a sequence starts a 200 and 30 is subtracted each time 200,170,140 what are the first two numbers in the sequence that are less
then zero

Answers

Answer 1

Answer:

- 10, - 40

Step-by-step explanation:

200, 170, 140, .... - 10, - 40 ....

30 × 5 = 150

140 - 150 = - 10

- 10 - 30 = - 40


Related Questions

Mr. Ruiz has $438.60 taken from
his account each month to pay for
the loan on his car. What is the
change in the account caused by
4 months of payments?

Answers

Answer: $1754.4


Explanation: 438.60 x 4 = 1754.4

pie r formula is 22/7 when we divide 22/7 it will be 3.14 and 3.14 is an irrational number and irrational number can not be formula of any sum then how the pie formula is 22/7.explain it with reason.

Answers

Answer:

22/7 is not pi

Step-by-step explanation:

22/7 is just a close approximation for pi, not pi itself.

If you put 22/7 into a calculator, you get:

3.142857...

While the number pi itself is:

3.1415926...

You can notice that pi is actually different than 22/7, even though the two numbers start out the same and are close to each other. Frequently in geometry, you use 22/7 as pi because it's so close and makes calculation easier.

Hope this helps!

Estimate the correlation coefficient that would best describe the data below.

Answers

Answer:

Last option

....... -0.4

A turtle was crawling at the rate of 43 cm per minute. How many kilometers would this turtle crawl in one day (24 hours) if it did not rest and continued to crawl at a continuous pace?

Answers

Answer:

0.6192

Step-by-step explanation:

Daniel practises his guitar for 40 minutes every day

If Daniel practises six days per week for 50 weeks per year, how many years will it take him to log up 10 000 hours of practice?

Answers

It would take him 50 years

What is the difference between the highest and the lowest medal counts.​

Answers

Answer:

by observation we get to know

highest is 28

lowest is 4

hence difference = 28 - 4 = 24

brainliest plsss

The highest has 28 medals and the lowest has 4 medals, from observation they have 24 medal difference.

Solve the following equation for b. Be sure to take into account whether a letter is capitalized or not.
t+1/2b=Y

Answers

Answer:

b = 2(Y - t)

Step-by-step explanation:

Given:

t + 1/2b = Y

Isolate b:

1/2b = Y - t

Find b:

b = 2(Y - t)

[tex]\\ \sf\longmapsto t+\dfrac{1}{2}b=Y[/tex]

take t right side

[tex]\\ \sf\longmapsto \dfrac{1}{2}b=Y-t[/tex]

[tex]\\ \sf\longmapsto \dfrac{b}{2}=Y-t[/tex]

[tex]\\ \sf\longmapsto b=2(Y-t)[/tex]

[tex]\\ \sf\longmapsto b=2Y-2t[/tex]

Wanja had 240 orange trees.Elephant destroyed 36 of them .What was the percentage decrease in the number of the orange trees ​

Answers

That's my Answer

Pls mark me brainliest

5 x 1/4
how can you use addition to show that your answer is correct?​

Answers

Answer:

Step-by-step explanation:

[tex]5*\dfrac{1}{4}=\dfrac{5}{4}\\[/tex]

Using addition,

Add (1/4) , five times

[tex]\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{1+1+1+1+1}{4}\\\\=\dfrac{5}{4}[/tex]

Answer:

5/4

Step-by-step explanation:

Add 1/4 together 5 times:

1/4 + 1/4 + 1/4 + 1/4 + 1/4 = 5/4

0.008 x 2.5 in standard form is (A) 2 x 10-² (B) 2 x 10 (C) 2 x 10-¹ (D) 2 x 10²​

Answers

Answer:

(D) 2 x 10²

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Hope it is helpful.....

Answer:

2 × 10 ^2

Step-by-step explanation:

(d) option is correct

carol invests $6250 at a rate of 2% per year compound interest.
calculate the total amount Carol has after 3 Years

Answers

Answer:

6632.55

Step-by-step explanation:

P=A*(1+r/100)^x

P=6250*(1+2/100)^3

P=6632.55

Answer:

$6632.55

Step-by-step explanation:

→ Find the multiplier

( 100 + 2 ) ÷ 100 = 1.02

→ Multiply the investment by the multiplier to the power of years

6250 × ( 1.02 )³ = 6632.55

Find tan 0 if sin 0 = 1/2
is in the second quadrant.

