A football team has a probability of 0.76 of winning when playing any of the other four teams in its conference. If the games are independent, what is the probability the team wins all its conference games

Answer:

Ask in English then I can help u

Answer:

undefined, invalid

and for a limit expression like a/x, x->0 we also say this is infinite.

Answer:

C

Step-by-step explanation:

Since the triangles are similar, the scale factor is 100/5=20. So L/15=20, L=300

Answer:

the number is 788......

first invert fraction of the slope from 4/1 to 1/4 and switch sign. then figure out the y-intercept

the algebraic approach would work like this:

-4x + 10 = 1/4x + b

plug in what you got, here: the intersection information

-4*(4) + 10 = 1/4*(4) + b

-16 + 10 = 1 + b

-6 = 1 + b

-7 = b

Answer:

12x - 28° = 116°

7x + 32° = 116°

Step-by-step explanation:

12x - 28° and 7x + 32° are vertical angles. Vertical angles are congruent.

Therefore, to find the measure of each angle, we have to set each equation equal to each other as follows:

12x - 28° = 7x + 32°

Collect like terms

12x - 7x = 28 + 32

5x = 60

Divide both sides by 5

5x/5 = 60/5

x = 12

✔️12x - 28°

Plug in the value of x

12(12) - 28

= 144 - 28

= 116°

✔️7x + 32°

7(12) + 32

= 84 + 32

= 116°

Answer:

m= 11/5 (11 over 5)

Hope this helps! :)

First let's compute dx/dt

[tex]x = t - \frac{1}{t}\\\\x = t - t^{-1}\\\\\frac{dx}{dt} = \frac{d}{dt}\left(t - t^{-1}\right)\\\\\frac{dx}{dt} = 1-(-1)t^{-2}\\\\\frac{dx}{dt} = 1+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2}{t^{2}}+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2+1}{t^{2}}\\\\[/tex]

Now compute dy/dt

[tex]y = 2t + \frac{1}{t}\\\\y = 2t + t^{-1}\\\\\frac{dy}{dt} = \frac{d}{dt}\left(2t + t^{-1}\right)\\\\\frac{dy}{dt} = 2 - t^{-2}\\\\\frac{dy}{dt} = 2 - \frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2}{t^2}-\frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2-1}{t^2}\\\\[/tex]

From here, apply the chain rule to say

[tex]\frac{dy}{dx} = \frac{dy*dt}{dx*dt}\\\\\frac{dy}{dx} = \frac{dy}{dt} \times \frac{dt}{dx}\\\\\frac{dy}{dx} = \frac{dy}{dt} \div \frac{dx}{dt}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \div \frac{t^2+1}{t^{2}}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \times \frac{t^{2}}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\[/tex]

We could use polynomial long division, or we could add 2 and subtract 2 from the numerator and do a bit of algebra like so

[tex]\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1+2-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{(2t^2+2)-1-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)-3}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)}{t^2+1}-\frac{3}{t^2+1}\\\\\frac{dy}{dx} = 2-\frac{3}{t^2+1}\\\\[/tex]

This concludes the first part of 4b

=======================================================

Now onto the second part.

Since t is nonzero, this means either t > 0 or t < 0.

If t > 0, then,

[tex]t > 0\\\\t^2 > 0\\\\t^2+1 > 1\\\\\frac{1}{t^2+1} < 1 \ \text{ ... inequality sign flip}\\\\\frac{3}{t^2+1} < 3\\\\-\frac{3}{t^2+1} > -3 \ \text{ ... inequality sign flip}\\\\-\frac{3}{t^2+1}+2 > -3 + 2\\\\2-\frac{3}{t^2+1} > -1\\\\-1 < 2-\frac{3}{t^2+1}\\\\-1 < \frac{dy}{dx}\\\\[/tex]

note the inequality signs flipping when we apply the reciprocal to both sides, and when we multiply both sides by a negative value.

You should find that the same conclusion happens when we consider t < 0. Why? Because t < 0 becomes t^2 > 0 after we square both sides. The steps are the same as shown above.

So both t > 0 and t < 0 lead to [tex]-1 < \frac{dy}{dx}[/tex]

We can say that -1 is the lower bound of dy/dx. It never reaches -1 itself because t = 0 is not allowed.

We could say that

[tex]\displaystyle \lim_{t\to0}\left(2-\frac{3}{t^2+1}\right)=-1\\\\[/tex]

---------------------------------------

To establish the upper bound, we consider what happens when t approaches either infinity.

If t approaches positive infinity, then,

[tex]\displaystyle L = \lim_{t\to\infty}\left(2-\frac{3}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2t^2-1}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2-\frac{1}{t^2}}{1+\frac{1}{t^2}}\right)\\\\\\\displaystyle L = \frac{2-0}{1+0}\\\\\\\displaystyle L = 2\\\\[/tex]

As t approaches infinity, the dy/dx value approaches L = 2 from below.

The same applies when t approaches negative infinity.

