A 25.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to 50.00 grams of water initially at 10.55 degrees Celcius. The final temperature of the system is 20.15 degrees Celcius. Calculate the specific heat of the metal. (The specific heat of water is 4.184 J/g*C).

Answers

Answer 1

Answer:

1.0188 J/g*C

Explanation:

Using the formula; Q = m × c × ∆T

Q(water) = -Q(metal)

m × c × ∆T (water) = -{m × c × ∆T (metal)}

According to this question,

mass of metal = 25g

initial temp of metal = 99°C

mass of water = 50g

initial temp of water = 10.55°C

final temperature of the system = 20.15°C

c of water = 4.184 J/g*C

50 × 4.184 × (20.15 - 10.55) = 25 × c × (20.15 - 99)

209.2 × 9.6 = 25c × -78.85

2008.32 = -1971.25c

c = 2008.32 ÷ 1971.25

c of metal = 1.0188 J/g*C


Related Questions

The first step of electrophilic aromatic substitution involves the formation of the arenium ion intermediate.

a. True
b. Fasle

Answers

Answer:

True

Explanation:

Aromatic compounds undergo substitution rather than addition reactions because the aromatic structure is maintained.

Electrophilic aromatic substitution begins with attack of the electrophile on the aromatic ring to yield a delocalized intermediate called the arenium intermediate. Loss of hydrogen from this intermediate yields the final product.

Which chemical can remove color of red/Pink phenol and make it clear like water transparent?

Answers

Lethal of skin by absorption

calculate the hydrogen ion concentration of a solution who's pH is 2.4​

Answers

Answer:

I don't know sorry yyyyyyy6yyyyyyyyyyyyyyyyyyyyyyyyyyy

The graph below shows how the temperature and volume of a gas vary when
the number of moles and the pressure of the gas are held constant. What
happens to the
temperature of a gas as its volume increases?
A. The temperature decreases
B. The temperature increases
C. The temperature remains the same.
D. The temperature doubles.

Answers

Answer:

C

Explanation:

because it remains the same

Calculate the molarity of a solution consisting of 65.5 g of K2S0 4 in 5.00 L of solution. ​

Answers

Answer:

Molarity is 0.075 M.

Explanation:

Moles:

[tex]{ \tt{ = \frac{65.5}{RFM} }}[/tex]

RFM of potassium sulphate :

[tex]{ \tt{ = (39 \times 2) + 32 + (16 \times 4)}} \\ = 174 \: g[/tex]

substitute:

[tex]{ \tt{moles = \frac{65.5}{174} = 0.376 \: moles}}[/tex]

In volume of 5.00 l:

[tex]{ \tt{5.00 \: l = 0.376 \: moles}} \\ { \tt{1 \: l = ( \frac{0.376}{5.00} ) \: moles}} \\ { \tt{molarity = 0.075 \: mol \: l {}^{ - 1} }}[/tex]

Which one of these statements is/are true: I. All redox reactions with positive emfs are spontaneous. II. If a redox reaction is spontaneous, it must be fast. III. A spontaneous redox reaction will have a cathode reaction that has a more negative reduction potential than the anode. III only. I and III are true. I only. II only. All of I, II, and III are true.

Answers

Answer:

yea all the answers are true

Redox reaction is the transfer of the electron from one species to another. All of the three statements are true about the redox reaction.

What is a redox reaction?

A redox reaction is a type of chemical reaction in which the electrons are gained and lost by a species. The positive EMF of the cell results in spontaneous and will move the reaction in the forward direction.  

In a redox reaction, the cathode reaction is comparatively more negative than the reduction potential present at the anode.

Therefore, option E. All I, II, and III are true.

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At what velocity (m/s) must a 20.0g object be moving in order to possess a kinetic energy of 1.00J

Answers

Answer:

10 ms-1

Explanation:

Kinetic energy = 1/2 × m × v^2

1 = 1/2× 20 ×10^ -3 × v^2

v ^ 2 = 100

v = 10 ms-1

note : convert grams in to kg before substitution as above

The velocity will be "10 m/s".

Given:

Kinetic energy,

K.E = 1.00 J

Mass,

m = 20.0 g

We know the formula,

→ [tex]K.E = \frac{1}{2} mv^2[/tex]

By putting the values, we get

       [tex]1 = \frac{1}{2}\times 20\times 10^{-3}\times (v)^2[/tex]

     [tex]v^2 = 100[/tex]

       [tex]v = \sqrt{100}[/tex]

       [tex]v = 10 \ m/s[/tex]

Thus the above response is correct.

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1. Metallic strontium crystallizes in a face-centered cubic lattice, with one Sr atom per lattice point. If the edge length of the unit cell is found to be 608 pm, what is the metallic radius of Sr in pm?
2. The substance beta manganese is found to crystallize in a cubic lattice, with an edge length of 630.0 pm. If the density of solid beta manganese is 7.297 g/cm3, how many Mn atoms are there per unit cell?

Answers

Answer:

[tex]r=215pm[/tex]

[tex]N_{Mn}=20[/tex]

Explanation:

From the question we are told that:

Edge length of the unit cell [tex]l=608pm[/tex]

a)

Generally the equation for The relationship between edge length and radius is mathematically given by

[tex]4r=\sqrt{2a}[/tex]

Therefore

[tex]4r=\sqrt{2*608}[/tex]

[tex]r=\frac{\sqrt{2*608}}{4}[/tex]

[tex]r=215pm[/tex]

b)

From the question we are told that:

Density [tex]\rho=7.297[/tex]

Edge length of [tex]l=630.0 pm=>630*10^-{10}[/tex]

Therefore Volume  is given as

[tex]V=l^3[/tex]

[tex]V=630*10^-{10}^3[/tex]

[tex]V=2.50047*10^{−22}[/tex]

Generally the equation for Mass is mathematically given by

[tex]m=Volume*density[/tex]

[tex]m=V*\rho[/tex]

[tex]m=2.50047*10^{−22}*7.297[/tex]

[tex]m=1.83*10^{-21}g[/tex]

Therefore Molarity is given as

[tex]n=\frac{M}{Molar M}[/tex]

[tex]n=\frac{1.83*10^{-21}g}{55}[/tex]

[tex]n=3.32*10^{-23}[/tex]

Finally The atoms in a unit cell is

[tex]N_{Mn}=Moles*Avogadro\ constant[/tex]

[tex]N_{Mn}=3.32*10^{-23}*6.023*10^{23}[/tex]

[tex]N_{Mn}=20[/tex]

What is the molecular formula of following show how it is done.1 nitric acid 2 Sulphuric acid 3 Methane 4 Potassium oxide 5 Silver chloride 6 Limestone . Answer it ASAP.Thank u​

Answers

Answer:

1.HNO₃

Nitric acid is a nitrogen oxoacid of formula HNO3 in which the nitrogen atom is bonded to a hydroxy group and by equivalent bonds to the remaining two oxygen atoms.

2.H₂SO₄

3.CH₄

Methane (US: , UK: ) is a chemical compound with the chemical formula CH4 (one atom of carbon and four atoms of hydrogen). It is a group-14 hydride and the simplest alkane and is the main constituent of natural gas.

4.K₂O

5.AgCl

6.CaCO3

Limestone consists of calcium carbonate, which has the chemical formula CaCO3. Limestone exists in sedimentary and crystalline form.

Explanation:

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Magnesium metal is reacted with hydrochloric acid to produce
hydrogen gas. A sample of hydrogen gas is collected over water
in a eudiometer at 28.0°C. The atmospheric pressure is 636
mmHg. Determine the pressure (in atm) of the hydrogen gas
produced
Pressure =
atm

Answers

The pressure of hydrogen gas is 607.7 mmHg

According of Dalton's law of Partial pressure, the total pressure of a mixture of gases is the sum of the partial pressures of the individual gases in the mixture.

We can now write;

The for hydrogen collected over water, we have a mixture of hydrogen gas and water vapour.

