Answer:
[tex]1.694*10^3KW/hr[/tex]
Explanation:
Formula:
[tex]KW/hr=E_{(change)}[/tex]
[tex]P=\frac{E}{t}[/tex]
[tex](KW)(s)=1000J[/tex]
[tex](3600)(KW)(s)=3600*1000J[/tex]
[tex]KW=3.6*10^6[/tex]
[tex]\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}[/tex]
[tex]1.694*10^3KW/hr[/tex]
Hope it helps
Hi I need the answer to this please
Answer:
its A
Explanation:
because that's how reality works
Answer:
B
Explanation:
thermal energy (heat) flows from a highest to lowest
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy is loaded into it. The roller coaster starts from rest at point A which is 35 m above the ground. The cart is observed to roll down the track to point B, which is 10 m above the ground. In your own words, what physics ideas would you be able to use to predict how fast the cart is moving at point B? What calculations would you use, what things would you be measuring, and what physics principles or laws would you use to make this calculation?
Answer:
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
Explanation:
In order to find the speed at the point B, we will use the Law of conservation of energy between points A and B to get the required results, as follows:
Total Energy of Cart at Point A = Total Energy of Cart Point B
K.E at A + P.E at A = K.E at B + P.E at B
(1/2)mv₁² + mgh₁ = (1/2)mv₂² + mgh²
(1/2)m(v₁² - v₂²) = mg(h₂ - h₁)
(1/2)(v₁² - v₂²) = g(h₂ - h₁)
where,
v₁ = velocity of cart at Point A = 0 m/s
v₂ = Velocity of Cart at Point B = ?
h₁ = height of point A relative to the ground = 35 m
h₂ = height of point B relative to the ground = 10 m
g = 9.8 m/s²
Therefore,
(1/2)[(0 m/s)² - v₂²] = (9.8 m/s²)(10 m - 35m)
- v₂² = - (2)(245 m²/s²)
v₂ = √(490 m²/s²)
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
In which of the following cases is the displacement's magnitude half the distance traveled?
a. 24 steps east followed by 12 steps west
b. 5 steps east followed by 25 steps west
c. 7 steps east followed by 28 steps west
O d. 9 steps east followed by 3 steps west
e. 13 steps east followed by 4 steps west
c
Answer:
a. 24 steps east followed by 12 steps west
Explanation:
displacement is how much you distance you moved from the starting point so in this example 12 steps even though you move 36 steps all together.
A man steps off a diving platform lands in the water below. If he were to miss the water and land on the concrete, his change in momentum would be the same as if he landed in the water. Why is the change in momentum the same for both situations?
Answer:
if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface
Explanation:
that's the explanation now i gotta execute order 66
The equation of a transverse wave traveling along a string is given by y=0.3sin (0.5x-50t) find the maximum displacement of the particles for the equilibrium position
Answer:
0.3cm
Explanation:
Y = 0.3 sin(0.5x - 50t) compare with,
y = A sin(kx - wt)
A = 0.3m
Which safety rule is MOST important when smelling the product of a chemical reaction?
Group of answer choices
Keep nose directly above open container.
Hold with tongs
Wear closed -toed shoes.
use a wafting motion.
Answer:
group of answer choices
Explanation:
When a 5.0 kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length. (a) In an elevator accelerating upward at 2.0 m/s2 , how far does the spring stretch with the same box attached? (b) How fast and in which direction should the elevator accelerate for the spring stretch to be zero (that is, the spring returns to its relaxed length)?
Answer:
a) the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
Explanation:
Given that;
Gravitational acceleration g = 9.81 m/s²
Mass m = 5 kg
Extension of the spring X = 50 mm = 0.05 m
Spring constant k = ?
we know that;
mg = kX
5 × 9.81 = k(0.05)
k = 981 N/m
a)
Given that; Acceleration of the elevator a = 2 m/s² upwards
Extension of the spring in this situation = X1
Force exerted by the spring = F
we know that;
ma = F - mg
ma = kX1 - mg
we substitute
5 × 2 = 981 × X1 - (5 ×9.81 )
X1 = 0.06019 m
X1 = 60.19 mm
Therefore the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
B)
Acceleration of the elevator = a
The spring is relaxed i.e, it is not exerting any force on the box.
Only the weight force of the box is exerted on the box.
ma = mg
a = g
a = 9.81 m/s² downwards.
Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
The extension of the spring in the elevator is 60 mm.
