A sample of gas occupies 12 L under a pressure of 1.2 atm. What
would its volume be if the pressure were increased to 3.6 atm?
(assume temp is constant)

Answers

Answer 1

Explanation:

here's the answer to your question

A Sample Of Gas Occupies 12 L Under A Pressure Of 1.2 Atm. Whatwould Its Volume Be If The Pressure Were

Related Questions

Which type of organic compound is shown below?
A. Carboxylic acid
B. Ester
C. Amine
D. Alcohol ​

Answers

Answer:

I think its A maybe am not sure

A chemist collects hydrogen gas over water in an apparatus shown below. If the eudiometer reads 17.3800 mL of gas and has a total pressure of
95.090 mm Hg at 15.0°C, then how many moles of hydrogen gas were collected? (the vapor pressure of water at 15.0°C is 12.8 mm Hg)

Answers

Answer:

7.93 × 10⁻⁵ mol

Explanation:

Step 1: Calculate the pressure of hydrogen

The total pressure is the sum of the partial pressures of hydrogen and water vapor.

P = pH₂ + pH₂O

pH₂ = P - pH₂O

pH₂ = 95.090 mmHg - 12.8 mmHg = 82.3 mmHg

We can convert it to atm using the conversion factor 1 atm = 760 mmHg.

82.3 mmHg × 1 atm/760 mmHg = 0.108 atm

Step 2: Convert 15.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 15.0 + 273.15 = 288.2 K

Step 3: Calculate the moles of hydrogen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 0.108 atm × 0.0173800 L / (0.0821 atm.L/mol.K) × 288.2 K

n = 7.93 × 10⁻⁵ mol

WHAT WOULD THE RIGHT OPTION??

how many resonance structures of benzene are known?
A) 3
B) 4
C) 5
D) 6 ​

Answers

Answer:

C) 5

Step-by-step explaination:

Benzene has 5 resonance structures.

How many oxygen atoms are there in 0.25 mole of CO2?

Answers

Answer:

It is known that 1 mol of a molecule contains 6.023×1023 6.023 × 10 23 number of molecules. So, 0.25 moles of CO2 C O 2.

The correct option for the given question about Mole Concept is Na / 2 atom of oxygen.

What is mole?In chemistry, a mole is a unit. A mole of a substance is the mass of the substance containing precisely 12 gram of the same number of atoms as 12C.The mole is the SI unit used to measure a substance's quantity. It has the symbol mol.

How to solve this question?

In 1 mole number of molecules of CO₂ = Na (Avagadro Number)

In 0.25 mole number of molecules of CO₂ = 0.25 × Na molecules

In 1 molecule number of oxygen atom = 2 atom

In 0.25 × Na molecules number of oxygen atom = 2 × 0.25 × Na atom

In 0.25 × Na molecules number of oxygen atom = 0.5 × Na atom

So in 0.25 mole of CO₂ number of oxygen atom = Na / 2 atom

Thus we can conclude that in 0.25 mole of CO₂ number of oxygen atom will be Na / 2, where Na is Avagadro Number.

Learn more about Mole Concept here:

https://brainly.com/question/16488605

#SPJ2

What is the volume of 6 moles of hydrogen gas, H2 (g)

Answers

Answer:

Molar volume, or volume of one mole of gas , depends on pressure and temperature, and is 22.4 liters - at 0 °C (273.15 K) and 1 atm (101325 Pa), or STP (Standard Temperature and Pressure), for every gas which behaves similarly to an ideal gas. The ideal gas molar volume increases to 24.0 liters as the temperature increases to 20 °C (at 1 atm).

When should a line graph be used

Answers

Answer:

Line graphs are used to track changes over short and long periods of time. When smaller changes exist, line graphs are better to use than bar graphs. Line graphs can also be used to compare changes over the same period of time for more than one group.

When water reaches the metastable state, the phase of water will be?​

Answers

Answer:

water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.

Explanation:

Select True or False: The equilibrium constant for the chemical equation 2NO(g) O2(g) 2NO2(g) is two times the equilibrium constant for the chemical equation NO(g) 1/2O2(g) NO2(g).

Answers

Answer:

False

Explanation:

The first reaction is;

NO(g) + 1/2O2(g) ---->NO2(g)

K= [NO2]/[NO] [ O2]^1/2

The second reaction is;

2NO(g) + O2(g) ---->2NO2(g)

K'= [NO2]^2/[NO]^2 [O2]

It now follows that;

K'= K^2

Hence the statement in the question is false

What is the formula for manganese (IV) oxide?
A. MnO4
B. Mn40
C. MNO2
D. Mn20

Answers

The formula of manganese (IV) oxide is MNO2

The formula for manganese (IV) oxide is [tex]MnO_4[/tex]. Therefore, the correct option is A.

A manganese atom is bonded to four oxygen atoms to produce an inorganic compound known as manganese(IV) oxide with the chemical formula [tex]MnO_4[/tex]. It is often referred to as manganese dioxide. The +4 oxidation state of a manganese compound is indicated by the Roman numeral "IV" in the name.

Pyrolusite, a naturally occurring mineral, is a dark brown or black solid consisting of manganese(IV) oxide. Due to its favorable properties, it is often employed in a wide variety of applications. It acts as a catalyst, especially when breaking down hydrogen peroxide. Additionally, it is used to make batteries, ceramics, glass and pigments.

Therefore, the correct option is A.

Learn more about chemical formula, here:

https://brainly.com/question/32018188

#SPJ6

How many chromosomes do we not understand?

Answers

Answer:

we don't understand why humans have only 46 chromosomes

Answer:

46 chromosomes is what we don't understand

What functional group is found in an alcohol?
A. Ester
B. Amino
C. Carbonyl
D. Hydroxyl ​

Answers

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

The functional group found in an alcohol is Hydroxyl . Therefore, the correct option is option D.

What is functional group?

A functional group in organic chemistry is a substituent and moiety inside a molecule that triggers the molecule's distinctive chemical processes. No matter how the rest of a molecule is made up, the very same functional group would experience the same or a similar set of chemical events.

This permits the design of synthetic chemistry as well as the methodical forecasting of chemical reactions as well as the behaviour of chemical molecules. Other functional groups close by can affect a functional group's reactivity. Retrosynthetic analysis can be used to design organic synthesis by using functional group interconversion. The functional group found in an alcohol is Hydroxyl .

Therefore, the correct option is option D.

To know more about functional group, here:

https://brainly.com/question/29263610

#SPJ7

how is the molecule of substance formed​

Answers

Answer:

When atoms approach one another closely, the electron clouds interact with each other and with the nuclei. If this interaction is such that the total energy of the system is lowered, then the atoms bond together to form a molecule.

Explanation:

For each reaction, write the chemical formulae of the oxidized reactants.

a. ZnCl2 (aq) + 2Na(s) → Zn(s) + 2NaCl(aq)
b. Al(s) + FeBrz (aq) → AlBrz (aq) + Fe(s)
c. FeSO4 (aq) + Zn (s) → Fe(s) + ZnSO4(aq)

Answers

Answer:

a. Na(s); b. Al(s); c. Zn(s)

Explanation:

Let's consider the following redox reactions.

a. ZnCl₂ (aq) + 2 Na(s) → Zn(s) + 2 NaCl(aq)

Na is oxidized because its oxidation number increases from 0 to +1 (in NaCl) whereas Zn is reduced because its oxidation number decreases from 2+ (in ZnCl₂) to 0.

b. Al(s) + FeBr₃ (aq) → AlBr₃ (aq) + Fe(s)

Al is oxidized because its oxidation number increases from 0 to +3 (in AlBr₃) whereas Fe is reduced because its oxidation number decreases from 3+ (in FeBr₃) to 0.

c. FeSO₄ (aq) + Zn(s) → Fe(s) + ZnSO₄(aq)

Zn is oxidized because its oxidation number increases from 0 to +2 (in ZnSO₄) whereas Fe is reduced because its oxidation number decreases from 2+ (in FeSO₄) to 0.

