A 2013 study by pediatrician investigates whether it in better to give children the diphtheria, tetanus and pertussis (DTaP) vaccine in the thigh or the arm. The pediatricians collected the data from two different random samples. The first random sample was collected from children who were given the vaccine in the thigh. The second random sample was collected from children who were given the vaccine in the arm. Pediatricians recorded whether the children had a severe reaction or not. Reference: Jackson. LA., Peterson. D., Nelson. J.C., et al. (13 00 authors). 2013. Vaccination site and risk of local reaction in children one through six years of age. Pediatrics 131:283-289 Pediatricians conducted a chi square test of independence. The chi square test statistic fix this data is 2.0609 with a P value of O 1511. What can the pediatrician conclude? A) There is a statistically significant association between vaccine location and severe reaction. B) Pediatrician, have strong evidence that the severe reaction, to vaccine depend on location of the vaccine. C) The pediatricians cannot make a conclusion The conditions, for use of the chi-square test are not met. D) There is not enough evidence to conclude that there is. an association between vaccine location and severe reaction.

Answers

Answer 1

Answer:

A

Step-by-step explanation:

Since chi-squared calculated value is greater than p-value, there is a relationship between vaccine location and severe reaction.

Answer 2

Answer:

Step-by-step explanation:

This survey is testing for an association between the vaccine location and severe reactions using the chi-square test of independence.

Null hypothesis: Vaccine location and severe reactions are independent

Alternative: Vaccine location and severe reactions are not independent

With a chi square test statistic of 2.0609 with a P value of 0.1511. Using the p- value in comparison to either α = 0.05 or 0.01, the pediatricians can fail to reject the null as the p-value is greater than 0.05 or 0.01 and can conclude that there is a statistically significant association between vaccine location and severe reaction.

This approach was appropriate because the sampling method was simple random sampling, the variables that were under study were categorical, and the expected frequency count was at least 5 in all values to be able to reach  value of 283 and 289.


Related Questions

Which problem situation matches the equation below 59+74+62+x/4=70

Answers

Answer:

x = 85

Step-by-step explanation:

The equation is not properly written. Here is the correct expression

[tex]\frac{59+74+62+x}{4} = 70[/tex]

Find the problem situation that matches according to the steps below:

Step 1: We will cross multiply

[tex]59+74+62+x = 4*70\\59+74+62+x = 280\\195+x = 280\\[/tex]

Step 2: Subtract 195 from both sides of the equation

[tex]195+x-195 = 280-195\\x = 280-195\\x = 85[/tex]

Micaela tried to rotate the square 180 about the origin. Is her rotation correct? If not, explain why

Answers

Answer:no the vertices of the image and pre image don’t correspond

Step-by-step explanation:

Just did it

No, the vertices of the image and pre-image do not correspond

Step-by-step explanation:

It’s correct

simplify the expression 4^4/4^6

Answers

Answer:

[tex]1/16[/tex]

Step-by-step explanation:

[tex]\frac{4^{4} }{4^{6} }[/tex]

[tex]4^{4-6}[/tex]

[tex]4^{-2}[/tex]

[tex]\frac{1}{4^{2} }[/tex]

[tex]\frac{1}{16}[/tex]

What’s the correct answer for this?

Answers

Answer:

x=5

Step-by-step explanation:

5x- 7 = 18

5x=18+7

5x=25

Therefore, 5 will cancel 25 five(5) times.

x= 5.

Answer:

x = 5

Step-by-step explanation:

Since AB is the bisector, so MO is equal to NO

MO = NO

5x-7 = 18

5x = 18+7

5x = 25

Dividing both sides by 5

x = 5

On average, 24% of customers who buy shoes in a particular store buy two or more pairs. One weekend, 350 customers purchased shoes. How many can be predicted to buy two or more pairs? If 107 customers buy more than two pairs, did more customers than normal buy two or more pairs?



It is predicted that__________


customers bought two or more pairs out of 350 customers. There were customers than normal who bought two or ___ pairs.

Answers

Hello I know this may be difficult on your end but you don’t always have to get the answer from someone you can contact a teacher and get help this keep be very helpful keep this in your head you are intelligent no matter what anyone tells you ask your teacher a question about the problem tell them you don’t get how to do it if you have to just whatever it takes for you to learn how to do it have a wonderful day or night bye!

The average life expectancy in a certain country is 50.2 years. Estimate the​ country's life expectancy in hours by rounding the life expectancy to the nearest year.