So we see that [tex]\frac{dy}{dx} < 2[/tex]

---------------------------------------

Since [tex]-1 < \frac{dy}{dx} \text{ and } \frac{dy}{dx} < 2[/tex], those two inequalities combine into the compound inequality [tex]-1 < \frac{dy}{dx} < 2[/tex]

So dy/dx is bounded between -1 and 2, exclusive of either endpoint.

Step-by-step explanation:

we don't see the parallelogram nor any description of it.

so, it is impossible to tell you the right answer.

as I only answer questions by don't ask any, I don't know how you can add a picture.

9514 1404 393

Answer:

Step-by-step explanation:

  5(x-8)^2=y-12 . . . . given

  y = 5(x -8)^2 +12 . . . . add 12

Comparing to the required form, we see that ...

Answer: 9 miles I think but I dont know where her house is exactly.

Answer:

84.7

Step-by-step explanation:

of is another way to say multiply so what your doing is muliplying all the numbers

Answer:

84.7

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Answer:

y = 9√3

x = 18

Step-by-step explanation:

taking 30 as reference angle

b = y

p = 9

h = x

so

tan30 = p/b

1/√3 = 9/b

or, b = 9√3

so

[tex]h^2 = p^2 + b^2\\x^2 = 9^2 + y^2\\or, x^2 = 81 + (9\sqrt{3} )^2\\or, x^2 = 81 + 243\\or, x ^2 = 324\\or, x =\sqrt{324} \\\\so x = 18[/tex]

Step-by-step explanation:

if that is truly the full problem description, then we have

10x - x + 5 = 41

=>

9x = 36

our simply

x = 4

so, I am not sure, what your teacher wants to see as result.

there is an infinite number of equations I could find, all with the solution x = 4.

Answer:

A. 1 + 3x = -89

B. x = -30

Step-by-step explanation:

Let the unknown variable be x.

A. Translating the word problem into an algebraic expression, we have;

1 + 3x = -89

B. To solve for the unknown variable;

1 + 3x = -89

3x = -89 -1

3x = -90

x = -90/3

x = -30

Check:

1 + 3x = -89

Substituting the value of x;

1 + 3(-30) = -89

1 + (-90) = -89

1 - 90 = -89

-89 = -89

y=x²-10x-7

a>0 so we will be looking for minimum

x=-b/2a=10/2=5

y=25-50-7=-32

Answer: (5;32)

y=-4x²-8x+1

а<0 so we will be looking for maximum

х=-b/2a=8/-8=-1

у=4+8+1=13

Maximum point (-1;13)

Answer:

Y =-4X +21

Step-by-step explanation:

x1 y1  x2 y2

4 5  3 9

(Y2-Y1) (9)-(5)=   4  ΔY 4

(X2-X1) (3)-(4)=    -1  ΔX -1

slope= -4          

B= 21          

Y =-4X +21    

Step-by-step explanation:

the guys is wrong i checked

Answer:

$30.1 million * .000000038

$1.14

did the question say how much the ticket cost?

if it was $1 then you would have to subtract $1 so the expected value would be 14 cents

Step-by-step explanation:

Step-by-step explanation:

here's the answer to your question

Answer:

1a 300

b 180

c 330

d 1470

e 180

f 7344

Step-by-step explanation:

Answer:

‼️D) To the right‼️

Explanation

There is an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

Answer:

The average speed of the 747 was of 600 miles per hour.

Step-by-step explanation:

A small airplane flies 750 miles with an average speed of 250 miles per hour.

Velocity is distance divided by time, and here, we find the time of the small airplane. So

[tex]v = \frac{d}{t}[/tex]

[tex]250 = \frac{750}{t}[/tex]

[tex]250t = 750[/tex]

[tex]t = \frac{750}{250}[/tex]

[tex]t = 3[/tex]

1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;

This means that it traveled 750 miles in 3 - 1.75 = 1.25 hours.

What was the average speed of the 747?

[tex]v = \frac{d}{t} = \frac{750}{1.25} = 600[/tex]

The average speed of the 747 was of 600 miles per hour.

Answer:

y = -1/2x -7

Step-by-step explanation:

3x + 6y = -42

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Subtract 3x from each side

3x-3x+6y = -3x-42

6y = -3x-42

Divide each side by 6

6y/6 = -3x/6 - 42/6

y = -1/2x -7

5x - 2 = 4 + 2x

3x - 2 = 4

3x = 6

x = 2

Hope this helps!

Answer:

[tex](y - 0) = \frac{1}{3} (x - 0)[/tex]

[tex]y = \frac{1}{3} x[/tex]

Answer:

cos C = 12/13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

Cos theta = adj/ hyp

cos C = 36/39

Dividing the top and bottom by 3

cos C = 12/13

CosØ=Base/Hypotenuse

Answer:

Answer is D.

Step-by-step explanation:

Let the inverse be m:

[tex]{ \sf{m = \sqrt{x} - 8 }} \\ { \sf{m + 8 = \sqrt{x} }} \\ { \sf{x = {(m + 8)}^{2} }} \\ { \bf{f {}^{ - 1} (x) = {(x + 8)}^{2} }}[/tex]

Domain:

[tex]{ \sf{x \geqslant - 8}}[/tex]

Answer:

Could you add a picture or answer choices so we know what to choose from?