According to a survey done at your school, about 42% of all the female students participate in 2 sport seasons. You randomly ask 5 female students at your school how many sport seasons they participate in. What is the probability that at least 3 of the 5 female students surveyed participate in 2 sport seasons? Show your work.

Answer:

17 dominoes

Step-by-step explanation:

21 and 1/4 in divided by how far they need to be spaced apart, 1 and 1/4 in, is equal to 17 dominoes.

The probability that a number less than or equal to three is rolled is 1/2.

Given that, a number cube is rolled, we need to find that what is the probability that a number less than or equal to three is rolled,

So, the probability = favorable outcomes / total outcomes

Here, the favorable outcome = 1, 2, 3 = 3

The total outcomes = 1, 2, 3, 4, 5, 6 = 6

So, the probability = 3/6 = 1/2

Hence, the probability that a number less than or equal to three is rolled is 1/2.

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Answer:

-1/5

Step-by-step explanation:

h(0) is 5, and h^-1 is 1/h, so 1/-5 is -1/5.

Answer:

42

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

There are 46 children attending the field trip.

Each van needs to transport 8 children.

To find the number of vans they need, we will divide the number of children by the number of children per van:

46 / 8 = 5.75 ≅ 6 vans

They need 6 vans.

Answer:

The number of different combinations of three students that are possible is 35.

Step-by-step explanation:

Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

The number of different combinations of three students that are possible is given as:

7C3 (read as 7 Combination 3)

xCy (x Combination y) is defines as

x!/(x-y)!y!

Where x! is read as x - factorial or factorial-x, and is defined as

x(x-1)(x-2)(x-3)...2×1.

Now,

7C3 = 7!/(7 - 3)!3!

= 7!/4!3!

= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)

= (7×6×5)/(3×2×1)

= 7×5

= 35

Therefore, the number of different combinations of three students that are possible is 35.

There are 35 different combinations to chose 3 students from the 7 students

The given parameters are:

Students, n = 7

Selected , r = 3

The number of different combinations is calculated using:

Combination = nCr

This gives

Combination = 7C3

Using the combination formula, we have:

Combination = 35

Hence, there are 35 different combinations to chose 3 students from the 7 students

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Answer:

Step-by-step explanation:

We all know that the inner degrees of a pentagon add up to 540°

thus we can use the following equation to solve for x:

33+140+2x+x+x+75=540

173+4x+75=540

248+4x=540

4x=540-248

4x=292

x=292/4

x=73

Thus, the answer is 73 degrees

Answer:

[tex]x=73[/tex]

Step-by-step explanation:

The sum of all interior angles of a pentagon is 540°.

[tex]33+140+2x+x+x+75=540[/tex]

Add all like terms.

[tex]33+140+4x+75=540[/tex]

[tex]4x+248=540[/tex]

Subtract 248 on both sides.

[tex]4x=540-248[/tex]

[tex]4x=292[/tex]

Divide 4 on both sides.

[tex]x=292/4[/tex]

[tex]x=73[/tex]

Answer:42.5%

Step-by-step explanation:

Answer:

the answer is 42.5%

Step-by-step explanation:

you multiply both 40 and 17 by 2.5 to get 42.5/100 which is the percent in fraction form

Answer:

2/3

Step-by-step explanation:

.that's the answer

Answer:

$39.6

Step-by-step explanation:

Answer:

(x+1) (x^2+3)

Step-by-step explanation:

x^3 + x^2 + 3x + 3

x^3 + x^2      + 3x + 3

Factor out x^2 from the first group and 3 from the second group

x^2(x+1)   +3(x+1)

Then factor out (x+1)

(x+1) (x^2+3)

Answer:

[tex](x + 1)( {x}^{2} +3 )[/tex]

Answer A is correct

Step-by-step explanation:

[tex] {x}^{3} + {x}^{2} + 3x + 3 \\ {x}^{2} (x + 1) + 3(x + 1) \\ = ( {x}^{2} + 3)(x + 1)[/tex]

hope this helps

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good luck! have a nice day!

Answer:

StartFraction 5 over 3.5 EndFraction = StartFraction 12 over x EndFraction

or [tex]\frac{5}{3.5}[/tex] = [tex]\frac{12}{x}[/tex]

Step-by-step explanation:

Answer:

it’s D

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Standard form is just descending powers.

Highest power in the polynomial is 5,

Second highest is 2,

Third Highest is 1 (x^1 = 9x)

Lowest is x^0 (the 12 is actually 12*x^0 = 12*1)

:-)

Answer:

$96.50

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

The simplest and fastest way to answer this question is to graph the equations given. Once you do so, then you should see that D is the correct answer.

