a. Some materials exhibit the property of superconductivity under certain conditions.
State what is meant by superconductivity and explain the required conditions for the
material to become superconducting.

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Answer:

E.P.E = 1.27 x 10⁻⁴ J = 0.127 mJ

Explanation:

From Law of Conservation Energy, we know that:

Elastic Potential Energy Stored = Gain in Kinetic Energy + Gain in Gravitational Potential Energy

E.P.E = (1/2)mv² + mgh

where,

E.P.E = Elastic Potential Energy = ?

m = mass of flea = 0.1 g = 1 x 10⁻⁴ kg

v = speed = 1.25 m/s

g = 9.8 m/s²

h = height = 5 cm = 0.05 m

Therefore,

E.P.E = (1/2)(1 x 10⁻⁴ kg)(1.25 m/s)² + (1 x 10⁻⁴ kg)(9.8 m/s²)(0.05 m)

E.P.E = 0.78 x 10⁻⁴ J + 0.49 x 10⁻⁴ J

E.P.E = 1.27 x 10⁻⁴ J = 0.127 mJ

Answer:

Explanation:

F

Answer:

Explanation:

Using the pythagoras theorem, the displacement is expressed as;

d² = x²+y²

y = 36m (north)

x = 20m east

Substitute;

d² = 36²+20²

d² = 1296+400

d² = 1696

d = √1696

d = 41.18m

For the direction;

theta = tan^-1(y/x)

theta = tan^-1(36/20)

theta = tan^-1(1.8)

theta = 60.95°

Hence the magnitude is 41.18m and the direction is 60.95°

Answer:

B) brittle

Explanation:

This describes most covalent compounds.

Answer:

B.)

Explanation:

The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.

Answer:

answers, the correct one is b

Explanation:

For this problem we use the fact that since the ends are open at these points we have a maximum,

fundamental L =λ/2 λ = 2L

second harmonic L = λ λ = 2L / 2

third harmonic L = 3 λ/2 λ = 2L / 3

n harmonic lam = 2L / n

 with n an integer

therefore the length of the first three harmonics are: 2L, L, 2L / 3

when examining the different answers, the correct one is b

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 3.6

We have the final answer as

Hope this helps you

Answer:

Explanation:

The mass of the car can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{1850}{2.4} \\ = 770.83333...[/tex]

We have the final answer as

Hope this helps you

Answer:

Explanation:

Step one:

given

length of rod=2m

mass of object 1 m1=1kg

let the unknown mass be x

center of mass c.m= 1.6m

hence 1kg is 1.6m from the c.m

and x is 0.4m from the c.m

Taking moment about the c.m

clockwise moment equals anticlockwise moments

1*1.6=x*0.4

1.6=0.4x

divide both sides by 0.4 we have

x=1.6/0.4

x=4kg

The mass of the other object is 4kg

Answer:

The object takes 3.84 seconds to return to earth.

Explanation:

Projectile Motion

It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.

The initial velocity has two components, given by:

[tex]v_x=vo_x[/tex]

[tex]v_y=vo_y-gt[/tex]

Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.

The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:

[tex]vo_y-gt=0[/tex]

[tex]\displaystyle t_m=\frac{vo_y}{g}[/tex]

The initial vertical component of the velocity is 18.8 m/s, thus:

[tex]\displaystyle t_m=\frac{18.8}{9.8}=1.92~s[/tex]

The total time is double that time:

[tex]t_t=2*1.92~s=3.84~s[/tex]

The object takes 3.84 seconds to return to earth.

Solution :

The moment of inertia for a circular disc about its centre is given by

[tex]$I=\frac{mr^2}{2}$[/tex]

Given , radius of CD, [tex]$r=\frac{d}{2}$[/tex]

[tex]$r=\frac{1.5 \times 10^{-2}}{2}$[/tex]

  [tex]$=7.5 \times 10^{-2} \ m$[/tex]

A).

The moment of inertia of CD about its centre is

[tex]$I_{centre}=\frac{mr^2}{2}$[/tex]

          [tex]$=\frac{25 \times 10^{-3}\times (7.5 \times 10^{-2})^2}{2}$[/tex]

          [tex]$= 7\times 10^{-5} \ kg \ m^2$[/tex]

B).

The moment of inertia about parallel axis of CD with respect to its central axis is given by the parallel axis theorem,

[tex]$I_{p}=I_c + md^2$[/tex]

where, d is the distance between the parallel axis and central axis

Therefore, moment of inertia of CD about its edge is

[tex]$I_p=I_c +md^2$[/tex]

   [tex]$=\frac{mr^2}{2}+mr^2$[/tex]

   [tex]$=\frac{3}{2}mr^2$[/tex]

   [tex]$=\frac{3(25 \times 10^{-3})\times (7.5 \times 10^{-2})^2}{2}$[/tex]

   [tex]$=2.1 \times 10^{-4} \ kg \ m^2$[/tex]

(a) The  CD's moment of inertia for rotation about a perpendicular axis through its center is [tex]7.031 \times 10^{-5} \ kgm^2[/tex]

(b) The CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk is [tex]2.11 \times 10^{-4} \ kgm^2[/tex]

The given parameters;

(A) The  CD's moment of inertia for rotation about a perpendicular axis through its center is calculated as follows;

[tex]I_c = \frac{1}{2} mr^2\\\\I_c = \frac{1}{2} \times 0.025 \times (0.075)^2\\\\I_c = 7.03 1 \times 10^{-5} \ kgm^2[/tex]

(B) The CD's moment of inertia for rotation about a perpendicular axis through the edge of the disk is calculated as;

[tex]I_p = I_c + mr^2\\\\I_p = (7.031 \times 10^{-5}) \ + \ 0.025 \times (0.075)^2\\\\I_p = 2.11 \times 10^{-4} \ kgm^2[/tex]

Learn more here:https://brainly.com/question/19091222

Answer:

Explanation:

Focal length (f) can be defined as the distance from the focal point to the centre of the surface of the mirror.

While radius of curvature (r) is the radius of the sphere of which the mirror forms a part.

Hence the relationship between the two is that the focal length is half of the length of the radius of curvature.

Mathematically,

F = r/2

Answer: u failed both sad welp ill try to help

Explanation: