a) |9+x|=2x
b) |x+6|=2x+9

HOPE ITS HELPFUL ^_^

The volume of this pipe considering the thickness of the pipe is 154 cubic inches.

The general formula to calculate the volume of a cylindric object such as a pipe is:

In this formula, d represents the diameter and h represents the height.

The external diameter is 6 inches; however, the pipe is 1.25 inches thick, which implies the real internal diameter is 3.5.

Now, let's calculate the volume:

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Answer:

D. 154 cubic inches

Step-by-step explanation:

Answer:

Center ( 4 , -2) and r = 6

Step-by-step explanation:

x² - 8x + y² + 4y - 16 = 0

x² - 8x  + y² + 4 y = 16

x²- 2*4x + y² + 2 *2y = 16

(x² - 2*4x + 16 ) - 16 + (y² + 2*2y + 4) -4 = 16

(x - 4)² + (y + 2)² = 16 + 16 + 4

(x - 4)² + (y -[-2])² = 36

(x- 4)² + ( y - [-2] )² = 6²

Compare with (x - h)²+ (y - k)² = r²

Center ( 4 , -2) and r = 6

Answer:

total surface area  = 298.45105 m2

lateral surface area = 141.37155 m2

top surface area = 78.53975 m2

bottom surface area = 78.53975 m2

Step-by-step explanation:

Joanna will need approximately 298.3 square inches of frosting to cover the entire cake.

To calculate the amount of frosting Joanna will need for the entire cake, we first need to find the surface area of the cylindrical cake.

The formula for the surface area of a cylinder is given by:

Surface Area = 2πr² + 2πrh

Where r is the radius of the base and h is the height of the cylinder.

Given that the diameter of the cake is 10 inches, we can find the radius by dividing it by 2: r = 10/2 = 5 inches.

Plugging in the values, we have:

Surface Area = 2π(5)² + 2π(5)(4.5)

Simplifying the equation:

Surface Area = 2π(25) + 2π(22.5)

Surface Area = 50π + 45π

Surface Area = 95π

To find the actual numerical value, we can approximate π as 3.14:

Surface Area ≈ 95 * 3.14

Surface Area ≈ 298.3 square inches

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Answer:

Its that squiglly one on top

Step-by-step explanation:

cuh cuh cuh cuh cuhc

Answer:

x/x∈R,x≤5 1/6

Step-by-step explanation:

Answer:

Create a function representing number of published articles per month:

[tex]a=12m+60[/tex]

Where:

Now substitute in the values of m to get the a-value:

Answer: D. Angles that form a linear pair are sometimes supplementary.

That is not true, linear pairs are always supplementary.

Answer:

D. Angles that form a linear pair are sometimes supplementary.

~OAmalOHopeO

Answer:

The area of rectangle BEFD is 180 square units.

Step-by-step explanation:

After checking the figure given, we have the following information:

[tex]AD = 15[/tex], [tex]AB = 12[/tex], [tex]BC = 15[/tex], [tex]CD = 12[/tex]

By Pythagorean Theorem, we determine the length of the line segment BD:

[tex]BD = \sqrt{AB^{2}+AD^{2}}[/tex] (1)

[tex]BD = \sqrt{12^{2}+15^{2}}[/tex]

[tex]BD = 3\sqrt{41}[/tex]

In addition, we know the following characteristics of the rectangle BEFD:

[tex]BD = EF[/tex], [tex]EF = EC + CF[/tex], [tex]BE = FD[/tex] (2), (3), (4)

By Pythagorean Theorem:

[tex]BC^{2} = BE^{2}+EC^{2}[/tex] (5)

[tex]CD^{2} = CF^{2}+DF^{2}[/tex] (6)

By (3), (4), (5) and (6):

[tex]BC^{2} = BE^{2} + EC^{2}[/tex] (7)

[tex]CD^{2} = (EF-EC)^{2} + BE^{2}[/tex] (8)

By (7) in (8):

[tex]CD^{2} = (EF-EC)^{2}+ (BC^{2}-EC^{2})[/tex]

[tex]CD^{2} = EF^{2}-2\cdot EF\cdot EC + EC^{2}+BC^{2}-EC^{2}[/tex]

[tex]CD^{2} = EF^{2}-2\cdot EF\cdot EC +BC^{2}[/tex]

