A stone is thrown horizontally. In

0.5s

after the stone began to move, the numerical value of its

velocity was 1.5 times its initial velocity. Find the initial velocity of the stone. Disregard the

resistance of the air.​

Answers

Answer 1

Answer:

Approximately [tex]4.39 \; \rm m \cdot s^{-1}[/tex] (assuming that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Let the initial velocity of this stone be [tex]v\; \rm m \cdot s^{-1}[/tex] ([tex]v \ge 0[/tex] because speed should be non-negative.) That should be numerically equal to the initial horizontal speed of this stone. Because the stone was thrown horizontally, its vertical speed would initially be zero ([tex]0\; \rm m \cdot s^{-1}[/tex].)

The weight of this stone will accelerate the stone downwards. Because the weight of the stone is in the vertical direction, it will have no effect on the horizontal speed of the stone.

Therefore, if air resistance is indeed negligible, the horizontal speed of this stone will stay the same. The horizontal speed of the stone after [tex]0.5\; \rm s[/tex] should still be [tex]v\; \rm m \cdot s^{-1}[/tex]- same as its initial value.

On the other hand, if [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex], the (downward) vertical speed of this stone will increase by [tex]9.81\; \rm m \cdot s^{-2}[/tex] every second. After [tex]0.5\; \rm s[/tex], the vertical speed of this stone would have become:

[tex]0.5\; \rm s \times 9.81\; \rm m \cdot s^{-2} = 4.905\; \rm m \cdot s^{-1}[/tex].

[tex]t = 0\; \rm s[/tex]:

Horizontal speed: [tex]v\; \rm m \cdot s^{-1}[/tex].Vertical speed: [tex]0\; \rm m \cdot s^{-1}[/tex].

[tex]t = 0.5\; \rm s[/tex]:

Horizontal speed: [tex]v\; \rm m \cdot s^{-1}[/tex].Vertical speed: [tex]4.905\; \rm m \cdot s^{-1}[/tex].

Refer to the diagram attached. Consider the vertical speed and the horizontal speed of this rock as lengths of the two legs of a right triangle. The numerical value of the velocity of this stone would correspond to the length of the hypotenuse of that right triangle. Apply the Pythagorean Theorem to find that numerical value:

[tex]\begin{aligned} &\text{numerical value of velocity} \\ &= \sqrt{{\left(\text{horizontal speed}\right)}^2 + {\left(\text{vertical speed}\right)}^2}\end{aligned}[/tex].

At [tex]t = 0\; \rm s[/tex], the magnitude of the velocity of this stone would be [tex]\sqrt{v^{2} + 0^2} = v\; \rm m \cdot s^{-1}[/tex].

At [tex]t = 0.5\; \rm s[/tex], the magnitude of the velocity of this stone would be [tex]\left(\sqrt{v^2 + 4.905^2}\right)\; \rm m \cdot s^{-1}[/tex].

The question requires that the magnitude of the velocity of the stone at [tex]t = 0.5\; \rm s[/tex] should be [tex]1.5[/tex] times the value at [tex]t = 0\; \rm s[/tex]. In other words:

[tex]\sqrt{v^2 + 4.905^2} = 1.5 \, v[/tex].

Square both sides of this equation and solve for [tex]v[/tex]:

[tex]v^2 + 4.905^2 = 2.25\, v^2[/tex].

[tex]v \approx 4.39[/tex] ([tex]v \ge 0[/tex] given that speed should be non-negative.)

Therefore, the initial velocity of this stone should be approximately [tex]4.39\; \rm m \cdot s^{-1}[/tex].

A Stone Is Thrown Horizontally. In 0.5safter The Stone Began To Move, The Numerical Value Of Its Velocity

Related Questions

A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manager. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?

Answers

Answer:

  t = 6 s

Explanation:

This is a free fall exercise

          y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

         0 = y₀ + 0  - ½ g t2

         t = √(2yo / g)

let's calculate

         t = √ (2 176.4 / 9.8)

         t = 6 s

the balloon must be released 6 s before the person reaches the building

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Comentarios

In the picture below, sphere X swings down and collides with sphere Y. Identify the action and reaction forces. 

Action force: 
Reaction force: 

Answers

Answer:

Action force is force acting in one direction. Reaction force is force acting in the opposite direction.

Does lighting striking the earth considered the speed of light?

Answers

Answer:

i would tell you but im a hobbit

Explanation:

biden 2020

Problem (8):
A projectile is fired at an angle of 53° above the horizontal with initial speed of 10.0 m/s. After
one second, what is X and Y components of the position of that projectile?
A60m 20 m
B. 6.0 m. 8.0 m
C. 3.0 m, 6.0 m
D.4.0 m, 3.0 m​

Answers

Answer:

x=6 m, y= 3 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the components of the velocity at a given time t are:

[tex]v_x=v_o\cos\theta[/tex]

[tex]v_y=v_o\sin\theta-g.t[/tex]

And the components of the displacement are:

[tex]x=v_o\cos\theta .t[/tex]

[tex]\displaystyle y=v_o\sin\theta.t-\frac{g.t^2}{2}[/tex]

The projectile of the problem is fired at θ=53° with an initial speed of vo=10 m/s.