Answer:

[tex]\angle ADE =[/tex] [tex]69^\circ[/tex]

Step-by-step explanation:

Given:

[tex]\angle ABD = 32^\circ[/tex]

BA = BD

CB = CD

In [tex]\triangle ABD:[/tex]

BA = BD

We know that in a triangle, angles opposite to equal sides will also be equal.

[tex]\Rightarrow \angle BAD = \angle BDA[/tex]

We know that sum of internal angles of a triangle is equal to [tex]180^\circ[/tex]

[tex]\angle BAD + \angle BDA +\angle ABD=180^\circ\\\Rightarrow \angle BAD + \angle BDA +32=180\\\Rightarrow \angle BAD + \angle BDA = 180 -32\\\Rightarrow \angle BAD + \angle BDA = 148\\\Rightarrow \angle BAD = \angle BDA = \dfrac{148}{2} = 74^\circ[/tex]

Quadrilateral ABCD is cyclic so, sum of opposite angles is equal to [tex]180^\circ[/tex].

[tex]\angle BAD + \angle BCD = 180^\circ\\\Rightarrow 74 + \angle BCD = 180\\\Rightarrow \angle BCD = 180-74 = 106^\circ[/tex]

In [tex]\triangle BCD:[/tex]

BC = CD

We know that in a triangle, angles opposite to equal sides will also be equal.

[tex]\Rightarrow \angle DBC = \angle CDB[/tex]

We know that sum of internal angles of a triangle is equal to [tex]180^\circ[/tex]

[tex]\angle DBC + \angle BCD +\angle CDB=180^\circ\\\Rightarrow \angle DBC + 106 +\angle CDB=180\\\Rightarrow \angle DBC +\angle CDB=180 - 106\\\Rightarrow \angle DBC =\angle CDB=\dfrac{74}{2} = 37^\circ[/tex]

It is given that the line CDE is a straight line, so the sum of angles on one side of point D is [tex]180^\circ[/tex].

[tex]\angle CDB + \angle BDA +\angle ADE = 180^\circ\\\text{Putting values of } \angle CDB \text{ and }\angle BDA:\\\Rightarrow 37 + 74 + \angle ADE = 180\\\Rightarrow \angle ADE = 180 -111\\\Rightarrow \angle ADE = 69^\circ[/tex]

So, the answer is [tex]\angle ADE =[/tex] [tex]69^\circ[/tex]

The size of ∠ADE of the cyclic quadrilateral is;

∠ADE = 53°

We are given;

BA = BD

CB = CD

∠ABD = 32°

Now, ΔABD is an isosceles triangle and since sum of angles in a triangle is 180°, then;

∠ABD + ∠BAD + ∠BDA = 180°

∠BAD + ∠BDA = 180 - 32

∠BAD + ∠BDA = 148°

Since isosceles, then;

∠BAD = ∠BDA = 148/2

∠BAD = ∠BDA = 74°

Now, in cyclic quadrilaterals, opposite angles are supplementary and as such add up to 180°. Quadrilateral ABCD is cyclic and Thus;

∠BAD + ∠BCD = 180°

74 + ∠BCD = 180°

∠BCD = 180 - 74

∠BCD = 106°

ΔBCD is an isosceles triangle and as such;

∠CBD = ∠CDB = 106/2

∠CBD = ∠CDB = 53°

Now, sum of angles on a straight line add up to 180°. Thus;

∠CBD + ∠BDA + ∠ADE = 180°

Plugging in the relevant values gives;

53° + 74° + ∠ADE = 180°

∠ADE = 180 - (53 + 74)

∠ADE = 53°

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Answer:

4%

Step-by-step explanation:

R=INTEREST X 100% / TIME X PRINCIPAL

r=40 x 100=4000

4000/500 x 2=1000

4000/1000=4%

Answer:

18°

Step-by-step explanation:

sin 2x=cos zy

m(2x)=72°

cos(π/2-a)=sin a

cos(π/2-72°)=sin72°

cos18°=sin72°

=>m(zy)=18°

Answer:

Two imaginary solutions.

Step-by-step explanation:

In order to simplify the equation, we square root both sides. As the argument (value in the root) is negative, and we know that the square root function's domain is only positive numbers, we would have two imaginary solutions.

This would be positive/negative [tex]3i\sqrt{5}[/tex].

Another way to visualize this is by looking at the parabola's graph. Through algebraic manipulation, we know that the parabola is z^2 + 45. This parabola never crosses the x-axis. Therefore there are two solutions that are imaginary.

I hope this helps!

