Answer:
t = 9.25 s
Explanation:
Given that,
Initial angular velocity, [tex]\omega_o=0[/tex] (at rest)
Final angular velocity, [tex]\omega_o=0.25\ rad/s[/tex]
Angular acceleration, [tex]\alpha =0.027\ rad/s^2[/tex]
We need to find the time it take the wheel to come up to operating speed. We know that the angular acceleration in terms of angular speed is given by :
[tex]\alpha =\dfrac{\omega_f-\omega_o}{t}\\\\t=\dfrac{\omega_f-\omega_o}{\alpha }\\\\t=\dfrac{0.25-0}{0.027}\\\\t=9.25\ s[/tex]
So, it will reach up to the operating speed in 9.25 s.
Thomson effect is the combined effect of Seebeck effect
and Peltier effect. Justify your answer.plz help me
Answer:
its c
Explanation:
Is the electric field produced only by charges within the slab, or is the field also due to charges outside the slab? How can you tell?
Answer:
hello your question is incomplete attached below is the missing figure of the question
Answer: The field is due to the charges outside the slab
Explanation:
The Electric field produced is due to the charges outside of the slab and this is due to the fact that the Electric field inside the slab will always be zero
as seen in the fig attached ; given x = 0 , Ex = 125 N/C
If an object that is dropped from the roof of a building takes 12 seconds to hit the ground, how
tall is the building?
Answer:
The height of the building is 705.6 m
Explanation:
Given that,
When an object is dropped from the roof of a building, it takes 12 seconds to hits the ground.
We need to find the height of the building. Let it is h. Initially, the object was at rest. Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
Here, a = g and u = 0
[tex]h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times (12)^2\\\\h=705.6\ m[/tex]
So, the building is 705.6 m tall.
A 25.0-g object moving to the right at 20.0 cm/s overtakes and collides elastically with a 10.0-g object moving in the same direction at 15.0 cm/s. Find the velocity of each object after the collision.
Answer:
v₁ = 17.1 cm/s
v₂ = 22.1 cm/s
Explanation:
From the principle of linear momentum, the momentum is conserved
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where m₁ = mass of first object = 25.0 g
u₁ = initial velocity of first object = 20 cm/s
m₂ = mass of second object = 10.0 g
u₂ = initial velocity of second object = 15.0 cm/s
v₁ = final velocity of first object
v₂ = final velocity of second object
25 * 20 + 10 * 15 = 25 * v₁ + 10 * v₂
650 = 25v₁ + 10v₂ ----(1)
Also in an elastic collision, Kinetic energy is conserved and sum of initial and final velocities is conserved
u₁ + v₁ = u₂ + v₂
20 + v₁ = 15 + v₂
v₂ = 5 + v₁
Substitute v₂ = 5 + v₁ in (1)
650 = 25v₁ + 10(5 + v₁)
90 = 25v₁ + 10v₁ + 50
35v₁ = 600
v₁ = 600/35
v₁ = 17.1 cm/s
Therefore, v₂ = 5 + 17.1 cm/s
v₂ = 22.1 cm/s
The motion with respect to the direction is called velocity. The change of velocity is known as acceleration.
According to the question. The value is as follows:-[tex]25 * 20 + 10 * 15 = 25 * v_{1} + 10 * v_{2}[/tex]
[tex]650 = 25v_{1} + 10v_{2} ----(1)[/tex]
Also in an elastic collision, Kinetic energy is conserved and the sum of initial and final velocities is conserved
[tex]u_{1} + v_{2} = u_{1} + v_{2}[/tex]
After putting the value:- [tex]20 + v_{1} = 15 + v_{2}[/tex]
Hence:- v₂ = 5 + v₁
After solving both the equation, the value of V will be
v₁ = [tex]\frac{600}{35}[/tex]
Hence the value of V is 17.1 cm/s
Therefore, v₂ = 5 + 17.1 cm/s
v₂ = 22.1 cm/s
For more information, refer to the link:-
https://brainly.com/question/13639113
sound intensity varies inversely as the square of the distance from the sound source. if you are in a movie theater and you change your seat to one that is eight times as far from the speakers, how does the new sound intensity compare with that of your original seat
Answer:
[tex]\dfrac{1}{64}[/tex] as loud.
