Answer:
307.44 m (whatever 'm' is)
Explanation:
355 * cos (30) = 307.44
Find the equivalent resistance of this circuit. First, what is the equivalent resistance, Req(23), of the parallel combination of R2 and R3?
[tex]R_{eq(23)} = \left(\dfrac 1{R_2} + \dfrac{1}{R_3}\right)^{-1}\\\\\\~~~~~~~~~= \left( \dfrac 1{200} + \dfrac 1{300} \right)^{-1}\\\\~~~~~~~~~=\left( \dfrac{5}{600} \right)^{-1}\\\\\\~~~~~~~~~=\dfrac{600}5\\\\\\~~~~~~~~~= 120~ \Omega[/tex]
Step-by-step explanation :
Here we have to calculate the equivalent resistance of the parallel combination between R2 and R3.
As we know that,
1/Rp = 1/R2 + 1/R3 ... n>> 1/Rp = (1/200) + (1/300)
>> 1/Rp = (300 + 200 / 600)
>> 1/Rp = 500 / 600
>> 1/Rp = 5 / 6
>> Rp = 6 / 5
>> Rp = 1.2Ω
Therefore,
Resistance in parallel combination is of 1.2ΩWhat is the current in a circuit with a 9.0 v battery and a resistance of 36.0 ω? 0.25 a 4.0 a 45 a 324 a
The currrent flowing the circuit with the given voltage and resistance is 0.25 Ampere.
Option A) 0.25A is the correct answer.
What is Ohm's Law?Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.
It is expressed as;
V = I × R
Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.
Given that;
Voltage in the circuit V = 9.0VResistance R = 36.0ΩCurrent I = ?We substitute our given values into the expression above.
V = I × R
9.0V = I × 36.0Ω
I = 9.0V / 36.0Ω
I = 0.25A
Therefore, the currrent flowing the circuit with the given voltage and resistance is 0.25 Ampere.
Option A) 0.25A is the correct answer.
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A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?
A.
0.034 newtons/amp·meter
B.
0.17 newtons/amp·meter
C.
0.26 newtons/amp·meter
D.
0.77 newtons/amp·meter
E.
6.0 newtons/amp·meter
Answer:
the answer is letter D.
Explanation:
i hope this is help
Answer:
great answer warstep8! add me on disc colludy#8415
Explanation:
how long would it take for a resultant upward force of 100N to increase the speed of 50kg object from 100m/s to 150m/s
Answer:
25 sec
Explanation:
F = ma
100 = 50 a
a = 2 m/s^2
vf = vo + at
150 = 100 + 2 t
50 = 2 t
t = 25 sec
What is the total kinetic energy of a 5-kg hoop with a radius of 0. 5 m when it rolls without slipping at 4. 0 m/s?
The total kinetic energy of a 5-kg hoop with a radius of 0. 5 m when it rolls without slipping at 4. 0 m/s is 80 Joules.
What is kinetic energy?The kinetic energy is the ability to do work by virtue of its motion.
The mass of the hoop is 5 kg, the radius of the hoop is 0.5 m and the speed with which it is rolling is 4.0 m/s.
The angular speed of the hoop is
ω = v / r
ω = 4 / 0.5 = 8 rad/s
The moment of inertia of the hoop is I = m r² / 2
The kinetic energy of the rolling object is the addition of translation and rotational kinetic energy.
K.E = 1 / 2(mv²) + = 1 / 2(Iω²)
Substituting the values into the above equation and solving, we get the total kinetic energy.
K.E = 40 + 40 = 80 Joules
Thus, the total kinetic energy is a rolling hoop is 80 Joules.
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What is the force on a current-carrying wire that is in a magnetic field of 5.41*10-5 T if the current is 22.84 A and the length of the wire is 31.71 m
Answer:
3.918*10^-2N
Explanation:
force=magnetic flux*current*length
force=5.41*10^-5*22.84*31.71
force=3.918*10^-2N
A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate at which electrical energy is dissipated in the resistor is 316 w
The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
What is impedance Z of the circuit?The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.
[tex]Z=\dfrac{V}{I}[/tex]
Here, V is voltage amplitude and I maximum current.
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.
The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,
[tex]316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A[/tex]
The impedance Z of the circuit is,
[tex]Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm[/tex]
Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
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Electric current can be produced in a wire by simply moving a ________________ into or out of a wire coil.
magnet
stick
battery
uranium
Electric current can be produced in a wire by simply moving a magnet into or out of a wire coil. Option A is correct.
What is the Faraday law of electromagnetic induction?According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux link with the coil is responsible for generating emf in the coil to result in the flow of amount of current .
The phenomenon of inducing voltage by changing the magnetic field around a conductor will be Electromagnetic Induction.
