Chemistry College

A bottle labeled 0.01 M HCl is found in the laboratory. Assuming that the HCl is completely ionized calculate the [H+], [OH-] and the pH of the solution. ​

Answers

Answer 1

Answer:

[H⁺] = 0.01 M[OH⁻] = 1x10⁻¹² MpH = 2

Explanation:

The assumption that the HCl is completely ionized means that the original concentration of the acid is equal to [H⁺].

[H⁺] = 0.01 M

With [H⁺], we can calculate [OH⁻], by using the following formula:

[H⁺] * [OH⁻] = 10⁻¹⁴0.01 M * [OH⁻] = 10⁻¹⁴[OH⁻] = 1x10⁻¹² M

Finally we calculate the pH of the solution:

pH = -log[H⁺]pH = 2

Related Questions

Cells enter a futile substrate cycling during which increased intracellular glucose overwhelms the TCA cycle. As a result, non-oxidative glucose metabolism ____ producing _______.

Answers

Explanation: Reciprocal regulation is intended to prevent concurrent activity in two closely parallel pathways, as represented by gluconeogenesis and glycolysis. These pathways include potential futile cycles, which would simply waste ATP if allowed to run freely.

Calculate the grams of nitrogen in 125 g of NH4NO3


Pls quick AND WHO UR WORK I REALLY NEED HELP PLS

Answers

Answer:

43.75 g of Nitrogen

Explanation:

We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:

Mole of NH₄NO₃ = 1 mole

Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)

= 14 + 4 + 14 + 48

= 80 g/mol

Mass of NH₄NO₃ =?

Mass = mole × molar mass

Mass of NH₄NO₃ = 1 × 80 = 80 g

Next, we shall determine the mass of N in 1 mole of NH₄NO₃.

Mass of N in NH₄NO₃ = 2N

= 2 × 14

= 28 g

Thus,

80 g of NH₄NO₃ contains 28 g of N.

Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:

80 g of NH₄NO₃ contains 28 g of N.

Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.

Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen

Anyone knows gunpowder formula?​

Answers

yeah , balanced, but still simplified, equation is: 10 KNO3 + 3 S + 8 C → 2 K2CO3 + 3 K2SO4 + 6 CO2 + 5 N2
bro just go to sleep

Why is a wire used to connect the electrodes in an electrochemical cell?
O A. To provide the metal that is the oxidizing agent
B. To prevent the flow of protons from electrodes
C. So ions can flow from one electrode to another
D. So electrons can flow from one electrode to another

Answers

Answer:

D. So electrons can flow from one electrode to another

Explanation:

An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.

An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.

Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.

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