The magnitude of the electric field at the location, where a positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field is 0.25×10⁶ N/C.
What is electric field?The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.
It can be given as,
[tex]E=Fq[/tex]
Here, F is the electric force and q is the charge.
A positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field. Put the values in the fomula,
[tex]E=\dfrac{F}{q}\\E=\dfrac{0.75}{3\times10^{-6}}\\[/tex]
[tex]E=0.25\times10^{6}\rm\; N/C[/tex]
Thus, the magnitude of the electric field at the location, where a positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field is 0.25×10⁶ N/C.
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Who developed a way to measure speed
2) Which of the following images correctly depicts the direction of the
Earth's velocity if Sun was suddenly eliminated?
What is the total kinetic energy of a 5-kg hoop with a radius of 0. 5 m when it rolls without slipping at 4. 0 m/s?
The total kinetic energy of a 5-kg hoop with a radius of 0. 5 m when it rolls without slipping at 4. 0 m/s is 80 Joules.
What is kinetic energy?The kinetic energy is the ability to do work by virtue of its motion.
The mass of the hoop is 5 kg, the radius of the hoop is 0.5 m and the speed with which it is rolling is 4.0 m/s.
The angular speed of the hoop is
ω = v / r
ω = 4 / 0.5 = 8 rad/s
The moment of inertia of the hoop is I = m r² / 2
The kinetic energy of the rolling object is the addition of translation and rotational kinetic energy.
K.E = 1 / 2(mv²) + = 1 / 2(Iω²)
Substituting the values into the above equation and solving, we get the total kinetic energy.
K.E = 40 + 40 = 80 Joules
Thus, the total kinetic energy is a rolling hoop is 80 Joules.
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Suppose we observe a cepheid variable in a distant galaxy. The cepheid brightens and dims with a regular period of about 10 days. What can we learn from this observation?.
Answer:
something is passing infront of it
Explanation:
something is orbiting it and blocking its light
A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?
A.
0.034 newtons/amp·meter
B.
0.17 newtons/amp·meter
C.
0.26 newtons/amp·meter
D.
0.77 newtons/amp·meter
E.
6.0 newtons/amp·meter
Answer:
the answer is letter D.
Explanation:
i hope this is help
Answer:
great answer warstep8! add me on disc colludy#8415
Explanation:
Write the chemical symbols for three different atoms or atomic anions with 9 electrons
The chemical symbols for three different atoms or atomic anions with 9 electrons are Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²).
What is atom?An atom is the smallest unit of matter, consisting of the positively charged nucleus and the electrons which move around it. The atom can not be divided further.
The atom of a matter is made by three elements-
1) Neutron-Neutron is the element of an atom, which has zero charge.2) Proton-Proton is the element of an atom, which has a positive charge.3) Electron-Electron is the element of an atom, which has a negative charge.The chemical symbols for three different atoms or atomic anions with 9 electrons has to be write down. Anion is the element which has more number of electron compare to its protons.
This makes the element negatively charged. Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²) are the element which have atomic anions with 9 electrons.
Thus, the chemical symbols for three different atoms or atomic anions with 9 electrons are Neon (Ne), Florine (F⁻¹) and Oxide (O⁻²).
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A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate at which electrical energy is dissipated in the resistor is 316 w
The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
What is impedance Z of the circuit?The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.
[tex]Z=\dfrac{V}{I}[/tex]
Here, V is voltage amplitude and I maximum current.
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.
The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,
[tex]316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A[/tex]
The impedance Z of the circuit is,
[tex]Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm[/tex]
Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
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Which is a characteristic of atoms?
1 They come in ten major types.
2 They are the smallest units of matter.
3 They can be found in nonliving things only.
4 They cannot combine together.
Answer: 2
Explanation: bro this is literally basic knowledge
Temperature measures the average kinetic energy per molecule. true or false
Answer:
true
Explanation:
An electromagnetic wave has a frequency of 8.2 x 10¹⁴ Hz. What is the wavelength of the wave?
Explanation:
Given parameters:-
Frequency of EMW is - 8.2 x 10¹⁴ HzTo find:-
Wavelength([tex]\lambda[/tex])?Solution:-
Here , we are provided frequency of electromagnetic wave and we have to find the wavelength of the wave. To find the wavelength we have to divide the speed of light by given frequency. therefore,
[tex]\tt\red{wavelength( \lambda)= \frac{speed(c)}{frequency(f)}}[/tex]
[tex] \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} }{8.2 \times {10}^{14} } \\ \\ \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} \times {10}^{ - 14} }{8.2} \\ \\ \rightarrow \sf \: \lambda = 0.36 \times {10}^{6} \\ \\ \rightarrow \sf \: \lambda = 36 \times {10}^{4}m[/tex]
The volume of empty space between gas particles is.
Answer:
either atoms or molecules
An 80-g arrow is fired from a bow whose string exerts an average force of 95 N on the arrow aver a distance of 80 cm.
What was the work done on the arrow?
The ISS can, at times, be seen from Earth.
True or false
Answer:
True but mostly false.
Explanation:
If you squint enough at night, you'd be able to see it. Otherwise it's not really possible.
Recall that Hubble's law is written v = H0d, where v is the recession velocity of a galaxy located a distance d away from us, and H0 is Hubble's constant. Suppose H0 = 20 km/s/Mly. How fast would a galaxy 1000 Mly distant be receding from us?
Hubbles' law is applicated on galaxies. The galaxy which is 1000 Mly distant from us has the speed 20000 km/s.
What is Hubble's law?Hubble's law is defined as the galaxies are moving away from Earth at speeds proportional to their distance.
Hubble's law is written as
v = H₀d
Here v is the recession velocity of a galaxy located a distance d away from us, and H₀ is Hubble's constant.
Suppose H₀ = 20 km/s/Mly.
1 parsec = 3.08 ₓ 10¹⁶ m
1 M parsec = 3.08 ₓ 10²² m
The speed v of the galaxy is
v = 20 ₓ 1000
v = 20000 km/s
Thus, the galaxy which is 1000 Mly distant from us has the speed 20000 km/s.
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The half-life of I-137 is 8.07 days. If 25 grams are left after 40.35 days, how many grams were in the original sample?
Answer:
40.35 da / 8.7 da/half-life = 5 half lives
The sample has gone thru 5 half lives
2^5 = 32 only 1/32 of the original amount is left
25 g * 32 = 800 g present in the original sample
The speed of sound doubles from 330 m/s to 660m/s going from air to a vibrating tuning fork.
Compare the frequency and wavelength of the wave in these 2 mediums.
Lets learn the relationship
[tex]\\ \rm\dashrightarrow \lambda=\dfrac{v}{\nu}[/tex]
[tex]\\ \rm\dashrightarrow \nu=\dfrac{v}{\lambda}[/tex]
[tex]\\ \rm\dashrightarrow \nu\propto \lambda\propto v[/tex]
Hence.
frequency and wavelength will be. doubled also
Scientists in the laboratory create a uniform electric field e⃗ = 6. 0×105 k^v/m in a region of space where b⃗ =0⃗
Scientist in the laboratory create uniform electric field.
PART A: The electric field in rocket frame is (0,0, 6.0 × 10 ⁵).
PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .
What is uniform electric field?The electric field whose strength is not changing with respect to time is called uniform magnetic field.
The electric field is 6.0 × 10 ⁵ k^v/m and the magnetic field is zero.
E' = E + (V×B)
= 6.0 × 10 ⁵ + (1.1 × 10⁶ × 0)
E' = 6.0 × 10 ⁵ k∧
(Ex , Ey, Ez) = (0,0, 6.0 × 10 ⁵)
The new magnetic field is represented as
B' = B - 1 /c²(v × E)
=0 - 1 / (3× 10⁸)²(1.1 × 10⁶ i∧ × 6.0 × 10 ⁵k∧ )
B' = 7.3 × 10⁻⁶ j∧
PART A: The electric field in rocket frame is (0,0, 6.0 × 10 ⁵).
PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .
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Use the energy equation from this week’s notes, your answer from
An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.
What is energy?The term energy refers to the ability to do work. An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.
This question is incomplete as the former energy equation is not shown. However, such equations can be used to know an endothermic or exothermic reaction.
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Find the mass of a child who runs at a speed of 4 m/s to get a pizza with extra cheese. His momentum is 120 kg•m/s.
Electric current can be produced in a wire by simply moving a ________________ into or out of a wire coil.
magnet
stick
battery
uranium
Electric current can be produced in a wire by simply moving a magnet into or out of a wire coil. Option A is correct.
What is the Faraday law of electromagnetic induction?According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux link with the coil is responsible for generating emf in the coil to result in the flow of amount of current .
The phenomenon of inducing voltage by changing the magnetic field around a conductor will be Electromagnetic Induction.
So in order to increase the current, we need to increase the EMF;
so we can increase it by;
1) Increasing the number of turns
2) Increase the area of the loop
3) By moving the magnet faster
Hence, option A is correct.
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Explain how the water in the puddle forms part of the water cycle?
Answer:
The water makes a cloud when the warm moist air meets the colder air. This demonstrates the formation of what we know as "clouds". Then precipitation happens when the clouds gets to full of water droplets. Finally, accumulation happens when the water forms puddles and goes back to the lakes and streams.
how long would it take for a resultant upward force of 100N to increase the speed of 50kg object from 100m/s to 150m/s
Answer:
25 sec
Explanation:
F = ma
100 = 50 a
a = 2 m/s^2
vf = vo + at
150 = 100 + 2 t
50 = 2 t
t = 25 sec
how long does it take to do 278J of work with 17 W of power
Answer:
t= 278/17 =16.35s
Explanation:
p=w/t
t=w/p
∴t=278/17
Answer:
t=16.4
Explanation:
power = energy/time
p=e/t
17=278/t
t=278/17
t=16.352941
t=16.35
t=16.4
a vector has a magnitude of 355m and a direction of 30.0 degrees. What is the x component of the vector?
Answer:
307.44 m (whatever 'm' is)
Explanation:
355 * cos (30) = 307.44
What is the force on a current-carrying wire that is in a magnetic field of 5.41*10-5 T if the current is 22.84 A and the length of the wire is 31.71 m
Answer:
3.918*10^-2N
Explanation:
force=magnetic flux*current*length
force=5.41*10^-5*22.84*31.71
force=3.918*10^-2N
A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?
A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.
What is charge?Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.
A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.
Thus, the magnetic force exerted by the charge is zero.
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Because sound waves vibrate longitudinally, what can result?
A. Disruptions of fixed waves
B. Changes in the density of air
C. Pressure differences where compressions are rarefied
D. Regions of high pressure and low pressure
Answer:
D
Explanation:
toke the test Regions of high pressure and low pressure
What is the current in a circuit with a 9.0 v battery and a resistance of 36.0 ω? 0.25 a 4.0 a 45 a 324 a
The currrent flowing the circuit with the given voltage and resistance is 0.25 Ampere.
Option A) 0.25A is the correct answer.
What is Ohm's Law?Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.
It is expressed as;
V = I × R
Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.
Given that;
Voltage in the circuit V = 9.0VResistance R = 36.0ΩCurrent I = ?We substitute our given values into the expression above.
V = I × R
9.0V = I × 36.0Ω
I = 9.0V / 36.0Ω
I = 0.25A
Therefore, the currrent flowing the circuit with the given voltage and resistance is 0.25 Ampere.
Option A) 0.25A is the correct answer.
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How is energy transformed In a washing machine
Answer:
In earlier washing machine, the electrical energy is converted in rotational kinetic energy. Now a days, in washing machine, the electrical energy is converted in kinetic energy then the mechanical energy is converted into heat energy. In modern machines, we can wash and dry the clothes.
Find the voltage drop between points A and B in the circuit. [?] V 106 A 30 Ω 40 Ω B 50 Ω 20Ω 10Ω
[tex]30 \Omega || 40\Omega ~ \text{and}~50\Omega || 30 \Omega\\\\\text{Equivalent resistance of the whole circuit,}\\ \\R_{eq} = \left(\dfrac{30 \times 40}{30+40} \right) + \left( \dfrac{50 \times 30}{50+30} \right)\\\\\\~~~~~~=\dfrac{1005}{28}~ \Omega\\\\\text{By Ohm's law,}\\\\~~~~~V=IR\\\\\implies I = \dfrac{V}{R} = \dfrac{9}{\tfrac{1005}{28}} = \dfrac{252}{1005}= \dfrac{84}{335}~ A\\\\ \text{Voltage drop between points A and B,}\\\\V_{AB} = IR_{AB}\\\\\\[/tex]
[tex]~~~~~~~=\dfrac{84}{335} \cdot \left(\dfrac{30 \times 40}{30+40} \right)\\\\\\~~~~~~~= \left( \dfrac{84}{335} \right) \left(\dfrac{120} 7 \right)\\\\\\~~~~~~~=\dfrac{288}{67}~V\\\\\\~~~~~~~=4.298~V[/tex]