Explanation:
The sound intensity varies inversely as the square of the distance from the sound source. Mathematically,
[tex]I=\dfrac{k}{d^2}[/tex]
You change your seat to one that is eight times as far from the speakers, d' = 8d.
New sound intensity is :
[tex]I'=\dfrac{k}{d'^2}\\\\I'=\dfrac{k}{(8d)^2}\\\\I'=\dfrac{1}{64}\times \dfrac{k}{d^2}\\\\I'=\dfrac{1}{64}\times I[/tex]
So, the new intensity is (1/64) times of the initial sound intensity.
A student walks from her car to a tree, 29 meters away at 1 m/s, and returns at 6 m/s. What is her average speed for the entire trip in m/s?
What Florida city is directly west of the Space Center
Answer:
Merritt Island i think
Compared with falling on a stone floor, a wine glass may not break when it falls on a carpeted floor because the
Answer: The question is incomplete, options are not given and here are the options from another website.
A. Carpeted floor provide small impulse.
B. stopping time is shorter on the carpet.
C. stopping time is longer on the carpet.
D. carpet provides a smaller impulse and a longer time.
The correct option is C.
A wine glass may not break when it falls on carpet floor because the stopping time on carpet floor is longer to that of stone floor.
Explanation:
A wine glass may not break when it falls on carpet floor because the stopping time on carpet floor is longer to that of stone floor because the change in glass momentum is the same for both stone and carpet flow, therefore the impulses that is supplied by both carpet and stone floor is the same. Therefore,there is longer stopping time by the carpet floor because there is smaller force that act on it compared to stone floor which lead to less damage.
What is the difference between nuclear fission and nuclear fusion? ?
A
Nuclear fusion explodes the nucleus of an atom, while nuclear fission harnesses
the atom's kinetic energy.
B
Nuclear fission splits an atom apart, while nuclear fusion fuses two atoms
together.
с
Nuclear fission creates electrical energy, while nuclear fusion creates chemical
energy.
D
Nuclear fusion splits hydrogen atoms apart, while nuclear fission fuses uranium
atoms together.
Answer: ITS B
Explanation:
BECAUSE I GOT IT WRONG AND IT WAS ACTUALLYT B F IN THE CHAT FOR ME
IF U GIVE ME HEART FOR HELPING THAT WOULD BE GREAT, THANKS......
Answer: The answer is B. Nuclear fission splits an atom apart, while nuclear fusion fuses two atoms together.
Explanation:
Check all the answers that apply. Energy is the ability to
A. Change temperature
B. Change speed
C. Do work
D. Change direction
Answer:
D. Do work
Explanation:
Answer:
c: do work and b: change speed
Explanation:
Which in NOT a type of muscle?
a
Smooth
b
Flat
c
Cardiac
d
Skeletal
Answer:
flat lol, that's the answer
Calculating Acceleration
A football player kicks a 0.94 kg football with a force of 2.4 N.
Calculate the acceleration of the football as the player kicks the ball. Round your answer to the nearest tenth of a m/s2.
Explanation:
[tex]a = \frac{force}{mass } = \frac{2.4}{0.94} = 2.5 \frac{m}{ {s}^{2} } [/tex]
Was it helpful?
Answer: 2.6 m/s²
Explanation: acceleration = f/m
Force = 2.4 N
Mass = 0.94 kg
Acceleration = ?
Acceleration = 2.4 N/0.94 kg = 2.5531914894 (or 2.6).
How to round it: round to the nearest tenth of a m/s²; look at the tenth place, which is 2.(5), it's greater than 5, so you wanna change it into a 6.
Hope this helped.
