A car with a mass of 1.5 × 103 kilograms is traveling west at a velocity of 22 meters/second. It hits a stationary car with a mass of 9.0 × 102 kilograms. If the collision is inelastic, what is the final direction and approximate velocity of the two cars?

Answers

Answer 1

Answer:

A. 14 meters/second to the west

Explanation:

The collision is inelastic, which means that:

- only the total momentum is conserved (not the kinetic energy)

Answer 2

Answer:

14 meters/second to the west

Explanation:

That's the answer!


Related Questions

A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manager. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?

Answers

Answer:

  t = 6 s

Explanation:

This is a free fall exercise

          y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

         0 = y₀ + 0  - ½ g t2

         t = √(2yo / g)

let's calculate

         t = √ (2 176.4 / 9.8)

         t = 6 s

the balloon must be released 6 s before the person reaches the building

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Comentarios

According to the Law of the Conservation of Matter, if you dissolve 25 grams of sugar into 150 grams of water, the mixture should weigh how much?

Answers

19grams becauce if u

Problem (8):
A projectile is fired at an angle of 53° above the horizontal with initial speed of 10.0 m/s. After
one second, what is X and Y components of the position of that projectile?
A60m 20 m
B. 6.0 m. 8.0 m
C. 3.0 m, 6.0 m
D.4.0 m, 3.0 m​

Answers

Answer:

x=6 m, y= 3 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the components of the velocity at a given time t are:

[tex]v_x=v_o\cos\theta[/tex]

[tex]v_y=v_o\sin\theta-g.t[/tex]

And the components of the displacement are:

[tex]x=v_o\cos\theta .t[/tex]

[tex]\displaystyle y=v_o\sin\theta.t-\frac{g.t^2}{2}[/tex]

The projectile of the problem is fired at θ=53° with an initial speed of vo=10 m/s.

Thus, after 1 second, the components of the displacement are:

[tex]x=10\cos 53^\circ \cdot 1[/tex]

[tex]x\approx 6~m[/tex]

[tex]\displaystyle y=10\sin 53^\circ\cdot 1-\frac{9.8\cdot 1^2}{2}[/tex]

[tex]y\approx3~m[/tex]

Answer: x=6 m, y= 3 m

None of the options match this answer.

What happens in a convection current?

Answers

Answer:

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

Explanation:

A segment of wire of total length 3.0 m carries a 15-A current and is formed into a semicircle. Determine the magnitude of the magnetic field at the center of the circle along which the wire is placed. a. 1.6 mu T b. 4.9 mu T c. 1.0 mu T d. 9.8 mu T e. 15 mu T

Answers

Answer:

c. 1.0 mu T

Explanation:

From, the ampere's  circuit law:

∫B.dl = μ₀ I

B.(2πr) = μ₀ I

where,

B = Magnetic Field = ?

r = radius of the circle = length of wire = 3 m

μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A

I = Current = 15 A

Therefore,

B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)

B = 10 x 10⁻⁷ T

B = 1 x 10⁻⁶ T = 1 μT

Hence, the correct option is:

c. 1.0 mu T

How much heat does 56 L of water need to absorb to raise its temperature from 350C to 740C?​

Answers

Answer:

300 L of water

Explanation:

In the flowchart representation of the scientific method (the one that embraces the use of constructing models), what does one do immediately after making observations?

Answers

Answer:

The correct answer is - ask a question based on observation and then postulate a hypothesis.

Explanation:

The scientific method is the step by step process to find an answer to any scientific question with the help of scientific investigation or experiment. The steps that make an investigation successful are should be in the correct order. These steps are as follows:

*Make an Observation

*Ask a Question

*Do Background Research

*Form a Hypothesis

*Conduct an Experiment

*Analyze Results and Draw a Conclusion

*Report Your Results

In the picture below, sphere X swings down and collides with sphere Y. Identify the action and reaction forces. 

Action force: 
Reaction force: 

Answers

Answer:

Action force is force acting in one direction. Reaction force is force acting in the opposite direction.

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 36.0 A. Find the resistivity of the material.

Answers

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

       [tex]R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)[/tex]

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

       [tex]R = \rho* \frac{L}{A} (2)[/tex]

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

      [tex]A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)[/tex]

Replacing  the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

       [tex]\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m[/tex]

ρ = 1.6*10⁻⁸ Ω/m

As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?
a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.

Answers

Answer:

a. The pressure in the tubing is equal to the barometric pressure.

Explanation:

Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.

Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure

Hence, the correct option is a.

What name is given to the rate at which velocity changes?
Answer mere

Answers

Answer:

Acceleration

Explanation:

A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is
shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?
m
А
0
2
B
0.2"
C) 5
D
25"

Answers

Solution:

The gravitational force that acts on the bicycle system is

[tex]$F_{g} = 500 \ N$[/tex]

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

[tex]$F_g=mg$[/tex]

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

[tex]$F_f = ma$[/tex]

[tex]$a=\frac{F_f}{m}$[/tex]

  [tex]$=\frac{250}{50}$[/tex]

Therefore [tex]$a= 5 \ m/s^2$[/tex]

Hence (C) is correct option.  

Does lighting striking the earth considered the speed of light?

Answers

Answer:

i would tell you but im a hobbit

Explanation:

biden 2020

A metal block of density 900kgm^-3 weighs 60N in air, find its weight when it is immersed in paraffin wax of density 800kgm^-3

Answers

Given;Density of metal block : 900 kg/m3Weight in air of block : 60NWeight of block when it is immerse in paraffin wax = ? Mass of block = 6kg

NOW,

Volume = 6 kg / 900 kg/m3 = 0.0067 m3And

Mass = 800 × 0.0067

= 5.333And Weight = 5.33 × 10 =53.33

What's the name for how you see the world through your perception
in cognitive theory.