Answers

The awnser to this question is 60.4 I believe

A consulting firm submitted a bid for a large research project. The firm's management initially felt they had a chance of getting the project. However, the agency to which the bid was submitted subsequently requested additional information on the bid. Past experience indicates that for of the successful bids and of the unsuccessful bids the agency requested additional information. a. What is the prior probability of the bid being successful (that is, prior to the request for additional information) (to decimal)?

Answers

Answer:

A or D i think..

Step-by-step explanation:

Solve the quadratic equation 3x² + 2x-4=0
Give your answers to 2 decimal places.

Answers

3x² + 2x - 4 = 0

Δ = b² - 4.a.c

Δ = 2² - 4 . 3 . -4

Δ = 4 - 4. 3 . -4

Δ = 52

x = (-b +- √Δ)/2a

 

x' = (-2 + √52)/2.3    

x'' = (-2 - √52)/2.3

x' = 0,8685170918213297    

x'' = -1,5351837584879966

2 Decimal places

x' = 0,87

x'' = -1,54

Answer: .8685

Step-by-step explanation:

In the town of Maplewood a certain type of DVD player is sold at just two stores. 36% of the sales are from store A and the rest of the sales are from store B. 7% of the DVD players sold at store A are defective while 3% of the DVD players sold at store B are defective. If Kate receives one of these DVD players as a gift and finds that it is defective, what is the probability that it came from store A

Answers

Answer:

56.76% probability that it came from store A

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective.

Event B: Store A.

36% of the sales are from store A

This means that [tex]P(B) = 0.36[/tex]

7% of the DVD players sold at store A are defective.

This means that [tex]P(A|B) = 0.07[/tex]

Probability of a defective DVD:

36% come from store A, and of those, 7% are defective.

100 - 36 = 64% come from store B, and of those, 3% are defective. So

[tex]P(A) = 0.07*0.36 + 0.03*0.64 = 0.0444[/tex]

What is the probability that it came from store A

[tex]P(B|A) = \frac{0.36*0.07}{0.0444} = 0.5676[/tex]

56.76% probability that it came from store A

Find the value of x that will make a || B

Answers

Answer:

x = 30

Step-by-step explanation:

4x + 2x = 180

6x = 180  

x = 30

A circle has a circumference that is greater than 8 meters. The inequality 3.14d> 8 can be used to determine the possible lengths

of the diameter of the circle. What are the possible values of d, the length of the diameter in meters?

d<25.1

d>25.1

d<25

d>2.5

Answers

Answer:

(D)d>2.5

Step-by-step explanation:

Given that the circumference of a circle is greater than 8 meters.

For a circle of diameter d:

Circumference[tex]=\pi d[/tex]

Since [tex]\pi =3.14[/tex]

[tex]3.14d>8[/tex]

To obtain possible values of the diameter d, we divide both sides of the equation by 3.14.

[tex]\dfrac{3/14d}{3.14}>\dfrac{8}{3.14}\\\\ d>2.5$ (correct to 1 decimal places)[/tex]

The correct option is D.

Answer:

To simplify the answer above, D

Step-by-step explanation:

Between what two integers does square root 10 lie on?

Answers

Answer:

between 3 and 4

Step-by-step explanation:

type sqrt(10) into your calculator

The requried, square root 10 lies between integers 3 and  4.

What are integers?

Integers are a set of whole numbers and their negative counterparts. They include positive numbers, negative numbers, and zero.

Examples of integers include -3, -2, -1, 0, 1, 2, 3, and so on.

The integer squares nearest to 10 are 9 and 16, which are the perfect squares of 3 and 4, respectively.

Since [tex]$\sqrt{9}=3$[/tex] and [tex]$\sqrt{16}=4$[/tex], we know that [tex]$\sqrt{10}$[/tex]  is between these two integers, we can say that [tex]$3 < \sqrt{10} < 4$[/tex].

Learn more about integers here:

https://brainly.com/question/15276410

#SPJ3

at a school concert the total value of tickets sold was $994. Student tickets sold for $5 and adult tickets sold for $8. The number of adults tickets sold was 14 more than 2 times the number of student tickets. How many student tickets and adult tickets were sold?

Answers

Answer:

42 student tickets and 98 adult tickets

Step-by-step explanation:

Let's call the number of student tickets 's' and the number of adult tickets 'a'.

Then, we can write the two equations below:

5s + 8a = 994

a = 2s + 14

Using the value of 'a' from the second equation in the first one, we have:

5s + 8*(2s + 14) = 994

5s + 16s + 112 = 994

21s = 882

s = 42

Now, finding the value of 'a', we have:

a = 2*42 + 14 = 98

Answer:

The total sold was 98 tickets for adults and 42 for students.