Total pressure = pressure of hydrogen gas + vapour pressure of water

Pressure of hydrogen gas = Total pressure - vapour pressure of water

Pressure of hydrogen gas =  636 mmHg - 28.3 mmHg

Pressure of hydrogen gas = 607.7 mmHg

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he FAA restricts how much lithium to carry on an airplane. The rule-of-thumb is a battery has 0.3 g of lithium per Ampere-hour (Ah). A laptop battery is rated as 5 Ah per cell and contains 4 cells. Find the lithium content in grams. (compare with the FAA limit of 8 grams)

Answers

Answer:

The right answer is "6 gm".

Explanation:

Given:

Amount of Li,

= 0.3 gm

Battery rated,

= 5 Ah per cell

Total number of cells,

= 4

The total power limit will be:

= [tex]5\times 4[/tex]

= [tex]20 \ Ah[/tex]

hence,

The amount of Li in battery will be:

= [tex](0.3)\times 20[/tex]

= [tex]6 \ gm[/tex]

(Allowed for transportation).

The products of nuclear reaction usually have a different mass than the reactants why?

Answers

Answer:

Explanation:

The best way to explain this is to use an example

[tex]I\frac{125}{53} + e \frac{0}{-1} ====> Te\frac{125}{52}[/tex]

You have to understand what happened. A electron was shot into the nucleus of the Iodine. That electron change the entire composition of the nucleus resulting in 52 protons. The mass remained the same (125) but the nucleus was altered. The chemical became 125 52 Tellurium.  But what is important is that it takes a tremendous amount of energy to disrupt a nucleus, and a new chemical is born from that disruption.

State the different radiations emitted by radioactive elements.

Answers

The emissions of the most common forms of spontaneous radioactive decay are the alpha (α) particle, the beta (β) particle, the gamma (γ) ray, and the neutrino.

Answer: Alpha, beta, and gamma after the first three letters of the Greek alphabet. Alpha and beta particles consist of matter, and gamma rays are bursts of energy. The type of radiation emitted depends on the radioactive substance; cesium-137, for example, produces beta and gamma radiation but not alpha particles.

Sally has constructed a concentration cell to measure Ksp for MCln. She constructs the cell by adding 2 mL of 0.05 M M(NO3)n to one compartment of the microwell plate. She then makes a solution of MCln by adding KCl to M(NO3)n. She adds 7.903 mL of the resulting mixture to a second compartment of the microwell plate. Sally knows n = +2. She has already calculated [Mn+] in the prepared MCln solution using the Nernst equation. [Mn+] = 8.279 M

Required:
How many moles of [Cl-] must be dissolved in that compartment?

Answers

Answer:

0.1309 mol

Explanation:

From the given information:

The metal ion, two ions of [tex]M^{+}[/tex] reacted with Cl⁻ to form [tex]MCl_n[/tex] i.e. the compound formed is [tex]MCl_2[/tex].

The concentration of the metal ion formed [tex][M^+][/tex] = 8.279 M

The concentration of the chlorine ion formed [tex][Cl^-][/tex] = 2 × 8.279 M

= 16.558 M

We know that:

[tex]\mathsf{Molarity = \dfrac{no \ of \ moles }{volume (mL)}}[/tex]

The number of moles of [tex][Cl^-][/tex] = [tex]16.558 \ mol.L^{-1} \times 7.903 \ mL \times \dfrac{1 \ L}{1000 \ mL}[/tex]

= 0.1309 mol

Arrange the following ions in order of increasing ionic radius.

a. sulfide ion
b. calcium ion
c. phosphide ion
d. potassium ion

Answers

Answer:

Ca 2+ <K  +  <Ar<Cl  −  <S  2−

Explanation:

Ar,K  + ,Cl  − ,S  2− ,Ca  2+

 have the same number of electrons. Their radii would be different because of their different nuclear charges. The cation with the greater positive charge will have a smaller radius because of the greater attraction of the electrons to the nucleus. Anion with the greater negative charge will have the larger radius. In this case, the net repulsion of the electrons will outweigh the nuclear charge and the ion will expand in size. Hence the correct order will be Ca  

2+  <K +  <Ar<Cl  −  <S  2−

 

Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar, 520 K. If the carbon dioxide behaves as an ideal gas, determine the amount of entropy produced, in kJ/K.