Answers

sin O = 1/2 = p/h

p=1, h = 2.

by pythagoras tgeorem,

b =

[tex] \sqrt{3} [/tex]

tan0= p/b

[tex]1 \div \sqrt{3} [/tex]

Given the function f(x) = -2c+cx-x^2, and f^-1(5) = -1, find c

Answers

Answer:

[tex]c=-2[/tex]

Step-by-step explanation:

We are given the function:

[tex]f(x) = -2c + cx - x^2[/tex]

And that:

[tex]\displaystyle f^{-1} (5) = -1[/tex]

And we want to determine the value of c.

Recall that by definition of inverse functions:

[tex]\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a[/tex]

So, since f⁻¹(5) = -1, then f(-1) = 5.

Substitute:

[tex]f(-1) = 5 = -2c + c(-1) - (-1)^2[/tex]

Simplify:

[tex]5 = -2c - c - (1)[/tex]

Combine like terms:

[tex]6 = -3c[/tex]

And divide. Hence:

[tex]c = -2[/tex]

In conclusion, the value of c is -2.

Plzz help me with this question ​

Answers

Answer:

4

Step-by-step explanation:

The degree is equal to the largest exponent on a variable. In this instance, it is 4.

Someone help asapppp

Answers

Answer:

1

Step-by-step explanation:

Answer:

1/ a

Step-by-step explanation:

go to desmos graphing calculator :) yea

////

p-83=129 ?????????????????????????

Answers

Answer:

p = 212

Step-by-step explanation:

p-83=129

Add 83 to each side

p-83+83=129+83

p =212

Answer:=212

Step-by-step explanation:

add 83 to both sides and then simplify

−83=129

p-83=129

p−83=129

−83+83=129+83

1 upon sec A -tan a minus one upon cos A is equal to 1 upon Cos A minus one upon sec a + tan a prove it​

Answers

Step-by-step explanation:

1/(seca-tana) - 1/cosa=1/cosa -1/(seca+tana)

There are many ways to solve this, let's take a look at a simple one

1/(seca-tana) + 1/(seca+tana) =1/cosa + 1/cosa

((seca-tana)+(seca+tana))/(sec^2a-tan^2a)=2/cosa

(seca-tana+seca+tana)/1=2*1/cosa

2seca=2seca

Help anyone can help me do this question,I will mark brainlest.​

Answers

Answer:

8 cm

Step-by-step explanation:

AM = MC = BM = (1/2) BC => AM , MC , BM = 5, => BC = 10apply pytago => (AC ^ 2) + (AB ^ 2) = (BC ^2)AB = [tex]\sqrt{BC ^2 - AC ^2}[/tex] = [tex]\sqrt{10 ^2 - 6 ^ 2}[/tex] = 8 (cm)

Answer:

4

Step-by-step explanation:

So first let's write the information we got

Angle BAC = 90 degrees

Midpoint of BC = M

AC = 6cm

Am= 5cm

Also I found MC = BM, since it has a line that represents both lines are same

so to find it we have to Pythagoras theorem (A^2 + B^2 = C^2), well it is question we have the 'A value and C Value', also we need to find the value of B to find the length of MC and BM

A = 5

C = 6

so therefore to find B^2, we have to do the reverse, we don't add but subtract

C^2 - A^2 = B^2

___________________________________________________________

Moving on to Calculation

6^2 - 5^2 = B^2

36 - 25 = B^2

B^2 = 9

B = √9

B = 3

MC and BM Length =  3 cm

____________________________

Now, we know the length we again need to use Pythagoras theorem to solve this.

Since we know

A = 5

B = 3

So..

A^2 + B^2 = C^2

5^2 + 3^2 = C^2

25 - 9 = C^2

C^2 = 16

C = √16

C = 4

Help plz Algebra 1

Simplify numbers 10 and 13 <3

Answers

Answer:

10t+2

Step-by-step explanation:

2-5t+8+5t-8

10t+2

The answer above is right

given that y/√5 = √20 ×10^-3×10^5x. and lgy- mx = c for x>0 and y>0, find the values of m and c​

Answers

Answer:

m = 5 and c = -2

Step-by-step explanation:

[tex]let \: y = \sqrt{20} \times {10}^{ - 3} \times {10}^{5x} \\ be \: equation \: 1[/tex]