Step-by-step explanation:

In order to calculate the number of tickets of each kind sold we need to create a system of equations with the given information. The first equation can be created is that the sum of adult tickets multiplied by its cost with the student tickets also multiplied by its cost must be equal to the total value of tickets sold, so:

[tex]5*\text{students} + 8*\text{adults} = 994[/tex]

We also know that the number of adult tickets was 14 more than 2 times the number of student tickets, therefore:

[tex]\text{adults} = 2*\text{students} + 14[/tex]

If we apply the second expression on the first one we can solve for the number of tickets sold to students, we have:

[tex]5*\text{students} + 8*(2*\text{students} + 14)= 994\\5*\text{students} + 16*\text{students} + 112 = 994\\ 21*\text{students} = 994 - 112\\\text{students} = \frac{882}{21} = 42[/tex]

We can use this value to find the number of adults ticket sold:

[tex]\text{adults} = 2*42 + 14\\\text{adults} = 98[/tex]

The total sold was 98 tickets for adults and 42 for students.

choose the equation of the line that is parallel to the x axis x=4, x+y=0, x=y, y=4

Answers

Answer:

y=4

Step-by-step explanation:

if we draw a function we see that y=4 is paralel to the x axis

A line that is parallel to the x-axis will pass through the y-axis, horizontally.

The equation of line parallel to the x-axis is y = 4

A line that is parallel to the x-axis is represented with the following equation

y = n

Where n can be any real number.

In other words, the following equations are parallel to the x-axis

y = 2

y = 3

y = -2

y = 10

And so on....

Hence, the equation of line parallel to the x-axis is y = 4

Read more about parallel equations at:

https://brainly.com/question/402319

Any help would be appreciated

Answers

Answer: 18.48

Step-by-step explanation:

To solve this problem, you would use the order of operations. You would solve the parenthesis first and then solve the rest.

(5.6-2.3)(5.4+0.2)

3.3(5.6)

18.48

Answer:

18.48

Step-by-step explanation:

(5.6 - 2.3) (5.4 + 0.2) 3.3 × 5.6

18.48

What is ansewer 1/6 of 30

Answers

Answer:

5

Step-by-step explanation:

The right answer is 5.

look at the attached picture

Hope it helps...

Good luck on your assignment

Consider a sample with data values of 10, 20, 12, 17, and 16. (a) Compute the mean and median. Mean = Median = (b) Consider a sample with data values 10, 20, 12, 17, 16, and 12. How would you expect the mean and median for these sample data to compare to the mean and median for part a (higher, lower, or the same)? The input in the box below will not be graded, but may be reviewed and considered by your instructor. Compute the mean and median for the sample data 10, 20, 12, 17, 16, and 12. If required, round your answers to one decimal place.

Answers

Answer:

Step-by-step explanation:

Consider a sample with data values of 10, 20, 12, 17, and 16. (a) Compute the mean and median. Mean = Median = (b) Consider a sample with data values 10, 20, 12, 17, 16, and 12.

Mean = Total of values/ Total number of observations

Total of values = 10+20+12+17+16 = 75

Total number of observations = 5

Mean = 75/5 = 15

Median:

Arrange in ascending order = 10, 12,16,17,20

Median = [n+1] / 2

N = number of observation = 5

Median = [5+1]/2 = 3rd observation

Median = 16

What is the value of x in the equation?4 (2x + 6) –10 = 30?

Answers

Answer: 10

Step-by-step explanation: 4(2 x 10 + 6) -10

X=2 with working out shown on photo

Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 222 days and standard deviation sigma equals 15 days.


What is the probability that a random sample of 26 pregnancies has a mean gestation period of 216 days or​ less?

The probability that the mean of a random sample of 26 pregnancies is less than 216 days is approximately

Answers

Answer:

[tex] z = \frac{216-222}{\frac{15}{\sqrt{26}}}= -2.040[/tex]

And we can find this probability on this way:

[tex]P(z<-2.040)=0.0207[/tex]

Step-by-step explanation:

Let X the random variable that represent the lenghts of the pregnencies of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(222,15)[/tex]  

Where [tex]\mu=222[/tex] and [tex]\sigma=15[/tex]

We are interested on this probability

[tex]P(\bar X<216)[/tex]

The z score formula is given by:

[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And if we find the z score we got:

[tex] z = \frac{216-222}{\frac{15}{\sqrt{26}}}= -2.040[/tex]

And we can find this probability on this way:

[tex]P(z<-2.040)=0.0207[/tex]