The windscreen of a window is made up of

Answers

Answer:

Modern windshields are generally made of laminated safety glass, a type of treated glass, which consists of, typically, two curved sheets of glass with a plastic layer laminated between them for safety, and bonded into the window frame.

Explanation:

mark me brain liest if my answer is correct

A nuclease enzyme breaks the covalent bond originally connecting the phosphate to the 5' carbon in a nucleic acid. After allowing this enzyme to completely digest the nucleic acid down to monomers, you perform tests to determine where the phosphate is attached to each monomer. Where do you expect to find this phosphate

Answers

Answer:

The phosphate will remain attached to the 5' carbon of the deoxy or the ribose sugar in the nucleic acid monomers.

Explanation:

The structure of nucleic acid polymers is built up from monomers of nucleotides.

A nucleotide consists of a sugar backbone which is either a ribose or deoxyribose sugar, a nitogenous base which is either a purine or pyrimidine, and a phosphate group. The nitrogenous base is attached to the carbon number 1 or C-1 of the sugar backbone by a covalent bond. The phosphate group on the other hand is covalently attached to the carbon number 5 or 5' carbon of the sugar backbone.

When polymers of nucleic acids are formed, the phosphate at the 5' carbon of the sugar backbone is covalently linked in a phosphodiester bond to the 3' carbon of the sugar backbone in another nucleotide molecule, thus extending the strands of the nucleic acid molecule.

Nucleases are enzymes that break down the phosphodiseter bonds in nucleic acids resulting in nucleotide monomers. After complete digestion ofmthe nucleic acid polymer by nucleases, the phosphate will remain attached to the 5' carbon of the deoxy or the ribose sugar in the nucleic acid monomers.

During electrophilic aromatic substitution, a resonance-stabilized cation intermediate is formed. Groups, already present on the benzene ring, that direct ortho/para further stabilize this intermediate by participating in the resonance delocalization of the positive charge. Assume that the following group is present on a benzene ring at position 1 and that you are brominating the ring at positon 4. Draw the structure of the resonance contributor that shows this group actively participating in the charge delocalization.

-----OCH3

Answers

Answer:

See explanation and image attached

Explanation:

Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.

Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.

Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.

The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.

34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 11.21°C. Calculate ∆H, in kJ/mol, for the dissolution of the unknown solid. (The specific heat of the solution is 4.184 J/g・°C and the density of the solution is 1.20 g/mL).

Answers

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

Where q is heat of reaction in J,

m is the mass of the solution in g,

S is specific heat of the solution = 4.184J/g°C

ΔT is change in temperature = 11.21°C

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2 6 H2O Which is the limiting reactant

Answers

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

Moles C6H12O6:

650g * (1mol/180.16g) = 3.608 moles C6H12O6

Moles O2:

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

O2 is limiting reactant

What mass of oxygen is needed for the complete combustion of 1.60-10^-3
g
of methane?
Express your answer with the appropriate units.

Answers

Answer:

6.4×10¯³ g of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

Next, we shall determine the masses of CH₄ and O₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of CH₄ = 12 + (4×1)

= 12 + 4

= 16 g/mol

Mass of CH₄ from the balanced equation = 1 × 16 = 16 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

SUMMARY:

From the balanced equation above,

16 g of CH₄ reacted with 64 g of O₂.

Finally, we shall determine the mass of O₂ needed to react with 1.6×10¯³ g of CH₄. This can be obtained as illustrated below:

From the balanced equation above,

16 g of CH₄ reacted with 64 g of O₂.

Therefore, 1.6×10¯³ g of CH₄ will react with = (1.6×10¯³ × 64) / 16 = 6.4×10¯³ g of O₂

Thus, 6.4×10¯³ g of O₂ is needed for the reaction.

According to the ideal gas law, a 9.998 mol sample of argon gas in a 0.8311 L container at 502.7 K should exert a pressure of 496.2
atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Ar
gas, a = 1.345 L’atm/mol? and b = 3.219x10-2 L/mol.
Pideal – Puan der Waals |
Percent difference
x 100

Answers

Answer:

[tex]\%diff=24.0\%[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set up the van der Waals' equation as shown below:

[tex]p=\frac{RT}{v-b}-\frac{a}{v^2}[/tex]

Thus, we secondly calculate the molar volume as:

[tex]v=\frac{0.8311L}{9.998mol} =0.083L/mol[/tex]

Then, we plug in the entire variables in the vdW equation to get such pressure:

[tex]p=\frac{0.08206\frac{atm*L}{mol*K}*502.7K}{0.08313L/mol-0.03219L/mol}-\frac{1.345L*atm/mol}{(0.08313L/mol)^2}\\\\p=615.2atm[/tex]

And the ideal gas pressure:

[tex]p=\frac{0.08206\frac{atm*L}{mol*K}*502.7K}{0.08313L/mol}\\\\p=496.2atm[/tex]

Finally, the percent difference:

[tex]\%diff=\frac{|496.2atm-615.2atm|}{496.2atm} *100\%\\\\\%diff=24.0\%[/tex]

Regards!

Which of these is an organic compound?

CaO

H2SO4

C3H8

H2O2​

Answers

Answer:

which class are you please mention

Many important analgesic compounds are derived from simple aromatic starting materials.

a. True
b. False

Answers

The shot answer for this question is (a) True
the answer is a (true)

If we slowly add a solution of mercury(II) ions to a solution of aqueous halide ions with roughly equal concentrations, a precipitate will form. Explain what the precipitate will consist of initially. g

Answers

Acid rain and it’ll be infection

Water, mercury chloride and nitrogen oxide.

Water, mercury chloride and nitrogen oxide will present in the precipitate when we slowly add a solution of mercury(II) nitrate to a solution of aqueous hydrochloric acid having halide ions both in equal concentrations. The equation of this reaction is Hg2(NO3)2 + 4 HCl ----> 2 HgCl2 + 2 H2O + 2 NO so it is concluded that from this reaction we get precipitate of water, mercury chloride and nitrogen oxide.

https://brainly.com/question/24261598.

GIVING BRAINLIEST
Which equations are used to calculate the velocity of a wave?
O velocity = distance ~ time
velocity = wavelength x frequency
velocity = distance/time
velocity = wavelength/frequency
velocity = distance/time
velocity = wavelength x frequency
velocity = distance ~ time
velocity = wavelength/frequency

Answers

Answer:

velocity = distance/time

velocity = wavelength × frequency

Both of these are commonly known equations to calculate velocity with different variables.

What is normality in chemistry?​

Answers

Answer:

a measure of concentration equal to the gram equivalent weight per liter of solution.

Explanation:

Gram equivalent weight is the measure of the reactive capacity of a molecule. The solute's role in the reaction determines the solution's normality. Normality is also known as the equivalent concentration of a solution.

hope it helped

Classify these bonds as ionic, polar covalent, or nonpolar covalent. You are currently in a sorting module.
Ionic Polar Covalent Nonpolar covalent
C-O , Mg-F , Cl-Cl

Answers

Answer:

C-O: polar covalent

Mg-F: ionic

Cl-Cl: nonpolar covalent

Explanation:

Ionic bonds are formed between an atom of a metallic element and another atom of a non-metallic element. Thus, Mg-F is an ionic bond, in which Mg is the metal and F is the nonmetal.

Covalent bonds are formed between two non-metallic elements. So, C-O and Cl-Cl are covalent bonds, because C, O, and Cl are nonmetals.

In C-O, the atom of oxygen (O) has more electronegativity than the atom of carbon (C). Thus, O will attract the electrons with more strength and a difference in charge will be established between the two bonded atoms. So, this covalent bond is polar.

In Cl-Cl, both atoms have the same electronegativity because they are from the same chemical element (Cl). Thus, this bond is nonpolar.

