A(6, -5) and B(-1, 2) in the ratio of 2:5​

.・。.・゜✭・Srry but which language is this!?

Answer:

[tex]{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}[/tex]

Step-by-step explanation:

[tex](x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6[/tex]

Answer:

it's very simple maybe it's in ur book?

9514 1404 393

Answer:

  π = 2A/r²

Step-by-step explanation:

Multiply by the inverse of the coefficient of π.

  A = π(r²/2)

  π = 2A/r²

Step-by-step explanation:

9) let number=x

Four times a number=4x

Condition:

4x+5=32

10) square of number=x²

Condition:

x²-4=12

11)

Condition:

3(x+4)=20

Note:if you need to know any question please let me know.

Answer:

the cost of filling the pool is $386.3

Step-by-step explanation:

Given;

dimension of the rectangular pool, = 25 yd by 30 yd by 5.1 ft

covert the given dimensions to feet;

1 yd = 3 ft

25 yd = 25 x 3 ft = 75 ft

30 yd = 30 x 3 ft = 90 ft

The volume of the rectangular pool in cubic feet (ft³);

Volume = 75 ft  x 90 ft  x 5.1 ft

Volume = 34,425 ft³

Convert the volume to gallons;

1 ft³ = 7.481 gallons

10,125 ft³ = 34,425 x 7.481 gallons

               = 257,533.425 gallons

The cost per a 1000 gallons is $1.50, then cost of the 257,533.425 gallons is calculated as;

[tex]cost = \frac{\$ 1.50}{1000 \ gallons} \times 257,533.425 \ gallons = \$ 386.3[/tex]

Therefore, the cost of filling the pool is $386.3

It will take Fred 42 minutes to type and spell check 60 pages.

Given the following data;

To find how long it takes him to type and spell check 60 pages;

We would use direct proportion to express the work described and solve for the unknown variable (time).

[tex]9 \;minutes : 13 \;pages\\\\X \;minutes : 60 \;pages[/tex]

Cross-multiplying, we have;

[tex]9[/tex] × [tex]60[/tex] [tex]= 13[/tex] × [tex]X[/tex]

[tex]540 = 13X\\\\X = \frac{540}{13}[/tex]

X = 41.54 ≈ 42 minutes

Therefore, it will take Fred 42 minutes to type and spell check 60 pages.

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Answer:

Step-by-step explanation:

3r(2r^2 - 5)

6r^(2 + 1) - 5*3r

6r^3 - 15r

Answer:

0

2

-1

Step-by-step explanation:

from f(0) we find that

y = mx - 1

from f(-1) we find that the equation is

y = -3x - 1

1)

inverse f(x) :

x = -3y - 1

y = -(x + 1) / 3           x = -1

y = -(-1 + 1) / 3

y = 0

2)

y also equal to 0 since x = -1

3)

f^-1(2) = -(2+1) / 3

          = -3/3

          = -1

f(-1) =  2

Answer:

70.908 is greater than 7.908 .

I hope your day goes nice

Answer:

both are different because of different placement of point.

Answer:

y=-2x-1

Step-by-step explanation:

The slope is - 2. The equation is y=-2x-1

Answer:

[tex]\sqrt{280}[/tex] = 2[tex]\sqrt{70}[/tex]

37^2 = 1369

33^2 =1089

1369-1089 = 280

Step-by-step explanation:

Answer:

[tex]cos49 = \frac{26}{x} \\ x = 39.6305[/tex]

The answer is prime! I hope this helps you out!

Answer:

23 is a prime number. Reason: Prime number are those numbers which are divisible by 1 and itself. Example: 5 is divisible by 1 and 5 only.

Answer:

10.2

Step-by-step explanation:

Length of arc=(2*pi*r)*(theta/360)

Length of arc=(2*pi*3)*(195/360)=10.2

Answer:

1051.9 minutes

Step-by-step explanation:

16 games at 58.35 minutes =

16* 58.35 =933.6 minutes

2 playoffs at 59.15

2 * 59.15 = 118.3 minutes

Add them together

933.6+118.3 =1051.9 minutes

Answer:

the answer is 1051.9 minutes

Step-by-step explanation:

[tex]\sf{}[/tex]

♛┈⛧┈┈•༶♛┈⛧┈┈•༶

Answer:

A. The median does not change.

Step-by-step explanation:

Original data set,

Put the numbers in order from smallest to largest

2,2, 4, 5, 5, 6,6, 8  

Median is the middle number

2,2, 4, 5,     5, 6,6, 8  

It is between the two 5's

(5+5)/2 = 10/2 = 5

New data set

Put the numbers in order from smallest to largest

2,2, 4, 5, 5, 6,6, 8,10  

Median is the middle number

2,2, 4, 5,     5,    6,6, 8,10  

The middle number is 5

Answer:

The answer is A

Step-by-step explanation:

[tex]\\ \sf\longmapsto 2(3x-7)+4(3x+2)=6(5x+9)+3[/tex]

[tex]\\ \sf\longmapsto 6x-14+12x+8=30x+54+3[/tex]

[tex]\\ \sf\longmapsto 6x+12x-14+8=30x+57[/tex]

[tex]\\ \sf\longmapsto 18x+6=30x+57[/tex]

[tex]\\ \sf\longmapsto 30x-18x=6-57[/tex]

[tex]\\ \sf\longmapsto 12x=51[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{51}{12}[/tex]

Answer:

Step-by-step explanation:

Temperature is a function of the time of day. There can be only one temperature at any particular time.

In contrast, a particular temperature can occur more than one time in a day, so time is not a function of temperature.