For the extension of the spring to be zero, the elevator must be moving downwards under free fall.
The given parameters;
mass of the box, m = 5 kgextension of the spring, x = 50 mm = 0.05 mThe spring constant is calculated as follows;
F = kx
mg = kx
[tex]k = \frac{mg}{x} \\\\k = \frac{5 \times 9.8}{0.05} \\\\k = 980 \ N/m[/tex]
The tension on the spring in an elevator accelerating upwards is calculated as follows;
T = mg + ma
T = m(g + a)
T = 5(9.8 + 2)
T = 59 N
The extension of the spring is calculated as follows;
[tex]T = kx\\\\x = \frac{T}{k} \\\\x = \frac{59}{980} \\\\x = 0.06 \ m\\\\x = 60 \ mm[/tex]
For the extension of the spring to be zero, the elevator must be under free fall, such that the tension on the spring is zero.
For free fall, a = g
T = m(g - a) = 0
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Plz help ASAP I will give brainliest PLZ
The weight of a bucket is 186 N. The bucket is being raised by two ropes. The free-body diagram shows the forces acting on the bucket.
A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = 186 N. The second vector is pointing up, labeled F Subscript 1 Baseline 105 N. The third vector is pointing upward from the tip of the second using the tail to tip method, labeled F Subscript 2 Baseline = 115 N. The combined two vectors pointing upward are shorter than the one pointing downward.
The acceleration of the bucket, to the nearest tenth, is
m/s2.
Answer:
1.8m/s^2
Explanation:
Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.
Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.
Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.
Therefore, 1.8m/s^2 is the correct answer.
Please mark brainliest!
Answer:
1.8
Explanation:
honestly i jus took the test
A student is walking back up the hill from the field to the school building. His
friends are slow, so he stops for a moment to wait for them to catch up. Once
they do, the group heads to class. Pick the graph that correctly shows the
motion in the story.
с
Distance from
home
Distance from
home
Time
Time
A
O
B
is in
Tim
Time
Answer:
Time cause it's so long ago I was just
A car accelerates at a rate of 8.8 m/s2 with a force from the tires of 11,968 N.
What is the mass of the car?
Answer:
1360 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{11968}{8.8} \\ [/tex]
We have the final answer as
1360 kgHope this helps you
Answer:
[tex]\displaystyle 1360\:kg.[/tex]
Explanation:
[tex]\displaystyle am = F_{net} \\ \\ \frac{11968}{8,8} = \frac{8,8m}{8,8} \\ \\ \boxed{1360 = m}[/tex]
I am joyous to assist you at any time.
Which method of heat transfer transmits heat from the lower layers of air to the upper layers of air as the lower layers of air warm up and rise and replace the upper layers of air that cool off and sink down?
Answer:
Convection
Explanation:
The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"
Answer:
Convection
Explanation:
Its Convection
A syringe has a fine needle with an inside diameter of 109μm. The barrel has a diameter of 2.22cm and is filled with water. Calculate the velocity of water as it squirts horizontally from the needle if you apply a force of 3.24N onto the plunger. (Hint: you may approximate the area of the barrel to be much larger than the area of the needle).
Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
Explanation:
Given that;
inside diameter = 109μm
barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m
force fair = 3.24 N
We know that the inside diameter is neglected; from the Bernoulli's equation
so
P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside
p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel
Fair = 1/2painv²outside . Abannel
therefore
3.24 = 1/2(1000) v²outside (πr²)
3.24 = 1/2(1000) v²outside (π × (0.0111)²
3.24 = 0.1935 v²_outlet
v²_outlet = 3.24 / 0.1934
v²_outlet = 16.7441
v_outlet = √16.7441
v_outlet = 4.09196 m/s
Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
A baseball is hit with an initial velocity of 49 meters per second at an angle of 30 degrees. What is the velocity of the ball in the X direction and what is the velocity of the ball in the y direction?
Answer:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
Explanation:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
Nicolas is playing with his toy car. A parachute in the back of the car is released to help slow down the car.
If the forces act on the car as shown in the picture, what is the net force?
Answer:3 N —->
Explanation:
In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
Calculation of the net force:Since
A parachute in the back of the car is released to help slow down the car.
So here the net force should be
= 10 N - 7N
= 3 N
Hence, In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
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Help me , what is the properties of fluids ?
The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.