Answer:

(2+sqrt3)

Step-by-step explanation:

Assertion(A): (2-√3) is one zero of the quadratic polynomial then the other zero will be (2+√3).

Reason (R): Irrational zeros (roots) always occurs in pairs.

Since the given polynomial is a quadratic so it has only two zeros. Let other zero be x. Hence, the other zero is (2 -√3).

Polynomials that have only one zero mean both values of the variable are the same. This is the case of equal zeros of a quadratic equation. Let x be the variable of a quadratic equation and both zeroes of the quadratic equation are 2, i.e., equal roots.

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the 11 units from 0 is c only

Answer:

4

Step-by-step explanation:

Starting at the left end of the wall, you'll find that you can set four (4) tiles end to end along this wall.

Answer:

Equation is;

P = I(1 + r)^n

The population is 328

Step-by-step explanation:

Here we want to model the situation and use the modeled equation to predict population.

This follows an exponential pattern with similarity to the amount paid on a compound interest

Mathematically, we can have the equation as;

P = I(1 + r)^n

Where P is the population we want to calculate

I is the initial population in 1995 = 200 people

r is the rate of increase = 2% = 2/100 = 0.02

n is the difference in the number of years = 2020-1995 = 25

Thus the population would be;

P = 200(1 + 0.02)^25

P = 200(1.02)^25

P = 328.12

which is 328 approximately

[tex](a + b) {}^{3} = a {}^{3} + 3a {}^{2} b + 3ab {}^{2} + b {}^{3} \\ \\ x {}^{6} + 6x {}^{4} y + 12x {}^{2} y {}^{2} + 8y {}^{3} [/tex]

Answer:

x^6 + 6x^4 y + 12x^2 y^2 + 8y^3.

Step-by-step explanation:

Using the Binomial Theorem:

(x^2 + 2y)^3 = (x^2)^3 + 3C1 (x^2)^2 (2y) + 3C2 x^2 (2y)^2 + (2y)^3

= x^6 + 3*x^4*2y + 3*x^2*4y^2 + 8y^3

= x^6 + 6x^4 y + 12x^2 y^2 + 8y^3.

Answer:

C. Inverse

Step-by-step explanation:

The second statement is the inverse, because in an inverse, the hypothesis and the conclusion are both negated. In this case, the sun doesnt shine and the people wont be in a good mood, as opposed to the sun will shine, and the people will  be in a good mood.

Answer:

Inverse

Step-by-step explanation:

Step-by-step explanation:

0 = 4 - 7 x^2 + x

0= (-7)x^2 + (1)x + 4

a= -7

b = 1

c= 4

Answer:

Step-by-step explanation:

if we have n people and we want to do groups of 5, the total number of different combinations is:

[tex]c = \frac{n!}{(n - 5)!5!}[/tex]

find the smallest n such c > 365.

let's do it by brute force:

if n = 5, we have:

[tex]c = 5C_5 = 5[/tex]

if n = 6

[tex]c =6C_5 =6[/tex]

if n = 7

[tex]c = 7C_ 5= 21[/tex]

if n = 8

[tex]c = 8C_5 = 56[/tex]

if n = 9

[tex]C = 9!/(4!*5!) = 126[/tex]

so 9 is not enough, let's see N = 10

C = 10!/(5!*5!)  = 252

10 is not enough, let's see with 11.

C = 11!/(6!*5!) =  462

So you need at least 11 members in the club.

Then the minimum number of members such we have more than 365 combinations is 11 members

Client need al least 11 members in the club.

According to the question,

Group of five members, the combination will be:

→ [tex]c = \frac{n!}{(n-5)! \ 5!}[/tex]

By using Brute force,

If n = 5,

c = 5,

C₅ = 5

If n = 6,

c = 6,

C₅ = 6

If n = 7,

c = 7,

C₅ = 21

If n = 8,

c = 8,

C₅ = 56

Now,

If n = 9,

→ C = [tex]\frac{9!}{(4!\times 5!)}[/tex]

      = 126

and, If n = 10,

→ C = [tex]\frac{10!}{(5!\times 5!)}[/tex]

      = 252

and, If n = 11,

→ C = [tex]\frac{11!}{(6!\times 5!)}[/tex]

      = 462

Then perhaps the minimal number of individuals required to have more than 365 possible combinations seems to be 11.

Thus the response above is correct.

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Answer:

10x³ - 6x² - 9x + 12

Extra information:

★ Cubic polynomial: A polynomial of degree three is called cubic polynomial.

It is of the form P ( x ) = ax³ + bx² + cx + d [ Where a,b,c,d are real numbers and a is not equal to 0 . ]