Starting at (0,0) an object travels 36 meters north and then it covers 20 meters east. What is
the magnitude and direction of its displacement? (
Answer:
Explanation:
Using the pythagoras theorem, the displacement is expressed as;
d² = x²+y²
y = 36m (north)
x = 20m east
Substitute;
d² = 36²+20²
d² = 1296+400
d² = 1696
d = √1696
d = 41.18m
For the direction;
theta = tan^-1(y/x)
theta = tan^-1(36/20)
theta = tan^-1(1.8)
theta = 60.95°
Hence the magnitude is 41.18m and the direction is 60.95°
Which best describes most covalent compounds? resilient brittle cold warm
Answer:
B) brittle
Explanation:
This describes most covalent compounds.
Answer:
B.)
Explanation:
The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.
A roller coaster car is traveling 1 m/s at the top of the track. At the bottom of the track, 5 seconds later, it is traveling 36 m/s. What is the average acceleration?
Answer:
Explanation:
F
A car travels with a constant acceleration of 2.4 m/s2. Find the mass of the car if an 1850 N net force is required to produce this acceleration.
Answer:
770.83 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{1850}{2.4} \\ = 770.83333...[/tex]
We have the final answer as
770.83 kgHope this helps you
An object is thrown with a horizontal velocity of 49mt/sec and a vertical velocity of 18.8 mt/sec. How long will the object take to return to earth. Please help asap
Answer:
The object takes 3.84 seconds to return to earth.
Explanation:
Projectile Motion
It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.
The initial velocity has two components, given by:
[tex]v_x=vo_x[/tex]
[tex]v_y=vo_y-gt[/tex]
Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.
The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:
[tex]vo_y-gt=0[/tex]
[tex]\displaystyle t_m=\frac{vo_y}{g}[/tex]
The initial vertical component of the velocity is 18.8 m/s, thus:
[tex]\displaystyle t_m=\frac{18.8}{9.8}=1.92~s[/tex]
The total time is double that time:
[tex]t_t=2*1.92~s=3.84~s[/tex]
The object takes 3.84 seconds to return to earth.
