Answer:
The selling price after the markup is $1.82
Step-by-step explanation:
$1.40 * .30 =
Multiply $1.40 times .30 (which is same as 30%)
$1.40 * .30 = $0.42
Add $1.40 and $0.42
= $1.82
Hope this helps.
If P is (-5, 4) and Q is (7, -5), what is 2/3 of that?
Answer: 10
Step-by-step explanation:
Sqrt (7- -5)^2+(-5-4)^2 =
Sqrt (12)^2+(-9)^2 =
Sqrt 225 = 15
2/3 * 15 = 30/3 = 10
Reduce to Standard form : (a) -21/91 (b) 32/(-256)
Answer:
a) -3/13
b) -1/8
Step-by-step explanation:
a) - (21 / 7) / (91 / 7) = 3/13
b) (32 / 32 ) / - (256 / 32) = -1/8
Write an expression to show the total cost of an
item x with a 35% discount.
65/100 * x or 0.65 * x
Find the first, second, third and fourth order Maclaurin polynomials of f(x) =
arctan(x). Draw the graph of f(x) and the four polynomials on the same
diagram. (Sketch by hand or use software.)
#urgent please give me this answer and help me#
The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can see the graph on the attached picture.So let's start by finding the first order maclaurin polynomial:
f(x)=f(0)+f'(0)x
so let's find each part of the function:
f(0)=arctan(0)
f(0)=0
now, let's find the first derivative of f(x)
f(x)=arctan(x)
This is a usual derivative so there is a rule we can use here:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
so now we can find f'(0)
[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]
f'(0)=1
So we can now complete the first order Maclaurin Polynomial:
f(x)=0+1x
which simplifies to:
f(x)=x
Now let's find the second order polynomial, for which we will need to get the second derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]
so:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
we can rewrite this derivative as:
[tex]f'(x)=(x^{2}+1)^{-1}[/tex]
and use the chain rule to get:
[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]
which simplifies to:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
now, we can find f''(0):
[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]
which yields:
f''(0)=0
so now we can complete the second order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]
which simplifies to:
f(x)=x
Now let's find the third order polynomial, for which we will need to get the third derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]
so:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
In this case we can use the quotient rule to solve this:
Quotient rule: Whenever you have a function in the form , then it's derivative is:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
p=2x
p'=2
[tex]q=(x^{2}+1)^{2}[/tex]
[tex]q'=2(x^{2}+1)(2x)[/tex]
[tex]q'=4x(x^{2}+1)[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]
which simplifies to:
[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
now, we can find f'''(0):
[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]
which yields:
f'''(0)=-2
so now we can complete the third order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]
so:
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
In this case we can use the quotient rule to solve this:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
[tex]p=6x^{2}-2[/tex]
p'=12x
[tex]q=(x^{2}+1)^{3}[/tex]
[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]
[tex]q'=6x(x^{2}+1)^{2}[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]
which simplifies to:
[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]
[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]
now, we can find f^{4}(0):
[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]
which yields:
[tex]f^{4}(0)=0[/tex]
so now we can complete the fourth order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
you can find the graph of the four polynomials in the attached picture.
So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can find further information on the following link:
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A lighthouse casts a
revolving beam of light as far as the pier. What
is the area that the light covers?
Answer:
First, let's find how far away the pier is.
Using the distance formula, we can see that the pier is [tex]\sqrt{58}[/tex] units away.
So, the radius is sqrt 58.
Area = pi (r)^2
So, the area is 182.82 square units.
Let me know if this helps!
We have that The area that the light covers is is mathematically given as
[tex]A=\pi x^2[/tex]
From the Question we are told that
Revolving beam of light as far as the pier
Let distance to pier be x
Generally the revolving beam turns a complete angle of 360
Therefore
Its goes in a circle
The area that the light covers is is mathematically given as
[tex]A=\pi r^2[/tex]
[tex]A=\pi x^2[/tex]
In conclusion
The area that the light covers is is mathematically given as
[tex]A=\pi x^2[/tex]
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Name the indicated geometric figures for the figure shown. Be sure to use correct notation
A Name a point.
B Name a ray through Y.
C Name a line through Z.
D Name a plane.
9514 1404 393
Answer:
see below
Step-by-step explanation:
[tex]\text{A. point: }X\\\\\text{B. ray through Y: }\overrightarrow{XY}\\\\\text{C. line through Z: }\overleftrightarrow{XZ}\\\\\text{D. plane: plane } XYZ[/tex]
__
Additional comment
When you don't have the benefit of typesetting, you can refer to the geometry by name: ray XY, line XZ,
In the arithmetic sequence -7, -6, -5 what term is 2?
The term 2 is the ___th term of the sequence
Answer:
10th term
Step-by-step explanation:
The equation of the arithmetic sequence is an=-7+(n-1)*1=-8+n, plugging in 2 and solving for n we have
2=-8+n, n=10
Problem E2 Moving points B and C are on circle x² + y2 = 25. Let A be (2,0) and M be mid-point of BC. If BAC is a straight line, what is the locus of M?
Answer:
Step-by-step explanation:
The perpendicular bisector of any chord is a diameter and therefore passes through the center of the given circle.
The triangle OMA is thus rectangle.
The locus of M is the circle of diameter OA with center (1,0) and radius 1.
Divide 500 in the ratio 4:5:1
Answer:
200 : 250 : 50
Step-by-step explanation:
Sum the parts of the ratio, 4 + 5 + 1 = 10 parts
Divide the amount by 10 to find the value of one part
500 ÷ 10 = 50 ← value of 1 part of ratio , then
4 parts = 4 × 50 = 200
5 parts = 5 × 50 = 250
500 = 200 : 250 : 50
Answer:
200, 250 and 50.
Step-by-step explanation:
First find the 'multiplier'.
4 + 5 + 1 = 10
500/10 = 50 = multiplier.
So the answer is
4*50 = 200
5 * 50 = 250
and 1 * 50 = 50.
Suppose every interior angle in a regular polygon is approximately 152.31∘. What kind of polygon is this?
To solve this question, we have to understand the sum of all angles of a polygon and identify the polygon, which is classified according to the number of sides, getting that, since the polygon has 13 sides, it is a tridecagon.
-----------------------------
Sum of angles:
The sum of angles of a polygon of n sides is given by:
[tex]S_n = 180(n-2)[/tex]
-----------------------------
Regular polygon, with interior angles of 152.31∘.
In a regular polygon, all of the n angles have the same measure, which means that the sum of the angles is:
[tex]S_n = 152.31n[/tex]
-----------------------------
Finding n:
To classify the polygon, we have to find n, which we do equaling the two equations for [tex]S_n[/tex]. Then
[tex]180(n-2) = 152.31n[/tex]
[tex]180n - 152.31n = 360[/tex]
[tex]27.69n = 360[/tex]
[tex]n = \frac{360}{27.69}[/tex]
[tex]n = 13[/tex]
-----------------------------
Since the polygon has 13 sides, it is a tridecagon.
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,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Answer:
c
Step-by-step explanation:
use the distributive property to expand the expression:
-2(9 + 32n)
-2*9 + (-2*32n)
-18 - 64n
Which expression corresponds to this graph?
Answer: Choice A
The number line graph is visually showing every number that is 19 or smaller; hence [tex]x \le 19[/tex]
Note the use of a closed or filled in circle at the endpoint (in contrast to an open circle). This indicates we are including the endpoint 19 as part of the solution set, and that's why we go for "or equal to" as part of the inequality sign.
what's the standard answer for (5×1)+(7×.2)+(2×0.4)
9514 1404 393
Answer:
7.2
Step-by-step explanation:
The order of operations tells you that quantities in parentheses are evaluated first.
(5×1)+(7×.2)+(2×0.4) = 5 + 1.4 + 0.8
Then the addition is performed, left to right.
= 6.4 +0.8
= 7.2
_____
Your calculator can work this problem for you, if necessary.
Find the greatest number than divides 45, 60 and 75 without leaving remainder
Answer:
15
Step-by-step explanation:
15×3=45
15×4=60
15×5=75
Answer:
15
Step-by-step explanation:
45 = 1 × 3^2 × 5
60 = 2^2 × 3 × 5
75 = 3 × 5^2
greatest number than divides 45, 60 and 75 without leaving remainder = GCF of 45,60,75 = 3 × 5 = 15
A geometric sequence is a sequence of numbers where the next term equals to
the previous term multiplied by a common factor (for example, (3, 6, 12, 24, ...)
is a geometric sequence with the first term ”3” and the common factor ”2”). If
the 5th term of a geometric sequence is 24 and the 7th term is 144, what is the
first term of the sequence?
(A) 2
(B) 3/2
(C) 2/3
(D) 1/3
(E) 1/4
Answer:
C
Step-by-step explanation:
Let the first term be a and the common ratio be r.
ATQ, ar^4=24 and ar^6=144, r=sqrt(6) and a=24/(sqrt(6))^2=24/36=2/3
help with number 1 please. Thank you.
Answer:
Hello,
Step-by-step explanation:
Q1:
[tex]\left\{\begin{array}{ccc}x&=&t+\dfrac{1}{t} \\\\y&=&t-\dfrac{1}{t} \\\end{array}\right.\\\\\left\{\begin{array}{ccc}x^2&=&t^2+\dfrac{1}{t^2} +2\\\\y^2&=&t^2+\dfrac{1}{t^2} -2\\\end{array}\right.\\\\\\x^2-y^2=4: \ equilater\ hyperbola.\\[/tex]
Q2:
1)
[tex]\left\{\begin{array}{ccc}x&=&2t^2} \\\\y&=&4t \\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}t&=&\dfrac{y}{4} \\\\x&=&2*(\dfrac{y}{4})^2 \\\end{array}\right.\\\\\\\boxed{x=\dfrac{y^2}{8}} :\ parabola\ with\ x-axis\ as\ axis\ of\ symmetry[/tex]
2)
[tex]y=\dfrac{25}{x} \\[/tex]
equilater hyperbola (centre (0,0))
if 75% think the action is morally wrong, and we say there are 249 million adults in the country, how many believe that the action is morally wrong?
Answer: 186.75 million which is the same as saying 186,750,000
Work Shown:
75% = 75/100 = 0.75
75% of 249 million = 0.75*249 million = 186.75 million
186.75 million = 186.75*10^6 = 186,750,000
Answer:
186,750,000
Step-by-step explanation:
Take 75% of 249 million
.75 * 249,000,000
186,750,000
Which best describes the relationship between the line that passes through the points (9, -1) and (11,3) and the line that passes through
the points (-6, 4) and (-4,0)?
Answer:
Option B, parallel
Step-by-step explanation:
for the first line,
[3-(-1)]/[11-9]
= 4/2 = 2
for the second line,
(0-(-4))/(-4-(-6))
= 4/2 = 2
Both has same slope so they're parallel but it doesn't seem like they are the same line
How to write -.04 as a fraction?
Answer:
[tex]0.04 = 4 \div 100 [/tex]
Write the equation of the line that passes through the points (- 4, - 3) and (3, - 5) . Put your answer in fully reduced slope intercept form, unless it is a vertical or horizontal line
Help me pls:(
Answer:
(-4, -3) y (3, -5)
{-12 y, 15 y}
-12 y + 15 y = 3 y
(3 y)/2
3 sqrt(41) abs(y)
If a triangular pyramid has a base area of 10ft and a height of 6ft, what is the volume?
. 20ft^3
. 40ft^3
.60ft^3
.80ft^3
.120ft^3
Answer: 20 ft³
Step-by-step explanation:
volume of triangular pyramid = [tex]\frac{1}{3} bh[/tex]
b = base area = 10 fth = height = 6 ftTherefore, the volume is:
[tex]\frac{1}{3} *10*6=\frac{1}{3}*60=\frac{60}{3}=20[/tex]
Explain FOUR reasons why the government charge indirect taxes
Answer:
spread over a wide range
cannot be evaded
Everyone can contribute
convenient
Step-by-step explanation:
Pls Help ASAP..................
Answer:
1. 8+(30/(2+4)) = 8+(30/6) = 8+5 = 13
2. ((8+30)/2)+4 = (38/2)+4 = 19+4 = 23
Step-by-step explanation:
:)
Answer:
Step-by-step explanation:
23:
(8 + 30) ÷ 2 + 4
13:
8 + 30 ÷ (2 + 4)
please give me the brainliest if u can
The graph of [tex]y = ax^2 + bx + c[/tex] is a parabola. The axis of symmetry is [tex]x = -b/2a[/tex]. What are the coordinates of the vertex?
The vertex can be written as:
(-b/2a, b^2/(4*a) - b^2/2a + c)
For a general parabola:
y = a*x^2 + b*x + c
We can write the vertex as:
(h, k)
The x-value of the vertex is the value of the axis of symmetry.
Then we have:
h = x = -b/2a
Now we need to find the y-value of the vertex.
To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:
k = y = a*(-b/2a)^2 + b*(-b/2a) + c
k = b^2/(4*a) - b^2/2a + c
Then the coordinates of the vertex are:
(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)
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You have $28, and you want to get half-dollar coins from the bank to give to children who
come into your store. What is the most you can get?
Answer:
56 half dollars
Step-by-step explanation:
A half dollar is 1/2 of a dollar so divide 28 by 1/2
28 / 1/2
Copy dot flip
28 * 2/1
56
56 half dollars
What is 9,000,000 + 8,000 + 90,000,000 + 100 + 2 + 90,000 + 90 in standard form?
Answer:
i thank its 4000
Step-by-step explanation:
please mark this answer as brainlist
what is the main protein of a scientific investigation A. To form an opinion B. to test a hypothesis C. To persuade a bias D. To teach a lesson
Answer:
D.To teach a lesson
Step-by-step explanation:
Hope it helps you
I add 7 to a certain number. I double the result. My final answer is 34. What was my number?
Answer:
answer is 10
explanation
when u add 7 with 10 u get 17 then double of 17 is 34
I hope It helps
It is found that the unknown number was 10.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables. The addition is one of the mathematical operations. then the addition of two numbers results in the total amount of the combined value.
Given that "I add 7 to a certain number. I double the result. My final answer is 34".
Let consider the number be 10.
When we add 7 with 10 we get;
7 + 10 = 17
then double the result of 17 = 34
Hence, the unknown number was 10.
Learn more about equations here;
https://brainly.com/question/25180086
#SPJ2
Help!!! QUICK! What is the pattern of the exponents on the a terms in Pascal's Triangle?
A. The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values then decrease from left to right.
B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.
C. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values are then equal to 0 throughout the expansion.
D.The largest exponent value of the a terms is equal to one more than the value of the exponent on the binomial. The exponent values are then equal to 1 throughout the expansion.
Answer:
B. The largest exponent value of the a terms is equal to the value of the exponent on the binomial. The exponent values then decrease from left to right.
Step-by-step explanation:
The exponent values of the a terms increase from one side of the binomial to the other. The value of the largest exponent is equal to part of the binomial expression.
Find the counterclockwise circulation and outward flux of the field F=7xyi+5y^2j around and over the boundary of the region C enclosed by the curves y=x^2 and y=x in the first quadrant.
Split up the boundary of C (which I denote ∂C throughout) into the parabolic segment from (1, 1) to (0, 0) (the part corresponding to y = x ²), and the line segment from (1, 1) to (0, 0) (the part of ∂C on the line y = x).
Parameterize these pieces respectively by
r(t) = x(t) i + y(t) j = t i + t ² j
and
s(t) = x(t) i + y(t) j = (1 - t ) i + (1 - t ) j
both with 0 ≤ t ≤ 1.
The circulation of F around ∂C is given by the line integral with respect to arc length,
[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf T \,\mathrm ds[/tex]
where T denotes the tangent vector to ∂C. Split up the integral over each piece of ∂C :
• on the parabolic segment, we have
T = dr/dt = i + 2t j
• on the line segment,
T = ds/dt = -i - j
Then the circulation is
[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf T\,\mathrm ds = \int_0^1 (7t^3\,\mathbf i+5t^4\,\mathbf j)\cdot(\mathbf i+2t\,\mathbf j)\,\mathrm dt + \int_0^1 (7(1-t)^2\,\mathbf i+5(1-t)^2\,\mathbf j)\cdot(-\mathbf i-\mathbf j)\,\mathrm dt \\\\ = \int_0^1 (7t^3+10t^5)\,\mathrm dt - 12 \int_0^1 (1-t)^2\,\mathrm dt =\boxed{-\frac7{12}}[/tex]
Alternatively, we can use Green's theorem to compute the circulation, as
[tex]\displaystyle\int_{\partial C}\mathbf F\cdot\mathbf T\,\mathrm ds = \iint_C\frac{\partial(5y^2)}{\partial x} - \frac{\partial(7xy)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = -7\int_0^1\int_{x^2}^x x\,\mathrm dx \\\\ = -7\int_0^1 xy\bigg|_{y=x^2}^{y=x}\,\mathrm dx \\\\ =-7\int_0^1(x^2-x^3)\,\mathrm dx = -\frac7{12}[/tex]
The flux of F across ∂C is
[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf N \,\mathrm ds[/tex]
where N is the normal vector to ∂C. While T = x'(t) i + y'(t) j, the normal vector is N = y'(t) i - x'(t) j.
• on the parabolic segment,
N = 2t i - j
• on the line segment,
N = - i + j
So the flux is
[tex]\displaystyle \int_{\partial C}\mathbf F\cdot\mathbf N\,\mathrm ds = \int_0^1 (7t^3\,\mathbf i+5t^4\,\mathbf j)\cdot(2t\,\mathbf i-\mathbf j)\,\mathrm dt + \int_0^1 (7(1-t)^2\,\mathbf i+5(1-t)^2\,\mathbf j)\cdot(-\mathbf i+\mathbf j)\,\mathrm dt \\\\ = \int_0^1 (14t^4-5t^4)\,\mathrm dt - 2 \int_0^1 (1-t)^2\,\mathrm dt =\boxed{\frac{17}{15}}[/tex]