Have a good day. :)
4300 seconds is equal to:
a. 1 hour, 11 minutes, 40 seconds
b. 2 hours, 10 minutes, 0 seconds
c. 11 hours, 56 minutes, 40 seconds
d. 71 hours, 40 minutes, 0 seconds
Answer:
A
Explanation:
4300 ÷ 60 = 71.6666 minutes
60 mins = 1 hour
71.6666 - 60 = 11.6666
1 hour and 11 mins
Air at 20 Celsius and 483 kPa (70 psig) gauge expands to atmospheric pressure (79 kPa). If the process is isentropic, what is the final temperature in Celsius? Present answer using three significant digits.
Answer:
Explanation:
Process is isentropic that means the process is adiabatic .
[tex]PV^\gamma = constant \\P^{(1 -\gamma)}\times T^\gamma = constant[/tex]
[tex]\frac{T_1}{T_2} = \frac{ P_1 ^ {(\gamma-1) }}{P_2^{(\gamma-1 )}}[/tex]
For air
[tex]\gamma = 1.4[/tex]
[tex]\frac{293}{T_2} = \frac{ 483^ {(1.4-1) }}{79^{(1.4-1 )}}[/tex]
[tex]\frac{293}{T_2} = 2.06[/tex]
[tex]T_2 = 142 K[/tex]
= - 131 ⁰C .
When did Kentucky host its first national cluster meeting?
Answer:
1988
Explanation:
in Louisville
100 points!
Define density
What is the difference between weight and mass?
What is volume?
Answer:
volume is the amount of space occupied by matter
mass is the quantity of matter present in an object while weight is a measure of the pull of gravity on the object
Density is mass per unit volume
Explanation:
I hope I get brainliest
What is the force F on a 1 nC charge placed in the middle of a square with side 1 cm due to the charges of -2nC placed at the four square corners?
Answer:
The total force on the charge placed in the middle will be zero (0).
Explanation:
The force on the charge in the middle of a square due to one of the charges placed at the square corner is given by:
[tex] F = \frac{KQq_{1}}{d^{2}} [/tex]
Where:
Q: is the charge in the middle = 1 nC
[tex]q_{1} = q_{2} = q_{3} = q_{4}[/tex] are the charge placed at the 4 square corners = -2 nC
The distance between the charge Q and q₁, q₂, q₃, and q₄ is:
[tex] d = \frac{\sqrt{2a^{2}}}{2} = \frac{\sqrt{2(1 cm)^{2}}}{2} = 0.707 cm = 7.07 \cdot 10^{-3} m [/tex]
Now, the magnitude of the force is:
[tex] |F_{Qq_{1}}| = \frac{KQq_{1}}{d^{2}} = \frac{9\cdot 10^{9}*1 \cdot 10^{-9} C*2 \cdot 10^{-9} C}{(7.07 \cdot 10^{-3} m)^{2}} = 3.60 \cdot 10^{-4} N = |F_{Qq_{2}}| = |F_{Qq_{3}}| = |F_{Qq_{4}}| [/tex]
Since the magnitude of the force on the charge placed in the middle of the square is the same due to the 4 charges placed in the square corners (because the charge of q₁, q₂, q₃, and q₄ charges is the same) and due to the geometry, the vectorial sum of the total force on the charge placed in the middle will be zero (0).
Therefore, the total force on the charge placed in the middle will be zero (0).
I hope it helps you!
please help explain how to do this
Answer:
= 72640 [gramm]
Explanation:
Yes, in fact we are only going to use one conversion factor.
1 lb = 454 g
Therefore using the conversion factor we can find the value.
[tex]160lb*454\frac{gramm}{1lb}\\ = 72640 [gr][/tex]
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axis. Just before the collision, one ball, of mass , is moving upward at and the other ball, of mass , is moving downward at . How high do the combined two balls of putty rise above the collision point
Complete question is;
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axis. Just before the collision, one ball, of mass 3.0 kg, is moving upward at 20 m/s and the other ball, of mass 2.0 kg, is moving downward at 12 m/s. How high do the combined two balls of putty rise above the collision point? (Neglect air drag.)
Answer:
2.64 m
Explanation:
We are told the collision between the two balls is completely inelastic. This means that they will stick together after collision.
