Algebraic expression for 2a+3b-c if a=3 b=-4 c=-2

Answer:

9 grams of paint

Step-by-step explanation:

6×8=48

48÷4= 12

48-12=36

36÷4=9

first multiply 6 by 8 because a cube has six faces and you cut that cube eight times

second after you cut that you will have 48 faces and for every six faces there are 4 grams of paint so you divide 48 by 4 and you get 12 this means that 12 of the faces are painted

next you subtract 12 from 48 and you get 36 this means that 36 faces are not painted

lastly you divide 36 by 4 and you will get 9 grams of paint

Answer:

Common Ratio = 2.5

Step-by-step explanation:

Given

Points: (1, 1), (2, 2.5), (3, 6.25)

Required

Determine the common ratio

The points can be rewritten as:

x --- f(x)

1 ---- 1

2 --- 2.5

3 ---- 6.25

The data under the x column are the domain of the function and in this case,  they are not needed;

To calculate common ration, Lena should use data in function f(x) column

Common ratio is calculated by dividing a term by the previous term;

Hence;

Common Ratio = 2.5/1 or 6.25/2.5

Common Ratio = 2.5 or 2.5

Notice that, the results are the same;

Hence, the usable common ratio is 2.5

Answer: 2.5 or "C"

Step-by-step explanation: this is right on the edge i just did the test.....Hope this helps :D

Answer:

Degree: 2

Polynomial type: Quadratic

Step-by-step explanation:

One is asked to identify the degree and type of polynomial when given the following expression:

[tex]-10k^2+7[/tex]

The degree of a polynomial refers to the exponent to which it is raised. In essence, the largest exponent in the expression. In this case, the largest exponent in this polynomial is (2). An expression to the second degree is referred to as a quadratic expression.

Given:

The equation for the linearized regression line is:

[tex]\log y=0.30x+0.296[/tex]

where x represents number of weeks and y be the customer's stock.

To find:

The number of weeks that will pass before the value of the stock reaches $200.

Solution:

We have,

[tex]\log y=0.30x+0.296[/tex]

Substituting y=200, we get

[tex]\log (200)=0.30x+0.296[/tex]

[tex]2.301=0.30x+0.296[/tex]

[tex]2.301-0.296=0.30x[/tex]

[tex]2.005=0.30x[/tex]

Divide both sides by 0.30.

[tex]\dfrac{2.005}{0.30}=x[/tex]

[tex]6.6833333=x[/tex]

[tex]x\approx 6.7[/tex]

Therefore, the correct option is C.

Answer:

d. -4x² + 8x - 6

Step-by-step explanation:

(3x² + 2x - 4) + (-7x² + 6x - 2)

3x² + 2x - 4 - 7x² + 6x - 2

3x² - 7x² + 2x + 6x - 4 - 2

-4x² + 8x - 6

Answer:

X=5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Answer:

Answer:

21b

Step-by-step explanation:

Answer:

Step-by-step explanation:

The first box is 'not closed'

Second is ' an element'

Third = 'closed' and last is 'an element'.

Answer:

105897 ft²

Step-by-step explanation:

let, r be the radius, so r = 106 ft

Surface area of a hemisphere,

2πr²+πr²

= 2π×106²+π×106²

= 105897 (rounded to the nearest whole number)

Answer:

A is the answer...........

Explanation

8x+3=3x+8

8x-3x=8-3

5x=5

x=5/5

x=1

Answer:

x=9

Step-by-step explanation:

4(x-2)=2x+10

<=> 4x-8=2x+10

<=> 2x=18

<=>x=9

Answer:

x=3 the explanation is above

Answer:

24

Step-by-step explanation:

2*1+1+2*2+1+2*3+1+2*4+1=24

Answer:

(0, -2)

(-3, 1)

(3, -4)

Step-by-step explanation:

The constraints given as;

x + y ≥ -2

3x - y ≤ 2

x - y ≥ -4

Since we want to find vertices of the feasible region, we will ignore the less than or greater than sign and use the equal to sign to some simultaneously.

Let's add first and third constraint together to get;

2x = -6

x = -6/2

x = - 3

Put - 3 for x in equation 1 to get;

-3 + y = -2

y = 3 - 2

y = 1

Thus, vertex here is; (-3, 1)

Lets add first and third equations to get;

4x + 0 = 0

Thus, x = 0

Putting this for x in eq 1;

0 + y = -2

y = -2

vertex here is; (0, -2)

Lets subtract eq 3 from eq 2 to get;

2x = 6

x = 6/2

x = 3

Put 3 for x in eq 3;

x - y = -4

vertex here is; (3, -4)

Answer:

2^0

Step-by-step explanation:

When you are dividing 2 exponents with the same base (in this case, 2) you subtract them. 2^5 ➗ 2^5 => 2^(5-5) = 2^0 => which is equal to 1, but the answer here would be 2^0.

There are two ways to go about this problem.

The first way, the generic way, is to know that,

[tex]\frac{a^n}{a^m}=a^{n-m},a\neq0[/tex].