In a previous​ year, 54​% of females aged 15 and older lived alone. A sociologist tests whether this percentage is different today by conducting a random sample of 700 females aged 15 and older and finds that 369369 are living alone. Is there sufficient evidence at the alphaαequals=0.10.1 level of significance to conclude the proportion has​ changed? Because np 0 left parenthesis 1-p 0 right parenthesis np01−p0 equals= nothing not equals≠ less than< greater than> equals= ​10, the sample size is less than greater than ​5% of the population​ size, and the sample cannot be reasonably assumed to be random, is given to be random, can be reasonably assumed to be random, is given to not be random, the requirements for testing the hypothesis are not satisfied. ​(Round to one decimal place as​ needed.) 1. Identify the null and alternative hypotheses for this test. Upper H 0​: alpha α p μ greater than> not equals≠ equals= less than< nothing versus Upper H 1​: α μ p equals= not equals≠ less than< greater than> nothing ​(Type integers or decimals. Do not​ round.) 2. Find the test statistic for this hypothesis test. z 0 equals= nothing ​(Round to two decimal places as​ needed.) 3. Determine the​ P-value for this hypothesis test. ​P-value equals= nothing ​(Round to three decimal places as​ needed.) 4. State the conclusion for this hypothesis test. A. Do not reject Upper H0. There is not sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. B. Reject Upper H 0. There is sufficient evidence at the alpha equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. C. Reject Upper H 0. There is not sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed. D. Do not reject Upper H0. There is sufficient evidence at the alpha α equals=0.10.1 level of significance to conclude that the proportion of females who are living alone has changed.

Answers

Answer:

D.

Step-by-step explanation:

A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classes. College A samples 11 graduates and finds the mean is 4 math classes with a standard deviation of 1.5 math classes. College B samples 9 graduates and finds the mean is 3.5 math classes with a standard deviation of 1 math class. The community group believes that a student who graduates from college A has taken more math classes, on the average. Test at a 10% significance level. Assume the requirements for a valid hypothesis test are satisfied.

Answers

Answer:

[tex]t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890[/tex]  

The p value for this case would be:

[tex]p_v =P(t_{18}>0.890)=0.193[/tex]  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

Step-by-step explanation:

Information given

[tex]\bar X_{1}=4[/tex] represent the mean for sample A

[tex]\bar X_{2}=3.5[/tex] represent the mean for sample B

[tex]s_{1}=1.5[/tex] represent the sample standard deviation for A

[tex]s_{2}=1[/tex] represent the sample standard deviation for B  

[tex]n_{1}=11[/tex] sample size for the group A

[tex]n_{2}=9[/tex] sample size for the group B  

[tex]\alpha=0.1[/tex] Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:  

Null hypothesis:[tex]\mu_{1}-\mu_{2} \leq 0[/tex]  

Alternative hypothesis:[tex]\mu_{1} - \mu_{2}> 0[/tex]  

The statistic is given by:

[tex]t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}[/tex] (1)  

And the degrees of freedom are given by [tex]df=n_1 +n_2 -2=11+9-2=18[/tex]  

Replacing we got:

[tex]t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890[/tex]  

The p value for this case would be:

[tex]p_v =P(t_{18}>0.890)=0.193[/tex]  

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

What is the area of an rectangle with sides lengths of 5/12 foot and 2/3 foot

Answers

Answer:

Area = 5/18 square feet

Step-by-step explanation:

To find the area of a rectangle, you need to multiply 5/12 and 2/3. You multiply the numerators and then multiply the denominators. Then you should get 10/36. This fraction can be simplified into 5/18. To do this find the greatest common factor of 10 and 36 (you'll get 2 as the GCF). Then divide 2 to both the numerator and denominator.

Given a+b=7 and a–b=3, find: 3a÷3b

Answers

Answer & Step-by-step explanation:

We are given two equations...

a + b = 7

a - b = 3

We are asked to find 3a ÷ 3b. In order to find the value of a and b, we have to rearrange one of the equations so it will be easier to find the values of the variables. Let's rearrange the second equation.

a - b = 3 → a = 3 + b

Now that we have an equation that shows the value of a, we can use this equation and plug it into the first equation.

a + b = 7

a = 3 + b

(3 + b) + b = 7

3 + 2b = 7

2b = 4

b = 2

We have the value of b. Now, we have to find the value of a by plugging b into the second equation.

a - b = 3

b = 2

a - 2 = 3

a = 5

Now that we have the values of both variables, we can plug them into (3a÷3b)

3a ÷ 3b

3(5) ÷ 3(2)

15 ÷ 6

5/2 or 2.5

So, 3a ÷ 3b equals 5/2 or 2.5

A model of a house was built using the scale 5 in: 25 ft. If a window in the model is 1.5 in. wide, how wide is the actual window?​

Answers

Answer:

7.5 feet

Step-by-step explanation:

Scale of the Model =5 in: 25 ft.

If we divide both sides by 5

[tex]\dfrac{5 in.}{5} : \dfrac{25 ft.}{5}\\\\$1 inch: 5 feet[/tex]

If a window on the model is 1.5 inch wide, from the unit ratio derived above we then have that:

1 Inch X 1.5 : 5 feet X 1.5 feet

1.5 Inch : 7.5 feet

Therefore, if a window in the model is 1.5 in. wide, the actual window is  7.5 feet wide.

Bacteria culture doubles every 20 minutes. After two hours there are 28800 bacteria. What was the initial amount?

Answers

Answer:

450 bacteria.

Step-by-step explanation:

To find this, we can set up an exponential equation as shown:

[tex]28800 = a (2)^{\frac{120}{20} }[/tex]

**'a' being the initial value

** '2' representing the culture doubling

Simplify the equation down:

[tex]28800 = a (2)^{6}[/tex]

[tex]28800 = 64a\\a = 450.[/tex]

Therefore, the initial amount of bacteria was 450.

who can answer this question the fastest​

Answers

Step-by-step explanation:

1. 45/5 = 9

2. 53 is not a multiple of 5

3. 164 - 20 = 144

4. 372 rounded is 400.

5. 5 edges

6. 382 + 200 = 582

7. 6500 meters

8. -6

9. 65 cm

10. 90/2 = 45

11. idk since i live in us

12. 8 * 3 = 24

13. July 30th

14. 6

15. 28

16. 2.5 * 3 = 7.50

Can someone help me pls, I will really appreciate it

Answers

Use the law of cosines to find the missing length, which we'll call [tex]d:[/tex]

[tex]d^2=100^2+120^2-2(100)(120)\cos 45^\circ[/tex]

[tex]d^2=24400-12000\sqrt{2}[/tex]

[tex]\boxed{d\approx 86\text{ cm}}.[/tex]

the value pi/24 is a solution for the equation 4 cos^4 (4x)-3

Answers

Answer:

False

Step-by-step explanation:

4 cos^4 (4x)-3 = 0

Substitute into the equation

4 cos^4 (4pi/24)-3 = 0

4 cos^4 (pi/6)-3 = 0

Take the cos pi/6

4 ( sqrt(3)/2) ^4 -3 =0

Take it to the 4th power

4 ( 9/16) -3 =0

9/4 -3 =0

9/4 - 12/4 = 0

-3/4 =0

False

Answer:

THE ANSWER IS TRUE.

Step-by-step explanation:

I did this on my homework.

Please number them but left to right from the top please.

Answers

Answer: Three have a right angle. These are the green rectangle, the pinkish square, and the orange trapezoid.

Step-by-step explanation:

watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. The mean number of hours was 2.8 with a standard deviation of 2.6. A sociologist claims that people watch a mean of 3 hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day is less the claim? Use the a=0.5 level of significance and the P-value method with the TI-84 Plus calculator.

(a) State the appropriate null and alternate hypotheses.

H0: Mu = 3
H1: Mu < 3

This hypothesis test is a _____ test.

(b) Compute the P-value. Round the answer to at least four decimal places

P-value =

Answers

Answer:

a) Null hypothesis:[tex]\mu \geq 3[/tex]  

Alternative hypothesis:[tex]\mu < 3[/tex]  

This hypothesis test is a left tailed test.

b) [tex]t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784[/tex]  

The p value for this case can be calculated with this probability:  

[tex]p_v =P(z<-2.784)=0.0027[/tex]  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value [tex]\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310[/tex] and for the alternative we select [tex]< \mu_o[/tex]. Then press Calculate.

And we got the same results.  

Step-by-step explanation:

Information given

[tex]\bar X=2.8[/tex] represent the sample mean

[tex]s=2.6[/tex] represent the population standard deviation  

[tex]n=1310[/tex] sample size  

[tex]\mu_o =3[/tex] represent the value to test

[tex]\alpha=0.5[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic

[tex]p_v[/tex] represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 3[/tex]  

Alternative hypothesis:[tex]\mu < 3[/tex]  

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

Replacing the info given we got:

[tex]t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784[/tex]  

The p value for this case can be calculated with this probability:  

[tex]p_v =P(z<-2.784)=0.0027[/tex]  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value [tex]\mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310[/tex] and for the alternative we select [tex]< \mu_o[/tex]. Then press Calculate.

And we got the same results.  

Other Questions
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