Answer:
mk7000000.0000000000
A bus is moving to the right at an absolute velocity U. You throw a water balloon at the bus at an absolute velocity V (greater than U) after the bus passes you. A person on the bus sees the balloon hit the bus at a speed of:
Answer:
The person on the bus will see the balloon hit the bus at a velocity = V - U
Explanation:
There is relative motion between the water balloon and the person sitting in the bus.
Relative motion is the motion of a body with respect to another body (eg. an observer) from the point of reference of the second body (observer).
The person on the bus has a velocity which is the same as that of the moving bus = U
The velocity of the thrown water balloon (greater than U) = V
The relative motion between the person and the water balloon is the difference between their velocities (since they are both moving in the same direction) = V - U
Therefore, the person on the bus will see the balloon hit the bus at a velocity = V - U
A pencil is dropped from rest from a height of 1.8 meters above the ground. How much time does it take the pencil to hit the ground?
Answer:
0.60s
Explanation:
Using the motion equation as follows:
S = ut + 1/2gt²
Where;
S = distance travelled (m)
u = initial velocity (m/s)
t = time (s)
g = acceleration due to gravity (m/s²)
Based on the information provided, S = 1.8m, u = 0m/s, t = ?
S = ut + 1/2gt²
1.8 = (0×t) + 1/2 (9.8t²)
1.8 = 0 + 4.9t²
1.8 = 4.9t²
t² = 1.8/4.9
t² = 0.3673
t = √0.3673
t = 0.6060
t = 0.60s
PLS HELP PLS 10. This graph represents the velocity of an object over time. What is the average acceleration of the
object during the first 4 seconds?
Answer:
8 M/S
Explanation:
This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.
Problem 6 (20 points) A ballistic pendulum is a device often used for measuring the velocity of a projectile. Assume to projectile fully embeds itself in the pendulum. If the projectile mass is 25 grams, the pendulum mass is 2.5 kg, and the vertical displacement of the pendulum after the collision is 12 cm, find the velocity of the projectile just prior to the collision.
Answer:
The velocity of the projectile just prior to the collision is 154.934 meters per second.
Explanation:
Let consider the projectile-pendulum system as our system of study, from statement we know that projectile gives kinetic energy to the pendulum and turns into gravitational potential energy. By Principle of Energy Conservation we construct the following expression:
[tex]U_{g,1}+K_{1} = U_{g,2}+K_{2}[/tex] (Eq. 1)
Where:
[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Initial and final gravitational potential energies, measured in joules.
[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies, measured in joules.
By applying definitions of gravitational potential and kinetic energies, we expand and simplify the equation above:
[tex](m+M)\cdot g \cdot (y_{2}-y_{1}) = \frac{1}{2}\cdot (m+M)\cdot (v_{1}^{2}-v_{2}^{2})[/tex]
[tex]g\cdot (y_{2}-y_{1})=\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex]
And we clear the initial velocity of the pendulum-projectile system:
[tex]v_{1}=\sqrt{v_{2}^{2}+2\cdot g\cdot (y_{2}-y_{1})}[/tex] (Eq. 2)
Where:
[tex]m[/tex] - Mass of the projectile, measured in kilograms.
[tex]M[/tex] - Mass of the ballistic pendulum, measured in kilograms.
[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the pendulum-projectile system, measured in meters per second.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]y_{1}[/tex], [tex]y_{2}[/tex] - Initial and vertical position of the pendulum-projectile system, measured in meters.
Under the consideration of inellastic collision, we find the velocity of the projectile prior to the collision by Principle of Linear Momentum Conservation:
[tex]m\cdot v_{o, P} + M\cdot v_{o,B} = (m+M)\cdot v_{1}[/tex]
[tex]v_{o,P} = \frac{(m+M)\cdot v_{1}-M\cdot v_{o,B}}{m}[/tex] (Eq. 2)
Where:
[tex]v_{o, P}[/tex] - Velocity of the project prior to the collision, measured in meters per second.
[tex]v_{o,B}[/tex] - Velocity of the ballistic pendulum prior to the collision, measured in meters per second.
