Answer:
A.) 37.8 m/s
B.) No
C.) 172 m
Explanation:
Given that car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.89 m/s^2 for t1 = 20 s. At that point the driver notices a tree limb that has fallen on the road and brakes hard for t2 s until it comes to a stop. Required:
a.) Write an expression for the car's speed just before the driver begins braking, v1.
Since the car accelerate from rest, initial velocity U = 0
Using first equation of motion
V1 = U + at
V1 = 1.89 × 20
V1 = 37.8 m/s
b.) If the limb is on the road at a distance of 550 meters from where the car began its initial acceleration, will the car hit the limb?
Using third equation of motion
V^2 = U^2 + 2as
37.8^2 = 0 + 2 × 1.89 × S
1428.84 = 3.78S
S = 1428.84 / 3.78
S = 378m
Since the limb is on the road at a distance of 550 meters from where the car began its initial acceleration, we can therefore conclude that the car will not hit the limb.
c. How far, in meters, from the original location of the limb will the car be when it stops?
550 - 378 = 172 m
The car will be 172 metres from the limb.
What happens to the acceleration of a system when the mass of the system increases but the net force stays constant?
Explanation:
acceleration is inversely proportional to mass so acceleration will decrease if mass increases
If the mass of the system will increase, then the acceleration of the system will decrease because mass and acceleration are inversely proportional to each other.
What is Acceleration?In mechanics, acceleration refers to the rate at which the velocity of an object changes in relation to time. The magnitude of accelerations as a vector. The acceleration of an object depends on the direction of the net force acting on it.
It is a vector quantity because acceleration has both a magnitude and a direction. Additionally, velocity is a vector quantity. The change in the vector of velocity during a period of time divided by the period of time is the definition of acceleration.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationWhen the mass of the system will increase it will become heavy, and it will affect the acceleration of the body because due to this the acceleration of the body will decrease because both mass and acceleration are inversely proportional to each other.
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You throw a ball downward from a window at a speed of 1.7 m/s. How fast will it be moving when it hits the sidewalk 2.5 m below?
Answer:
7.43m/s
Explanation:
Given parameters:
Initial velocity = 1.7m/s
Height = 2.5m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we apply one of the motion equation. The most fitting one given the parameters is;
V² = U² + 2gh
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s
h is the height
Input the parameters and solve;
V² = 2.5² + 2(9.8)(2.5)
V = 7.43m/s
Which statement is true about an object that is traveling in uniform circular motion?
Jennifer hits a stationary 0.04-kg ball, and it leaves her racket at 41.3 m/s. Time-lapse photography shows that the ball was in contact with the racket for 26.5 ms. What average force, in N, did the ball exert on the racket?
Answer:
62.33NExplanation:
We know that the relationship for the impulse and momentum is given as
Ft=mv
given data
mass m=0.04kg
t= 26.5ms= 26.5/1000= 0.0265seconds
velocity v= 41.3m/s
substituting in the expression we have
Ft=mv
make F subject of formula we have
F=mv/t
F=(0.04*41.3)/0.0265
F=1.652/0.0265
F=62.33N
gas is escaping from a sperical ballom 4 cm3 per minute .how fast is the surface area shrinking when radius is 24cm
Answer:
dS/dt = 0.33 cm²/min
Explanation:
Volume of sphere is given by;
V = (4/3)πr³
We are told that gas is escaping from a spherical balloon 4 cm³ per minute. Thus; dV/dt = 4 cm³/min
Now, let's find the rate at which the radius is changing.
dr/dt = (dV/dt) ÷ (dV/dr)
Now, dV/dr = 4πr²
Thus;
dr/dt = 4/(4πr²)
dr/dt = 1/(πr²)
Now, surface area of sphere is given by;
S = 4πr²
Thus, dS/dr = 8πr
Now, let's find the rate at t which area is shrinking.
dS/dt = (dS/dr) × (dr/dt)
Plugging relevant terms, we have;
dS/dt = 8πr × 1/(πr²)
dS/dt = 8/r
At r = 24 cm, we have;
dS/dt = 8/24
dS/dt = 1/3
dS/dt = 0.33 cm²/min
What is the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope
Answer:
Explanation:
We have that the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is
N=275N
From the question we are told
Mountain goats can easily scale slopes angled at 60∘ from horizontal. What is the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope?Generally the equation for the normal force acting on a mountain goat is mathematically given as
N=mgcos
N=550*cos60
N=275N
Therefore
The normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is
N=275N
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When a velocity vs time graph is slowed downwards, is the object still moving forward? Explain why or why not.