Now

[tex]y = \sqrt{5} ( \sqrt{20} \times {10}^{ - 3} \times {10}^{5x} ) \\ y = \sqrt{100} \times {10}^{ - 3} \times {10}^{5x} \\ y = 10 \times {10}^{ - 3} \times {10}^{5x} [/tex]

[tex]using \: rules \: of \: indices \: we \: get \\ y = {10}^{1 - 3 + 5x} \\ y = {10}^{ - 2 + 5x} \\ [/tex]

[tex]now \: take \: log \: of \: both \: sides \: and \: use \: laws \: of \: logarithm \\ we \: get \\ [/tex]

[tex] log(y) = log( {10}^{ - 2 + 5x} ) \\ log(y) = ( - 2 + 5x) log(10) \\ log(y) = - 2 + 5x \\ log(y) - 5x = - 2 \\ \\ comparing \: this \: to \: \\ log(y) - mx = c \\ \\ we \: get \: m \: = 5 \: and \: c = - 2[/tex]

how to solve 5/6=v+2/7

Answers

Answer:

5/6 = v + 2/7

Step-by-step explanation:

5/6 = v + 2/7  

23/42 - v = 0

5/6 = 1/7 (7 v + 2)

Answer:

23/42 = v

Step-by-step explanation:

5/6=v+2/7

Multiply each side by the common denominator, 42

42( 5/6=v+2/7)

35 = 42v + 12

Subtract 12 from each side

35-12 = 42v

23 = 42 v

Divide each side by 42

23/42 = v

PLEASE HELP ASAP T^T

Answers

9514 1404 393

Answer:

  no feasible solutions

Step-by-step explanation:

There are so many inequalities that determining the area covered by all 5 of them is problematic. Hence, we have reversed all of them in the attached graph, so any feasible solution region would remain white. Alas, there is no such region.

This system of inequalities has no feasible solution.

Pleaseeeee help!!!!!!!!

Answers

Answer:

30

Step-by-step explanation:

The total number of people is

5+6+4+7+5+3 = 30 people

Answer:

30

Step-by-step explanation:

pizza:5+7=12

Burger:6+5=11

Other:4+3=7

Total:12+11+7=30

10.4825 rounded to the nearest cent plz show work ty ! :D

Answers

Answer:

$10.48

Step-by-step explanation:

To the nearest cent, your answer would be 10.48

9) Determine which sides, if any, of the figures are parallel, perpendicular, or neither.
Rectangle BACD has coordinate B(-4,-3), A(-1, -7),C(3,-4), and D(0,0).

Answers

Answer:

Parallel: AC and DB, BA and CD

Perpendicular: AC and CD, DB and CD, DB and BA, BA and AC

Neither: None

Step-by-step explanation:

Step 1: Find Slopes

Let's first find the slopes of each side of the rectangle, as that will helps us determine which sides are parallel, perpendicular, or neither.

Recall that the formula for finding the slope between two points is [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex] where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the two points. To avoid confusion, I will be taking the first point I list as [tex](x_1,y_1)[/tex] and the second point as [tex](x_2,y_2)[/tex].

Slope of [tex]BA[/tex]:

[tex]\frac{-7-(-3)}{-1-(-4)}\\=\frac{-7+3}{-1+4} \\= -\frac{4}{3}[/tex]

Slope of [tex]AC[/tex]:

[tex]\frac{-4-(-7)}{3-(-1)} \\=\frac{-4+7}{3+1} \\=\frac{3}{4}[/tex]

Slope of [tex]CD[/tex]:

[tex]\frac{0-(-4)}{0-3} \\=\frac{4}{-3} \\=-\frac{4}{3}[/tex]

Slope of [tex]DB[/tex]:

[tex]\frac{-3-0}{-4-0} \\=\frac{-3}{-4} \\=\frac{3}{4}[/tex]

Step 2: Determine which sides are parallel, perpendicular, or neither

Now that we found the slopes of the sides, we can determine which sides are parallel, perpendicular, or neither.

Recall that parallel lines have the same slope. [tex]\bf AC[/tex] and [tex]\bf DB[/tex], along with [tex]\bf BA[/tex]and [tex]\bf CD[/tex], have the same slope, so they are parallel. No other pair of sides has the same slope, so these are our only parallel pairs.