If we know that [tex]v_{2} = 0\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y_{2}-y_{1} = 0.12\,m[/tex], [tex]m = 0.025\,kg[/tex], [tex]M = 2.5\,kg[/tex] and [tex]v_{o,B} = 0\,\frac{m}{s}[/tex], then the velocity just prior to the collision is:
By (Eq. 1):
[tex]v_{1} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.12\,m)}[/tex]
[tex]v_{1} \approx 1.534\,\frac{m}{s}[/tex]
By (Eq. 2):
[tex]v_{o,P} = \frac{(0.025\,kg+2.5\,kg)\cdot \left(1.534\,\frac{m}{s} \right)-(2.5\,kg)\cdot \left(0\,\frac{m}{s} \right)}{0.025\,kg}[/tex]
[tex]v_{o,P} = 154.934\,\frac{m}{s}[/tex]
The velocity of the projectile just prior to the collision is 154.934 meters per second.
the whale shark is the largest of all fish and can have the mass of 3 adult elephants. suppose that a crane is lifting a whale shark into a tank for delivery to an aquarium. The crane must exert a force of 25000 N to lift the shark from rest. if the sharks acceleration equals 1.25m/s^2, what is the sharks mass ?
Answer: The whale shark is the largest type of fish in the world. Its mass can be as large as 2.00 x 10^4kg, which is the equivalent mass of three average adult elephants. Suppose a crane lifts a net with a 2.00 x 10^4kg whale shark off the ground. The net is steadily accelerated from rest over an interval of 2.5s until the net reaches a speed of 1.0 m/s.
Explanation:
At room temperature, most metals are
Select one:
a. gas
O b. liquid
O c. an alloy
O d. solid
A biker pushes on the pedal and accelerates her 50 kg bike from 0 m/s to 10 m/s. What is the the impulse?
Answer:
3.7
Explanation:
An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. The maximum speed of the object is 1.54 m/s, and its maximum acceleration is 8.13 m/s2. How much time elapses betwen an instant when the object's speed is at a maximum and the next instant when its acceleration is at a maximum
Answer:
Explanation:
The spring will move under SHM .
Maximum speed is at the middle equilibrium position . Maximum acceleration is when the particle is at one of the extreme position . So time gap between the two position is one fourth of time period of oscillation .
= T / 4
If A be the amplitude and ω be angular velocity
ω A = maximum velocity = 1.54
ω² A = maximum acceleration = 8.13
dividing
ω = 5.28
2π / T = 5.28
T = 1.189
T / 4 = 0.3 s.
A 5.00 gg bullet is fired horizontally into a 1.20 kgkg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 mm along the surface before stopping.
Answer:
V= 295.2m/s
Explanation:
Given that mass of bullet = 5.0g = 0.005kg
Mass of wooden block = 1.20kg
The coefficient of kinetic friction between block and surface = 0.20
The force of friction of the block
Fk = (μ) mg
Fk = 0.2×1.2×9.8m/s
F = 2.352N
= Force × distance
The work done = 2.352× 0.390
= 0.91728J
The initial velocity of the block can be calculated
1/2mv^2
0.5×1.2×v^2 = 0.917J
0.6V^2 = 0.917J
V^2 = 0.917J/0.6
V^2 = 1.52
V = √1.52
V = 1.23m/s
Now we shall use conservation of momentum to find the velocity of the bullet
0.005kg×v = 1.2kg × 1.23m/s
0.005v = 1.476
V= 1.476/0.005
V= 295.2m/s
I WILL MARK YOU AS BRAINLIEST IF RIGHT
What is the magnitude of the net force acting on this object? And what direction?
Answer:
20N to the North
Explanation:
the west and east forces cancel out, that leaves us with 50 to the north, and 30 to the south, the difference would be 20 N to the North
PLEASE HELPP WITH QUESTIONS :(
Answer:no
Explanation: lol
Two ropes are tied to a 50 kg boat. One pulls with a force of 120 N due West and the other rope pulls with a force of 140 N due South. Find the net force of the boat (magnitude and direction) and the acceleration.
The net force on the boat is the vector
F = (-120 N) i + (-140 N) j
where we take West and South to be the negative directions going left-and-right and up-and-down, respectively.