So in order to increase the current, we need to increase the EMF;
so we can increase it by;
1) Increasing the number of turns
2) Increase the area of the loop
3) By moving the magnet faster
Hence, option A is correct.
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How is energy transformed In a washing machine
Answer:
In earlier washing machine, the electrical energy is converted in rotational kinetic energy. Now a days, in washing machine, the electrical energy is converted in kinetic energy then the mechanical energy is converted into heat energy. In modern machines, we can wash and dry the clothes.
An electromagnetic wave has a frequency of 8.2 x 10¹⁴ Hz. What is the wavelength of the wave?
Explanation:
Given parameters:-
Frequency of EMW is - 8.2 x 10¹⁴ HzTo find:-
Wavelength([tex]\lambda[/tex])?Solution:-
Here , we are provided frequency of electromagnetic wave and we have to find the wavelength of the wave. To find the wavelength we have to divide the speed of light by given frequency. therefore,
[tex]\tt\red{wavelength( \lambda)= \frac{speed(c)}{frequency(f)}}[/tex]
[tex] \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} }{8.2 \times {10}^{14} } \\ \\ \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} \times {10}^{ - 14} }{8.2} \\ \\ \rightarrow \sf \: \lambda = 0.36 \times {10}^{6} \\ \\ \rightarrow \sf \: \lambda = 36 \times {10}^{4}m[/tex]
Because sound waves vibrate longitudinally, what can result?
A. Disruptions of fixed waves
B. Changes in the density of air
C. Pressure differences where compressions are rarefied
D. Regions of high pressure and low pressure
Answer:
D
Explanation:
toke the test Regions of high pressure and low pressure
how long does it take to do 278J of work with 17 W of power
Answer:
t= 278/17 =16.35s
Explanation:
p=w/t
t=w/p
∴t=278/17
Answer:
t=16.4
Explanation:
power = energy/time
p=e/t
17=278/t
t=278/17
t=16.352941
t=16.35
t=16.4
The ISS can, at times, be seen from Earth.
True or false
Answer:
True but mostly false.
Explanation:
If you squint enough at night, you'd be able to see it. Otherwise it's not really possible.
Scientists in the laboratory create a uniform electric field e⃗ = 6. 0×105 k^v/m in a region of space where b⃗ =0⃗
Scientist in the laboratory create uniform electric field.
PART A: The electric field in rocket frame is (0,0, 6.0 × 10 ⁵).
PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .
What is uniform electric field?The electric field whose strength is not changing with respect to time is called uniform magnetic field.
The electric field is 6.0 × 10 ⁵ k^v/m and the magnetic field is zero.
E' = E + (V×B)
= 6.0 × 10 ⁵ + (1.1 × 10⁶ × 0)
E' = 6.0 × 10 ⁵ k∧
(Ex , Ey, Ez) = (0,0, 6.0 × 10 ⁵)
The new magnetic field is represented as
B' = B - 1 /c²(v × E)
=0 - 1 / (3× 10⁸)²(1.1 × 10⁶ i∧ × 6.0 × 10 ⁵k∧ )
B' = 7.3 × 10⁻⁶ j∧
PART A: The electric field in rocket frame is (0,0, 6.0 × 10 ⁵).
PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .
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A 3kg mass is dropped from a height of 12m. What is the KE as it strikes the ground?
Explanation:
Givenmass=3kg
height=12m
and all of them now
gravity=9.8m/S2
required
k.e = ?
solution
k.e=p.e
so p.e=MGH
p.e=MGH
=3kg*9.8m/S2*12m
=352.8kg m2/S2
=352.8 J
so we said p.e=k.e
therefore 352.8 J = k.e
If a ball has a speed of 10 m/s and a momentum of 2.5 kg∙m/s,
what is its mass?
0.25 kg
Explanation:
[tex]p = m \times v \\ 2.5 = m \times 10 \\ m = \frac{2.5}{10} \\ \boxed{m = 0.25} [/tex]
The speed of sound doubles from 330 m/s to 660m/s going from air to a vibrating tuning fork.
Compare the frequency and wavelength of the wave in these 2 mediums.
