a local pizzaria offers 15 toppings for their pizzas you can choose any 4 of them for a fixed price how many different types of pizzas can you order with 4 toppings

Answer:

Your answer is A and B

Step-by-step explanation:

A. Has 8 by 3 by 2 = 48

B. 6 by 4 by 2 = 48

C. 4 by 4 by 4 = 64

D. 11 by 2 by 2 = 44

Answer:

This is an Application of Boyle's Law.

Step-by-step explanation:

The relationship between the Pressure and Volume have been made available and is given as ;

P =k/v

Simply making k(constant) subject...

K =PV (With this, we can conclude that :

P₁V₁ = P₂V₂

150 x 4 = P₂ x 3

P₂ = 150 x 4/(3)

P =200kPa

Now, This is all math.

But what really happened?

Pay attention.

The relationship between Pressure and Volume according to Robert Boyle in his Law, as stated in the question is P = k/v

This is an inverse relationship.

simply interpreted, It reads " When pressure increases by a certain factor, Volume decreases by that factor". This is the concept behind inverse relationships.

So from the question, Volume decreased from 4ML to 3L.

Initial Pressure was 150kPa.

According to Boyle, Pressure has to increase by 4/3

Therefore, New pressure is undoubtedly 150 x 4/3 = 200kPa

Have a splendid day.

Answers:

Domain:  [tex](-\infty, 5)[/tex]

Range:  [tex][-3, \infty)[/tex]

Both are in interval notation. There's a square bracket next to the -3, and everything else is a curved parenthesis.

===========================================================

Explanation:

The domain is the set of allowed x input values of a function. We have a hole at x = 5, so this value is not allowed in the domain. But we can use anything smaller than this. The domain as an inequality is [tex]x < 5[/tex] which is the same as writing [tex]-\infty < x < 5[/tex] and that directly translates to the interval notation of [tex](-\infty, 5)[/tex]

The curved parenthesis say "exclude this endpoint". The domain is anything between negative infinity to 5, excluding both endpoints.

----------------------

The range is the set of possible y outputs of a function.

The lowest the function goes is at y = -3. The arrow indicates it goes up forever, meaning that the range as an inequality is [tex]y \ge -3[/tex] which is the same as [tex]-3 \le y[/tex] and the same as [tex]-3 \le y < \infty[/tex]

Then that directly turns into the interval notation of [tex][-3, \infty)[/tex]

We have a square bracket at -3 to include this endpoint. We can't ever reach infinity, so we of course can't include this endpoint. Always use parenthesis for either infinity.

Answer: hii

real :)

Step-by-step explanation:

"While it is not a real number — that is, it cannot be quantified on the number line — imaginary numbers are "real" in the sense that they exist and are used in math. Imaginary numbers, also called complex numbers, are used in real-life applications, such as electricity, as well as quadratic equations."

Hopefully this helps you

- Matthew

Answer:

B

Step-by-step explanation:

Let's take a look at each statement.

A: ∠1 ≅ ∠8

Angle 1 is congruent to angle 8.

If lines are parallel then angle 1 and angle 8 would be same side (consecutive) exterior angles which are supplementary and not congruent.

Therefore this statement would prove that the lines are not parallel.

B: ∠1 ≅ ∠7

Angle 1 is congruent to angle 7.

If lines are parallel then angle 1 and angle 7 would be alternate exterior angles which are congruent.

This statement proves that the lines are parallel. We have angle 1 that is at line AB and angle 7 which is at line CD. It's important that one angle is at one line and the second angle at the other line, otherwise we cannot prove that the lines are parallel.

C: ∠6 ≅ ∠8

Angle 6 is congruent to angle 8.

Angles 6 and 8 are vertical angles and they are congruent.

This statement is correct but it doesn't tell us anything about the relationship of angles at the other line, therefore it proves nothing.

D: ∠1 and ∠2 are supplementary.

Angles 1 and 2 create a linear pair, therefore they are supplementary.

This statement is also correct but again it tells us nothing about the angles at the other line so it again proves nothing.

The shapes that are under the trapezoid in the quadrilateral hierarchy are parallelogram and isosceles trapezoid.

A quadrilateral is a polygon that has four sides and four angles. Types of quadrilateral are kite, square, parallelogram and so on.

The shapes that are under the trapezoid in the quadrilateral hierarchy are parallelogram and isosceles trapezoid.

Find out more on quadrilateral at: https://brainly.com/question/23935806

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2,400 + 70N = S

hope this helps ya mate

Answer:

  1/6x -1

Step-by-step explanation:

"Simplify" generally means, "eliminate parentheses and combine like terms." In general, parentheses are eliminated by making use of the distributive property.

