A bus is moving to the right at an absolute velocity U. You throw a water balloon at the bus at an absolute velocity V (greater than U) after the bus passes you. A person on the bus sees the balloon hit the bus at a speed of:

Answer:

F = 240 N

Explanation:

Let the mass of the puck, m = 160 g = 0.16 kg

Initial speed, u = 0 (at rest)

Final speed, v = 5 m/s

Time, t = 0.03 s

We need to find the average force on the hockey puck while it is in contact with the stick. Force is given by the formula as follows :

F = ma, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.16\times (45-0)}{0.03}\\\\F=240\ N[/tex]

So, the average force is 240 N.

Answer:

Different ions are deflected by the magnetic field by different amounts. The amount of deflection depends on: the mass of the ion. Lighter ions are deflected more than heavier ones.

Answer:

117

Explanation:

Answer:

Explanation:

See attachment

Answer:

D

Explanation:

Answer:

Hydroelectric power plants

Explanation:

This is because hydropower is a form of renewable energy that uses water stored in dams, rivers to create electricity

Answer:

The breaking strength of the string is 717.19 N

Explanation:

Given;

initial tension on the string, T₁ = 53.9 N

initial radius of the string, r₁ = 2.59 m

initial speed of the rock, v₁ = 21.8 m/s

final radius of the string, r₂ = 1.23 m

final speed of the rock, v₂ = 54.8 m/s

the final tension on the string = breaking strength, T₂ = ?

Apply centripetal force equation due to inward motion;

[tex]T= \frac{mv^2}{r}\\\\Tr = mv^2\\\\m =\frac{Tr}{v^2}\\\\ \frac{T_1r_1}{v_1^2} = \frac{T_2r_2}{v_2^2}\\\\T_2 = \frac{T_1r_1v_2^2}{r_2v_1^2}\\\\ T_2 = \frac{(53.9)(2.59)(54.8)^2}{(1.23)(21.8)^2}\\\\ T_2 = 717.19 \ N[/tex]

Therefore, the breaking strength of the string is 717.19 N

Answer:

The value is [tex]v = 7.89 \ m/s[/tex]

Explanation:

From the question we are told that

  The mass  of the object is [tex]m = 0.414 \ kg[/tex]

   The force is [tex]F = 2.08 \ N[/tex]

  The time taken is  [tex]t = 1.57 \ s[/tex]

Generally the force acting on the object according to Newton's second law is

        [tex]F = \frac{ m (v -u )}{t}[/tex]

=>     [tex]v = \frac{F * t}{m} + u[/tex]

Here u is the initial velocity with value  0 m/s since the object was initially at rest

        [tex]v = \frac{2.08 * .57}{0.414 } + 0[/tex]

     [tex]v = 7.89 \ m/s[/tex]

Answer:

Explanation:

According to law of conservation of momentum

(m1+m2)v = m1u1+m2u2

Let m1 and m2 be the masses

u1 and u2 be their respective velocities

v is the velocity of combined objects

Given

m1 =60kg

m2 = 40kg

v =0 m/s

u2 -  u1 = 60 ............ 1

0 = 60u1 + 40u2 = 0 .......... 2

From 1: u2 = 60+u1

Substitute into 2:

60u1 + 40(60+u1) = 0

60u1 +2400 +40u1 = 0

100u1 = -2400

u1 = -2400/100

u1 = -24m/s

Hence the speed of the 60 kg mass is 24m/s (in the negative direction)

Answer: Height = 0.45m

Explanation:

According to the conservation of energy, When there are no interactions outside a system ie  neglecting air resistance,The change in kinetic energy is equal to the change in potential energy in a closed system.

Therefore the kinetic energy decrease, the potential energy increases, and  decreases for increase in Kinetic energy

an is represented by the formulae

ΔKinetic energy + ΔPotential energy = 0

ΔKinetic energy = -ΔPotential energy ( where negative sign represent decrease as kinetic energy increases.

ΔK.E=ΔP.E

420J- 220J= mgh

mass = 45kg

g =gravitational acceleration =9.8 m/s^2

200J = 45 X 9.8 X h

h = 200/45 x 9.8 /= 0.45m

The correct expression for the mass m of the bone is m=Fs-Fb/a.

The force is defined as the shear stress or pressure applied per unit area.

A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is m, the big dog’s leftward force magnitude is Fb and the small dog’s rightward force magnitude is Fs. The bone accelerates to the right along the table with no friction.

Across the bottom is green grass. In the center, there is a brown table with a large bone on top. To the left is a black outline of a large dog facing rightwards that is pulling leftwards on the bone. To the right is a black outline of a small dog facing leftwards that is pulling rightwards on the bone. The small dog stands on a grey box. Across the bottom is green grass.

Two dogs pulling on a large bone. Big dog and small dog images courtesy of pixabay. Consider rightward as the positive direction.

The net force acting on bone will be

F = Fs -Fb

From the Newton's second law of motion, Force  = mass x acceleration

F = ma

m = F/a

m = Fs-Fb/a

Thus, correct expression for the mass m of the bone is m=Fs-Fb/a.

Learn more about force.

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Answer:

u = 0.334 m/s

Explanation:

The formula for Reynold's number is given as follows:

Re = ρuL/μ

where,

Re = Reynold's Number = 2511

ρ = Density of air = 1.25 kg/m³

μ = Dynamic Viscosity of Air = 1.83 x 10⁻⁵ Pa.s

L = Characteristic Length = Diameter of Sphere = 11 cm = 0.11 m

u = Speed = ?

Therefore,

2511 = (1.25 kg/m³)(u)(0.11 m)/(1.83 x 10⁻⁵ Pa.s)

u = (2511)/(7513.66 s/m)

u = 0.334 m/s

Answer:

Explanation:

it is C

Answer:

2.385 m/s

Explanation:

Here there is a transformation of potential energy of the water at the top to Kinectic energy at the hole

This can be expressed as

Potential energy= Kinect energy

mgh= 1/2m v²

Where m= mass of water

h= Lenght below the level of the water that is in the tank.

v= the speed of the water as it leaves the hole

g= acceleration due to gravity= 9.81m/s

Here there is 'm' at both sides which can cancelled beach other out.

Then we have

gh= ¹/₂v²

making v² subject of the formular

v²=gh/(¹/₂)

v=√(2gh)

V=√2g h

V= √(2×9.81×0.29)

V=2.385 m/s

Therefore, the speed of the water as it leaves the hole is 2.385 m/s

Answer:

Cccccccc GIVE BRAINLYEST PLEASE

Answer: It´s c-skeletal

Explanation:

Answer:

3 m/s

Explanation:

We can solve with kinematics or with energy.

Using kinematics, and taking down to be positive, we're given:

Δy = 0.45 m

v₀ = 0 m/s

a = 10 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (10 m/s²) (0.45 m)

v = 3 m/s

Or, we can use energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 0.45 m)

v = 3 m/s

Answer:

2.31m/s² downwards

Explanation:

The sum of forces on the object is expressed as;

T-W

T is the tension on the rope

W is the weight

According yo Newton's second law:

T-W= ma

m is the mass

a is the acceleration

Given

T = 75N

W = mg = 10×9.81

W = 98.1N

Substitute

75-98.1 = 10a

-23.1 = 10a

a = -23.1/10

a = -2.31m/s²

The magnitude of the acceleration is 2.31m/s² and directions is downwards

Answer:

Explanation:

Force F = GMm / R²

mass of the sun M = 1.99 x 10³⁰ kg

mass of the earth = 5.97 x 10²⁴ kg

value of G = 6.67 x 10⁻¹¹

for perihelion point R = 1.48 x 10¹¹ m

Force = 6.67 x 10⁻¹¹ x  1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.48 x 10¹¹ )²

= 36.17 x 10²¹ N  

for aphelion point R = 1.52 x 10¹¹ m

Force = 6.67 x 10⁻¹¹ x  1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.52 x 10¹¹ )²

= 34.29  x 10²¹ N  

Answer:

Air resistance

Explanation:

Air resistance encountered as the person falls

Answer:

the location where potential energy is zero

Explanation:

Hi! Compressibility is the capacity of something to be flattened or reduced in size by pressure. I hope this helps you! Good luck and have a great day. ❤️

Answer:

9.63 m

Explanation:

We know that

Δx = vt.

Therefore, v = Δx / t

v = 5 / 0.378

v = 13.23 m/s

h = ½gt, so that

h = ½ * 9.8 * 0.378²

h = 4.9 * 0.1429

h = 0.7 m

Finally, using the law of conservation of energy, we know that

½mv² = mg(H - h)

½v² = g(H - h)

½v²/g = H - h, substituting the values and solving, we have

(½ * 13.23²) / 9.8 = H - 0.7

(½ * 175) / 9.8 = H - 0.7

87.5 / 9.8 = H - 0.7

8.93 = H - 0.7

H = 8.93 + 0.7

H = 9.63 m

Answer:

Explanation:

weight of the car mg = m g

frictional force acting on the car = μ mg where μ is coefficient of friction

= m μ g

This force provides centripetal force , hence

m μ g  = m v² / R

μ = v² / rg

= 22 x 22 / 65 x 9.8

= .759  

Answer:b

Explanation:

I got the answer right

The main advantage of using nuclear power over natural gas to generate the electricity that nuclear power does not contribute to climate change, therefore the correct answer is option B.

It is a particular kind of power plant where electricity is produced using a nuclear reactor that may use nuclear fusion or nuclear fission .

When a radioactive substance undergoes a nuclear reaction, a tremendous quantity of energy is produced .

As given in the problem , we have to find out what is an advantage of using nuclear power over natural gas to generate electricity .

Option B is the proper response , since employing nuclear power instead of natural gas to produce electricity has the advantage of not causing the climate change .

To learn more about Nuclear power plants here , refer to the link given below ;

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Answer:

a = - 1 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} = v_{o} +(a*t)[/tex]

where:

Vf = final velocity = 0 (velocity at 10 seconds)

Vo = initial velocity = 4 [m/s]

a = desacceleration [m/s²]

t = time = 4 [s]

From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.

In the second 6, the velocity is 4 [m/s]

0 = 4 + (a*4)

4*a = -4

a = - 1 [m/s²]

Answer:

Explanation:

What is the first law of thermodynamics?

"The first law of thermodynamics state that energy is conserved"

the expression bellow is the  Change in internal energy of a system

Change in internal energy of a system

= heat put into the system - work done by the system on its surroundings,

or

ΔU = ΔQ - ΔW.

given data

Work done=125J

Heat= 75J

change=?

Substituting we have

ΔU = 75- 125

ΔU = -50J

"ΔQ is positive if heat flows into the system, negative if it flows out of the system.

ΔW is positive if the system does work on its surroundings and it is negative if work is done on the system. "

Answer:

The object travels a distance of 40 meters before it stops.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time.

Torricelli's equation relates the speed to the space traveled by the body in u.a.r.m. To calculate the velocity of a body as a function of space, the expression is used:

[tex]v^{2} =v0^{2} +2*a*d[/tex]

Where :

In this case:

Replacing:

[tex](0\frac{m}{s} )^{2} =(20 \frac{m}{s} )^{2} +2*(-5\frac{m}{s^{2} }) *d[/tex]

Solving:

[tex]0\frac{m^{2} }{s^{2} } =400 \frac{m^{2} }{s^{2} } -10\frac{m}{s^{2} } *d[/tex]

[tex]0\frac{m^{2} }{s^{2} } -400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]-400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]\frac{ -400 \frac{m^{2} }{s^{2} }}{ -10\frac{m}{s^{2} }} = d[/tex]

40 m= d

The object travels a distance of 40 meters before it stops.

Answer:

The speed of the ball is 7.36 m/s

Explanation:

Constant Acceleration Motion

It happens when the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

[tex]v_f=v_o+at[/tex]

Since the situation corresponds to a vertical motion, the acceleration is g=9.8 m/s^2.

The ball is thrown downward at vo=0.5 m/s. Its speed at t=0.7 seconds is

[tex]v_f=0.5+9.8\cdot 0.7[/tex]

[tex]v_f=7.36\ m/s[/tex]

The speed of the ball is 7.36 m/s

Note: There is no use of the height it was released from

Answer:

The acceleration on an object due to the gravity of any massive body is represented by g (small g). The force of attraction between any two unit masses separated by unit distance is called universal gravitational constant denoted by G(capital g). The relation between G and g is not proportional.

Explanation:

Answer:

my answer is in explanation below

Explanation:

You would convince him by saying the pattern adds elevation to the shoe therefore causing more friction.

(If it's wrong, I am sorry, I'm not in college)

(If it's right, can I get that brainliest?)