A magnet can be used to.
Bubble A. attract metal objects
Bubble B. measure the length of an object
Bubble C. measure the temperature of an object
Bubble D. measure the mass of an object

Answer:

C

Explanation:

The nervous system sends signals, or in this case, impulses to parts of your body that direct them to move.

Answer:

Ether group.

Explanation:

Ethers are the compounds that connect two aryl or alkyl groups by an oxygen atom and represented by R–O–R′ where R either aryl or alkyl groups. Ether can be identified by the presence of alKyl groups on either side of the oxygen atom commonly. Diethyl ether, methyl ethyl ether are some of the examples of alkyl ether

Thus, the correct answer is - Ether group.

Answer:

Outcome Variable

Explanation:

Control group and Hypothesis are not what your measuring.

Test variable would be like- "amount of water added"

Outcome variable would be something like- "amount plants grew"

You would be measuring the amounts the plants grew, based on the water added.

Answer:

CH2O

Explanation:

According to the valence shell electron pair repulsion theory, electron pairs tend to position themselves as far apart in space as possible to minimize repulsion.

The shape of a molecule depends on the number of electron pairs present on the valence shell of the central atom in the molecule- both lone pairs and bond pairs.

CH2O has three electron domains. the possession of three electron domains and no lone pairs of electrons on the central atom corresponds to a trigonal planar geometry.

Answer:

2 Na⁺(aq) + S²⁻(aq) + Fe²⁺(aq) + 2 NO₃⁻(aq) ⇒ FeS(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of sodium sulfide and iron(II) nitrate are mixed.

Na₂S(aq) + Fe(NO₃)₂ ⇒ FeS(s) + 2 NaNO₃(aq)

The complete ionic equation includes all the ions and the species that do not dissociate in water.

2 Na⁺(aq) + S²⁻(aq) + Fe²⁺(aq) + 2 NO₃⁻(aq) ⇒ FeS(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)

The complete ionic equation for the reaction between aqueous solution of sodium sulfide and iron(II) nitrate is

2Na⁺(aq) + S²⁻(aq) + Fe²⁺(aq) + 2NO₃⁻(aq) —> FeS(s) + 2Na⁺(aq) + 2NO₃⁻(aq)

The complete ionic equation for the reaction between aqueous solution of sodium sulfide and iron(II) nitrate can be written as follow:

In solution, Na₂S and Fe(NO₃)₂ will dissociate as follow:

Na₂S(aq) —> 2Na⁺(aq) + S²¯(aq)

Fe(NO₃)₂(aq) —> Fe²⁺(aq) + 2NO₃¯(aq)

The reaction will proceeds as illustrated below to give the complete ionic equation:

Na₂S(aq) + Fe(NO₃)₂(aq)—>

2Na⁺(aq) + S²¯(aq) + Fe²⁺(aq) + 2NO₃¯(aq) —> FeS(s) + 2Na⁺(aq) + 2NO₃¯(aq)

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Answer: The answer is C. 0.1MCaCl2

Explanation:

We have AgCl whose least solubility is to be determined at 25degree Celsius

so upon looking at the options given we observe C 0.1MCaCl2 and D 0.1MHCl both have chlorine ions present and we know that here common ion effect will happen that causes decreases the solubility of the AgCl here

but when Calcium chloride dissociates it gives 2 moles of chlorine ions

[tex]CaCl2[/tex]→[tex]Ca^+2 + 2Cl^-[/tex]

so chlorine ion will be present in more amount [tex]2*0.1\\[/tex]=[tex]0.2[/tex] as compared to the chlorine produced by HCl

[tex]HCl[/tex]→[tex]H^+ +Cl^-[/tex] only 1 mole of chlorine is produced.

Hence AgCl will be least soluble in 0.1M CaCl2

Answer:

  about 121.5 K or -151.7 °C

Explanation:

Volume of an ideal gas is proportional to the absolute temperature. At 67 °C, the absolute temperature is 67+273.15 K, or 340.15 K.

Then 50.0/140.0 times that temperature is ...

  (5/14)(340.15 K) ≈ 121.482 K ≈ -151.668 °C

The volume would be 50.0 mL at a temperature of about 121.5 K or -151.7 °C.