Answers

i’m sorry what- that’s so

Answer:

Perception: Perception is a cognitive process that allows people to take in information through their senses (sensation) and then utilize this information to respond and interact with the world. Thought: Thought is an essential part of every cognitive process.

I hope it helped

Witch is not true about longitudinal waves?

Answers

Answer:

light is a longitudinal wave.

Explanation:

lol

On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Find the acceleration due to gravity on this planet's surface. What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.450 kg attached to a spring of force constant 9.75 N/m?

Answers

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

can a body have mass but no weight give reasion for your answer​

Answers

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

Answer:

yes a body can have mass but no wt at a centre of the earth

Explanation:

this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre

A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hitting the ground?​

Answers

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

A nail driven into a board increases in temperature.
If 59.0 % of the kinetic energy delivered by a 1.60 kg hammer with a speed of 7.70 m/s is transformed into heat that flows into the nail and does not flow out, what is the increase in temperature of an 7.60 g aluminum nail after it is struck 10 times?

Answers

Answer:

ΔT = 40.91 °C

Explanation:

First we find the kinetic energy of one hit to the nail:

K.E = (1/2)mv²

where,

K.E = Kinetic energy = ?

m = mass of hammer = 1.6 kg

v = speed of hammer = 7.7 m/s

Therefore,

K.E = (1/2)(1.6 kg)(7.7 m/s)²

K.E = 47.432 J

Now, for 10 hits:

K.E = (10)(47.432 J)

K.E = 474.32 J

Now, we calculate the heat energy transferred (Q) to the nail. As, it is the 59% of K.E. Therefore,

Q = (0.59)K.E

Q = (0.59)(474.32 J)

Q = 279.84 J

The change in energy of nail is given as:

Q = mCΔT

where,

m = mass of nail = 7.6 g = 0.0076 kg

C = specific heat capacity of aluminum = 900 J/kg.°C

ΔT = Increase in temperature = ?

Therefore,

279.84 J = (0.0076 kg)(900 J/kg.°C)ΔT

ΔT = (279.84 J)/(6.84 J/°C)

ΔT = 40.91 °C

(30points pls help ASAP) How many grams of sodium would there be in 70 g of NaCl?

Answers

I believe 1.05g:))))))

27.52g grams of sodium would there be in 70 g of NaCl.

What is molecular mass ?

The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.

The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.

Here I have direct method for the calculation of mass of particular atom in the molecule.

Molecular weight of the NaCl is,

(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.

in this we can see that 58.5 g of Nacl contains 23 g of Na.

we can write 58.5 NaCl = 23g Na

therefore 70g of NaCl = (23÷58.5)×70 Na

70g of NaCl = 27.52g of Na

Hence 70g of NaCl contains 27.52g of sodium.

To know more about molecular mass, click :

https://brainly.com/question/18446366

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When Royce was 10 years old, he had a mass of
30 kg. By the time he was 16 years old, his mass
increased to 60 kg. How much larger is the
gravitational force between Royce and Earth at
age 16 compared to age 10?

Answers

Answer:

The gravitational force between Royce and Earth would be doubled at 16 years.

Explanation:

"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.

Given:

At 10 years old,

Mass,

m = 30 kg

now,

→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]

                                          [tex]= mg[/tex]

or,

→ [tex]g = \frac{GM}{r^2}[/tex]

then,

Gravitational force = 30 g

Now,

At 16 years old,

Mass,

m = 60 kg

Now,

→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]

       [tex]=\frac{1}{2}[/tex]

  [tex]F_2 = 2F_1[/tex]

Thus the above response is right.

Learn more:

https://brainly.com/question/22416758

Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one week later?

Answers

Answer:

it should be a new moon

Explanation:

what is the mass of an object with a density of 74 g/mL and a volume of 7 mL?

Answers

Answer:

518 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 74 × 7

We have the final answer as

518 g

Hope this helps you

Two car's are racing! The winner of the race will always be be the vehicle with the greater...

Answers

velocity i believe ?
The velocity using the speed down flow of the wind and aerodynamics of the cars body and build it would be velocity with a higher down flow to the ground it go’s faster because it’s closer the the ground like an F1 racing car especially if the car has a spoiler is brings it closer down to the ground

Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another 9
km. That part of her trip takes her 2 h. What is her average speed?

Answers

Answer:

24km/h

Explanation:

go it right on ingenuity 2020

An unknown mass is hung from a very light spring with a spring constant of 13.6 N/m. Neglect the mass of the spring. If the period of oscillation of the mass-spring system is 3.35 s, then the unknown mass is:__________

Answers

Answer:

The unknown mass is 3.87 kg.

Explanation:

Given;

spring constant of the spring, k = 13.6 N/m

period of oscillation, T = 3.35 s

The period of oscillation of the mass-spring system is given by;

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where;

m is the mass attached to the spring

[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]

Therefore, the unknown mass is 3.87 kg.

In which type of collision is the kinetic energy of the system unchanged?
A. Perfectly inelastic
O B. Elastic
C. No type of collision
D. Inelastic

Answers

B.) Elastic

Took the test and this is the answer

Picture question please answer do in 5 mins

Answers

Answer:

Can't see anything, please share clearly

A student walks 300 meters due east and then 100 meters due north,
then 500 meters due west. The total distance travelled by the student
-
is
meters.

Answers

Answer:

900 meter hhgffhffhhfcbjhggjdswexaazcgh

Answer:

900 meters

Explanation:

If you are talking about how many meters student walked then its 900 metes

But if you are talking about how many meters student travelled from the start point then its 200 meter

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