A mass that has a force of the 10N to the right, 7N up, 3N down, and 4N to the left. What is the net external force on that mass? If the mass is 2kg find the acceleration.

Answers

Answer 1
Net force = square root (6^2 + 4^2) = sq root (36+16) = 7.2 N
acceleration = 7.2 / 2 = 3.6 m/s^2

Related Questions

A biker pushes on the pedal and accelerates her 50 kg bike from 0 m/s to 10 m/s. What is the the impulse?

Answers

Answer:

3.7

Explanation:

A conveyor belt dumps 2500 yd3 of gravel to form a cone-shaped pile. How high could this pile of gravel be, and what could the circumference of the pile of gravel be at ground level

Answers

Answer:

Explanation:

Volume of the cone = 1/3πr²h

r is the radius

h is the height

2500 = 1/3πr²h

Criss multiply

r²h = 2500 × 3π

Rewrite the expression

r²h = 50² × 3π

Compare values

r² = 50²

r = √50²

r = 50yd

The radius is 50yards

Also;

h = 3π yards

h = 3(3.14)

h = 9.42yards

Hence the pile is 9.42yards high

Circumference of the pile = 2πr

Given r = 50

Substitute

Circumference = 2π(50)

Circumference = 100π

Circumference = 100(3.14)

Circumference = 314yards

Hence the circumference of the pile at the ground level is 314yards

A water balloon is thrown horizontally with a
speed of 8.31 m/s from the roof of a building of
height H=23.0 m. How far does the balloon travel
horizontally before striking the ground? (Use the
vertical formula Av=v0v+1 2aw/2 to solve for time
and plug your components into the equation for
the horizontal direction Ar-vxt)
Your answer

Answers

Answer:

18m

Explanation:

Given

speed of water balloon = 8.31m/s

Height of building = 23.0m

Required

Horizontal distance

First we need to get the time using the equation of motion

S  = ut + 1/2at²

23 = 0+1/2(9.81)t²

23 = 4.905t²

t² = 23/4.905

t² = 4.689

t = √4.689

t = 2.17secs

Next is to get the horizontal direction expressed as:

Sh = Vxt

Sh =  8.31 * 2.17

Sh = 17.99m

Sh ≈ 18m

Hence the horizontal distance of the object before striking the ground is approximately 18m

What is the angle between a wire carrying an 8.00-A current and the 1.20-T field it is in if 50.0 cm of the wire experiences a magnetic force of 2.40 N? (b) What is the force on the wire if it is rotated to make an angle of 90 ∘ 90∘ with the field?

Answers

Answer:

(a) the angle between the wire and field is 30⁰

(b) the force is 4.8 N

Explanation:

Given;

current in the wire, I = 8 A

magnetic field, B = 1.2 T

length of the wire, L = 50.0 cm = 0.5 m

magnetic force, F = 2.4 N

The magnetic force on the wire is given by;

F = BILsinθ

where;

θ is the angle between the wire and field

sinθ = F / BIL

sinθ = 2.4 / (1.2 x 8 x 0.5)

sinθ = 0.5

θ = sin ⁻¹ (0.5)

θ = 30⁰

(b) the force on the wire if it is rotated to make an angle of 90⁰

F = BIL(sin90⁰)

F = BIL(1)

F = BIL

F = 1.2 x 8 x 0.5

F = 4.8 N

A speeding car is traveling at a constant 30.0 m/s when it passes a sationary police car. If the police car delays for 1.00s before starting, what must be the magnitude of the constant accleration of the police car. pdf

Answers

Answer:

30.0m/s²

Explanation:

Given

final speed v = 30.0m/s

initial velocity u = 0m/s

Time taken t = 1.00s

Required

constant acceleration of the police car a

Substitute the given parameters into this equation of motion

v = u + at

30 = 0 +1a

30 = a

a = 30.0m/s²

Hence the magnitude of the constant acceleration of the police car is 30.0m/s²

Determine the required height h of the crest of the roller coaster to thebottom so that when it is essentially at rest at the crest of the hill it will reacha speed of 28 m/s when it comes to the bottom.

