A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of of Rs. 20 per metre leaving a space 3m wide for a gate on one side?​

Answers

Answer 1

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

Answer 2

$\sf\underline\bold{Answer:}$

$\sf\small\underline{\underline{Area\: planted\: by\: the\: gardener : 1452.36m^2}}$

$\sf\small\underline{\underline{The\:cost\:of\:fencing\:the\:park:Rs.4940}}$

$\space$

$\sf\underline\bold{Step-by-Step:}$

$\space$

$\sf\bold{Given(In \:the\:Q):}$

Sides of the triangular park are 120m,80m and 50m.

$\space$

$\sf\bold{To \: find:}$

How much area of the park does she need to plant?The cost of fencing the park ?

$\space$

$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$

$\space$

$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$

$\space$

Use heron's formula to find the area of the triangle.

$\space$

$\mapsto$ $\sf\small{Heron's\:formula=}$

[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]

$\sf{Where\:s=semi\:perimeter}$$\sf{a,b,c\: = side\:of\:the\:∆}$$\sf\small{Here\:a=120,b=80 \:and\: c=50}$

$\space$

$\sf\bold{Now,find\:semi\:parameter:-}$

$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$

$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$

$\space$

$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$

$\sf{Area\:of\:the\:∆:-}$

$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]

$\space$

$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$

$\space$

$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$

______________________________

$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$

$\sf{Cost\:of\:fencing-}$

$\sf{Rate = Rs.20 per \:meter}$ $\sf{Left\:space=3m}$

$\space$

$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$

$\sf{= 250-3=247m.}$

$\space$

So,total cost of fencing at the rate of Rs.20 per m:-

$\sf\underline\bold\purple{=247\times20=4940}$

___________________________________


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Answers

Answer:

D. 15/√346

Hope this helps! Have a nice day :)!

(5.9)(1.102)


What’s does that mean

Answers

Answer:

brackets stand for multiplication therefore this means multiply 5.9 by 1.102..

I hope this helps and sorry if it's wrong

Brackets usually stand for multiplication and are commonly seen in BEDMAS induced equations.
The answer to that question would be founded as normally as you would with multiplication.

(5.9)(1.102) = 6.5018 -> 5.9 x 1.102 = 6.5018

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Answer:

Step-by-step explanation:

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Answers

Answer:

Options (C)

Step-by-step explanation:

For the congruence of the triangles ΔADB and ΔADC,

                Statements                             Reasons

1). AB ≅ AC                                   1). Given

2). AD ≅ AD                                 2). Reflexive property

3). ∠BAD ≅ ∠CAD                       3). Given

4). ΔABD ≅ ΔCAD                       4). SAS postulate

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Answers

Answer:

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