__

  [tex]\dfrac{2}{3}x-\left(\dfrac{1}{2}x+1\right)=\dfrac{2}{3}x-\dfrac{1}{2}x-1=\left(\dfrac{2}{3}-\dfrac{1}{2}\right)x-1\\\\=\left(\dfrac{4}{6}-\dfrac{3}{6}\right)x-1=\boxed{\dfrac{1}{6}x-1}[/tex]

Answer:

See below ~

Step-by-step explanation:

Solving :

(a) Coordinates of P and Q

⇒ Equate the lines' equations

⇒ 2x² - 6x - 8 = 2x - 14

⇒ 2x² - 8x + 6 = 0

⇒ x² - 4x + 3 = 0

⇒ (x - 3)(x - 1) = 0

⇒ x = 3 and x = 1

Substitute each x-value in the any of the 2 equations :

⇒ y = 2(3) - 14

⇒ y = 6 - 14

⇒ y = -8

⇒ P = (3, -8)

⇒ y = 2(1) - 14

⇒ y = 2 - 14

⇒ y = -12

⇒ Q = (1, -12)

(b)

(i) 2x² - 6x - 8 = 0

⇒ x² - 3x - 4 = 0

⇒ (x - 4)(x + 1) = 0

⇒ x = 4 and x = -1

(ii) 2x² - 6x = -4

⇒ 2x² - 6x + 4 = 0

⇒ x² - 3x + 2 = 0

⇒ (x - 1)(x - 2) = 0

⇒ x = 1 and x = 2

(c) Line of symmetry

Finding the vertex :

⇒ Vertex = (h, k)

⇒ h = -b/2a

⇒ h = -(-6)/2(2)

⇒ h = 6/4

⇒ h = 1.5

⇒ The axis of symmetry's equation is : x = 1.5

(d)

⇒ As the mentioned function is a quadratic function, irrational values such as √2, √3, √6, etc. cannot be taken into consideration

50m ≅164 ft (3s.f.)

50m/s≅164 ft/s

distance after 20s:

d=164 ft/s ⋅20s

=3280ft

Hope This Helps!

fixed cost= $8

cost= $4.50

payed= $50

recieved= $10.50

how many days Hannah rented the bike.

let the unknown be ( x )

[tex]x = 50 - (10.50 + 8)[/tex]

[tex]x = 50 - 18.50[/tex]

[tex]x = 13.50[/tex]

[tex]x = \frac{13.50}{4.50} [/tex]

[tex]x = 7[/tex]

hence, Hannah rented the bike for 7 days.

THIS ONE I CANT FIGURE OUT SORRY :C

Answer:

(x +2y ) ( 2x-3y)

= 2x² + 4xy -3xy -6y²

= 2x² +xy -6y²

Step-by-step explanation:

2x^2 +xy-6y is the answer

Answer:

Step-by-step explanation:

x² - 2x + 5 = 0

x² - 2x = -5

x² - 2x + 1 = -5 + 1

(x - 1)² = -4

(x - 1) = ±2i

Answer:

they are really different

Answer:

I will answer them from top to bottom

1. 2A

2. 2A-B

3. 2A+3A

4. 2(A-B)

Step-by-step explanation:

You don't need an explanation. I am just putting this here so my answer does not get taken down.

The attached diagram represents the required line plot

From the table, we have the following frequency table:

Minutes spent           Frequency

25                                     1

25 1/2                                2

26                                     1

27 1/2                                 1

27 3/4                                1

28 1/4                                1

28 1/2                                2

29                                     1

Total                                10

Using the above frequency table, we can now plot the line plot

See attachment for the line plot

Read more about line plots at:

https://brainly.com/question/21862696

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Answer:

you first can check online, call your bank, visit an ATM, set up alerts, or ask a teller.

quaddale dingle said hey, whats up

Answer:

I just edited the file you linked.

Answer:

HERE IS THE REAL ANSWER!!! >

Step-by-step explanation:

I added the file so yeah also its correct!

[tex]\\ \rm\Rrightarrow (f+g)(x)[/tex]

[tex]\\ \rm\Rrightarrow f(x)+g(x)[/tex]

[tex]\\ \rm\Rrightarrow x^2-4x+6+2x^2+2x-5[/tex]

[tex]\\ \rm\Rrightarrow 3x^2-2x+1[/tex]

Done!

Answer:

[tex](f+g)(x)=3x^2-2x+1[/tex]

Step-by-step explanation:

[tex]\begin{aligned}\textsf{Given functions}: \quad f(x) &=x^2-4x+6\\g(x) &=2x^2+2x-5\\\end{aligned}[/tex]

[tex]\begin{aligned}(f+g)(x) & =f(x)+g(x)\\& =(x^2-4x+6)+(2x^2+2x-5)\\& =x^2-4x+6+2x^2+2x-5\\& =x^2+2x^2-4x+2x+6-5\\& =3x^2-2x+1\end{aligned}[/tex]

Answer:

10/10

Step-by-step explanation:

Answer:

5747.37

Step-by-step explanation:

5 000 ( 1 + .01) ^14

 =   5747.37