Lets learn the relationship
[tex]\\ \rm\dashrightarrow \lambda=\dfrac{v}{\nu}[/tex]
[tex]\\ \rm\dashrightarrow \nu=\dfrac{v}{\lambda}[/tex]
[tex]\\ \rm\dashrightarrow \nu\propto \lambda\propto v[/tex]
Hence.
frequency and wavelength will be. doubled also
Find the voltage drop between points A and B in the circuit. [?] V 106 A 30 Ω 40 Ω B 50 Ω 20Ω 10Ω
[tex]30 \Omega || 40\Omega ~ \text{and}~50\Omega || 30 \Omega\\\\\text{Equivalent resistance of the whole circuit,}\\ \\R_{eq} = \left(\dfrac{30 \times 40}{30+40} \right) + \left( \dfrac{50 \times 30}{50+30} \right)\\\\\\~~~~~~=\dfrac{1005}{28}~ \Omega\\\\\text{By Ohm's law,}\\\\~~~~~V=IR\\\\\implies I = \dfrac{V}{R} = \dfrac{9}{\tfrac{1005}{28}} = \dfrac{252}{1005}= \dfrac{84}{335}~ A\\\\ \text{Voltage drop between points A and B,}\\\\V_{AB} = IR_{AB}\\\\\\[/tex]
[tex]~~~~~~~=\dfrac{84}{335} \cdot \left(\dfrac{30 \times 40}{30+40} \right)\\\\\\~~~~~~~= \left( \dfrac{84}{335} \right) \left(\dfrac{120} 7 \right)\\\\\\~~~~~~~=\dfrac{288}{67}~V\\\\\\~~~~~~~=4.298~V[/tex]
Suppose we observe a cepheid variable in a distant galaxy. The cepheid brightens and dims with a regular period of about 10 days. What can we learn from this observation?.
Answer:
something is passing infront of it
Explanation:
something is orbiting it and blocking its light
Recall that Hubble's law is written v = H0d, where v is the recession velocity of a galaxy located a distance d away from us, and H0 is Hubble's constant. Suppose H0 = 20 km/s/Mly. How fast would a galaxy 1000 Mly distant be receding from us?
Hubbles' law is applicated on galaxies. The galaxy which is 1000 Mly distant from us has the speed 20000 km/s.
What is Hubble's law?Hubble's law is defined as the galaxies are moving away from Earth at speeds proportional to their distance.
Hubble's law is written as
v = H₀d
Here v is the recession velocity of a galaxy located a distance d away from us, and H₀ is Hubble's constant.
Suppose H₀ = 20 km/s/Mly.
1 parsec = 3.08 ₓ 10¹⁶ m
1 M parsec = 3.08 ₓ 10²² m
The speed v of the galaxy is
v = 20 ₓ 1000
v = 20000 km/s
Thus, the galaxy which is 1000 Mly distant from us has the speed 20000 km/s.
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The volume of empty space between gas particles is.
Answer:
either atoms or molecules
Who developed a way to measure speed
Find the mass of a child who runs at a speed of 4 m/s to get a pizza with extra cheese. His momentum is 120 kg•m/s.
a high efficiency shower can save... 1. water 2. energy 3. both ?
Answer:
both
Explanation:
You'll use less water....less hot water so water and energy are saved
Temperature measures the average kinetic energy per molecule. true or false
Answer:
true
Explanation:
2) Which of the following images correctly depicts the direction of the
Earth's velocity if Sun was suddenly eliminated?
Use the energy equation from this week’s notes, your answer from
An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.
What is energy?The term energy refers to the ability to do work. An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.
This question is incomplete as the former energy equation is not shown. However, such equations can be used to know an endothermic or exothermic reaction.
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Write the chemical symbols for three different atoms or atomic anions with 9 electrons
The chemical symbols for three different atoms or atomic anions with 9 electrons are Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²).
What is atom?An atom is the smallest unit of matter, consisting of the positively charged nucleus and the electrons which move around it. The atom can not be divided further.
The atom of a matter is made by three elements-
1) Neutron-Neutron is the element of an atom, which has zero charge.2) Proton-Proton is the element of an atom, which has a positive charge.3) Electron-Electron is the element of an atom, which has a negative charge.The chemical symbols for three different atoms or atomic anions with 9 electrons has to be write down. Anion is the element which has more number of electron compare to its protons.
This makes the element negatively charged. Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²) are the element which have atomic anions with 9 electrons.
Thus, the chemical symbols for three different atoms or atomic anions with 9 electrons are Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²).
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The distance from the center of a ferris wheel to a passenger seat is 12 m. What centripetal acceleration does a passenger experience when the wheel's angular speed is 0. 50 rad/s?
A passenger experiences centripetal acceleration when there is circular motion around a center. The centripetal acceleration is 3 m/s².
What is centripetal acceleration?The centripetal acceleration is the acceleration acting when a body is moving on a circular path. It is acted towards the center of the path. Centripetal acceleration is the product of the square of angular speed and radius of path.
a =ω²r
Given the radius of path r is 12 m and angular speed ω is 0.50 rad/s².
The resulting centripetal acceleration is
a = (0.50)²×12
a = 3 m/s²
Thus, the centripetal acceleration is 3 m/s².
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Which is a characteristic of atoms?
1 They come in ten major types.
2 They are the smallest units of matter.
3 They can be found in nonliving things only.
4 They cannot combine together.
Answer: 2
Explanation: bro this is literally basic knowledge