Explanation:

A. 3 groups bound to it with no lone pairs

Answer:

0.167 mol Fe

Explanation:

4 Fe  +  3 O₂  ⇒  2 Fe₂O₃

Convert moles of oxygen to moles of iron using the mole ratio.  You can find the mole ratio using the chemical equation.  For every 4 moles of iron, you will need 3 moles of oxygen.

(0.125 mol O₂)  (4 mol Fe/3 mol O₂) = 0.167 mol Fe

Answer:

Your mom says to stop cheating

Explanation:

Answer:

0.41 M

Explanation:

A -> B

rate constant (k) = 0.039L/mol s

t = 23

Final concentration, [A]  = 0.30M

Initial concentration, [A]o = x

1 / [A]  = kt + 1 / [A]o

1 / [A]o = 1 / [A] - kt

1 / [A]o  = 1 / 0.30   - 0.039 (23)

1 / [A]  = 3.33 -  0.897 = 2.433

[A] = 0.41 M

Answer:K,Potassium

Explanation:

D. Plutonium-238 is the most stable isotope

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles (such as alpha (α), beta (β), gamma (γ) particles)

General formulas used in decay:

[tex]\large {\boxed {\bold {N_t = N_0 (\dfrac {1} {2}) ^ {t / t \frac {1} {2}}}}[/tex]

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Half-life shows the time it takes for an atom to get half of its initial mass (to decay to half of its initial mass)

The longer the half-life indicates the stability of the atom

Half-life (hr) of isotopes :

Polonium-210  : 3,310

Uranium-237  : 162

Francium-227  : 0.04

Plutonium-238 : 768,000

The half-life value above shows that Plutonium-238 has the longest time, making it the most stable

The question is incomplete; the complete question is;

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.80g of carbon dioxide is produced from the reaction of 3.4g of octane and 5.9g of oxygen gas, calculate the percent yield of carbon dioxide. Be sure your answer has the correct number of significant digits in it.

Answer:

55%

Explanation:

The balanced equation is:

C8H18(g) + 25/2O2(g) ----------> 8CO2(g) + 9H2O(g)

The limiting reactant IS first determined. This is the reactant that yields the least amount of product.

3.4 g octane / 114 g/mol = 0.030 mol octane

From the reaction equation;

1 mole of octane yields 8 moles of CO2

0.030 mol octane yields 0.030 * 8/1 = 0.24 moles of CO2

5.9 g O2 / 32 g/mol = 0.18 mol O2

25/2 moles of O2 yields 8 moles of CO2

0.18 moles of O2 yields 8 * 0.18/25/2 = 0.1152 moles of CO2

Oxygen is the limiting reactant.

Number of moles of carbon dioxide produced (actual yield) = 2.8 g/44g/mol = 0.0636 moles of CO2

% yield = actual yield/ theoretical yield * 100

% yield =   0.0636/0.1152 * 100= 55%

Answer:

D

Explanation:

The cathode rays are being deflected towards the positive plate because the particles of the ray are negatively charged

Explanation:

So, from this, we can conclude that the cathode rays are being deflected towards the positive plate because the particles of the ray are negatively charged.

Learn more about cathode rays here:

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Answer:

everything.

Explanation:

You need nice weather,good realation ships as well as convection

Answer:

A C D F

Explanation:

Answer:

[tex]r_{N_2O_5}=-4.00mol/min\[/tex]

Explanation:

Hello.

In this case, since the chemical reaction is:

[tex]2N_2O_5\rightarrow 4NO_2+O_2[/tex]

We can write the rate ratio between N2O5 and NO2 as shown below:

[tex]\frac{1}{-2} r_{N_2O_5}= \frac{1}{4} r_{NO_2}[/tex]

Since N2O5 is consumed and NO2 produced at a rate of 8.00 mol/s, therefore, the rate of disappearance is N2O5 is:

[tex]r_{N_2O_5}= \frac{-2}{4} r_{NO_2}\\\\ r_{N_2O_5}=\frac{-1}{2} *8.00 mol/min\\\\ r_{N_2O_5}=-4.00mol/min[/tex]

Which is negative since N2O5 is a reactant.

Best regards!

Answer:

11280

Explanation:

Answer:

Glucose. Fructose. Galactose.

Explanation:

Glucose +fructose=succrose(normal sugar)

Glucose+Glucose= Maltose(wheat sugar)

Glucose+Galactose= Lactose(milk sugar)

Answer:

[tex]P_2=2.04atm[/tex]

Explanation:

Hello.