_________ players per team are allowed to be on the floor at a time during a game.
Group of answer choices
1
5
7
10
Answer:
5
Explanation:
Answer:
5
Explanation:
explain the Kepler s law of planetary motion
A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). If this system of masses rotated about the Z-axis perpendicular to the X-Y plane, then the moment of inertia of this system is:_______
Answer:
The moment of inertia of this system is 68 kilogram-square meters.
Explanation:
We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:
[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)
Where:
[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.
[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.
By Pythagorean Theorem we calculate each distance:
[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]
[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{1} = 4\,m[/tex]
[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]
[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{2} = 3\,m[/tex]
If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:
[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)
[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]
[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]
The moment of inertia of this system is 68 kilogram-square meters.
A 5100 kg rocket almost in orbit and traveling horizontally is propelled by a thrust force of 7450 Newtons. How fast is it accelerating while the force is applied? ROUND YOUR ANSWER TO THE NEAREST TENTH DECIMAL PLACE (TEKS 4D)
Answer:
[tex]a=1.46\ m/s^2[/tex]
Explanation:
Given that,
Mass of a rocket, m = 5100 kg
Thrust force acting on the rocket, F = 7450 N
We need to find the acceleration of the rocket. The net force acting on an object is given by the formula as follows :
F = ma
a is acceleration of the rocket
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{7450}{5100}\\\\a=1.46\ m/s^2[/tex]
So, the acceleration is [tex]1.46\ m/s^2[/tex].
help me please answer this
Answer:
that's fusion
Explanation:
Answer:
the answer is fusion for this
A 20kg block slides a cross a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.20, what is the force of kinetic friction that acts on the block?
Compute the block's weight:
w = m g = (20 kg) (9.8 m/s²) = 196 N
The net vertical force is 0, so the normal force has the same magnitude:
n + (-w) = 0 → n = 196 N
The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that
f = 0.20 (196 N) = 39.2 N ≈ 39 N
The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N
We'll begin by calculating the the normal reaction (N). This can be obtained as follow:Mass (m) = 20 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?N = mg
N = 20 × 9.8
N = 196 NFinally, we shall determine the force of kinetic friction. This can be obtained as follow:Coefficient of kinetic friction (µ) = 0.2
Normal reaction (N) = 196
Force of kinetic friction (F) =?F = µN
F = 0.2 × 196
F = 39.2 NTherefore, the force of kinetic friction acting on the block is 39.2 N
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How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N?
Which statements describe independent assortment? Check all that apply. Independent assortment occurs during meiosis II. Independent assortment happens during fertilization. Independent assortment results in different combinations of genes in sex cells. Independent assortment makes offspring identical to their parents. Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
Answer:
The CORRECT answer is:
C. Independent assortment results in different combinations of genes in sex cells.
E. Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The statements describe independent assortment are Independent assortment results in different combinations of genes in sex cells and Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The correct options are C and E.
What is independent assortment?The Principle of Independent Assortment depicts how various qualities autonomously separate from each other when regenerative cells create. Free combination of qualities and their comparing attributes was first seen by Gregor Mendel in 1865 during his investigations of hereditary qualities in pea plants.
So, Independent assortment results in different combinations of genes in sex cells.
Also, Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
Thus, correct options are C and E.
Learn more about independent assortment.
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1000-kg car travelling down on a steepest road, which has inclined angle of 18
degree. Coefficient of kinetic friction is 0.3.
Calculate
1. Weight (force due to gravity).
2.Horizontal and vertical component of the weight
3. Normal force
4.Friction force
5. Net force along the plane down
6. Acceleration
Answer:
1
Explanation:
it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser
What is the wavelength of an FM radio wave of frequency 90Mhz?
a) 0.033m
b) 0.3m
c) 3.3m
d) 30m
Show calculation
Answer:
3.3m
Explanation:
Given parameters:
Frequency = 90Mhz
Unknown:
Wavelength = ?
Solution:
To find the wavelength, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 90 x 10⁶ x wavelength
Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex] = 3.3m
Find the y-component of this
vector:
Answer:
Dy = 49.01 [m]
Explanation:
The vertical component of the vector can be determined with the sine of the angle.