Answers

This question is incomplete, the complete question is;

Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar, 520 K. If the carbon dioxide behaves as an ideal gas, determine the amount of entropy produced, in kJ/K. Assuming;

a) constant specific heats Cp = 0.939 kJ/Kg K

b) variable specific heats

Answer:

a) the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced is 0.69845 kJ/K

Explanation:

Given the data in the question;

5 kg of carbon dioxide (CO₂) gas undergoes a process in a well-insulated piston-cylinder assembly.

m = 5 kg

Molar mass M = 44.01 g/mol

P₁ = 2 bar, P₂ = 20

T₁ = 280 K, P₂ = 520 K

Since its insulated { q = 0 } ( kinetic and potential energy effects = 0 )

Now,

a) the amount of entropy produced, in kJ/K, Assuming constant specific heats with Cp = 0.939 kJ/Kg K

S[tex]_{Generation[/tex] = m × ((Cp × In( T₂/T₁) - R × In( P₂/p₁ ))

we substitute

S[tex]_{Generation[/tex] = 5 × (( 0.939  × In( 520/280) - 0.1889 × In( 20/2 ))

= 5 × ( 0.5812778 - 0.434958 )

= 5 × 0.1463198

= 0.731599 kJ/K

Therefore, the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced, in kJ/K, Assuming variable specific heats.

Now, from  Table A-23: Ideal Gas Properties of Selected Gases;

T₁,T₂ : s₁⁰ = 211.376 kJ/kmol-K, s₂⁰ = 236.575 kJ/kmol-K

now, s₁ = s₁⁰ / M and s₂ = s₂⁰ / M

we substitute

s₁ = s₁⁰ / M = 211.376 / 44.01  = 4.8029 kJ/kg

s₂ = s₂⁰ / M = 236.575 / 44.01 = 5.37548 kJ/kg

S[tex]_{Generation[/tex] = m × (( s₂ - s₁ ) - R × In( p₂ / p₁ ))

we substitute

S[tex]_{Generation[/tex] = 5 × (( 5.37548 - 4.8029  ) - 0.1880 × In( 20 / 2 ))

= 5 × ( 0.57258 - 0.432885997 )

= 5 × 0.13969

= 0.69845 kJ/K

Therefore, the amount of entropy produced is 0.69845 kJ/K

Two flasks are connected by a closed valve. One contains gas particles and the other contains a vacuum. If the valve is opened such that the particles move until they fill both flasks, the process by which the particles can reconvene entirely in one of the flasks is:

Answers

Answer: The process by which the particles can reconvene entirely in one of the flasks is: NONSPONTANEOUS.

Explanation:

The spontaneity of a process can affect the distribution of energy and matter within the system. Different chemical or physical processes have the natural tendency to occur in one direction under a given set of conditions. For example:

--> when water is pour down a hill it naturally flows down but it requires outside energy maybe from a water pump to flow up the hill and ,

--> during an iron rust, iron that is exposed to atmosphere will corrode, but rust is not converted to iron without intentional chemical treatment.

Therefore, a spontaneous process is one that occurs naturally under certain conditions. While a NONSPONTANEOUS process, on the other hand, will not take place unless it is initiated by the continual input of energy from an outside source. A process that is spontaneous in one direction under a particular set of conditions is nonspontaneous in the REVERSE direction.

From the two flasks that where connected through a valve, once the valve was opened, the gas spontaneously becomes evenly distributed between the flasks. To reverse this, it would require an external energy making the reconvening of the particles back to the first flask a NONSPONTANEOUS PROCESS .

12.39 HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-Markovnikov addition product). What intermediates leading to the formation of the major product are observed when 1-butene is treated with 1) HBr or 2) HBr/peroxides

Answers

Answer:

See explanation and image attached

Explanation:

The reaction of HBr with 1-butene is an addition reaction. The HBr adds across the double bond to yield a saturated halogenoalkane.

In the absence of peroxides, the reaction proceeds in accordance with Markovnikov rule which states that;''the negative part of the addendum, is attached to the carbon atom with the least number of hydrogen atoms attached.'' This occurs in the first reaction shown in the image.