Since momentum is conserved and they stick together after collision, the formula for inelastic collision is;
m1•v1 + m2•v2 = (m1 + m2)v
Where v is the velocity after Collision.
We are given;
m1 = 3 kg
v1 = 20 m/s
m2 = 2 kg
v2 = -12 m/s (negative because it's moving downwards)
Thus, plugging into the equation, we have;
(3 × 20) + (2 × -12) = (3 + 2)v
60 - 24 = 5v
36 = 5v
v = 36/5
v = 7.2 m/s
To find the height that the combined two balls of putty rise above the collision point, we will use the formula;
v² = u² + 2gh
After the collision, initial velocity is the one they moved with after colliding. Thus, u = 7.2 m/s and final velocity is v = 0 m/s
Making h the subject and Plugging in relevant values, we have;
h = (v² - u²)/2g
Since gravity is acting in a direction opposite to the motion, then g = -9.81 m/s²
Thus;
h = (0² - 7.2²)/(2 × -9.81)
h = -51.84/-19.62
h = 2.64 m
A student is analyzing the forces on a 400 kg car driving at a constant velocity of 20 m/s. They draw the following diagram:
dawg im doin dat same quiz for ms matthews.
Explanation:
.
If the car is moving at a constant velocity, no force is acting on it therefore, there should be no arrows.
According to Newton's first law of motion which is also called the law of inertia, a body will remain at rest or in a state of uniform motion unless it is acted upon by a net force.
A car that is moving at constant velocity is in a state of uniform motion and this will not change unless the car is acted upon by a net force. No net force is acting on the car as long as it remains in a state of uniform motion hence the diagram is wrong. There should be no forward arrow in the diagram. The forces acting on the car are exactly balanced.
Learn more: https://brainly.com/question/461254
A 1391.3 kg car is traveling at 29.8 m/s when the driver takes his foot off the gas pedal. It takes 4.9 s for the car to slow down to 20 m/s. How large is the net force slowing the car
Answer:
Fnet = 2782.6 N
Explanation:
Newton's 2nd Law states that the net force applied to an object, is equal to its mass times the acceleration.By definition, acceleration is the rate of change of velocity with respect to time, as follows:[tex]a = \frac{\Delta v}{\Delta t}[/tex]
where Δv = vf - v₀ and Δt = tfi - t₀, replacing by the givens:
[tex]\Delta v = v_{f} - v_{o} = 20 m/s - 29.8 m/s = -9.8 m/s[/tex]
Δt = 4.9 s
⇒[tex]a = \frac{-9.8m/s}{4.9s} = -2 m/s2[/tex]
We can now apply Newton's 2nd Law, solving for Fnet, as follows:[tex]F_{net} = m* a = 1391.1 kg * (-2 m/s2) = -2782.6 N[/tex]
The magnitude of the is net force (How large it is ) is just:Fnet = 2782.6 NHow would you describe energy transfers
Answer:
Energy is transferred from one object to another when a reaction takes place.
Explanation:
Newton's law of restitution
Answer:
Explanation:
Newton's law of restitution states that when two bodies collide, the speed with which they move after the collision actually depends on the material from which they are made. The Coefficient of Restitution (e) tells us about the bounciness, or elasticity, of the collision.
A cyclist is riding a bike with an initial speed of 4 m/s and accelerates uniformly at 2 m second squared in the same direction of its motion along the street what is the speed of the cyclist after traveling 6 m ?
Answer:
6.32m/s
Explanation:
Given parameters:
Initial velocity = 4m/s
Acceleration = 2m/s²
Distance covered = 6m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we have to apply the appropriate motion equation;
V² = U² + 2aS
where V is final speed
U is the initial speed
a is the acceleration
S is the distance
Insert the given parameters and solve;
V² = 4² + 2 x 2 x 6
V² = 16 + 24
V² = 40
V = √40 = 6.32m/s
The compass of an airplane indicates that the airplane is heading north. The airplane is moving at an airspeed of 230 km/h. The wind is blowing east at 55 km/h.
1.What is the speed of the plane with respect to the ground?
2.How many degrees east of north is the plane’s velocity with respect to the ground?