Thus, after 1 second, the components of the displacement are:

[tex]x=10\cos 53^\circ \cdot 1[/tex]

[tex]x\approx 6~m[/tex]

[tex]\displaystyle y=10\sin 53^\circ\cdot 1-\frac{9.8\cdot 1^2}{2}[/tex]

[tex]y\approx3~m[/tex]

Answer: x=6 m, y= 3 m

None of the options match this answer.

A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is
shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?
m
А
0
2
B
0.2"
C) 5
D
25"

Answers

Solution:

The gravitational force that acts on the bicycle system is

[tex]$F_{g} = 500 \ N$[/tex]

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

[tex]$F_g=mg$[/tex]

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

[tex]$F_f = ma$[/tex]

[tex]$a=\frac{F_f}{m}$[/tex]

  [tex]$=\frac{250}{50}$[/tex]

Therefore [tex]$a= 5 \ m/s^2$[/tex]

Hence (C) is correct option.  

A car with a mass of 1.5 × 103 kilograms is traveling west at a velocity of 22 meters/second. It hits a stationary car with a mass of 9.0 × 102 kilograms. If the collision is inelastic, what is the final direction and approximate velocity of the two cars?

Answers

Answer:

A. 14 meters/second to the west

Explanation:

The collision is inelastic, which means that:

- only the total momentum is conserved (not the kinetic energy)

Answer:

14 meters/second to the west

Explanation:

That's the answer!

an object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. what is the amount of the force?

Answers

Answer:

I believe the answer is 62.25 N

Explanation:

You just multiply 7.5 and 8.3 and you get 62.25

Answer:

62.25N or 62.25 newtons

Explanation:

F=ma where F is the force in newtons, m is the mass in kilograms (kg), and a is the acceleration

m=7.5kg

a=8.3m/s^2

Therefore, F=ma=7.5*8.3=62.25N

The amount of force is 62.25N or 62.25 newtons

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Answers

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} -a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]

A student walks 300 meters due east and then 100 meters due north,
then 500 meters due west. The total distance travelled by the student
-
is
meters.

Answers

Answer:

900 meter hhgffhffhhfcbjhggjdswexaazcgh

Answer:

900 meters

Explanation:

If you are talking about how many meters student walked then its 900 metes

But if you are talking about how many meters student travelled from the start point then its 200 meter

As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?
a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.

Answers

Answer:

a. The pressure in the tubing is equal to the barometric pressure.

Explanation:

Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.

Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure

Hence, the correct option is a.

8.
'A 6.00 kg ball, A, moving at velocity 3.00 m/s due east collides with a 6.00 kg ball, B, at rest.
After the collision, A moves off at 40.0°N of E and ball B moves off at 50.0° S of E
please help me.​

Answers

Answer:

brrrrrakabrrrrrrrrra

Explanation:

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 36.0 A. Find the resistivity of the material.

Answers

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

       [tex]R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)[/tex]

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

       [tex]R = \rho* \frac{L}{A} (2)[/tex]

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

      [tex]A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)[/tex]

Replacing  the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

       [tex]\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m[/tex]

ρ = 1.6*10⁻⁸ Ω/m

A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m/s?

Answers

Answer:

153J

Explanation:

Step one:

given data

mass m= 8.5kg

radius r= 10cm in meters = 0.01m

velocity v= 6m/s

The work done will be the same as the energy possessed by the sphere at such speed

Required

the work one in Joules

we know that

KE=1/2mv^2

KE=1/2*8.5*6^2

KE= 1/2*8.5*36

KE=306/2

KE=153J

An unknown mass is hung from a very light spring with a spring constant of 13.6 N/m. Neglect the mass of the spring. If the period of oscillation of the mass-spring system is 3.35 s, then the unknown mass is:__________

Answers

Answer:

The unknown mass is 3.87 kg.

Explanation:

Given;

spring constant of the spring, k = 13.6 N/m

period of oscillation, T = 3.35 s

The period of oscillation of the mass-spring system is given by;

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where;

m is the mass attached to the spring

[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]

Therefore, the unknown mass is 3.87 kg.

The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?

Answers

Answer:

0.79g/cm³

Explanation:

Given parameters:

Volume of acetone = 120cm³

Mass of empty flask  = 49.74g

Mass of flask + acetone  = 144.78g

Unknown:

Density of acetone = ?