Answer:
Since velocity is considered a vector quantity and vectors show you in what direction it goes the object wont be moving forward but backwards because its a negative and negatives go to the left and that would be considered backwards.
Explanation:
Hope this helps
Consider the situation a book a sliding to a stop while moving across the classroom floor. Of the forces listed identify which act upon the book
The forces which act upon the book are Normal, Gravity, Air resistance, and Friction. Therefore, the (A), (B), (D), and (E) options are correct.
What are Normal force, Gravity, Air resistance, and Friction?The normal force is a contact force that surfaces exert to prevent objects from passing through each other. If two surfaces are not in direct contact, they are able to exert a normal force on each other. The book and the floor are exerting normal on each other.
Gravity is the force by which the earth draws objects toward its center. The force of gravity keeps everything on the surface of the earth. Therefore, the sliding book on the floor experiences the force of gravity.
Air resistance is a force that arises due to air. The force acts in the opposite direction to the motion of an object through the air. As the book slides across the floor, it experiences resistance due to air.
Friction is the resistance caused by the surfaces that are in contact when they slide over each other. Friction arises due to the irregularities on the two surfaces. The book and floor both have irregularities on their surfaces which is caused friction between them.
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Your question is incomplete, but most probably the complete question was,
Consider the situation a book a sliding to a stop while moving across the classroom floor. Of the forces listed identify which act upon the book:
A)Normal,
B) Gravity
C)Applied
D) Air resistance,
E) Friction
F) Tension
What happens when the forces applied to an object at rest produce a net force of zero?
1.The object will not move at all.
2.The object will have positive acceleration.
3.The object will change its direction of motion.
Answer:
1. The object will not move at all.
Explanation:
The question above is related to "Newton's First Law of Motion." According to this law, an object that is at rest will remain in its position (at rest) unless acted upon by "unbalanced forces." If the forces applied to an object are balanced, the net force is zero. This means that the object will not move nor accelerate.
The law also mentioned that if the object is in motion, it will remain in same velocity (speed with direction) if there's no net force.
A person in a grocery store is standing carrying a big sack of rice (that has a mass of 10 kg) on the top of his head. Where is his CG located relative to his original CG (i.e when he is standing without the sack of rice on his head)
a) Higher than his original CG
b) Lower than his original CG
c) At the same point as his original CG
d) Insufficient information
Answer:
The CG is located higher than his original CG.
Explanation:
Centre of gravity (CG), in physics, an imaginary point in a body of matter where, for convenience in certain calculations, the total weight of the body may be thought to be concentrated. In a uniform gravitational field the centre of gravity is identical to the centre of mass, a term preferred by physicists.
His CG is located higher than his original CG when he is standing without the sack of rice on his head.
A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement. A system is in unstable equilibrium if, when displaced, it experiences a net force or torque in the same direction as the displacement from equilibrium. A system is in neutral equilibrium if its equilibrium is independent of displacements from its original position. A marble on a flat horizontal surface is an example.
Large igneous provinces are formed by ____________________, which can flow tens to hundreds of kilometers.
Answer:
Large igneous provinces are formed by flood basalt, which can flow tens to hundreds of kilometers.
Explanation:
The fastest recorded pitch in major league baseball, thrown by Aroldis Chapman in 2010, was clocked at 169.1km/hr. If a pitch were thrown horizontally with this velocity, how far would the ball fall vertically (in meters) by the time it reached the home plate, 18.3m away?
Answer:
The ball would fall vertically for 112.45m
Explanation:
The vertical height of a horizontal throw is affected only by the speed of the throw and the acceleration due to gravity.
At this point, we may use this formula to determine the vertical height of the throw
vertical height = [tex]-v^2/2g[/tex]
The initial throwing speed has to be converted to m/s to ensure uniformity during the calculations. To do this we multiply by 1000 and divide by 3600
169.1km/hr = 46.972m/s
Maximum height = [tex]46.972^2 /2 \times 9.81=112.45[/tex] m
The pitch would make the ball fall vertically for 112.45m by the time it reached the home plate 18.2 m away
A current of 6.67 A in a solenoid of length 13.6 cm creates a 0.373 T magnetic field at the center of the solenoid. How many turns does this solenoid contain?