In this case, by using the combined ideal gas law, we can identify the change in pressure, temperature an volume as shown below:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

In such a way, since we are asked to compute the final pressure, P2, we proceed as follows:

[tex]P_2=\frac{P_1V_1T_2}{T_1V_2} \\\\P_2=\frac{1.12atm*2.29L*302K}{285K*1.33L}\\ \\P_2=2.04atm[/tex]

Best regards!

Answer:

[tex]\Delta G=8015\frac{J}{mol}[/tex]

Explanation:

Hello.

In this case, for the following chemical reaction in gaseous phase:

[tex]C_2H_4+H_2O\rightleftharpoons C_2H_5OH[/tex]

We can write the equilibrium expression as:

[tex]Kp=\frac{p_{C_2H_5OH}}{p_{H_2O}*p_{C_2H_4}}[/tex]

it means that given the pressures, we can compute Kp as shown below:

[tex]Kp=\frac{0.100atm}{0.275atm*0.350atm}=1.04[/tex]

Next, we compute Kc at 298 K:

[tex]Kc=\frac{Kp}{(RT)^{1-1-1}}=\frac{Kp}{(RT)^{-1}}[/tex]

Whereas 1-1-1 comes from the stoichiometric coefficients of products minus reactants. Therefore, Kc is:

[tex]Kc=\frac{1.04}{(0.08206*298)^{-1}}=25.4[/tex]

Thus, the Gibbs free energy for this reaction is:

[tex]\Delta G=RTln(kC)=8.314\frac{J}{mol*K}*298K*ln(25.4)\\ \\\Delta G=8015\frac{J}{mol}[/tex]

Best regards!

Answer:

pH = 11.179

Explanation:

The sodium carbonate, Na2CO3, is in equilibrium with water as follows:

Na2CO3 + H2O ⇆ NaHCO3 + OH⁻

Where Kb is 1.786x10⁻⁴:

Kb = 1.786x10⁻⁴ = [NaHCO3] [OH-] / [Na2CO3]

Where [NaHCO3] = [OH-] = X, our incognite

And [Na2CO3] is molar concentration of sodium carbonate:

[Na2CO3] = 0.3379g * (1mol / 105.99g) = 3.188x10⁻³ moles Na2CO3

In 250.0mL = 0.2500L:

3.188x10⁻³ moles Na2CO3 / 0.2500L = 0.01275M

Replacing in Kb expression:

1.786x10⁻⁴ = [NaHCO3] [OH-] / [Na2CO3]

1.786x10⁻⁴ = [X] [X] / [0.01275]

2.278x10⁻⁶ = X²

X = [OH⁻] = 1.509x10⁻³M

As pOH = -log [OH⁻] = 2.821

And pH = 14 - pOH

Answer:

61.8 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Next, the data obtained from the question include:

Molarity of acid, HCl (M1) = 0.341 M

Volume of base, NaOH (Vb) = 43.9 mL

Molarity of base, NaOH (Mb) = 0.480 M

Volume of acid, HCl (Va) =?

The volume of the acid needed for the reaction can be obtained as follow:

MaVa/MbVb = nA/nB

0.341 × Va / 0.480 × 43.9 = 1/1

Cross multiply

0.341 × Va × 1 = 0.480 × 43.9 × 1

0.341 × Va = 21.072

Divide both side by 0.341

Va = 21.072 /0.341

Va = 61.8 mL

Therefore, 61.8 mL of the acid, HCl is needed for the reaction.

Answer:

[HF] = 0.23M

0.02M = [F⁻]

[H₃O⁺] = 0.02M

Explanation:

The equilibrium of HF with water is:

HF + H₂O ⇄ H₃O⁺ + F⁻

Where F⁻ is the conjugate base of the HF

The initial concentration of HF is:

[HF] = 0.0500mol / 0.200L = 0.25M

Now, in equilibrium, if the 7.90% is dissociated, the undissociated HF is the 100 - 7.90 = 92.1%

0.25M*92.1% = 0.23M = [HF]

The conjugate base will be 0.25M - 0.23M = 0.02M = [F⁻]

And as the H₃O⁺ ion comes from the same equilibrium of F⁻ and is produced in the same proportion:

[H₃O⁺] = 0.02M