Then, we clear [tex]EC[/tex]:

[tex]2\cdot EF\cdot EC = EF^{2} + BC^{2} - CD^{2}[/tex]

[tex]EC = \frac{EF^{2}+BC^{2}-CD^{2}}{2\cdot EF}[/tex]

If we know that [tex]EF = 3\sqrt{41}[/tex], [tex]BC = 15[/tex] and [tex]CD = 12[/tex], then the length of the segment [tex]EC[/tex] is:

[tex]EC = \frac{75\sqrt{41}}{41}[/tex]

And the length of the line segment [tex]CF[/tex] is:

[tex]CF = EF - EC[/tex]

[tex]CF = 3\sqrt{41}-\frac{75\sqrt{41}}{41}[/tex]

[tex]CF = \frac{48\sqrt{41}}{41}[/tex]

And the length of the line segment [tex]DF[/tex] is determined by Pythagorean Theorem:

[tex]FD = \sqrt{CD^{2}-CF^{2}}[/tex]

[tex]FD = \sqrt{12^{2}-\left(\frac{48\sqrt{41}}{41} \right)^{2}}[/tex]

[tex]FD = \frac{60\sqrt{41}}{41}[/tex]

And the area of the rectangle is determined by the following formula:

[tex]A = FD\cdot EF[/tex]

[tex]A = \left(\frac{60\sqrt{41}}{41} \right)\cdot (3\sqrt{41})[/tex]

[tex]A = 180[/tex]

The area of rectangle BEFD is 180 square units.

Answer:

n = 3

Step-by-step explanation:

Given

5 + 8n = 7(- 7 + 4n) - 6 ← distribute parenthesis on right side

5 + 8n = - 49 + 28n - 6 ( subtract 28n from both sides )

5 - 20n = - 55 ( subtract 5 from both sides )

- 20n = - 60 ( divide both sides by - 20 )

n = [tex]\frac{-60}{-20}[/tex] = 3

Yes. When a graph has more than one line it is a piece wise graph.

Answer:

42.1

Step-by-step explanation:

The height of the main triangle is,

h = 47√3/2 (since it's an 30-60-90 triangle)

so to find x,

tan(44) = h/x

x = h/tan(44)

x = 42.1 (rounded to the nearest tenth)

Answered by GAUTHMATH

Answer:

Factored Form: y=(x+1) ( x+3)y=(x+1)(x+3)

X-intercepts: (-1,0), (-3,0)(−1,0),(−3,0)

Axis of Symmetry: x= -2x=−2

Vertex: (-2,-1)(−2,−1)

Domain: (\begin{gathered}(-\infty , \infty ), ( x | x ER)\\\end{gathered}

(−∞,∞),(x∣xER)

Range: y > =-1y>=−1

Answer:

The smallest number is -10

Answer:

it's -10

Step-by-step explanation:

Well, if you look at the number line, numbers start from the left going to the right and the ones before the 0 ( the negative ones) are the smaller ones. And here if you arrange them from the smallest, -10 is the smallest and 2 is the biggest.

hope this helps

Answer:

-27tn

Step-by-step explanation:

Use KIO (keep, inverse, opposite) then divide.

Answer:

Slope is (1/4)

Step-by-step explanation:

The slope is calculated by (6-5)/(5-1)=1/4

Answer:

Step-by-step explanation:

6 + 2 = 4,  given

6 + 5 = 11, correct

Answer:

y - 4 = 8/5 (x - 0)

Step-by-step explanation:

first, find the slope using the points given ((0,4) and (-5,-4))

use the following formula to find the slope:

m= y2 - y1/x2 - x1

using this formula you should get the following:

m= -4-4/-5-0 = -8/-5 = 8/5

using the point (0,4) and the slope, it into the slope-point form (y-y1=m(x-x1)

the answer should be: y - 4 = 8/5(x - 0)

Answer:

C) x=2

[tex]3x+8=4x+6[/tex]

[tex]8-6=4x-3x[/tex]

[tex]x=2[/tex]

~OAmalOHopeO

3x + 8 = 4x + 6

3x - 4x = 6 - 8

-x = -2

x = 2

Answer:

(3+3) / (2+3) = 6/5

:)))

..........