Answer:

4 i believe that's the answer

Answer:

f(g(4))=79

Step-by-step explanation:

given:

f(x) = 4x + 3

g(x) = 22 – 3

g(x) = 19

the x in parentheses represents x's value. if it is just x then example f(x)=3x would be 3x. if f(x) was f(2)=3x, then x would be 2 and f(2)=3x would be 3*2=6

f(g(4))

first solve g(4)

g(x) = 19

g(4)=19     because there are no x

then substitute

f(g(4))

f(19)

f(19) = 4x + 3

all x become 19

f(19) = 4(19) + 3

       =76+3

        =79

hope this helps.

Answer:

Hello,

Answer C

Step-by-step explanation:

Since ln(1)=0

if x=1 then y=4 ==> y=ln(x)+4

y=ln(x) is translated up for 4 units.

Answer:

y=(3/7)*x+52/7

Step-by-step explanation:

The slope of the line will be (3/7). The equation of line will be y=(3/7)*x+52/7

The equivalent resistance of the network shown is: [tex]R_{eq}=16.463\Ohm[/tex]

So, first of all, we can start by determining what each of the resistances is equal to. In this case we can start by saying that [tex]R_{1}=11R_{11}[/tex] This means that:

[tex]R_{1}=11(3\Ohm)[/tex]

Therefore:

[tex]R_{1}=33\Ohm[/tex]

We can now use this value to find the value of the other resistances. The given condition for the resistances can be represented with the following formula:

[tex]R_{n}=\frac{R_{1}}{n}[/tex]

so:

[tex]R_{2}=\frac{R_{1}}{2}=\frac{33}{2}\Ohm[/tex]

[tex]R_{3}=\frac{R_{1}}{3}=\frac{33}{3}\Ohm=11 \Ohm[/tex]

[tex]R_{4}=\frac{R_{1}}{4}=\frac{33}{4}\Ohm[/tex]

[tex]R_{5}=\frac{R_{1}}{5}=\frac{33}{5}\Ohm[/tex]

[tex]R_{6}=\frac{R_{1}}{6}=\frac{33}{6}\Ohm=\frac{11}{2}\Ohm[/tex]

[tex]R_{7}=\frac{R_{1}}{7}=\frac{33}{7}\Ohm[/tex]

[tex]R_{8}=\frac{R_{1}}{8}=\frac{33}{8}\Ohm[/tex]

[tex]R_{9}=\frac{R_{1}}{9}=\frac{33}{9}\Ohm=\frac{11}{3}\Ohm[/tex]

[tex]R_{10}=\frac{R_{1}}{10}=\frac{33}{10}\Ohm[/tex]

[tex]R_{11}=3\Ohm[/tex]

So now that we know what each resistance is equal to, we can go ahead and analyze the circuit.

In this case we can see that [tex]R_{10}[/tex] and [tex]R_{11}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{1011}=\frac{R_{10}R_{11}}{R_{10}+R_{11}}[/tex]

Which yields:

[tex]R_{1011}=\frac{(\frac{33}{10}\Ohm)(3\Ohm)}{\frac{33}{10}\Ohm+3\Ohm}[/tex]

[tex]R_{1011}=\frac{11}{7}\Ohm[/tex]

Now, [tex]R_{8}[/tex], [tex]R_{9}[/tex] and [tex]R_{1011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{891011}=R_{8}+R_{9}+R_{1011}[/tex]

[tex]R_{891011}=\frac{33}{8}+\frac{11}{3}+\frac{11}{7}[/tex]

[tex]R_{891011}=\frac{1573}{168}\Ohm[/tex]

Now,  we can see that [tex]R_{7}[/tex] and [tex]R_{891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{7891011}=\frac{R_{7}R_{891011}}{R_{7}+R_{891011}}[/tex]

Which yields:

[tex]R_{7891011}=\frac{(\frac{33}{7}\Ohm)(\frac{1573}{168})}{\frac{33}{7}\Ohm+\frac{1573}{168}\Ohm}[/tex]

[tex]R_{7891011}=\frac{4719}{1505}\Ohm[/tex]

Now, [tex]R_{5}[/tex], [tex]R_{6}[/tex] and [tex]R_{7891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{567891011}=R_{5}+R_{6}+R_{7891011}[/tex]

[tex]R_{567891011}=\frac{33}{5}\Ohm+\frac{11}{2}\Ohm+\frac{4719}{1505}\Ohm[/tex]

[tex]R_{567891011}=15.236\Ohm[/tex]

Next,  we can see that [tex]R_{4}[/tex] and [tex]R_{567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{4567891011}=\frac{R_{4}R_{567891011}}{R_{4}+R_{567891011}}[/tex]

Which yields:

[tex]R_{4567891011}=\frac{(\frac{33}{4}\Ohm)(15.236\Ohm)}{\frac{33}{4}\Ohm+15.236\Ohm}[/tex]

[tex]R_{4567891011}=5.352\Ohm[/tex]

Now, [tex]R_{2}[/tex], [tex]R_{3}[/tex] and [tex]R_{4567891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{234567891011}=R_{2}+R_{3}+R_{4567891011}[/tex]

[tex]R_{234567891011}=\frac{33}{2}\Ohm+11\Ohm+5.352\Ohm[/tex]

[tex]R_{234567891011}=32.852\Ohm[/tex]

Finally, we can see that [tex]R_{1}[/tex] and [tex]R_{234567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{eq}=\frac{R_{1}R_{234567891011}}{R_{1}+R_{234567891011}}[/tex]

Which yields:

[tex]R_{eq}=\frac{(33\Ohm)(32.852\Ohm)}{33\Ohm+32.852\Ohm}[/tex]

[tex]R_{eq}=16.463\Ohm[/tex]

See attached picture for images on how to reduce the circuit.

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