A cube of ice is taken from the freezer at -5.5 ∘C and placed in a 75-g aluminum calorimeter filled with 300 g of water at room temperature of 20.0 ∘C. The final situation is observed to be all water at 17.0 ∘C. The specific heat of ice is 2100 J/kg⋅C∘, the specific heat of aluminum is 900 J/kg⋅C∘, the specific heat of water is is 4186 J/kg⋅C∘, the heat of fusion of water is 333 kJ/Kg.

What was the mass of the ice cube?Express your answer to two significant figures and include the appropriate units.

Answer:

a = - 3.75 m/s²

negative sign indicates deceleration here.

Explanation:

In order to find the constant deceleration of the car, as it stops, we will use the 3rd equation of motion. The 3rd equation of motion is as follows:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration of the car = ?

Vf = Final Velocity = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity = 30 m/s

s = distance covered by the car = 120 m

Therefore,

a = [(0 m/s)² - (30 m/s)²]/(2)(120 m)

a = - 3.75 m/s²

negative sign indicates deceleration here.

Answer:

The current flowing through the outer coils is  

Explanation:

From the question we are told that

   The number of turn of inner coil is [tex]N _i = 110 \ turns[/tex]

    The radius of inner coil is  [tex]r_i = 0.014 \ m[/tex]

     The current flowing through the inner coil is  [tex]I_i = 9.0 \ A[/tex]

     The number of turn of outer coil is [tex]N_o = 160 \ turns[/tex]

     The radius of outer  coil is [tex]r_o = 0.022\ m[/tex]

For net magnetic field at the common center of the two coils to be  zero  the current flowing in the outer coil must be opposite to current flowing inner coil

   The magnetic field due to inner coils  is mathematically represented as

            [tex]B_i = \frac{N_i \mu I}{2 r_i}[/tex]

     The magnetic field due to inner coils  is mathematically represented as

            [tex]B_o = \frac{N_o \mu I_o}{2 r_o}[/tex]

Now for magnetic field at center to be zero

             [tex]B_o = B_i[/tex]

So

         [tex]\frac{N_i \mu I_i}{2 r_i} = \frac{N_o \mu I_o}{2 r_o}[/tex]

=>      [tex]\frac{110 * 9}{2 * 0.014} = \frac{160 *I_o}{2 0.022}[/tex]

         [tex]I_o = 9.72 \ A[/tex]

Answer:

A) receding from the earth

B) [tex]3.078x10^6m/s[/tex]

Explanation:

The wavelength went from 434.1nm to 438.6nm, there was an increase in wavelength (also knowecn as redshift due to the doppler efft), this increase is due to the fact that the source that emits the radiation (the distant galaxy) is moving away and therefore the light waves it emits are "stretched", causing us to see a wavelength greater than the original.

to calculate the relative speed we use the following formula:

[tex]v_{rel}=c(1-\frac{\lambda_{1}}{\lambda_{2}} )[/tex]

where [tex]c[/tex] is the speed of light: [tex]c=3x10^8m/s[/tex]

[tex]\lambda_{1}[/tex] is the wavelength emited by the source, and

[tex]\lambda_{2}[/tex] is the wavelength measured on earth.

we substitute all the values and do the calculations:

[tex]v_{rel}=(3x10^8m/s)(1-\frac{434.1nm}{438.6nm} )\\\\v_{rel}=(3x10^8m/s)(1-0.98974)\\\\v_{rel}=(3x10^8m/s)(0.01026)\\\\v_{rel}=3.078x10^6m/s[/tex]

the relative speed is: [tex]3.078x10^6m/s[/tex]

Answer: current I = 1.875A

Explanation:

If the resistors are connected in series,

Then the equivalent resistance will be

R = 6 + 18 + 15 + 9

R = 48 ohms

Using ohms law

V = IR

Make current I the subject of formula

I = V/R

I = 90/48

I = 1.875A

And if the resistors are connected in parallel, the equivalent resistance will be

1/R = 1/6 + 1/18 + 1/15 + 1/9

1/R = 0.166 + 0.055 + 0.066 + 0.111

R = 1/0.3999

R = 2.5 ohms

Using ohms law

V = IR

I = 90/2.5

Current I = 35.99A

Answer:

right is the correct answer to the given question .