Answer:
The value is [tex]N = 6051 \ turns[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 6.67 \ A[/tex]
The length is [tex]l = 13.6 \ cm = 0.136 \ m[/tex]
The magnetic field is [tex]B = 0.373 \ T[/tex]
Gnerally the number of turn per unit length is mathematically represented as
[tex]n = \frac{B}{\mu_o * I}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4*\pi*10^{-7}[/tex]
So
=> [tex]n = \frac{0.373}{ 4\pi * 10^{-7} * 6.67 }[/tex]
=> [tex]n = 44496 \ turns /m[/tex]
Generally the number of turn is mathematically represented as
[tex]N = n * l[/tex]
=> [tex]N = 44496 * 0.136[/tex]
=> [tex]N = 6051 \ turns[/tex]
The no of turns dos this solenoid contains will be 6051 turns.
What is a solenoid?A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil .
The given data in the problem is;
B is the current =6.67 A
L is the length =13.6 cm=0.136 m
B is the magnetic field =0.373 T
The number of turns per unit length is found as;
[tex]\rm n= \frac{B}{\mu_0I} \\\\ \rm n= \frac{0.373}{4 \times 3.14 \times 10^{-7}\times 6.67} \\\\ \rm n = 44496 \ turn /m[/tex]
The number of turns is found as;
[tex]\rm N=n\times l \\\\ \rm N=44496\times 0.136 \\\\ \rm N=6051 \ turns[/tex]
Hence the no of turns dos this solenoid contains will be 6051 turns.
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What is the wavelength emitted by compound BB that have spectral line detected at position 12.15 cmcm
Complete question is;
A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glow, sending the light through a diffraction grating, and measuring the positions of first-order spectral lines on a detector 15.0 cm behind the grating. Unfortunately, she has lost the card that gives the specifications of the grating. Fortunately, she has a known compound that she can use to calibrate the grating. She heats the known compound, which emits light at a wavelength of 461 nm, and observes a spectral line 9.95 cm from the center of the diffraction pattern.
What is the wavelength emitted by compound B that have spectral line detected at position and 12.15 cm?
Answer:
λ ≈ 525 nm
Explanation:
The diffraction grating equation of n-th order is given by;
nλ = dsinθₙ
For 1st order, n=1. Thus;L, we have;
λ = dsinθ₁
We are told that the first-order spectral lines on a detector 15.0 cm behind the grating. Also that, she observes a spectral line 9.95 cm from the center of the diffraction pattern.
Therefore, the angle of the known compound's 1st order is given by the relation:
tanθ₁ = 9.95/15
tanθ₁ = 0.6633
θ₁ = tan⁻¹(0.6633)
θ₁ = 33.56º
We are told that the unknown compound emits light at a wavelength of 461 nm.
Thus, from the first order equation above, we have;
d = λ/sinθ₁
d = 461nm/sin(33.56º)
d = 461nm/0.55281
d ≈ 834nm
λ = dsinθ₁= 870nm sin(29.68º) = 431nm
Now, spectral line is given as 12.15 cm from the center of the diffraction pattern. Thus;
θ₁ = tan⁻¹(12.15/15)
θ₁ = tan⁻¹(0.81)
θ₁ = 39°
Since λ = dsinθ₁
Thus;
λ = 834sin(39°)
λ = 834 × 0.6293
λ ≈ 525 nm
A car traveling 14 m/s accelerates at a rate of 0.95 m/s2 for an interval of 8 s. What is the final
velocity of the car? Remember: Diagram, Knowns, Equation, Rearrange, Solve.
elastic limit is equal to:(a) stress (b)strain (c) young's modulus (d)modulus of rigidity
Answer:
A. stress
Explanation:
Hope this helped. Have an amazing day/night!!
We have that for the Question "elastic limit is equal to" it can be said that
Young's modulusThis speaks to a body retaining it shape after changes occur
Option C
From the question we are told
elastic limit is equal to
(a) stress
(b)strain
(c) young's modulus
(d)modulus of rigidity
Where
Where
Stress is the force acting on a material
and
strain
The effect of force acting on a material
Young's modulus
This speaks to a body retaining it shape after changes occur
Modulus of rigidity
m=sheer stress/shear strain
Now having that
Elastic limit is a point where an elastic body does not return to its original shape
The option chosen is'
Young's modulus
This speaks to a body retaining it shape after changes occur
Option C
Generally the equation for the is mathematically given as
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40 m north west
50m Northwest
120 m southeast
40 m south east
Which answer
Answer:
120 north west
Explanation:
A hungry rabbit sprints... what is the average velocity of the rabbit between the times t = 2 s and t = 12 s
Answer: -0.10m/s
Explanation:
khan academy
A car driver traveling on a linear segment of a level road at 60 miles per hour (mph) slows down to 40 miles per hour in a road construction zone. If the car traveled a distance of 360 ft from the original speed to the final speed then what is the car deceleration rate in ft per sec2
Answer:
a=5.98 ft/secExplanation:
given
initial velocity u=60mph to ft per sec= 88ft/s
final velocity v=40 mph to ft per sec= 58.6 ft/s
distance s=360ft
convert feet to mile 360ft is 0.06miles
we can apply the expression
v^2=u^2-2as
58.6^2=88^2-2*a*360
3433.96=7744-720a
3433.96-7744=-720a
-4310.04=-720a
a=4310.04/720
a=5.98 ft/sec
An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of the spring is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at 1.4 m/s2, what is the mass of the object?
Answer:
Approximately [tex]28.3\; \rm kg[/tex], assuming that the spring was pulled horizontally.
Explanation:
Let [tex]k[/tex] denote the spring constant of this spring. Calculate the size of tension in this spring that corresponds to the [tex]\Delta x = 0.88\; \rm m[/tex] stretch:
[tex]F(\text{tension}) = k\cdot \Delta x = 45\; \rm N \cdot m^{-1} \times 0.88\; \rm m = 39.6\; \rm N[/tex].
(The negative sign is ignored.)
If the spring is pulled horizontally, then the tension that the spring exerts would be the only unbalanced force on this object. The net force n this object would be equal to the tension that the spring had exerted: [tex]39.6\; \rm N[/tex].
Newton's Second Law of motion suggests the following relation between the net force [tex]\sum F[/tex] on the object, the mass [tex]m[/tex] of the object, and the acceleration [tex]a[/tex] of the object:
[tex]\sum F = m \cdot a[/tex].
For this object, [tex]a = 1.4\; \rm m \cdot s^{-2}[/tex]. It has been found that the net force on this object is [tex]\sum F = 39.6\; \rm N[/tex]. Rearrange the original equation [tex]\sum F = m \cdot a[/tex] and solve for [tex]m[/tex], the mass of this object:
[tex]\displaystyle m = \frac{\sum F}{a} = \frac{39.6\; \rm N}{1.4\; \rm m \cdot s^{-2}} \approx 28.3\; \rm kg[/tex].
In other words (based on all these assumptions,) the mass of this object should be approximately [tex]28.3\; \rm kg[/tex].
In which of the following situations shows no acceleration of the car?
O A car shortly after a stoplight turns green.
A car approaching a red light
O A car with the cruise control set at 80 km/h
O A car turning a curve at a constant speed
Other:
Answer:
I think A, a car shortly after a stoplight turns green OR if it's wrong it's B☺️
A force of 1.46 N pushes against an object with a mass of 0.10 kg for 3.00 min. The object does not move. What is the work done on the object by the force
Answer:
0 J
Explanation:
Given data
force F=1.46N
mass m=0.1kg
time t= 3min
distance= 0 meters----"the object did not move"
We know that work-done is given as
work= Force * distance moved
Work= 1.46*0
work =0joules
We understand that when this is no distance move, then there is no work done, for work to be done, the object must move through a distance
A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?
Answer:
20 m/s
Explanation:
velocity after 2 sec.
v=40+(−10)t
=40−10∗2=20m/s
We have that for the Question "A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?" it can be said that the balls velocity after 2 seconds
v=67.44m/s
From the question we are told
A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?
Generally the Newtons equation for the Motion is mathematically given as
[tex]v=u+at\\\\Therefore\\\\v=40+9.8*2.8\\\\v=67.44m/s\\\\[/tex]
Therefore
the balls velocity after 2 seconds
v=67.44m/s
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The position vector r of a particle relative to a certain point has a magnitude of 3m , and the force F on the particle has a magnitude of 4N . What is the angle between the directions of r and F if the magnitude of the associated torque equals
Answer:
θ = 0
Explanation:
As per the question Given that
Magnitude = 2m
Force F contains MAgnitude = 4N
Based on the above information
T = rFsinθ
Now if
T = 0,
so r and F would not be zero so that sinθ should be equivalent to zero for holding an equation
Therefore
θ = 0
The same is to be considered as it is relevant as per the question
Describe and give an example of a normal force.
Answer:
Normal force is the force exerted on an object that is in contact with another non-moving object. Force is push and pull
Ex: When a book rests on a surface (like a table), the table is exerting a force on the book in order to support the weight of it.
Answer:
Normal Force is a contact force. When 2 objects are touching each other, they are in contact. Like when a cup is sitting on a table they are in contact cause the table has to hold the force of the cup up on the table.
A example of normal force is when a book is sitting on a table, and the table is holding the force of the book up.
Explanation:
Hope this helps!!