Answer:

58,59

Step-by-step explanation:

Let x be the first integer

x+1 be the next consecutive integer

x + x+1 = 117

2x+1 = 117

2x +1-1 =117-1

2x = 116

2x/2 = 116/2

x = 58

x+1 = 59

Answer:

33.80

Step-by-step explanation:

AB = BC = AD√2

AB = BC = 7√2

AD = DC

AC = 2AD

perimeter = AC + AB + BC

= 2AD  + 2AB

= 2(7) + 2(7√2)

= 14 + 14√2

≈ 33.80

Answer:

33.8

Step-by-step explanation:

45-45-90 degree triangle rules states that the sides that are opposite the angles measure 45 degrees have the same value. That means that BD has the same value as AD, which is 7. Since triangle BDC is also a 45-45-90 degree triangle, DC is equal to BD, which is 7. We have the value of AC, which is 7+7=14. Now, we can use the Pythagorean theorem to figure out BC and AB. We know that [tex]DC^2+BD^2=BC^2[/tex]. We know that DC and BD is equal to 7, so we can simplify that to [tex]49+49=BC^2[/tex], and we can further simplify that to [tex]BC=\sqrt{98}[/tex]. This is also equal to [tex]7\sqrt{2}[/tex]. Since BC is also equal to AB because of 45-45-90 degree triangle rules, we have the perimeter of the triangle as

[tex]7\sqrt{2} + 7\sqrt{2}+14[/tex], which is equal to [tex]14\sqrt{2} + 14[/tex]. We can simplify 14 times the square root of 2 as 19.8 (rounded to 2 decimal places). We have the answer as 19.8 + 14, which is 33.8.

Answer: Approximately 17.69

Step-by-step explanation:

The formula needed to find the third side of this equation is the Pythagorean theorem. Which is as follows:

[tex]a^2+b^2=c^2\\c=\sqrt{a^2+b^2}[/tex]

The difference between the two is that the first one after you do [tex]a^2+b^2[/tex] you still need to square root the answer you get to get the third side, aka. the hypotenuse. If you do the second method, you get the answer after you do the calculation which is a lot easier.

Below are the calculations needed to be made in both ways:

[tex]12^2+13^2=313\\\sqrt{313}= 17.69[/tex]   17.69 was rounded to the hundredths place.

[tex]\sqrt{12^2+13^2}=17.69[/tex]   once again this answer was rounded to the hundredths place.

[tex]a^2+b^2[/tex] are respectively for the sides of the triangles.

[tex]c^2[/tex] is respectively for the hypothenuse, which is the longest side, and across from the right angle (located by a box).

Answer:

5 or 17.69

Step-by-step explanation:

1st case senario:

c^2=a^2+b^2

c^2=12^2+13^2

c^2=144+169

c^2=313

c^2=[tex]\sqrt{313}[/tex]

c=17.69

2nd case senario:

144+b^2=169

b^2=169-144

b^2=25

b^2=[tex]\sqrt{25}[/tex]

b+5

Answer:

-5, - 2, 3

Step-by-step explanation:

y=2x+3, y=-7, x=-5; y=-1, x=-2, y=9, x=3

Answer:

Perimeter, P = 112 meters

Step-by-step explanation:

Translating the word problem into an algebraic expression, we have;

L = 6W  ...... equation 1

Given the following data;

To find the perimeter of the rectangle;

First of all, we would determine the dimensions of the rectangle using its area.

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = LW  ..... equation 2

Substituting eqn 1 into eqn 2, we have;

384 = 6W(W)

384 = 6W²

Dividing both sides by 6, we have;

W² = 384/6

W² = 64

Taking the square root of both sides, we have;

W = √64

Width, W = 8 meters

Next, we would find the length;

L = 6W

L = 6 * 8

Length, L = 48 meters

Lastly, we would determine the perimeter of the rectangle using the above dimensions;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Substituting the values into the formula, we have;

Perimeter, P = 2(48 + 8)

Perimeter, P = 2(56)

Perimeter, P = 112 meters

Answer:

B

Step-by-step explanation:

x((7/2)-(7/3))=y+x

x(7/6)=y+x

7x=6y+6x, x=6y. y/x=1/6

It's bottom left

It says let C represent the cost of a one-year membership.

C is 80 in order to represent the day you must divide it by 10.

which gives one box for day and 10 boxes for year