A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pressure of 0.677 atm. The final volume is 63.2 L. What was the initial volume of the system if the internal energy of the system decreased by 108.3 J?
a. 65.6 L
b. 64.0 L
c. 70.8 L
d. 60.8 L
e. 54.4L

Answers

Answer:

d. 60.8 L

Explanation:

Step 1: Given data

Heat absorbed (Q): 53.1 JExternal pressure (P): 0.677 atmFinal volume (V2): 63.2 LChange in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J ×  1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

V1 = V2 - ΔV

V1 = 63.2 L - 2.35 L = 60.8 L

convert 36.52 mg to ?___ g

Answers

Answer:

0.0365 is your answer

Explanation:

hope it will help u

Answer:

365.2gㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Predict whether reactants or products will be favored at equilibrium for the below reaction.

Kp= 2.2 x 10^6 at 298K
2COF2 (g) + ⇌ CO2(g) + CF4(g)

Answers

Answer:

The products will be favored at equilibrium.

Explanation:

The balanced chemical equation for the reaction is the following:

2 COF₂ (g) + ⇌ CO₂(g) + CF₄(g)

The reactant is COF₂ (left side) and the products are CO₂ and CF₄ (right side).

The equilibrium constant is given by the ratio between the partial pressures (P) of products and reactants, because they are in the gas phase. Thus, the expression of the equilibrium constant is the following:

[tex]Kp = \frac{P(CO_{2}) P(CF_{4}) }{P(COF_{2} )^{2} } = 2.2 x 10^{6}[/tex]

Since Kp>>>>1 ⇒ (P(CO₂) x P(CF₄)) > (P(COF₂))²

So, the partial pressures of the products (CO₂ and CF₄) are higher than the partial pressure of the reactant (COF₂).

Therefore, products will be favored at equilibrium at 298 K.

A metal (C = 0.2158 cal/g· °C) is removed from a hot (350. °F) oven in which it had achieved thermal equilibrium. The metal is placed into 200. mL acetic acid. The temperature of the acid increases to 90.3 °C from 24.3 °C. What is the mass of the metal? (dacetic acid = 1.04 g/cm3; Cs, acetic acid = 2.055 J/g·°C) Group of answer choices 120. g 362 g 1452 g 347 g 281 g

Answers

Answer:

362g

Explanation:

heat lost by metal= heat gained by acetic acid

tfs are the same so you cando delta T

convert Cal/gc to J/gc

thectgod ig follow

Other Questions
M. magneticum can only survive in low-oxygen environments, which are typically found near the bottom of bodies of water. a. Trueb. False Indicate whether each statement is true or false: 1. Compliance is the tendency for blood vessel volume to increase as blood pressure decreases. True 2. Blood vessels with a large compliance exhibit a small increase in volume when the pressure increases a small amount. True 3. Venous compliance is approximately 24X greater than arterial compliance, so as venous pressure increases the volume of veins greatly increases. True What is the output of the function: f(x)=2x+5, if the input is 3? Which statements are true in regard to the VSEPR theory?Select all that apply.Molecules acquire a shape that results in the greatest charge.Molecules acquire a shape that minimizes the repulsions of electron groups.Molecules acquire a shape that maximizes the distance of electron groups.Molecules acquire a shape that results in the lowest possible energy state. What stage in the process of media production involves discussing the budget and timelines as well as identifying stakeholders? create/develop upload/display research/define plan/design HELP ASAPThe graph of f(x)= |x| is chosen below. Write the equation for the stretched graph, g(x). Traits can also be , which means they can be masked Read the passage from Animal Farm.Meanwhile life was hard. The winter was as cold as the last one had been, and food was even shorter. Once again all rations were reduced, except those of the pigs and the dogs. A too rigid equality in rations, Squealer explained, would have been contrary to the principles of Animalism. In any case he had no difficulty in proving to the other animals that they were NOT in reality short of food, whatever the appearances might be. For the time being, certainly, it had been found necessary to make a readjustment of rations (Squealer always spoke of it as a "readjustment," never as a "reduction"), but in comparison with the days of Jones, the improvement was enormous. Reading out the figures in a shrill, rapid voice, he proved to them in detail that they had more oats, more hay, more turnips than they had had in Jones's day, that they worked shorter hours, that their drinking water was of better quality, that they lived longer, that a larger proportion of their young ones survived infancy, and that they had more straw in their stalls and suffered less from fleas. The animals believed every word of it. Truth to tell, Jones and all he stood for had almost faded out of their memories. They knew that life nowadays was harsh and bare, that they were often hungry and often cold, and that they were usually working when they were not asleep. But doubtless it had been worse in the old days. They were glad to believe so. Besides, in those days they had been slaves and now they were free, and that made all the difference, as Squealer did not fail to point out.How does this passage demonstrate the use of propaganda? Select two options.It demonstrates repetition because Squealer reminds the animals that they are free at the farm because of the work they are doing.It demonstrates hyperbole because Squealer exaggerates the figures related to positive developments of the farm.It demonstrates bandwagon because Squealer convinces the animals that life is better now than it was before, and everyone agrees because the report says so.It demonstrates plain folks because Squealer explains why the pigs and dogs deserve better food rations than the other animals.It demonstrates glittering generalities because Squealer does not explain the claim that equality in rations would be contrary to the farms ideals. Find the area of the plot of land shown below. Water droplets are pulled towards earth by ______________. Where was the Mughal Empire located Please write 5 sentences Solve the quadratic equation by completing the square. Book information (overriding member functions) Given main() and a base Book class, define a derived class called Encyclopedia. Within the derived Encyclopedia class, define a PrintInfo() function that overrides the Book class' PrintInfo() function by printing not only the title, author, publisher, and publication date, but also the edition and number of volumes. Ex. If the input is: The Hobbit J. R. R. Tolkien George Allen & Unwin 21 September 1937 The Illustrated Encyclopedia of the Universe James W. Guthrie Watson-Guptill 2001 2nd 1 the output is: Book Information: Book Title: The Hobbit Author: J. R. R. Tolkien Publisher: George Allen & Unwin Publication Date: 21 September 1937 Book Information: Book Title: The Illustrated Encyclopedia of the Universe the output is: Book Information: Book Title: The Hobbit Author: J. R. R. Tolkien Publisher: George Allen & Unwin Publication Date: 21 September 1937 Book Information: Book Title: The Illustrated Encyclopedia of the Universe Author: James W. Guthrie Publisher: Watson-Guptill Publication Date: 2001 Edition: 2nd Number of Volumes: 1 Note: Indentations use 3 spaces. LAB ACTIVITY 11.14.1: LAB: Book information (overriding member functions) File is marked as read only Current file: main.cpp cin >> numVolumes; main.cpp Book.h 25 26 27 28 29 30 31 32 33 34 35 36 myBook. SetTitle(title); myBook. SetAuthor(author); myBook. SetPublisher(publisher); myBook.SetPublicationDate(publicationDate); myBook.PrintInfo(); Book.cpp Encyclopedia.h myEncyclopedia. SetTitle(eTitle); myEncyclopedia. SetAuthor(eAuthor); myEncyclopedia. SetPublisher(ePublisher); myEncyclopedia. SetPublicationDate(ePublicationDate); Encyclopedia.cpp The ultimate goal of contract damages is: Multiple Choice Put the nonbreaching party where it was before the contract was formed. Return any costs incurred by the nonbreaching party. Put the nonbreaching party where it was prior to breach. Put the nonbreaching party in the best position possible. Give the nonbreaching party the benefit of its bargain. What If smart phones / computers didn't exist? which expression is equivalent to c^2 - 4 / c + 3 / I do school w o r k, if you need any work done, just comment, I also do FLVS classes What are finite verbs explanation Which correlation best describes the data below. no correlation weak positive weak negative strong positive