For two lines to be perpendicular, the product of their slopes must be [tex]-1[/tex]. [tex]\bf AC[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf BA[/tex], and [tex]\bf BA[/tex] and [tex]\bf AC[/tex] [tex]\bf[/tex]meet that criteria, so they are perpendicular. No other pair of sides meets the criteria, so these are our only perpendicular pairs. Hope this helps!

Help me ? :( no spam or

Answers

tan30=1/√3tan60=√3

Now

[tex]\\ \sf\longmapsto tan(\alpha+\beta)=\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto \alpha+\beta=60\dots(1)[/tex]

And

[tex]\\ \sf\longmapsto tan(\alpha-\beta)=\dfrac{1}{\sqrt{3}}[/tex]

[tex]\\ \sf\longmapsto \alpha-\beta=30\dots(2)[/tex]

Adding both

[tex]\\ \sf\longmapsto 2\alpha=30+60=90[/tex]

[tex]\\ \sf\longmapsto sin2\alpha=sin90[/tex]

[tex]\\ \sf\longmapsto sin2\alpha=1[/tex]

if an angle is 10 degree less than its complement, find the angle.

Answers

Let one be x

Other one is x-10

ATQ

[tex]\\ \sf \longmapsto x+x-10=90[/tex]

[tex]\\ \sf \longmapsto 2x-10=90[/tex]

[tex]\\ \sf \longmapsto 2x=90+10[/tex]

[tex]\\ \sf \longmapsto 2x=100[/tex]

[tex]\\ \sf \longmapsto x=\dfrac{100}{2}[/tex]

[tex]\\ \sf \longmapsto x=50[/tex]

[tex]\\ \sf \longmapsto x-10=50-10=40[/tex]

If 5x:(x-2) = 11:3 , find the value of x ?​

Answers

Answer:

x = -11/2

Step-by-step explanation:

The ratios need to stay the same

5x        11

----- = -------

x-2       3

Using cross products

5x*3 = (x-2) 11

15x = 11x - 22

Subtract 11 from each side

15x-11x = -22

4x = -22

x = -22/4

x = -11/2

Answer:

5 whole number 1/2

Step-by-step explanation:

5x:(x-2)=11:3

(:)This simply means ''ratio''

5x/(x-2) = 11/3

(cross multiply)

11(x-2) = 3(5x)

11x-22 = 15x

collect like terms

15x - 11x = 22

4x = 22

x = 22/4, but it is best you put it as a Mixed number.

x = 5 whole number 2/4, which can be reduced to

x = 5 whole number 1/2

whats the gcf of 50,40
whats the gcf of 14,56,63

Answers

For 50 and 40 the GCF is 10
For 14,56,63 the GCF is 7
Hope this helps!
Would really appreciate it if given brainleist, thanks!

9514 1404 393

Answer:

107

Step-by-step explanation:

The GCF can be no larger than the difference between the numbers. That would be the first value you want to check to see if it is a factor of the numbers.

GCF(40, 50)

The difference is 10, which is a factor of both 40 and 50.

  GCF(40, 50) = 10

__

GCF(14, 56, 63)

You can figure the GCF pairwise, as GCF(14, 56) = 14; then GCF(14, 63) = 7. Or, you can look at the smallest difference between any pair of numbers. Here, that is 63 -56 = 7, which is a factor of all three numbers.

  GCF(14, 56, 63) = 7

_____

Additional comment

Euclid's algorithm has you compute the remainder from division of the largest by the smallest. When that remainder is non-zero, it replaces the largest, and you repeat. When the remainder is zero, the smallest is the GCF.

For example, let's look at the GCF of 14 and 63.

  63/14 = 4 r 7

  14/7 = 2 r 0 . . . . . 7 is the divisor, so is the greatest common factor

A father is now twice as old as his son. If the sum of their ages ten years ago was fifty two, how old are they today?​

Answers

Answer:

24 and 48

Today, the son is 24 years old, and the father is 48 years old.  

Step-by-step explanation:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

The father is 2 times his son's age.

2x

= 2(24)

= 48

So, the son is 24 and the father is 48.

10 years ago, son was 14 and father was 38, if added, this adds up to 52, so we know our calculations are correct.

Answer:

So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.

Step-by-step explanation:

If the son’s age is x, the father’s age is 2x.

Ten years ago:

(x - 10) + (2x - 10) = 52

3x + 20 = 52

3x = 72

x = 24

2x = 48

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