Solution:

Density is the mass per given volume of a substance. It is mathematically expressed as;

   Density  = [tex]\frac{mass}{volume}[/tex]  

     Mass of acetone  =( mass of flask + acetone)   - mass of empty flask

     Mass of acetone = 144.78  - 49.74  = 95.04g

Now insert the parameters and solve;

 Density  = [tex]\frac{95.04}{120}[/tex]   = 0.79g/cm³

A segment of wire of total length 3.0 m carries a 15-A current and is formed into a semicircle. Determine the magnitude of the magnetic field at the center of the circle along which the wire is placed. a. 1.6 mu T b. 4.9 mu T c. 1.0 mu T d. 9.8 mu T e. 15 mu T

Answers

Answer:

c. 1.0 mu T

Explanation:

From, the ampere's  circuit law:

∫B.dl = μ₀ I

B.(2πr) = μ₀ I

where,

B = Magnetic Field = ?

r = radius of the circle = length of wire = 3 m

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

I = Current = 15 A

Therefore,

B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)

B = 10 x 10⁻⁷ T

B = 1 x 10⁻⁶ T = 1 μT

Hence, the correct option is:

c. 1.0 mu T

In the flowchart representation of the scientific method (the one that embraces the use of constructing models), what does one do immediately after making observations?

Answers

Answer:

The correct answer is - ask a question based on observation and then postulate a hypothesis.

Explanation:

The scientific method is the step by step process to find an answer to any scientific question with the help of scientific investigation or experiment. The steps that make an investigation successful are should be in the correct order. These steps are as follows:

*Make an Observation

*Ask a Question

*Do Background Research

*Form a Hypothesis

*Conduct an Experiment

*Analyze Results and Draw a Conclusion

*Report Your Results

30.6*X+-2.56
Pls help

Answers

Answer:  10.16

Explanation:

Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another 9
km. That part of her trip takes her 2 h. What is her average speed?

Answers

Answer:

24km/h

Explanation:

go it right on ingenuity 2020

On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Find the acceleration due to gravity on this planet's surface. What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.450 kg attached to a spring of force constant 9.75 N/m?

Answers

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

what is the mass of an object with a density of 74 g/mL and a volume of 7 mL?

Answers

Answer:

518 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 74 × 7

We have the final answer as

518 g

Hope this helps you

Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and my work is 5321.7 J. After calculating work, I got -5321.7 J. I am supposed to calculate my power used over 3 trials. The time for trial 1 was 4.69 and the seconds for trials 2 and 3 are 4.25. After calculating my power I got -1134.69 W and -1252.16 W. I am not sure if I got my power right. Is my power really negative or is my power positive?

Answers

Answer:

Yes.

Explanation:

A negative power would just represent a loss of power. So in your case it lost -1252.16 W

Two car's are racing! The winner of the race will always be be the vehicle with the greater...

Answers

velocity i believe ?
The velocity using the speed down flow of the wind and aerodynamics of the cars body and build it would be velocity with a higher down flow to the ground it go’s faster because it’s closer the the ground like an F1 racing car especially if the car has a spoiler is brings it closer down to the ground

Check how you understand the principles of working of lenses. In some optical setup consisting of a single lens and an object magnification factor is measured as m-+4. We can conclude that:__________ a. Lens is converging, image is at the opposite side of lens from the object b. Lens is converging, image is the same side of lens as object c. Lens is diverging, image is at the opposite side of lens from the object d. Lens is diverging, image is the same side of lens as object

Answers

Answer:

b. Lens is converging, image is the same side of lens as object

Explanation:

A single converging lens is often used as a magnifying glass. The reason, behind its use as a magnifying glass is the configuration of the converging lens, when an object is placed inside its focal length. It forms the image of that object as magnified and at the same side as the object. So, the image is both magnified and erect. In this way, the converging lens serves as a magnifying glass with certain magnification factor, single handedly. The ray diagram of a magnifying glass is attached for reference. So, the correct option is:

b. Lens is converging, image is the same side of lens as object

Picture question please answer do in 5 mins

Answers

Answer:

Can't see anything, please share clearly

What happens in a convection current?

Answers

Answer:

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

Explanation:

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J

765,625 J

218,750 J

87,750 J

Answers

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

[tex]K.E_{max} = P.E_{max}[/tex]

[tex]K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J[/tex]

[tex]Thus, P.E_{max} = 109,375 \ J[/tex]

Therefore, the prediction for its maximum potential energy is 109,375 J

What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?

Answers

5.5 is the answer i think

A nail driven into a board increases in temperature.
If 59.0 % of the kinetic energy delivered by a 1.60 kg hammer with a speed of 7.70 m/s is transformed into heat that flows into the nail and does not flow out, what is the increase in temperature of an 7.60 g aluminum nail after it is struck 10 times?

Answers

Answer:

ΔT = 40.91 °C

Explanation:

First we find the kinetic energy of one hit to the nail:

K.E = (1/2)mv²

where,

K.E = Kinetic energy = ?

m = mass of hammer = 1.6 kg

v = speed of hammer = 7.7 m/s

Therefore,

K.E = (1/2)(1.6 kg)(7.7 m/s)²

K.E = 47.432 J

Now, for 10 hits:

K.E = (10)(47.432 J)

K.E = 474.32 J

Now, we calculate the heat energy transferred (Q) to the nail. As, it is the 59% of K.E. Therefore,

Q = (0.59)K.E

Q = (0.59)(474.32 J)

Q = 279.84 J

The change in energy of nail is given as:

Q = mCΔT

where,

m = mass of nail = 7.6 g = 0.0076 kg

C = specific heat capacity of aluminum = 900 J/kg.°C

ΔT = Increase in temperature = ?

Therefore,

279.84 J = (0.0076 kg)(900 J/kg.°C)ΔT

ΔT = (279.84 J)/(6.84 J/°C)

ΔT = 40.91 °C

What name is given to the rate at which velocity changes?
Answer mere

Answers

Answer:

Acceleration

Explanation:

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The night before, he had been putting the finishing touches on the speech when his mother snuck up the stairs and stopped by his bedroom door with a mug of tea. It looks like you will need this. Hows it coming? She tucked the long end of her sari under her leg and sat on his bed. The familiar smell that reminded him of trips to India tickled his nose as he took the warm mug from her; he pressed it to his lips and took a long sip. I dont think theyre going to understand it. Its okay if they dont understand it in their brains; its more important that they feel it here. She pressed her hand to his heart. My friends dont know what you went through to get here, and I want to get it just right because I need them to like the story. Your friends will like you no matter what. Practice it one more time, and then you need to get some sleep. He stared at the words that he had painstakingly crafted to tell the story of how his parents had immigrated to the United States from India. Even though he hadnt been born at the time, he could feel the heat on their skin as theyd packed up their belongings in Mumbai and boarded the plane for their new lives. After a twenty20-hour flight, they landed in the chill of Chicago; they hadnt brought enough heavy clothes with them and had to buy sweatshirts from the airport store before stepping out into snow for the first time. His mother had danced around in the swirling white like a fascinated child, tasting flakes on her tongue before the cab whisked them away to their new lives. He didnt know how his parents got by in those early days of loneliness and isolation, when they didnt know their neighbors and couldnt find their favorite spices or flavors in the local grocery store. He imagined his homesick mother making pungent curry in the tiny kitchen of the apartment that was their first homecurry that she didnt share with anyone except her husband because he was the only person she knew. Eventually they had made a life there, and one year after theyd brought Samir home as a newborn, his younger sister Aarti was born, and they became a family of four. Each year that his parents lived in Chicago, they spoke about Mumbai like it was more of a memory. Samir grew up hearing stories of Mumbai and taking summer trips where he heard his parents speak a language that was clumsy on his own English-speaking tongue. He couldnt imagine leaving his life and moving herefar away, but he knew that his parents had done it for him and his sister. It was the ultimate sacrifice, his mother had said, but it was worth it. When he had finished rehearsing his speech for his mother, she dabbed her face, and he knew she was crying. He didnt need to ask how the speech washer expression told him that it was perfect. Samirs thoughts came back to the present moment as he cleared his throat and stepped onto the stage in front of the entire middle schoolhis friends and teachers were all here. He had often felt different from his peers and wanted so much for them to understand his story. But looking out into the crowd at all the different faces he realized that his peers must have their own stories to tell as well. Perhaps they wanted to be understood, too. He realized the only way to be understood is to share those stories. Perhaps if he shared his own story, others would share theirs, too. Perhaps it would help them to understand one another. He found his moms eyes in the middle of the front row. When she nodded, he began. Im going to tell the story of how my parents became American citizens.How does the theme that it is important to understand our family stories develop in "The Speech"?The theme develops through the author's depiction of how Samir realizes that Chicago must have been as strange to his parents as Mumbai was to him as a child.The theme develops through the author's depiction of how Samir's recollection of his family's story before he gives his speech helps him to appreciate his family as well as the different experiences of others.The theme develops through the author's depiction of how Samir changes from being nervous about giving a speech about his family to feeling confident after he recalls his family's story.The theme develops through the author's depiction of how Samir changes from feeling different from his peers to feeling not so different after his mother tells him their family story. What is an example of how the abolitionist movement began to grow in the 1830s? Select three responses.Most Southern politicians argued to end slavery. Anti-slavery publications were produced. The American Anti-Slavery Society was founded. Petitions demanded that Congress end slavery. Southern states reduced the use of slave labor. i just need number 2 pls Why do we have different cells in our bodies if every cell has the same DNA?A. Gene expression B. Protein synthesis C. MeiosisD. Mitosis