Explanation:

In this question figure is missing

The main objective right-hand rule to decide the position of the magnetic force on the positive force acting, either the position of the thumb of a right hand with in position of v, the fingers throughout the position of B1, and a right angles throughout the position of F1 to the hand positions.

So    [tex]F1 \ =\ q\ v \ B1\ Sin\alpha[/tex]

Answer:

Right

Explanation:

Just did this on edgen, in the diagram, the fingers are pointing to the right, which indicates that the magnetic field is acting to the right.

Answer:

C. Material B has a negative coefficient of expansion and A has a positive coefficient of expansion

Explanation:

If both material A and material B have the same coefficient of thermal expansion and they were heated to same temperature, both will expand making it impossible to remove the pin from the hole.

Also, if the coefficient of thermal expansion of any of the materials is higher than the other and they were subjected to the same temperature, the material with lower coefficient of thermal expansion will expand, making it impossible to remove the pin.

However, materials with negative coefficient of thermal expansion will contract on heating instead of expanding, while materials with positive  coefficient of expansion will expand on heating. This makes it possible to remove the pin from the hole in the block.

Answer:

The weight of the pole can be assumed to act at the pole's midpoint, which is 2m from the fence / pivot point, giving us a moment of 490Nm (245N x 2m).  We have to counteract this moment by holding the end of the pole.  So, we have a lever arm of 3.65m (4.0m - 0.35m), so we would need to exert a force of 134.4N (490N / 3.65m) at a point 35cm from the end of the pole.

Explanation:

happy to help:)

Answer: Planetary nebular is

A shell of gas ejected by and expanding away from an extremely hot dying high-mass star

An expanding atmosphere of a low-mass star as it becomes a red Giants.

Explanation:

Planetary nebular is a form of nebula emission that comprises an expanding and glowing shell of gas that is ejected from red giant stars.

Planetary nebulae play an important role in the chemical evolution of the Milky Way by expelling elements into the interstellar medium from stars where those elements were produced.

Answer:

(a) Area(small piston)/Area(large piston) = 0.037

(b) h = 1336.36 cm = 13.36 m

Explanation:

(a)

The stress on the smaller piston is equally transmitted to the larger piston, in a hydraulic lift. Therefore,

Stress (small piston) = Stress (large piston)

Force (small piston)/Area (small piston) = Force (Large Piston)/Area (Large Piston)

Area(small piston)/Area(large piston) = Force (small piston)/Force(Large piston)

Area(small piston)/Area(large piston) = 550 N/(1500 kg)(9.8 m/s²)

Area(small piston)/Area(large piston) = 0.037

(b)

The work is also transmitted equally to the large piston. So,

Work(small piston) = Work(Large Piston)

Force(small piston).Displacement(small piston) = Force(large piston).Displacement(small piston)

(550 N)(h) = (1500 kg)(9.8 m/s²)(50 cm)

h = 735000 N.cm/550 N

h = 1336.36 cm = 13.36 m

(a) The ratio of area smaller piston to area of larger piston is 0.037.

(b) The distance the smaller piston will be pushed down to lift the car at the given height is 13.36 m.

The given parameters;

let the area of the small piston = A₁

let the area of the large piston = A₂

Apply constant pressure principle as shown below;

[tex]P = \frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\\frac{A_1}{A_2} = \frac{A_{small}}{A_{large}} = \frac{F_1}{F_2} = \frac{550}{mg} \\\\ \frac{A_{small}}{A_{large}} = \frac{550}{1500 \times 9.8} \\\\ \frac{A_{small}}{A_{large}} = 0.037[/tex]

The distance the effort will be applied is calculated as follows;

[tex]550 d = mgh\\\\550d = (1500 \times 9.8 \times 0.5)\\\\550 d = 7350\\\\d = \frac{7350}{550} \\\\d = 13.36 \ m[/tex]

Thus, the distance the smaller piston will be pushed down to lift the car at the given height is 13.36 m.

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Answer:

F / g = 138 kg

Explanation:

For this exercise let's use Newton's second law

    F- W = m a

the force is equal to the back of the balance

in this case the acceleration is centripetal

    a = v² / r

we substitute

   F - m g = m v² / r

   F = m (g + v²/ r)

calculus

   F = 80 (9.8 + 11²/17)

   F = 1353 N

the balance reading is this value between gravity

   F / g = 1353 / 9.8

   F / g = 138 kg

I = MR^2

The Attempt at a Solution:::

I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2

I total = 3ML^2/2

It says the answer is 3ML^2/4 though.

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mark it as brainliest.... ✌✌✌

The rotational inertia about the left is [tex]3ML^{2} /2[/tex].

[tex]I = I1 + I2 + I3\\ I= 3M(0^{2}) + 2M(L/2 )^{2} + M(L)^{2} \\I = 3ML^{2} /2[/tex]

The rotational inertia about the left is [tex]3ML^{2} /2[/tex]

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Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

[tex]\theta=35^{\circ}[/tex]

a.Let [tex]v_0[/tex] be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

[tex]v_x=v_0cos\theta=v_0cos35[/tex]

[tex]v_y=v_0sin\theta=v_0sin35[/tex]

[tex]x=v_0cos\theta\times t=v_0cos35\times t[/tex]

[tex]t=\frac{30}{v_0cos35}[/tex]

[tex]h=v_yt-\frac{1}{2}gt^2[/tex]

Substitute the values

[tex]1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2[/tex]

[tex]1.8=30tan35-\frac{6574.6}{v^2_0}[/tex]

[tex]\frac{6574.6}{v^2_0}=21-1.8=19.2[/tex]

[tex]v^2_0=\frac{6574.6}{19.2}[/tex]

[tex]v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s[/tex]

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

[tex]t=\frac{30}{18.5cos35}[/tex]

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

Answer:

Explanation:

The resistance of a wire can be given by the following expression

[tex]R=\frac{\rho\times L}{A }[/tex]

where R is resistance , ρ is specific resistance , L is length of wire and A is cross sectional area

specific resistance of metals are almost the same . So in the present case ρ and l are same . Hence the formula becomes

R = k / A where k is a constant .

The diameter of wire becomes two times hence area of cross section becomes 4 times or 4A .

Resistance becomes 1/4 times . Hence if resistance of metal wire is R , resistance of silver wire will be R / 4 .

current = voltage / resistance

In case of metal wire

8 x 10⁻³ = V / R

In case of silver wire

I = V / (R / 4 ) , I is current , V is potential difference .

I = 4 x V/R

= 4 x 8 x 10⁻³ A

= 32 mA.

Answer:

a) [tex]\eta_{th} = 46.1\,\%[/tex], b) [tex]\eta_{th,real} = 36.667\,\%[/tex]

Explanation:

a) The maximum possible thermal efficiency of the power plant is given by the Carnot's Cycle thermal efficiency, which consider a reversible power cycle according to the Second Law of Thermodynamics, whose formula is:

[tex]\eta_{th} = \left(1-\frac{T_{L}}{T_{H}} \right)\times 100\,\%[/tex]

Where:

[tex]T_{L}[/tex] - Temperature of the cold reservoir (Condenser), measured in K.

[tex]T_{H}[/tex] - Temperature of the hot reservoir (Evaporator), measured in K.

The maximum possible thermal efficiency is:

[tex]\eta_{th} = \left(1-\frac{298.15\,K}{553.15\,K} \right)\times 100\,\%[/tex]

[tex]\eta_{th} = 46.1\,\%[/tex]

b) The actual efficiency of the plant is the ratio of net power to input heat rate expressed in percentage:

[tex]\eta_{th, real} = \frac{\dot W}{\dot Q_{in}} \times 100\,\%[/tex]

[tex]\eta_{th, real} = \frac{1100\,MW}{3000\,MW}\times 100\,\%[/tex]

[tex]\eta_{th,real} = 36.667\,\%[/tex]

As per the question the nuclear power plant generates about 3000 MW of energy form the reactors and is due to the core of the reactor. The high pressure stream is 280 a C is used for the turbine to make it spin.

Learn more about  the plant generates 3000 MW of heat energy.

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Answer:

Time according to earth clock (T0) = 0.22 years (Approx)

Explanation:

Given:

Time taken by light = 4.5 years

Time taken by ship = 5 years

Speed of light = c

Speed of ship (v) = 90% of c = 0.9c

Find:

Time according to earth clock (T0) = ?

Computation:

Time dilation is ,

[tex]T(Difference) = \frac{T0}{\sqrt{1-\frac{v^2}{c^2} } }\\\\ (5-4.5)= \frac{T0}{\sqrt{1-\frac{(0.9c)^2}{c^2} } }\\\\ 0.5=\frac{T0}{\sqrt{1-0.81} }\\\\T0 =0.2179[/tex]

Time according to earth clock (T0) = 0.22 years (Approx)

Answer:

The materials used to make electronic components like transistor and integrated, circuit behave as if effective particles known as electron through them, causing electrical properties

Answer:

???????

Explanation:

????????

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

ΔL = α L₀ ΔT

where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.

Answer:

Option D. is correct

Explanation:

Daniel Levinson, a psychologist developed an adult development theory. This theory was referred to as the Seasons of Life theory. This theory describes the stage in which a person leaves adolescence and start making choices about adult life.

Daniel Levinson found that men and women go through the same stages of development, differ in terms of their social roles and identities, and deal with the development tasks in each stage differently.

Option D. is correct

Answer:

Daniel Levinson found that men and women

d.  all of the above

Explanation:

cause i got a 100 on edg;)

Answer:

Δt = 0.315s

Explanation:

To calculate the time difference, in which both fans hear the batterstrike, you first calculate the time which takes the sound to travel the distances to both fans:

[tex]t_1=\frac{d_1}{v_s}[/tex]

[tex]t_2=\frac{d_2}{v_s}[/tex]

d1: distance to the first fan = 18.3 m

d2: distance to the second fan = 127 m

vs: speed of sound = 345 m/s

You replace the values of the parameters to calculate t1 and t2:

[tex]t_1=\frac{18.3m}{345m/s}=0.053s\\\\t_2=\frac{127m}{345m/s}=0.368s[/tex]

The difference in time will be:

[tex]\Delta t =t_2-t_2=0.368s-0.053s=0.315s[/tex]

Hence, the time difference between hearing the sound at the location s of both fans is 0.315s

Answer:

a) 3.632 m/s

b) 0.462 m/s

Explanation:

Using the law of conservation of momentum:

[tex]m_{1} u_{1} + m_{2} u_{2}= m_{1} V_{1} + m_{2} V_{2}[/tex]..........(1)

[tex]m_{1} = 0.30 kg\\u_{1} = 2.4 m/s\\m_{2} = 0.80 kg\\u_{2} = 0 m/s[/tex]

Substituting the above values into equation (1) and make V2 the subject of the formula:

[tex]0.3(2.4) + 0.80(0)= 0.3 V_{1} + 0.8 V_{2}\\[/tex]

[tex]V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}[/tex]..................(2)

Using the law of conservation of kinetic energy:

[tex]0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\[/tex]

[tex]2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}[/tex].......(3)

Substitute equation (2) into equation (3)

[tex]2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8}) ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2} }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s[/tex]

Substituting [tex]V_{1}[/tex] into equation(2)

[tex]V_{2} = \frac{0.72 - 0.3 *3.632}{0.8}\\V_{2} = \frac{0.72 - 0.3 *(3.632)}{0.8}\\V_{2} = 0.462 m/s[/tex]

Answer:

Explanation:

The parametric equations of the cyclist are:

[tex]x(t)=100tcos(A)\\\\y(t)=-16t^2+100tsin(A)+10[/tex]   (1)

A) The horizontal velocity is the derivative of x(t), in time:

[tex]x'(t)=100cos(A)[/tex]

B) For A=20° the horizontal velocity is:

[tex]v_x=x'(t)=100cos(20\°)=93.9692ft/s[/tex]

For A=45°:

[tex]v_x=100cos(45\°)=70.7106ft/s[/tex]

C) To find the time in which the vertical velocity is zero you first obtain the derivative of, in time:

[tex]v_y=y'(t)=-32t+100sin(A)+10[/tex]

Next, you equal the vertical velocity to zero and solve for time t:

[tex]-32t+100sin(A)+10=0\\\\t=\frac{100sin(A)+10}{32}[/tex]

D) The maximum height is reached when the derivative of y (height) is zero. You use the previous value of t in the equation (1), equals y to 35. Next, you  solve for t:

[tex]y=35\\\\-16(\frac{100sin(A)+10}{32})^2+100(\frac{10sin(A)+10}{32})sinA+10=35\\\\-\frac{16}{1024}(10000sin^2A+2000sinA+100)+31.25sin^2A+31.25sinA+10=35\\\\-156.25sin^2A-31.25sinA-1.5625+31.25sin^2A+31.25sinA+10=35\\\\-125sin^2A-26.5625=0[/tex]

Answer: false

Explanation:

The slope of a velocity–time graph is the acceleration.

Answer:

a. 4.21 moles

b. 478.6 m/s

c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank

Explanation:

Volume of container = 100.0 L

Temperature = 293 K

pressure = 1 atm = 1.01325 bar

number of moles n = ?

using the gas equation PV = nRT

n = PV/RT

R = 0.08206 L-atm-[tex]mol^{-1}[/tex][tex]K^{-1}[/tex]

Therefore,

n = (1.01325 x 100)/(0.08206 x 293)

n = 101.325/24.04 = 4.21 moles

The equation for root mean square velocity is

Vrms = [tex]\sqrt{\frac{3RT}{M} }[/tex]

R = 8.314 J/mol-K

where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

Vrms = [tex]\sqrt{\frac{3*8.314*293}{0.0319} }[/tex]= 478.6 m/s

For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship

[tex]\frac{Voxy}{Vnit}[/tex] = [tex]\sqrt{\frac{Mnit}{Moxy} }[/tex]

where

Voxy = root mean square velocity of oxygen = 478.6 m/s

Vnit = root mean square velocity of nitrogen = ?

Moxy = Molar mass of oxygen = 31.9 g/mol

Mnit = Molar mass of nitrogen = 14.00 g/mol

[tex]\frac{478.6}{Vnit}[/tex] = [tex]\sqrt{\frac{14.0}{31.9} }[/tex]

[tex]\frac{478.6}{Vnit}[/tex] = 0.66

Vnit = 0.66 x 478.6 = 315.876 m/s

the root mean square velocity of the oxygen gas is

478.6/315.876 = 1.5 times the root mean square velocity of the nitrogen gas outside the tank

Answer:

Explanation:

We know that, the force responsible for circulating in circular path is the centripetal force given by the force on charged particle due to magnetic field.

Here the charge is antiproton is

p = -1.6 * 10⁻¹⁹C

the speed of proton is given by 1.5 * 10 ⁴ m/s

the magnetic field is B = 4.5 * 10⁻³T

we have force due to magnetic field is equal to centripetal force

Bqv = mv² / r

Bq = mv / r

[tex]r = \frac{mv}{Bq} \\\\r=\frac{mv}{Bq} \\\\r=\frac{1.67 \times 10^-^2^7\times 1.5 \times 10^4}{4.5 \times 10^-^3\times 11.6\times 10^-^1^9} \\\\r=347.9\times 10^-^4\\\\r=3.479cm[/tex]

The diameter d of the vacuum chamber have to allow these antiprotons to circulate without touching the walls is

d = 2r

d = 2 * 3.479

d = 6.958

d ≅ 7cm

Answer:

The force at the brake pad = 250 N

Explanation:

The hydraulic brake system works on the Pascal's Principle for pressure transmission in fluids; the pressure applied to a fluid is transmitted undiminished in all directions.

For hydraulic systems, the pressure applied to the brake pedal is transmitted undiminished through the fluid filled tube, connected at each end to a piston, to the brake pad.

Hence, mathematically,

P(brake pedal) = P(break pad)

Pressure is given as the force applied divided by the cross sectional Area perpendicular to the direction of applied force.

P(brake pedal) = (Force applied on the brake pedal) ÷ (Cross Sectional Area of the brake pedal)

Force applied on the brake pedal = 50 N

Cross Sectional Area of the brake pedal = 3 cm²

P(brake pedal) = (50/3) = 16.67 N/cm²

P(brake pad) = P(brake pedal) = 16.67 N/cm²

P(brake pad) = (Force applied on the brake pad) ÷ (Cross Sectional Area of the brake pad)

Force applied on the brake pad = F = ?

Cross Sectional Area of the brake pad = 15 cm²

16.67 = (F/15)

F = 16.67 × 15 = 250 N

Hence, the force at the brake pad = 250 N

Hope this Helps!!!

Answer:

d

Explanation:

Randell uses a computer at a public library to view his bank account online represents one of the cases when a when person is vulnerable to identity theft, therefore the correct answer is option D.

Identity theft occurs when criminals steal your confidential info and use it to create fresh accounts, rent or purchase property, file false financial records, or carry out other illegal activities.

This implies that a thief may steal sensitive data such as names, birthdates, Social Security numbers, information from driver's licenses, residences, and credit card or bank account numbers.

Once they have this information, they may use it to buy goods, apply for credit and debit cards, or even utilize it to pay for medical care with the assistance of health coverage.

Thus,the correct answer is option D.

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