Dy = 92.5*sin(32)
Dy = 49.01 [m]
1. A curious physics student drops a book from a high building.
A. What is the VELOCITY of the brick after 3.0s?
B. How FAR(Distance) does the book fall during this time?
2. Suppose a free-fall ride at an amusement park starts at a rest and then drops.
A. What is the VELOCITY of the ride after 2.5s?
B. How FAR do people on the ride fall during the 2.5s time period?
3. You throw a ball downward from a window at a speed of 3.0 m/s.
A. How FAST will it be moving when it hits the sidewalk 2.0m below?
4. If I drop a photo copier off of a 45m tall building and splats on the ground below:
A. Calculate the TIME to hit the ground:
B. Calculate the VELOCITY just before:
Answer:
1.
A. Vf = 29.4 m/s
B. h = 44.1 m
2.
A. Vf = 24.5 m/s
B. h = 30.625 m
3.
A. Vf = 5.5 m/s
4.
A. t = 3.03 s
B. Vf = 29.7 m/s
Explanation:
1.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 3 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3 s)
Vf = 29.4 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²
h = 44.1 m
2.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 2.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(2.5 s)
Vf = 24.5 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²
h = 30.625 m
3.
A.
using 3rd equation of motion:
2gh = Vf² - Vi²
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 3 m/s
g = 9.8 m/s²
h = height = 2 m
Therefore,
2(9.8 m/s²)(2 m) = Vf² - (3 ms)²
Vf² = 39.2 m²/s² - 9 m²/s²
Vf = √30.2 m²/s²
Vf = 5.5 m/s
4.
A.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 45 m
Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)
t = time = ?
g = 9.8 m/s²
45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²
t² = 2(45 m)/(9.8 m/s²)
t = √9.18 s²
t = 3.03 s
B.
using 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.03 s)
Vf = 29.7 m/s
What is the magnitude of the applied electric field inside an aluminum wire of radius 1.5 mm that carries a 5.5-A current?
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
E = 2.17 x 10⁻² V/m
If a leaf falls from a tree, has work been done on the leaf? Explain.
Answer:
Hope this helps!
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
What is work?
Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
When the force has a component that is parallel to the displacement, positive work results. A system gains energy via constructive effort. When the force contains a component that is opposed to or against the displacement, negative work results. Energy is removed from the system or lost through negative labor.
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
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Part One: Defining the Problem and Sub-Problems
Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
After you have researched the problem, explain in your own words who the problem impacts and why it is important.
List two sub-problems that are part of the bigger problem but are more manageable and solvable.
Explain how these sub-problems are related to or a direct result of the overall problem.
Part Two: Criteria, Constraints, and Prioritizations
Choose one sub-problem that you will investigate further and explain which one you chose here.
List two realistic criteria for the sub-problem.
Explain why it is important for these criteria to be met in order to solve the problem.
List two constraints for the sub-problem.
Explain why these constraints exist. (How do they limit solutions to the problem?)
Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1
2
3
4
Part Three: Generate Solutions
List two solutions that you have generated for the chosen sub-problem.
Describe how the sub-problem can be solved, and include the research supporting each solution.
Explain how prioritization was involved in designing each solution.
Explain how both solutions to the sub-problem play a role in solving the larger problem.
List of the sources (at least three) you used for research, following the MLA style guide.
Answer:
Part One: Defining the Problem and Sub-Problems
1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
o I chose pollution, due to the overwhelming pollution in todays day and age.
2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.
o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.
o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.
o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.
o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.
o Pollution is harmful things within an environment, that can cause decay within an environment.
3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.
o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.
4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.
o Man made factories, cars, and garbage dumps.
o Being a litter bug (throwing trash on the ground).
5. Explain how these sub-problems are related to or a direct result of the overall problem.
o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o Cars/fuel
2. List two realistic criteria for the sub-problem.
o Reducing fuel and oil can help fix the problem.
o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.
3. Explain why it is important for these criteria to be met in order to solve the problem.
o It would create less air pollution, and could help with sickness, plants dying, and animals dying.
4. List two constraints for the sub-problem.
o Electric cars are a bit to expensive for the average person.
o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1. Fuel and oil Its highly needed to run cars but causes sever pollution.
2. Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.
3. Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.
4. Solar powered electric charge stations Low pollution and easily earth friendly acceptable.
Part Three: Generate Solutions
1. List two solutions that you have generated for the chosen sub-problem.
o Lowering prices on electric cars.
o Creating solar powered charge stations to reduce more pollution.
2. Describe how the sub-problem can be solved, and include the research supporting each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.
3. Explain how prioritization was involved in designing each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.
4. Explain how both solutions to the sub-problem play a role in solving the larger problem.
o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.