In the presence of peroxides, the reaction proceeds in an anti-Markovnikov manner to yield the product shown in the second reaction.

You are titrating 24.3 mL of 2.00 M HCl with 1.87 M NaOH. How much NaOH do you expect to have added when you reach the equivalence point?

26.0 mL

15.4 mL

13.4 mL

Answers

Answer:

26mL

Explanation:

NaOH+HCl= NaCl+H2O

nHCl=0.0243*2=0.0486

nNaOh=nHCl

VNaOH=0.0486/1.87=0.026l=26ml

Answer:

26.0 mL

Explanation:

If ionization energy of hydrogen atom is 13.6 eV then its ionization potential will be

Answers

Ionization potential and ionization energy are two terms used to describe the same thing.

The ionization potential of hydrogen atom is 13.6 eV

The ionization potential is the energy that is required to remove an electron from the neutral atom. It is the same as the ionization energy.

From the question, we can see that the ionization energy of the hydrogen atom is 13.6 eV, it also means that the ionization potential of the hydrogen atom is also 13.6 eV.

Therefore, If ionization energy of hydrogen atom is 13.6 eV then its ionization potential will be 13.6 eV

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Avogradro's number is the number of particles in one gram of carbon- 12 atom true or false?​

Answers

Answer:

True

Explanation:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

How is the rate of a reaction affected when the temperature increases?
A. The rate decreases because the reactant particles move too
quickly to react.
B. The rate increases because the equilibrium constant increases.
C. The rate increases because the reactant particles collide more
often.
D. The rate decreases because the products reform the reactants more quickly
more quickly.

Answers

D the rate decreases because the products reform the reactants more quickly more quickly.

The rate of reaction increases when the temperature increases because the reactant particles collide more often and the correct option is option C.

What is Rate of reaction?

The rate of reaction refers to the speed at which the products are formed from the reactants in a chemical reaction. It gives some insight into the time frame under which a reaction can be completed.

The rate or speed of reaction can be defined as the change in the concentration of any one of the reactants or products per unit time.

The rate is higher at higher temperatures because colliding particles will have the required activation energy at high temperature and more successful collisions will take place.

Therefore, The rate of reaction increases when the temperature increases because the reactant particles collide more often and the correct option is option C.

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The standard redox potentials of isolated components of an electron transport chain in a cyanobacterium are found to be as follows:
Complex A: standard redox potential: -100 mV
Complex B: standard redox potential: -780 mV
Complex C: standard redox potential: +510 mV
Complex D: standard redox potential: +310 mV
Plastocyanin: standard redox potential: +360 mV
Which complex will likely have a binding site with high affinity for reduced plastocyanin?
A. Complex A.
B. Complex B.
C. Complex C.
D. Complex D.

Answers

Answer:

B. Complex B.

Explanation:

Complex B will have binding site with high affinity for reduced plastocyanin due to greater redox potential. The high number of redox potential will will transport electron chain in cyanobacteria.

Redox potential is the measure of the electron gain or loss to the electrode. For reduced plastocyanin complex B will have the highest affinity.

What is electron affinity?

Electron affinity is the energy released when the atom gets attached to the atom or other molecule. The high number of redox potential increases the electron transport in the cell.

The greater the redox potential more will be its tendency to show electron affinity. To bond with reduced species, the oxidized species must have greater redox potential.

Therefore, option B. complex b will have the highest affinity.

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What is alkaline and what is acidic pH

Answers

Answer:

An alkaline is a substance that dissolves in water to produce hydroxyl ions (OH-)

Explanation:

The pH range of an alkaline is from 8–14.

Acidic pH ranges from 0–6.9.

Determine the value of the equilibrium constant for the following reaction, where the following amounts of each species are present at equilibrium in a 5.00 L container: 1.34 mol HCl, 4.30 mol O2, 30 g H2O, and 2.42 mol Cl2.
4 HCl(g) O2(g) ----> 2 H2O(l) 2 Cl2(g)

Answers

Explanation:

here's the answer to your question about

You need to make an aqueous solution of 0.182 M aluminum sulfate for an experiment in lab, using a 250 mL volumetric flask. How much solid aluminum sulfate should you add

Answers

Answer:

Hence, 15.99 g of solid Aluminum Sulfate should be added in 250 mL of Volumetric flask.

