A student is walking back up the hill from the field to the school building. His
friends are slow, so he stops for a moment to wait for them to catch up. Once
they do, the group heads to class. Pick the graph that correctly shows the
motion in the story.
с
Distance from
home
Distance from
home
Time
Time
A
O
B
is in
Tim
Time

Explanation:

so sorry

don't know but please mark me as brainliest please

Answer:

66.7s

Explanation:

Given parameters:

Distance between Mars and Earth  = 2 x 10¹⁰m

Unknown:

Time it takes for light to travel  = ?

Solution:

The speed of light is given as 3 x 10⁸m/s

 Now;

   Speed  = [tex]\frac{distance}{time}[/tex]  

    Time  = [tex]\frac{distance}{speed}[/tex]

Insert the parameters and solve;

   Time  = [tex]\frac{2 x 10^{10} }{3 x 10^{8} }[/tex]   = 66.7s

Answer:

1.8m/s^2

Explanation:

Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.

Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.

Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.

Therefore, 1.8m/s^2 is the correct answer.

Please mark brainliest!

Answer:

1.8

Explanation:

honestly i jus took the test

Answer:

Explanation:

mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

ω = 1.57 rad/s

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

ac = 4.92 m/s²

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

μs = 0.5

Compute the block's weight:

w = m g = (20 kg) (9.8 m/s²) = 196 N

The net vertical force is 0, so the normal force has the same magnitude:

n + (-w) = 0   →   n = 196 N

The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that

f = 0.20 (196 N) = 39.2 N ≈ 39 N

The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N

Mass (m) = 20 Kg

Acceleration due to gravity (g) = 9.8 m/s²

N = mg

N = 20 × 9.8

Coefficient of kinetic friction (µ) = 0.2

Normal reaction (N) = 196

F = µN

F = 0.2 × 196

Therefore, the force of kinetic friction acting on the block is 39.2 N

Learn more: https://brainly.com/question/11902512

Answer:

E = 2.17 x 10⁻² V/m

Explanation:

First we will find out the current density by using the formula:

J = I/A

where.

J = Current Density = ?

I = Current = 5.5 A

A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²

Therefore,

J = 5.5 A/7.068 x 10⁻⁶ m²

J = 0.778 x 10⁶ A/m²

Now, we calculate the magnitude of applied field:

E = ρJ

where,

E = Magnitude of applied field = ?

ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m

Therefore,

E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)

E = 2.17 x 10⁻² V/m

Answer:3 N —->

Explanation:

In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

Since

A parachute in the back of the car is released to help slow down the car.

So here the net force should be

= 10 N - 7N

= 3 N

Hence, In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

Learn more about force here: https://brainly.com/question/21422036

Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

Explanation:

Given that;

inside diameter = 109μm

barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m

force fair = 3.24 N

We know that the inside diameter is neglected; from the Bernoulli's equation

so

P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside

p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel

Fair = 1/2painv²outside . Abannel

therefore

3.24 = 1/2(1000) v²outside (πr²)

3.24 = 1/2(1000) v²outside (π × (0.0111)²

3.24 = 0.1935 v²_outlet

v²_outlet = 3.24 / 0.1934

v²_outlet  = 16.7441

v_outlet = √16.7441

v_outlet  = 4.09196 m/s

Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

Answer:

Dy = 49.01 [m]

Explanation:

The vertical component of the vector can be determined with the sine of the angle.

Dy = 92.5*sin(32)

Dy = 49.01 [m]

The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that

p - f = 0

where p and f denote the magnitudes of the pulling force and friction.

So we have

p - 12 N = 0

p = 12 N

We are Given:

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

Solving for the acceleration:

From the seconds equation of motion:

s = ut + 1/2* (at²)

replacing the variables

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

Answer:

Part One: Defining the Problem and Sub-Problems

1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.

o I chose pollution, due to the overwhelming pollution in todays day and age.

2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.

o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.

o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.

o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.

o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.

o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.

o Pollution is harmful things within an environment, that can cause decay within an environment.

3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.

o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.

4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.

o Man made factories, cars, and garbage dumps.

o Being a litter bug (throwing trash on the ground).

5. Explain how these sub-problems are related to or a direct result of the overall problem.

o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.

Part Two: Criteria, Constraints, and Prioritizations

1. Choose one sub-problem that you will investigate further and explain which one you chose here.

o Cars/fuel

2. List two realistic criteria for the sub-problem.

o Reducing fuel and oil can help fix the problem.

o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.

3. Explain why it is important for these criteria to be met in order to solve the problem.

o It would create less air pollution, and could help with sickness, plants dying, and animals dying.