Answers

Answer:

h = 40 m

Explanation:

Assuming no friction present, total mechanical energy must be conserved, so the following expression stands:ΔK + ΔU = 0 (1)Now, if the car is at rest at the crest of the hill, the change in kinetic energy is just as follows:

       [tex]\Delta K = \frac{1}{2} * m* v_{b} ^{2}[/tex]  (2)

       where vb = speed at the bottom = 28 m/s

If we define the bottom as our zero reference level for the gravitational potential energy, we can write the following equation:

       [tex]\Delta U = U_{f} - U_{i} = 0- m*g*h = -m*g*h[/tex] (3)

From (1) we get:ΔK = -ΔUReplacing by (2) and (3), we get:

       [tex]\frac{1}{2} * m* v^{2} = m*g*h[/tex]

Simplifying and rearranging terms, we can solve for h (height required) as follows:

       [tex]h = \frac{v_{b} ^{2} }{2*g} = \frac{(28m/s)^{2}}{2*9.8m/s2} = 40 m[/tex]

A spacecraft is traveling in space at a velocity of 8200 m's. Turning a dial elicits the engines to accelerate the spacecraft at 2 m/s. How many seconds will it take
before the spacecraft reaches a velocity of 8400 m's?

Answers

spacecraft is ummm i’m not sure sorry oh it is 8,4000

What is one way radio waves are used?
А
to carry signals for televisions
B
to kill germs in hospitals
с
to treat cancer with radiotherapy
D
to take images of bones

Answers

Answer:

A

Explanation:

because it is used in tvs all the time

Answer is a to carry signals for televisions

A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 5th bounce is measured to be 1.51 m. Find the coefficient of restitution of the ball for a collision with asphalt

Answers

Answer: the coefficient of restitution of the ball for a collision with asphalt=0.95

Explanation:

Initial height of the bounce from the ball, h  =2.47m

height of the 5th bounce of the ball , h₁= 1.51m

Making e the coefficient of the restitution, then the height covered by the ball after the 5th bounce is

h₁= e²ⁿh

Where n = 5

h₁= e²⁽⁵⁾h

e¹⁰=h₁/h

e¹⁰=1.51/2.47

e= (1.51/2.47)¹/¹⁰

e=0.95198≈ 0.95

Therefore, the coefficient of restitution of the ball for a collision with asphalt is 0.95

Which of the following statements is correct about the energy
of water stored in a tank?
1. Water stored in the tank has kinetic energy and potential
energy
2. Water stored in the tank has kinetic energy only.
3. Water stored in the tank has no energy.
4. Water stored in the tank has potential energy only.

Answers

Answer:

4. Water stored in the tank has potential energy only.

Explanation:

when water begins to move the potential energy is converted into kinetic but until it is being used it has potential energy only.

5.3C The nozzle on a fire hose is connected to the hose via a coupling. When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is: a) in equilibrium, so there is no force on the coupling. b) in tension. c) in compression

Answers

Answer:

Tension ( B )

Explanation:

When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is in TENSION , this is because the force of flow in a stationary object will be in a compressive nature that will in turn cause the force on the coupling to be in a form of a Tension ( i.e. Tensile )

How do mass and the type of material affect thermal energy transfer?

Answers

Answer:

Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. ... Heat is the transfer of thermal energy between objects that have different temperatures.

PLEASE HELPP WITH QUESTIONS :(

Answers

Answer:no

Explanation: lol

What conditions are required so that the mechanical energy of a system is conserved? Select all that apply. View Available Hint(s) Select all that apply. No internal forces act on objects within the system. No net external force acts on the system No non-conservative forces, such as friction, act between objects within the system

Answers

Answer:

No non-conservative forces, such as friction, act between objects within the system

Explanation:

The law of conservation of mechanical energy in a closed system states that;'The total amount of mechanical energy, in a closed system in the absence of non-conservative forces, such as friction, remains constant.' Non-conservative forces  cause energy to be lost from the system, this lost energy can't be gotten back

This implication of this is that energy can not disappear. Kinetic energy can be converted into potential energy and vice-versa in accordance with this principle.

Problem 6 (20 points) A ballistic pendulum is a device often used for measuring the velocity of a projectile. Assume to projectile fully embeds itself in the pendulum. If the projectile mass is 25 grams, the pendulum mass is 2.5 kg, and the vertical displacement of the pendulum after the collision is 12 cm, find the velocity of the projectile just prior to the collision.

Answers

Answer:

The velocity of the projectile just prior to the collision is 154.934 meters per second.

Explanation:

Let consider the projectile-pendulum system as our system of study, from statement we know that projectile gives kinetic energy to the pendulum and turns into gravitational potential energy. By Principle of Energy Conservation we construct the following expression:

[tex]U_{g,1}+K_{1} = U_{g,2}+K_{2}[/tex] (Eq. 1)

Where:

[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Initial and final gravitational potential energies, measured in joules.

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies, measured in joules.

By applying definitions of gravitational potential and kinetic energies, we expand and simplify the equation above:

[tex](m+M)\cdot g \cdot (y_{2}-y_{1}) = \frac{1}{2}\cdot (m+M)\cdot (v_{1}^{2}-v_{2}^{2})[/tex]

[tex]g\cdot (y_{2}-y_{1})=\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex]

And we clear the initial velocity of the pendulum-projectile system:

[tex]v_{1}=\sqrt{v_{2}^{2}+2\cdot g\cdot (y_{2}-y_{1})}[/tex] (Eq. 2)

Where:

[tex]m[/tex] - Mass of the projectile, measured in kilograms.

[tex]M[/tex] - Mass of the ballistic pendulum, measured in kilograms.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the pendulum-projectile system, measured in meters per second.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]y_{1}[/tex], [tex]y_{2}[/tex] - Initial and vertical position of the pendulum-projectile system, measured in meters.

Under the consideration of inellastic collision, we find the velocity of the projectile prior to the collision by Principle of Linear Momentum Conservation:

[tex]m\cdot v_{o, P} + M\cdot v_{o,B} = (m+M)\cdot v_{1}[/tex]

[tex]v_{o,P} = \frac{(m+M)\cdot v_{1}-M\cdot v_{o,B}}{m}[/tex] (Eq. 2)

Where:

[tex]v_{o, P}[/tex] - Velocity of the project prior to the collision, measured in meters per second.

[tex]v_{o,B}[/tex] - Velocity of the ballistic pendulum prior to the collision, measured in meters per second.

If we know that [tex]v_{2} = 0\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y_{2}-y_{1} = 0.12\,m[/tex], [tex]m = 0.025\,kg[/tex], [tex]M = 2.5\,kg[/tex] and [tex]v_{o,B} = 0\,\frac{m}{s}[/tex], then the velocity just prior to the collision is:

By (Eq. 1):

[tex]v_{1} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.12\,m)}[/tex]

[tex]v_{1} \approx 1.534\,\frac{m}{s}[/tex]

By (Eq. 2):

[tex]v_{o,P} = \frac{(0.025\,kg+2.5\,kg)\cdot \left(1.534\,\frac{m}{s} \right)-(2.5\,kg)\cdot \left(0\,\frac{m}{s} \right)}{0.025\,kg}[/tex]

[tex]v_{o,P} = 154.934\,\frac{m}{s}[/tex]

The velocity of the projectile just prior to the collision is 154.934 meters per second.

In which disorder does a person find it difficult to fall asleep or stay asleep for a long time?
A.
somnambulism
B.
narcolepsy
C.
insomnia
D.
sleep apnea

Answers

Answer:c

Explanation:

I have it

Answer:

C.

insomnia

Explanation:

plato answer

Find the resistance that must be placed in series with a 25.0Ω25.0 Ω galvanometer having a 50.0µA50.0 μA sensitivity (the same as the one discussed in the text) to allow it to be used as a voltmeter with a 0.100-V full-scale reading

Answers

Answer:

1975 ohm

Explanation:

The maximum current that can pass through the galvanometer is 50.0µA

p.d across the galvanometer at a full scale deflection is given by

V = IR

V = (50.0×10^-6)*25

V1 = 1/800 or 0.00125volts

Since the p.d across the multiplier and galvanometer at full scale deflection is 0.100volts,the p.d across the multiplier alone must be given by

V2 = 0.100-0.00125

= 0.09875volts

Current passing through the multiplier is (50.0×10^-6)A

Hence if R is the resistance of the multiplier, we have that

V2 = (50.0×10^-6)×R

0.09875volts = (50.0×10^-6)×R

Divide both sides by 0.09875volts

R = 0.09875/(50.0×10^-6)

R =( 0.09875) ÷ 1/20000

R = 0.09875×20000

R = 1975 ohms

How long will it take an object that falls from rest to attain a velocity of 147 m/s?

Answers

Answer:

15 seconds

Explanation:

We can use this formula to solve this problem:

Velocity = Initial Velocity + Acceleration * Time

We know that initial velocity is 0, the velocity is 147, and acceleration is 9.8(because of earth's gravitational pull), so we can plug those numbers in and solve for time:

147 = 0 + 9.8*t

t = 15

Therefore, it will take 15 seconds for an object that falls from rest to reach 147 m/s.

What is the net work, in joules, required to stop a bullet of mass 7.73 g that is moving at a speed of 409 m/s

Answers

Answer:

KE=1.58J

Explanation:

In this problem we are required to solve for the total energy

"The kinetic energy is the energy possessed by a body by virtue of motion"

KE=1/2mv²

Given

Mass m=7.73g

Velocity v=409m/s

In kg= 0.00773kg

KE=1/2*0.00773*409

KE=3.16157/2

KE=1.58J

PLS HELP PLS 10. This graph represents the velocity of an object over time. What is the average acceleration of the
object during the first 4 seconds?

Answers

Answer:

8 M/S

Explanation:

This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.

Two ropes are tied to a 50 kg boat. One pulls with a force of 120 N due West and the other rope pulls with a force of 140 N due South. Find the net force of the boat (magnitude and direction) and the acceleration.

Answers

The net force on the boat is the vector

F = (-120 N) i + (-140 N) j

where we take West and South to be the negative directions going left-and-right and up-and-down, respectively.

The magnitude of the net force is

F = √((-120 N)² + (-140 N)²) = 20 √(85) N ≈ 180 N

and its direction is

tan(θ) = (-140 N) / (-120 N)   →   θ ≈ -130°

relative to due East, or approximately 50° South of West.

A running back weighing 100 kg runs headlong into a defender weighing 120 kg. The two players are moving at 7 m/s and 5 m/s, respectively. Calculate the total momentum and the total kinetic energy of the system. [Calculations including velocity should reflect direction of travel.]

Answers

Answer:

Explanation:

we know that momentum is given as

P=mv

given data

P1=?

mass m1=100kg

velocity v1=7m/s

P2=?

mass m2=120kg

velocity v2=5m/s

the total momentum =P1+P2

total=m1v1+m2v2

total= 100*7+120*5

total=700+600

total= 1300kgm/s

total kinetic energy

KE total= 1/2m1v1^2+1/2m2v2^2

KE total= 1/2*100*(7)^2+1/2*120*(5)^2

KE total= 1/2*100*49+1/2*120*25

KE total= 1/2*4900+1/2*3000

KE total=2450+1500

KEtotal=3950 J

If somebody asks me if i need help on my work and i say " no ty " , is that rude???

Answers

Answer:

no

Explanation:

2. Which is a non-example of matter?​

Answers

The human body............

Answer: there are multiple

Explanation:

light from a torch, the heat from a fire, and the sound of a police siren. You cannot hold, taste, or smell these things. They are not types of matter, but forms of energy.

Science Motion Problem pelase elp

Answers

Answer:120

Vav = S / t = (120 + 45) m / (4 + 60) sec = 2.6 m/s

Physics Freefall Name 1. You decide to drop a penny from the top of the hotel in New York. It hits a tourist in the head at 32 m/s. How far did the penny fall

Answers

Answer:

h = 52.24 m

Explanation:

Given that,

A penny is dropped from the top of the hotel in New York. It hits a tourist in the head at 32 m/s.

Let it falls at a height of h.

We can find the value of h using the conservation of energy such that,

[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(32)^2}{2\times 9.8}\\\\h=52.24\ m[/tex]

So, it will fall at a distance of 52.24 m.

A bus is moving to the right at an absolute velocity U. You throw a water balloon at the bus at an absolute velocity V (greater than U) after the bus passes you. A person on the bus sees the balloon hit the bus at a speed of:

Answers

Answer:

The person on the bus will see the balloon hit the bus at a velocity = V - U

Explanation:

There is relative motion between the water balloon and the person sitting in the bus.

Relative motion is the motion of a body with respect to another body (eg. an observer) from the point of reference of the second body (observer).

The person on the bus has a velocity which is the same as that of the moving bus = U

The velocity of the thrown water balloon (greater than U) = V

The relative motion between the person and the water balloon is the difference between their velocities (since they are both moving in the same direction) = V - U

Therefore, the person on the bus will see the balloon hit the bus at a velocity = V - U

A piece of pencil lead is connected in series with an ammeter and a power supply. The power supply is turned on. After a few minutes, although the potential difference across the pencil lead does not change, the current in the circuit increases significantly. Explain why the current increases.

Answers

Answer:

More electrons become free due to the potential which are charge carriers. More the charge carriers, more the current.

Current causes a heating effect. Resistance of lead decreases/ n increases [I=nAve]. Current increase

Explanation:

hello what is momentum?

Answers

Answer:

Momentum is vector quantity and it is defined as the product of mass of the object and velocity of the object.

As it is a vector quantity it has both direction and magnitude, and momentum is written as

p = m × v

p = momentum

m = mass of the object

v = velocity

Two kinds of momentum are there and they are:

Linear MomentumAngular Momentum

How can humans detect infrared waves?
А
They see them as color.
B
They feel them as heat.
с
They hear them as sound.
D
They feel them as vibrations.

Answers

The answer is B. They feel them as heat.
I’m not good with these type of Stuff so don’t pick my answer but I think the answer may be D
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