The magnitude of the net force is
F = √((-120 N)² + (-140 N)²) = 20 √(85) N ≈ 180 N
and its direction is
tan(θ) = (-140 N) / (-120 N) → θ ≈ -130°
relative to due East, or approximately 50° South of West.
It takes an airplane nearly 3/4 of a mile to stop. Which law is being used?
A) Newton's first law
B) Newton's second law
C) Newton's third law
D) Law of conservation of momentum
E) Law of universal gravitation
Answer:
I think it is D
Explanation:
might be wrong
If George Washington had become "King of America," our government might have become?
Answer:
Monachry
Explanation:
Hope this helped!!!
what is the answer to life and everything in the universe?
If the first stage provides a thrust of 5.25 mega-newtons [MN] and the space shuttle has a mass of 4,470,000 pound-mass [lbm], what is the acceleration of the spacecraft in miles per hour squared [mi/h2]
Answer:
20,861.65 mi/h²
Explanation:
We convert 4,470,000 pound-mass [lbm], to kg. Since 2.205 lbm = 1 kg, then 4,470,000 lbm = 4,470,000 lbm × 1 kg/2.205 = 2,027,210.88 kg
Since Force , F = ma where m = mass and a = acceleration, and our force of thrust , F = 5.25 MN = 5,250,000 N and or mass = mass of spacecraft = 2,027,210.88 kg, we then find the acceleration, a.
a = F/m = 5,250,000 N/2,027,210.88 kg = 2.59 m/s².
We now convert this acceleration into miles per hour. Since 1 mile = 1609 meters and 60 × 60 s = 1 hour ⇒ 3600 s = 1 hour, Our conversion factor for meter to mile is 1 mile/1609 m and that for second to hour is 3600 s/1 hour. We square the conversion factor for the time so we have (3600 s/1 hour)².
Multiplying both conversion factors with our acceleration, we have
a = 2.59 m/s²
= 2.59 m/s² × 1 mile/1609 m × (3600 s/1 hour)²
= 33566440/1609 miles/hour²
= 20,861.65 mi/h²
= 20,861.65 miles per hour squared
9. A 0.25-kg mass is attached to a string and swung in a vertical circle whose radius is 0.75 m. At the bottom of the circle, the mass is observed to have a speed of 10 m/s. What is the magnitude of the tension in the string at that point
Answer:
T = 33.34 N
Explanation:
Given that,
Mass attached to the spring, m = 0.25 kg
Radius of the vertical circle, r = 0.75 m
Speed of the mass, v = 10 m/s
We need to find the magnitude of the tension in the string at that point. We know that the tension in the string is equal to the centripetal force acting on it. It can be given by
[tex]T=\dfrac{mv^2}{r}\\\\T=\dfrac{0.25\times (10)^2}{0.75}\\\\T=33.34\ N[/tex]
So, the tension in the string is 33.34 N.
How do mass and the type of material affect thermal energy transfer?
Answer:
Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. ... Heat is the transfer of thermal energy between objects that have different temperatures.
I need help with this science work.
Answer:
1. Radiation
2. Conduction
3. Conduction
4. Convection
5. Convection
6. Convection
7. Radiation
How can humans detect infrared waves?
А
They see them as color.
B
They feel them as heat.
с
They hear them as sound.
D
They feel them as vibrations.
A student is standing on top of the school building and has a height of 44.1m. They kick a rock off the edge of the building with velocity of 6 m/s . how far away from the base of the building does the rock land?
how much tension (fm) must be supplied at the triceps to stabalize the arm against an external force (fe) of 200 N given dm
The missing part of the question is :
given dm-2 cm and de 25 cm
Answer:
The correct answer is = 2500 N
Explanation:
Given:
External force (fe) = 200 N
dm- 2 cm = 0.02 m
de = 25 cm = 0.25 m
Balancing torque about elbow
Fm*dm = Fe*de
By putting value
fm*0.02 = 200*0.25
fm= 200*0.25/0.02
fm = 50/0.02
fm = 2500 N
Thus, the correct answer is = 2500 N
Science Motion Problem pelase elp
Answer:120
Vav = S / t = (120 + 45) m / (4 + 60) sec = 2.6 m/s
Calculate the rms speed of helium atoms near the surface of the Sun at a temperature of about 5200 K.
