A horizontal spring attached to a wall has a force constant of 850 N/m. A block of mass 1.00 kg is attached to the spring and oscillates freely on a horizontal, frictionless surface as in Active Figure 5.20. The initial goal of this problem is to find the velocity at the equilibrium point after the block is released. (a) What objects constitute the system, and through what forces do they interact? (b) What are the two points of interest? (c) Find the energy stored in the spring when the mass is stretched 6.00 cm from equilibrium and again when the mass passes through equilibrium after being released from rest. (d) Write the conservation of energy equation for this situation and solve it for the speed of the mass as it passes equilibrium. Substitute to obtain a numerical value. (e) What is the speed at the halfway point? Why isn’t it half the speed at equilibrium

Answer:

B,C,D

Explanation:

Ap3X

Answer: [tex]0.00680\ m^3[/tex]

Explanation:

Given

The weight of the object, when submerged in the water is [tex]980\ N[/tex]

When it is submerged in the bromine liquid, it weighs [tex]840\ N[/tex]

Suppose,

[tex]\rho=\text{Density of object}\\\rho_w=\text{Density of water}\\\rho_b=\text{Density of bromine}\\V=\text{Volume of the object}[/tex]

for water,

[tex]\Rightarrow V(\rho -\rho_w)g=980\quad \ldots(i)[/tex]

For bromine

[tex]\Rightarrow V(\rho-\rho_b)g=840\quad \ldots(ii)[/tex]

Divide (i) and (ii)

[tex]\Rightarrow \dfrac{\rho-1000}{\rho-3100}=\dfrac{980}{840}\\\\\Rightarrow 840\rho -840\times 1000=980\rho-980\times 3100\\\\\Rightarrow 140\rho=(3038-840)\cdot 1000\\\\\Rightarrow \rho=15,700\ kg/m^3[/tex]

Put the density value in equation (i)

[tex]\Rightarrow V(15,700-1000)\cdot 9.8=980\\\\\Rightarrow V=\dfrac{100}{14,700}\\\\\Rightarrow V=0.00680\ m^3[/tex]

Answer:

105.1N

Explanation:

According to the newton second law

[tex]\sum F_x = ma_x\\F_m - F_f = ma_x\\[/tex]

Since the acceleration is zero, then;

[tex]F_m - F_f = 0\\Fm = F_f\\[/tex]

Since;

[tex]F_m = mg sin \theta, \ hence \ F_f = mg sin \theta[/tex]

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

[tex]F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\[/tex]

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

Answer:

because of moon  

Explanation:

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

[tex]v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s[/tex]

Therefore, the velocity of the mass is 8.44 m/s

Answer:

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Answer: [tex]1.67\ V[/tex]

Explanation:

Given

Work function [tex]\phi =1.17\ eV[/tex]

The wavelength of the light is [tex]\lambda =437\ nm[/tex]

Energy associated with this wavelength is

[tex]E=\dfrac{hc}{\lambda}\\\\\Rightarrow E=\dfrac{1.99\times 10^{-25}}{437\times 10^{-9}}\\\\\Rightarrow E=4.553\times 10^{-19}\ J\\\\\Rightarrow E=2.841\ eV[/tex]

Stopping potential is

[tex]V=\dfrac{E-\phi }{e}\\\\\Rightarrow V=\dfrac{\left(2.841-1.17\right)e}{e}\\\\\Rightarrow V=1.67\ V[/tex]

Answer:

B. Frequency

Explanation:

Answer:

Explanation:

A wave is a disturbance or oscillation that passes through spatial time and is followed by a transfer of energy. For transverse waves, the propagation direction is perpendicular to the oscillation direction. A wave moves energy rather than moving mass within the direction of propagation.

From the given information;

The direction = [tex]E^{\to}\times B^{\to}[/tex]

This implies that:  [tex]\hat i \times (-j)[/tex]

[tex]\implies - \hat k[/tex]

In the [tex]-z[/tex] direction

The resistance force of the water exerted on the whale is 19305 Newton.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Power = 150 kW = 150,000 Watt.

Constant speed = 7.77 m/s.

Now, Power = the resistance force × speed

150000 Watt =  the resistance force × 7.77 m/s

Hence, the resistance force = 150000 Watt/ 7.77 m/s

= 19305 Newton.