4. List two constraints for the sub-problem.

o Electric cars are a bit to expensive for the average person.

o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.

5. Explain why these constraints exist. (How do they limit solutions to the problem?)

o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.

6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.

Ranking Criteria or Constraint Reason for Prioritization

1.  Fuel and oil  Its highly needed to run cars but causes sever pollution.

2.  Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.

3.  Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.

4.  Solar powered electric charge stations Low pollution and easily earth friendly acceptable.

Part Three: Generate Solutions

1. List two solutions that you have generated for the chosen sub-problem.

o Lowering prices on electric cars.

o Creating solar powered charge stations to reduce more pollution.

2. Describe how the sub-problem can be solved, and include the research supporting each solution.

o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.

3. Explain how prioritization was involved in designing each solution.

o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.

4. Explain how both solutions to the sub-problem play a role in solving the larger problem.

o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.

Answer:

Convection

Explanation:

The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"

Answer:

Convection

Explanation:

Its Convection

Answer:

if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface

Explanation:

that's the explanation now i gotta execute order 66

Answer:

The moment of inertia of this system is 68 kilogram-square meters.

Explanation:

We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:

[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)

Where:

[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.

[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.

By Pythagorean Theorem we calculate each distance:

[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]

[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{1} = 4\,m[/tex]

[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]

[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{2} = 3\,m[/tex]

If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:

[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)

[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]

[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]

The moment of inertia of this system is 68 kilogram-square meters.

The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.

Answer:

20 m

Explanation:

Area under the speed-time graph = Distance Traveled

Area under Graph 1/2(2)(20)

=20 m

Answer:

6.64 Newtons

On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon's gravity is 1/6th of the Earth's gravity. Your mass on any planet on the solar system (Jupiter, Venus, Earth, or anywhere else) is the same because the amount of matter in you does not change.

Explanation:

Answer:

group of answer choices

Explanation:

Answer:

1.

A. Vf = 29.4 m/s

B. h = 44.1 m

2.

A. Vf = 24.5 m/s

B. h = 30.625 m

3.

A. Vf = 5.5 m/s

4.

A. t = 3.03 s

B. Vf = 29.7 m/s  

Explanation:

1.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 3 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3 s)

Vf = 29.4 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²

h = 44.1 m

2.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 2.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(2.5 s)

Vf = 24.5 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²

h = 30.625 m

3.

A.

using 3rd equation of motion:

2gh = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 3 m/s

g = 9.8 m/s²

h = height = 2 m

Therefore,

2(9.8 m/s²)(2 m) = Vf² - (3 ms)²

Vf² = 39.2 m²/s² - 9 m²/s²

Vf = √30.2 m²/s²

Vf = 5.5 m/s

4.

A.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 45 m

Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)

t = time = ?

g = 9.8 m/s²

45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²

t² = 2(45 m)/(9.8 m/s²)

t = √9.18 s²

t = 3.03 s

B.

using 1st equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.03 s)

Vf = 29.7 m/s

Answer:

5

Explanation:

Answer:

5

Explanation:

Answer:

The speed of the projectile upon returning to its starting point is 50 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

The velocity of the projectile is maximum before hitting the ground. As the object moves upward, the velocity reduces as it approaches the maximum height, at the maximum height the velocity becomes zero. Also, as the object moves downward, the velocity starts to increase and becomes maximum before hitting the ground.

Therefore, the speed of the projectile upon returning to its starting point is 50 m/s.

Answer:

280.6N

Explanation:

According to Newton's second law;

Force = mass * acceleration

Given

Mass = 280kg

velocity = 10m/s

Time = 10 secs

Acceleration = velocity?/Time

Force = mass * velocity/time

Force = 280 + (16-10/10)

Force = 280 + 0.6

Force = 280.6N

Hence the force exerted by the snowmobile to accelerate is 280.6N

Answer:168 N

Explanation:

Answer:

that's fusion

Explanation:

Answer:

the answer is fusion for this

Answer:

3.3m

Explanation:

Given parameters:

Frequency  = 90Mhz

Unknown:

Wavelength  = ?

Solution:

To find the wavelength, use the expression below;

  V  = f x wavelength

V is the speed of light = 3 x 10⁸m/s

f is the frequency

Now;

 Insert the parameters

     3 x 10⁸  = 90 x 10⁶ x wavelength

   Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex]   = 3.3m

Answer:

Streamline the body of the rocket to reduce drag

Keep weight to a minimum

Use higher pressures

Use the right amount of water