Answer: Root mean square speed, Vrms=5,694m/s
Explanation:
Root mean square speed is defined as the the square root of the average of the square of the velocity and given as [tex]\sqrt 3RT/M[/tex]
Where R =8.3145J/mol.k
M molar mass of the molecule in kg/mol
Helium= He=4g/mol = 0.004kg/mol
T= Temperature = 5200k
Vrms= [tex]\sqrt 3RT/M[/tex]
=[tex]\sqrt 3 x 8.3145 x 5200/0.004[/tex]
=[tex]\sqrt32426550[/tex]
Vrms =5,694m/s
A conveyor belt dumps 2500 yd3 of gravel to form a cone-shaped pile. How high could this pile of gravel be, and what could the circumference of the pile of gravel be at ground level
Answer:
Explanation:
Volume of the cone = 1/3πr²h
r is the radius
h is the height
2500 = 1/3πr²h
Criss multiply
r²h = 2500 × 3π
Rewrite the expression
r²h = 50² × 3π
Compare values
r² = 50²
r = √50²
r = 50yd
The radius is 50yards
Also;
h = 3π yards
h = 3(3.14)
h = 9.42yards
Hence the pile is 9.42yards high
Circumference of the pile = 2πr
Given r = 50
Substitute
Circumference = 2π(50)
Circumference = 100π
Circumference = 100(3.14)
Circumference = 314yards
Hence the circumference of the pile at the ground level is 314yards
A man accelerates at 2.52 m/s2 for 3.73s. If his initial velocity was 1.75 m/s, what is his final velocity?
Answer:
Final Velocity = 11.15 m/s
Explanation:
By using the equation v = u + at we can find the answer.
v = final velocity
u = initial velocity
a = acceleration
t = time
Plug the numbers in and you get 11.15 m/s, hope this helps!
In theory, if the airspeed of an airplane is doubled while in level flight, parasite drag will become
Answer:
Four times greater
Explanation:
Drag is comprised of parasite drag and induced drag. The Parasite drag is the drag that acts on an object when the said object happens to be moving through a fluid. Parasite drag is also a combination of two forms of drag. These two forms of drag are called form drag and skin friction drag.
As the speed of an airplane increases, the parasite drag also increases while the induced drag of the airplane decreases. The parasite drag of an airplane in theory becomes four times greater, when it's airspeed is doubled.
find the current of 20 c of charge pass a piticular point in a circuit in 10 seconds
Neil travelled 36km at a speed of 8km/h Grant travelled 48km at a speed of 10km/h whose journey was quickest
Answer:
[tex]\boxed {\tt Neil's \ journey}[/tex]
Explanation:
We want to find who travelled faster, so we must find the time for each person's journey. Time can be found by dividing distance by speed.
Neil
[tex]t=\frac{d}{s}[/tex]
Neil travelled 36 kilometers at a speed of 8 kilometers per hour.
[tex]d= 36 \ km \\s= 8 \ km/hr[/tex]
[tex]d=\frac{36 \ km}{8 \ km/hr}[/tex]
Divide (the kilometers or "km" will cancel each other out).
[tex]d=4.5 \ hr[/tex]
Grant
[tex]t=\frac{d}{s}[/tex]
Grant travelled 48 kilometers at a speed of 10 kilometers per hour.
[tex]d= 48 \ km \\s= 10 \ km/hr[/tex]
[tex]d=\frac{48 \ km} { 10 \ km/hr}[/tex]
Divide (the kilometers or "km" will cancel each other out).
[tex]d=4.8 \ hr[/tex]
Neil's journey took 4.5 hours and Grant's took 4.8 hours. We want to find the journey that was quicker and 4.5 is less than 4.8. So Neil's journey was quicker.
hello what is momentum?
Answer:
Momentum is vector quantity and it is defined as the product of mass of the object and velocity of the object.
As it is a vector quantity it has both direction and magnitude, and momentum is written as
p = m × v
p = momentum
m = mass of the object
v = velocity
Two kinds of momentum are there and they are:
Linear MomentumAngular Momentum