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Answer:

Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.

Explanation:

Answer:

When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy.

Answer:

2 m/s²

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 12 m/s

Time (t) = 6 s

Acceleration (a) =?

The acceleration of the player can be obtained as follow:

v = u + at

12 = 0 + (a × 6)

12 = 6a

Divide both side by 6

a = 12 / 6

a = 2 m/s²

Thus, the acceleration of the player is 2 m/s²

Answer:

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Answer:

E = 1.45 x 10⁹ J = 1.45 GJ

Explanation:

According to the law of conservation of energy:

Potential Energy Lost by Satellite = Kinetic Energy + Internal Energy

[tex]mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2[/tex]

where,

E = Internal Energy = ?

m = mass = 400 kg

g = acceleration due to gravity = 9.81 m/s²

h = height = 500 km = 500000 m

v = speed on ground = 1.6 km/s = 1600 m/s

Therefore,

[tex]E = (400\ kg)(9.81\ m/s^2)(500000\ m)-\frac{1}{2} (400\ kg)(1600\ m/s)^2\\E = 1.962\ x\ 10^9\ J - 0.512\ x\ 10^9\ J[/tex]

E = 1.45 x 10⁹ J = 1.45 GJ

Answer:

Y = V / f      where Y equals wavelength

4 Y1 = V / f1       for a closed pipe the wavelength is 1/4 the length of the pipe

2 Y2 = V / f2   for the open pipe the wavelength is 1/2 the length of the pipe

Y1 / Y2 = 2 = f2 / f1      dividing equations

f2 = 2 f1  

the new fundamental frequency is 2 * 130.8 = 261.6

(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.

The new fundamental frequency of the tube will be 261.6 Hz. Frequency is also the inverse of the time period.

Frequency is defined as the number of cycles per second. The time to make one complete cycle is frequency. The unit for frequency is Hertz.

The relation between the wavelength, speed, and the frequency is found as;

[tex]\lambda = \frac{v}{f}[/tex]

The fundamental frequency is,[tex]\rm f_1 = 261.6 \ Hz[/tex]

For the given condition the wavelength for the  closed pipe will be ;

[tex]\rm \lambda_1 = \frac{v}{f_1} \\\\ \rm \frac{1}{4}L = \frac{v}{f_1} \\\\[/tex]

For the given condition the wavelength for the open pipe will be ;

[tex]\rm \lambda_2= \frac{v}{f_2} \\\\ \rm \frac{1}{2}L = \frac{v}{f_2}[/tex]

Divide the wavelength of both cases;

[tex]\rm \frac{\lambda_2}{\lambda_1} =\frac{f_2}{f_1} \\\\ f_2=2f_1 \\\\ f_2 = 2 \times 13.08 \ Hz \\\\ f_2 = 261.6 Hz.[/tex]

Hence the new fundamental frequency of the tube will be 261.6 Hz.

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Explanation:

when soil builds up over time in the location

Answer:

a)  B = 0.9375 T  -z, b)      B = 1.54 T

Explication

a) The magnetic force is

         F = q v x B

         f = q v B sin θ

bold indicates vectors

For direction let's use the right hand rule.

If the charge is positive

the flea in the direction of velocity, toward + x

the fingers extended in the direction of B

the palm the direction of the force + and

therefore the magnetic field goes in the direction of -z

           F = q v B

           2.25 10-16 = 1.6 10-19  1.50 103 B

           B = 2.25 10-16 / 2.4 10-16

           B = 0.9375 T  -z

b) now an electron

thumb speed direction, -z

opposite side of palm force + y

therefore the direction of the magnetic field is + x

            B = F / qv

            B = 8.5 10-16 / 1.16 10-19 4.75 103

             B = 1.54 T

Explanation:

Let omega = angular velocity (in rad/s). Then

omega = (# of oscillations)/(6 s)

= (30 osc)/(6 s) = 5 osc/s

We need to convert this to rad/s:

omega = (5 osc/s)(2π rad/osc)

= 10π rad/s

= 31.4 rad/s

Answer:

3.46 A

Explanation:

electrical power = current × voltage

P = I × V

We have,

V = 7.8

P = 27

Thus, I  = P ÷ V

I = 27 / 7.8

= 3.46 A

Answer:

Explanation:

Density = Mass / Volume = 850 / 40*10*5 = 0.425 g /cm^3

Answer:

49 kg is the mass of the couch.

Explanation:

GPE = mgh

9800 = m * 10 * 20

9800 = 200m

m = (9800/20) = 49 m

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Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

[tex]K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\[/tex]

the final kinetic energy of the package;

[tex]K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J[/tex]

the fraction of the initial energy lost;

[tex]= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71[/tex]

Answer:

Step 1: A Bill Is Born

Anyone may draft a bill; however, only members of Congress can introduce legislation, and, by doing so, become the sponsor(s). The president, a member of the cabinet or the head of a federal agency can also propose legislation, although a member of Congress must introduce it.

Step 2: Committee Action

As soon as a bill is introduced, it is referred to a committee. At this point the bill is examined carefully and its chances for passage are first determined. If the committee does not act on a bill, the bill is effectively "dead."

Step 3: Subcommittee Review

Often, bills are referred to a subcommittee for study and hearings. Hearings provide the opportunity to put on the record the views of the executive branch, experts, other public officials and supporters, and opponents of the legislation.

Step 4: Mark up

When the hearings are completed, the subcommittee may meet to "mark up" the bill; that is, make changes and amendments prior to recommending the bill to the full committee. If a subcommittee votes not to report legislation to the full committee, the bill dies. If the committee votes for the bill, it is sent to the floor.

Step 5: Committee Action to Report a Bill

After receiving a subcommittee's report on a bill the full committee votes on its recommendation to the House or Senate. This procedure is called "ordering a bill reported."

Step 6: Voting

After the debate and the approval of any amendments, the bill is passed or defeated by the members voting.

Step 7: Referral to Other Chamber

When the House or Senate passes a bill, it is referred to the other chamber, where it usually follows the same route through committee and floor action. This chamber may approve the bill as received, reject it, ignore it, or change it.

Step 8: Conference Committee Action

When the actions of the other chamber significantly alter the bill, a conference committee is formed to reconcile the differences between the House and Senate versions. If the conferees are unable to reach agreement, the legislation dies. If agreement is reached, a conference report is prepared describing the committee members' recommendations for changes. Both the House and Senate must approve the conference report

Step 9: Final Action

After both the House and Senate have approved a bill in identical form, it is sent to the president. If the president approves of the legislation, he signs it and it becomes law. Or, if the president takes no action for ten days, while Congress is in session, it automatically becomes law.If the president opposes the bill he can veto it; or if he takes no action after the Congress has adjourned its second session, it is a "pocket veto" and the legislation dies.

Step 10: Overriding a Veto

If the president vetoes a bill, Congress may attempt to "override the veto." If both the Senate and the House pass the bill by a two-thirds majority, the president's veto is overruled and the bill becomes a law.

Explanation:

good luck!

Answer:

    vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = [tex]\sqrt{\frac{2GM}{R} }[/tex]

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( [tex]1+ \frac{\Delta M}{M}[/tex] )

            R ’= R + ΔR = R ( [tex]1 + \frac{\Delta R}{R}[/tex] )

we substitute

           vₐ = [tex]\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }[/tex]

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( [tex](1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )[/tex])

we make the product and keep the terms linear

        vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

The minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    [tex]E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}[/tex]

final point. At a very distant point

      [tex]E_{mf} = U = \dfrac{- G Mm }{ R_2}[/tex]

energy is conserved

         [tex]E{mo} = E{mf}[/tex]

          [tex]\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}[/tex]

[tex]v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})[/tex]

if we consider the speed so that it reaches an infinite position R₂ = ∞

[tex]v_c = \sqrt{\dfrac{2GM}{R}[/tex]

now indicates that the mass and radius of the planet changes slightly

[tex]M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})[/tex]  

[tex]R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )[/tex]

we substitute

   [tex]vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}[/tex]

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      [tex]v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})[/tex]

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

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Answer:

The answer is 420kgm/s

Explanation:

momentum = mass×velocity

= 12kg×35m/s

=420kgm/s

Answer:

ligma

Explanation:

Well, it's surely not conclusion.