So,

[tex]\frac{2^5}{2^5}=2^{5-5}=\boxed{2^0}[/tex].

The second way is to realise that both numerator and denominator are equal and when diving two equal numbers you obtain 1. (except when diving zeros) aka,

[tex]\frac{a}{a}=1, a\neq0[/tex]

And 1 equals to any number raised to the power of zero,

[tex]a^0=1,a\neq0[/tex]

So we just have to say that the 1 we got is rewritten as some base to the power of zero.

Since our base needs to be 2, we just simply say,

[tex]2^0[/tex].

Et Viola.

Hope this helps.

Answer:

the second one (the one on the bottom)

Step-by-step explanation:

An odd function is where f(x) = -f(x), and therefore is unchanged when rotated 180 degrees about the origin. This results in the bottom graph.

Answer:

The minimum value of f(x) is -21 and it occurs at x = 1

Step-by-step explanation:

f(x) =3x^2-6x-18

Factor out the greatest common factor out of the first two terms

f(x) =3(x^2-2x)-18

Complete the square

-2x/2 =-1  (-1)^2 = 1

Add 1  (But remember the 3 out front so we are really adding 3  so we need to subtract 3 to remain balanced)

f(x) = 3(x^2 -2x+1) -3 -18

f(x) = 3(x-1)^2 -21

This is vertex form

f(x) = a(x-h)^2 +k  where (h,k) is the vertex and a is a constant

The vertex is (1,-21)  

Since a > 0 this opens upward and the vertex is a minimum

The minimum value of f(x) is -21 and it occurs at x = 1

Answer:

the answer is a

Step-by-step explanation:

sory lawl

i mean e

answer e!

good luck w summer geometoery

Answer:

20 m

[tex]p = 4a \: thus \: a = p \div 4 = 80 \div 4 = 20 \: m[/tex]

Answer:

20

Step-by-step explanation:

P=4L

80=4L

L=80/4

L=20m

Answer:

7

Step-by-step explanation:

10 minus 3 will give you the number

Answer:

7

Step-by-step explanation:

let the number added to 3 be 'x'

we know;

X+3=10

X=10-3

X=7

Answer:

use Pisagor teorem

Step-by-step explanation:

The line which start on the edge and divided other side 64 and 36 be Y and we use Pisagor teorem so Y²=64*36...... y=8*6=48 .................(1)

use other triangle to find hipotenus 48²+36²=x² .... x= 60

Answer: x= 437.3 ft.

Step-by-step explanation:

Let the angle side at 29 be n

so

n+29 = 90

so, n = 61

now

sin 61= p/h

sin 61 = x/500

so, x = sin 61*500

so, x = 437.3

[tex]\huge\underline\pink{✏ANSWER}[/tex]

Sorry for answering a nonsense

#BrainliestBunch

Answer:

74

Step-by-step explanation:

16 more than 15 equals 31

13 more than 15 = 28

15 + 31  + 28 = 74

Answer:

1(6+13mn+7m^2n^2)

Step-by-step explanation:

The coefficients and variables in this equation have a common factor of 1, therefore the equation will go back to it's original state if you use 1 as the common factor.

I hope this helps and sorry if am wrong

Answer:

A

Step-by-step explanation:

side opposite to smallest angle is smallest=1

Hypotenuse=2

sin 30=1/2

Answer:

[tex]A' = (-2,2)[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (2,-2)[/tex]

Step-by-step explanation:

Given

[tex]A = (-6,6)[/tex]

[tex]B = (6,6)[/tex]

[tex]C = (6,-6)[/tex]

[tex]k = \frac{1}{3}[/tex]

Required

The new coordinates

To do this, we simply multiply the coordinates of [tex]\triangle ABC[/tex] by the factor of dilation.

i.e.:

[tex]A' = A * k[/tex]

[tex]B' = B * k[/tex]

[tex]C' = C * k[/tex]

So, we have:

[tex]A' = (-6,6) * \frac{1}{3}[/tex]

[tex]A' = (-2,2)[/tex]

[tex]B' = (6,6) * \frac{1}{3}[/tex]

[tex]B' = (2,2)[/tex]

[tex]C' = (6,-6) * \frac{1}{3}[/tex]

[tex]C' = (2,-2)[/tex]

Answer:

We can convert the 2/3 bag of candy that we got to 16/24, by multiplying both the top and bottom by 8. Similarly, we multipy the 1/8 bag of candy that our friend got by 3 on the top and bottom to get 3/24.

We find the difference between these two:

(16/24) - (3/24) = (16-3)/24 = 13/24

So we get 13/24 more of the bag of candy than our friend did.

Answer:

1/6

Step-by-step explanation:

you’re being asked the difference between the amounts of your candy and your friend’s candy.

So you must subtract 1/3 from 1/2.

=> 1/2 - 1/3

=> 3*1 - 2*1/3*2. ( You criss-cross and you multiply the denominators)

=>. 3 - 2 /6

=> 1/6

So you got 1/6 more candies in your bag than your friend.