Explanation:

To make 0.187 M of Aluminum Sulfate solution in a 250 mL (0.250 L) Volumetric flask  

The molar mass of Aluminum Sulfate = 342.15 g/mol  

Using the molarity formula:-  

Molarity = Number of moles/Volume of solution in a liter  

Number of moles = Given weight/ molar mass  

Molarity = (Given weight/ molar mass)/Volume of solution in liter  

0.187 M = (Given weight/342.15 g/mol)/0.250 L  

Given weight = 15.99 g  

A reaction rate increases by a factor of 500. in the presence of a catalyst at 37oC. The activation energy of the original pathway is 106 kJ/mol. What is the activation energy of the new pathway, all other factor being equal

Answers

Answer:

[tex]E_2=999984KJ/mole[/tex]

Explanation:

From the question we are told that:

Factor [tex]dK=500[/tex]

Temperature [tex]T=37 C=310k[/tex]

Activation energy [tex]E=10^6kJ/mol[/tex]

Generally the Arhenius equation is mathematically given by

[tex]ln \frac{K_2}{K_1}=\frac{ E_1-E_2}{RT}[/tex]

Where

[tex]\frac{K_2}{K_1}=500[/tex]

[tex]ln 500=\frac{ 10^6-10^3-E_2}{8.314*310}[/tex]

[tex]E_2=999984KJ/mole[/tex]

The activation energy of the new reaction is 105.99 kJ/mol.

Using the Arrhenius equation;

ln(k2/k1) = -Ea2/RT2 +  Ea1/RT1

Now, from the information in the question;

k2/k1 = 500

Ea = ?

R = 8.314 JKmol-1

T2 = 37oC + 273 = 310 K

T1 = 37oC + 273 = 310 K

Substituting values;

ln (500) =- Ea2 + Ea1

6.2 = -Ea2 + 106 × 10^3 J

Ea = 106 × 10^3 J - 6.2

Ea = 105.99 × 10^3 J  or 105.99 kJ/mol

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When the equation,
O2 + __C 10H 22 →
CO2 +
H2O is balanced, the coefficient of O2 is?

Please help!

Answers

(10)O_2+C_10 H_22-->(10)CO_2+(11)H_2 O

This is the correct balanced equation

The coefficient would be (20) when you multiply 10 by 2

cesium-131 has a half life of 9.7 days. what percent of a cesium-131 sample remains after 60 days?

Answers

1.37% of cesium–131 will remain after 60 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 9.7 days

Time (t) = 60 days

Percentage remaining after 60 days =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 9.7 days

Time (t) = 60 days

Number of half-lives (n) =?

n = t / t½

n = 60 / 9.7

Finally, we shall determine the percentage remaining. This can be obtained as follow:

Let the original amount be N₀

Let the amount remaining be N

Number of half-lives (n) = 60 / 9.7

N = N₀ / 2ⁿ

Divide both side by N₀

N/N₀ = 1/2ⁿ

N/N₀ = 1 / 2⁽⁶⁰÷⁹•⁷⁾

N/N₀ = 0.0137

Multiply by 100 to express in percentage

N/N₀ = 0.0137 × 100

N/N₀ = 1.37%

Therefore, the percentage remaining after 60 days is 1.37%

NOTE; N/N₀ is the fraction remaining.

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I don’t know what Ksp and Kf are stand for?

Answers

Answer:

Sorry but I know only what ksf stand for

Explanation:

Ksf stand for solubility product constant

Answer:

ksp stands for solubility product constant .

kf stands for molal freezing point depression constant ..

Explanation:

KSP = The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution. It represents the level at which a solute dissolves in solution. The more soluble a substance is, the higher the Ksp value it has .

KF = Kf is a constant for a given solvent. Kf is called the molal freezing point depression constant and represents how many degrees the freezing point of the solvent will change when 1.00 mole of a nonvolatile nonionizing (nondissociating) solute dissolves in one kilogram of solvent.

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