Answer:
Explanation:
airspeed is speed with respect to air .
Let speed of airplane with respect to ground be V .
wind is blowing east at 55 km/h
airplane is heading north with speed V
Resultant of V and 55 km /h is 230 km/h
V² + 55² = 230²
V² = 52900 - 3025
V = 223.32 km/h
Let θ be the required angle
Tanθ = 55 / 223.32 = .246
θ = 14⁰ .
Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in series with an ideal 12-V battery and a 2.0-Ω resistor, what is the current through the 10.0-Ω resistor
Answer:Current across 10ohm, I =0.59 A
Explanation:
Total Resistance n parallel s given as
1/Rt = 1/R1 + 1/R2 + 1/R3
1/Rt = 1/4 + 1/6 + 1/10
1/Rt = 0.51666
Rt = 1/0.51666
Rt = 1.935 ohms
which is now connected In series with a ohm resstor
Rnet in series = R1+ R2
Rnet = 1.935 + 2.0 = 3.935 ohms
Since a voltage of 12 V s connected with the resistors in series, we have that the net current flowing across the 2ohm and 1.935ohm will be
Current, I = Voltage, V/ Resistance, R net
I= I2 / 3.935= 3.049 A
the Voltage across the 1.935 ohm resistance
V= 1R
3.049 X 1.935 = 5.899 Volts
remember that 1.935 ohm s the resultant resistance connected in parallel, therefore The voltage across the 1.935 ohm is same for the 10 ohm, 4ohm and 6ohm resistances
Therefore, the current passing through the 10ohm resistance will be
Current across 10ohm, I = V/R = 5.899/10 = 0.5899 Ampere ≈0.59 A
No one will help jshajajababbahsbananananananannaabaj
Answer:
i will help what do you need help with
elements in group 2 are all called alkaline earth metals what is most similar about the alkaline metals
Answer:
Explanation:The alkali metals are more similar to each other than the elements in any other group are to each other. Indeed, the similarity is so great that it is quite difficult to separate potassium, rubidium, and caesium, due to their similar ionic radii; lithium and sodium are more distinct.
Answer:
its B. which chemical properties they have
Explanation:
Just trust me
13. How much water will flow in one minute through 200mm of a tube 1.5mm in diameter if the pressure across the tube is 10 cmHg
Answer:
The volumetric flow rate is 0.00589 cm³ /s
Explanation:
Given;
length of the tube, L = 200 mm = 20 cm
diameter of the tube, 1.5 mm
radius of the tube, r = 0.75 mm = 0.075 cm
Area of the tube is given by;
A = πr²
A = π(0.075)² = 0.0177 cm²
Velocity of water through the tube is given is by;
v = L / t
v = 20 cm / 60 s
v = 0.333 cm / s
Volumetric flow rate of water is given by;
Q = Av
Q = (0.0177 cm²)(0.333 cm / s)
Q = 0.00589 cm³ /s
Therefore, the volumetric flow rate is 0.00589 cm³ /s
At its peak, a tornado is 73.0 m in diameter and carries 395-km/h winds. What is its angular velocity in revolutions per second
Answer:
The angular velocity of the tornado at its peak is 0.478 revolutions per second.
Explanation:
Let consider that tornado rotates at constant speed. From Rotation Physics we get the following relationship between linear ([tex]v[/tex]) and angular speeds ([tex]\omega[/tex]), measured in meter per second and radians per second, respectively.
[tex]\omega = \frac{v}{R}[/tex] (Eq. 1)
Where [tex]R[/tex] is the radius of the tornado, measured in meters.
If we know that [tex]v = 109.722\,\frac{m}{s}[/tex] and [tex]R = 36.5\,m[/tex], then the angular speed of the tornado at its peak is:
[tex]\omega = \frac{109.722\,\frac{m}{s} }{36.5\,m}[/tex]
[tex]\omega = 3.006\,\frac{rad}{s}[/tex] [tex]\left(0.478\,\frac{rev}{s} \right)[/tex]
The angular velocity of the tornado at its peak is 0.478 revolutions per second.
