaystyle \frac{30 \times 29 \times 28 \times 27}{4 \times 3 \times 2 \times 1} = 27,\!405[/tex] would give the number of distinct ways to draw a hand of four out of this set of thirty distinct cards.
Need help plotting this on number line
Refer to the attaachment
For a certain country, the bar graph shows the population of it’s public school students, in millions, and the amount that the country’s government spent on public education, in billions of dollars, for five selected years. Complete part A and B.
A.
Express 2007 student population in scientific notation. (Use the multiplication symbol as needed)
B.
Express the amount that the government spent on public education in 2007 in scientific notation. (Use the multiplication symbol as needed)
Answer:
B
Step-by-step explanation:
I took a test in school and this was the answer...at least for my class.
In a lottery game, a player picks shox numbers from 1 to 20. If the player matches all six numbers, they win 20,000 dollars. Otherwise, they lose $1. What is the expected value of this game? $
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Please Help Polygons
Step-by-step explanation:
5.25....................
Graph the line for y+1=-3/5(r-4) on a cordinate plane.
Answer: Screenshot attached
Step-by-step explanation:
1. If A = {1, 2, 3,4}, B = {3,4,5,6}, C = {1, 2, 4, 6, 7}, then find i) AUB ii) BUC iii) (AUB)UC v) An(BNC) vi) AU(BUC) iv) AN(BUC)
Answer:
i) AUB={1,2,3,4,5,6}
ii) BUC={1,2,3,4,5,6,7}
iii)(AUB)UC={1,2,3,4,5,6,7}
iv) {1,2,3,4}
v) {4}
vi){1,2,3,4,5,6,7}
Step-by-step explanation
AUB means all the elements belongs to a and b
AnB means elements common to both sets
If 3, 9, 10, x are in proportion find the value of x.
Answer:
[tex]x = 30[/tex]
Step-by-step explanation:
If 3, 9, 10, x are in proportion. Then,
[tex]x \times 3 = 10 \times 9[/tex]
[tex]x \times 3 = 90[/tex]
[tex]x = \frac{90}{3} [/tex][tex]x = 30[/tex]
Hope it is helpful.....Step-by-step explanation:
Given that 3, 9, 10, x are in proportion <br> product of exterms = Product of means <br>
<br>
3x=9×10
X=(9x10)/3
X=90/3
X=30