Have a blessed day/night! <33
In the amusement park ride known as Magic Mountain Superman, powerful magnets accelerate a car and its riders from rest to 45 m/s (around 100 mi/h) in a time of 6.8 s. The mass of the car and riders is 5100 kg. Find the average net force exerted on the car and riders by the magnets.
Answer:
The average net force exerted on the car and riders by the magnets is 33751.8 newtons.
Explanation:
Let assume that car and its riders accelerate at constant rate, such that acceleration ([tex]a[/tex]), measured in meters per square second, can be found by using the following kinematic equation:
[tex]a = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 1)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the car and its riders, measured in meters per second.
[tex]t[/tex] - Acceleration time, measured in seconds.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 45\,\frac{m}{s}[/tex] and [tex]t = 6.8\,s[/tex], the average acceleration of the car is:
[tex]a = \frac{45\,\frac{m}{s}-0\,\frac{m}{s}}{6.8\,s}[/tex]
[tex]a = 6.618\,\frac{m}{s^{2}}[/tex]
By the Second Newton's Law, we find that average force exerted on the car and riders by the magnets ([tex]F[/tex]), measured in newtons, is:
[tex]F = m\cdot a[/tex] (Eq. 2)
Where [tex]m[/tex] is the mass of the car-riders system, measured in kilograms.
If we know that [tex]m = 5100\,kg[/tex] and [tex]a = 6.618\,\frac{m}{s^{2}}[/tex], the net force exerted on the car and riders is:
[tex]F = (5100\,kg)\cdot \left(6.618\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 33751.8\,N[/tex]
The average net force exerted on the car and riders by the magnets is 33751.8 newtons.
You are originally 1.0 m beneath the surface of a pool. If you dive to 2.0 m beneath the surface, what happens to the absolute pressure on you
Answer:
The absolute pressure on me increases to 130,900 Pa.
Explanation:
Since I dive to a depth of 2.0 m, there is a depth change of 2.0 m which will cause a corresponding pressure change. The pressure change is thus ΔP = ρgΔh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8m/s² and Δh = depth change = 2.0 m
ΔP = ρgΔh = 1000 kg/m³ × 9.8m/s² × 2.0 m = 19,600 Pa.
Since the absolute pressure P at 1.0 m is the pressure due to atmosphere plus the pressure of 1.0 m of water, we have
P = P₀ + ρgΔh' where P₀ = atmospheric pressure = 101,500 Pa and Δh' = 1.0 m
P = 101,500 Pa + 1000 kg/m³ × 9.8m/s² × 1.0 m = 101,500 Pa + 9800 Pa = 111,300 Pa
So, the absolute pressure at 2.0 m is P' = P + ΔP = 111,300 Pa + 19,600 Pa = 130,900 Pa.
So the absolute pressure on me increases to 130,900 Pa.
Photons with the lowest energy have the lowest
A. wavelength
B. self-esteem
C. frequency
D. speed
Answer:
c frequency
hope it helps:))
Explanation:
To solve this we must be knowing each and every concept related to photon. Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.
What is photon?A photon, also known as a light quantum, is a small energy packet containing electromagnetic radiation. The idea came from Albert Einstein's explanation of something like the photoelectric phenomenon (1905), in which he hypothesized the possibility of energy levels packets during light transmission.
Photons all move just at speed of light. Photons are bosons that have no electric charge and rest mass one and unit of spin; they were field particle that are assumed to be the bearers of electromagnetic field. Photons with the lowest energy have the lowest frequency.
Therefore, the correct option is option C. Photons with the lowest energy have the lowest frequency.
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The gravitational potential energy of a 88 kg person in a building that is 385 m tall is 332,024 J. The person then jogs up the stairs, an additional distance of 100 meters.
How would the potential energy of the person be affected?
A) There would be no change.
B) The potential energy would double.
C) The potential energy would increase almost 25%
D) The potential energy would decrease more than 50%.
Answer:
Part C
Explanation:
The potential energy would increase almost 25%
What is the difference between fast-twitch and slow-twitch muscle fibers?
A. They are almost identical.
B. Fast-twitch fibers can deliver a quick burst of power. Slow-twitch
fibers can maintain a contraction for a longer time.
C. Fast-twitch fibers are what keep us going on a long bike ride or
hike. Slow-twitch fibers are what we use while dashing for the bus
or jumping up for a rebound.
D. Fast-twitch fibers take a long time to warm up, but are stronger
than slow-twitch fibers once they get going.
Answer:
B. fast-twitch fibers can deliver a quick burst of power. Slow-twitch fibers can maintain a contraction for a longer time.
Answer:
the person above is right, just came for answers lol :')
Explanation:
