A card is drawn from a well shuffled deck of 52 cards what is the probability of drawing an ace or a six

Answers

Answer 1

Answer:

8/52

Step-by-step explanation:

The first thing to do is write it out;

How many aces are in a deck and how many sixes?

There are 4 of each so, 4+4 = 8 therefore our beginning ratio will be;

8/52 cards are going to be an ace or a six.


Related Questions

a string of length 60 cm is used to form two equal circles. what wil the total circumference of the two equal circles ?​

Answers

Answer:

Step-by-step explanation:

I don't know what other answer there could be but 60 cm. The circles have to have the same radius and the same circumference. They were made from a 60 cm string so their total must be 60 cm.

Is there a trick I don't see? Hope not?

The work shows how to use long division to find?

Answers

Answer:

remainder = [tex]\frac{1}{x-2}[/tex]

Step-by-step explanation:

The remainder is the value of the subtraction of the last 2 lines in the procedure.

  5x - 9

- (5x - 10)

That is

5x - 5x = 0 and - 9 - (- 10) = - 9 + 10 = 1

over the divisor x- 2 , gives

remainder = [tex]\frac{1}{x-2}[/tex]

What is the sum of the arithmetic sequence 3, 9, 15
if there are 34 terms?

Answers

Answer:  3468

===================================================

Work Shown:

a = first term = 3

d = common difference = 6

S(n) = sum of the first n terms of an arithmetic sequence

S(n) = (n/2)*(2a + d(n-1))

S(34) = (34/2)*(2*3 + 6(34-1))

S(34) = 3468

--------

Check:

3+9+15+21+27+33+39+45+51+57+63+69+75+81+87+93+99+105+111+117+123+129+135+141+147+153+159+165+171+177+183+189+195+201 = 3468

I used GeoGebra to generate the 34 terms shown above. You could do so by hand (start at 3; add 6 to each term to get the next one), but it's a tedious busywork type of problem in my opinion. It's best left to computer software.


Match each polynomial on the left with its two factors on the right.

Answers

Answer:

Hello

Step-by-step explanation:

[tex]Formula: \\\\\boxed{\Large a^3\pm b^3=(a \pm b)(a^2 \mp ab+b^2)}\\\\8x^3+1=(2x)^3+1^3=(2x+1)(4x^2-2x+1)\\\\8x^3-1=(2x)^3-1^3=(2x-1)(4x^2+2x+1)\\[/tex]

The factors of the expression 8x³ + 1 and 8x³ - 1³ will be (2x + 1) & (4x² – 2x + 1) and (2x – 1) & (4x² + 2x + 1), respectively.

What is a polynomial?

A polynomial expression is an algebraic expression with variables and coefficients. Unknown variables are what they're termed. We can use addition, subtraction, and other mathematical operations. However, a variable is not divisible.

The expression is given below.

8x³ + 1 and 8x³ - 1³

(2x)³ + 1³ and (2x)³ - 1³

We know that the formula is given as,

a³ + b³ = (a + b) (a² – ab + b²)

a³ – b³ = (a – b) (a² + ab + b²)

Then the expression is written as,

(2x)³ + 1³ = (2x + 1) [(2x)² – 2x + 1²]

(2x)³ + 1³ = (2x + 1) (4x² – 2x + 1)

(2x)³ – 1³ = (2x – 1) [(2x)² + 2x + 1²]

(2x)³ – 1³ = (2x – 1) (4x² + 2x + 1)

The factors of the expression 8x³ + 1 and 8x³ - 1³ will be (2x + 1) & (4x² – 2x + 1) and (2x – 1) & (4x² + 2x + 1), respectively.

More about the polynomial link is given below.

https://brainly.com/question/17822016

#SPJ2

This one is confusing

Answers

Answer:

it s just asking for negative d

Step-by-step explanation:

Answer:

D(-1) = 2

Step-by-step explanation:

replace x with D(x), which in this case is -1

D(x) = x²-2x-1

replace x with -1

D(x) = (-1)²-2(-1)-1

Now solve using PEMDAS

Look at the image for the question?

Answers

Answer:

Surface area = the sum of the area of all six sides:

(11 · 10) + (11 · 10) + (11 · 8) + (11 · 8) + (8 · 10) + (8 · 10)

= 110 + 110 + 88 + 88 + 80 + 80

= 220 + 176 + 160

= 556 ft²

Answer:

556 ft^2

Step-by-step explanation:

The surface area of a rectangular prism is

SA = 2(lw+wh+lh) where h is the height l is the length and w is the width

SA = 2( 11*10+10*8+11*8)

      = 2(110+80+88)

      =2(278)

     =556 ft^2

For a $1,000 loan at a rate of 16 3/4 % for 5 years, the simple interest is

Answers

Answer:

$837.50

Step-by-step explanation:

(1000×16.75×5)/100

83750/100=

$837.50

When it was built, the given stadium held 31,080 fans per game. Today, it holds 86,047. How many more fans could attend per year (12 games) compared to the year it was built?

Answers

Answer:

659604 students

Step-by-step explanation:

86047-31080=54967 more students per game

54967 students per game x 12 games = 659,604 students

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