A 0.320 kg ball approaches a bat horizontally with a speed of 14.0 m/s and after getting hit by the bat, the ball moves in the opposite direction with a speed of 22 m/s. If the ball is in contact with the bat for 0.0600 s, determine the magnitude of the average force exerted on the bat.

Answer:

The gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.

Explanation:

We can find the gravitational potential energy of the mass using the following equation:                      

[tex] E_{p} = m*g*h [/tex]

Where:

m: is the mass = 8.6 kg

g: is the gravity = 9.81 m/s^{2}  

h: is the height = Earth's radius = 6371 km

Hence, we have:

[tex]E_{p} = 8.6 kg*9.81 m/s*6371000 m = 5.38 \cdot 10^{8} J[/tex]

Therefore, the gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.

I hope it helps you!                                                            

Answer: Hale-Bopp was an unusually bright comet that flew by Earth, reaching its closest approach to the planet in 1997.

Explanation:

Hale-Bopp is the answer

Answer: This is Comet Hale--Bopp

Explanation:

Answer:

(D) the sphere

Explanation:

The bodies given are Disk and Solid sphere (uniform sphere)

Moment of inertia of the bodies are

I(disk) = [tex]\frac{MR^2}{2}[/tex]

I(sphere) = [tex]\frac{2MR^2}{5}[/tex]

Since the moment of inertia of sphere is less than that of disk, therefore sphere will reach the bottom first.

Isothermal means constant temperature.  On a P-V diagram, this appears as a curve.

Constant volume of course appears as a vertical line.

Work done BY an ideal gas at constant pressure is W = PΔV.

Work done BY an ideal gas at constant temperature is:

W = nRT ln(Vf / Vi)

W = nRT ln(Pi / Pf)

Heat added to an ideal gas at constant volume is Q = (Cᵥ/R) VΔP.

For a monotomic gas, Cᵥ = 3R/2.

For a diatomic gas, Cᵥ = 5R/2.

Change in internal energy equals heat added to the gas minus the work done BY the gas.

ΔE = Q − W

For an ideal gas, if the temperature is constant, ΔE = 0.

At state 1, the pressure is 94.0 kPa and the volume is 4.0 L.  From ideal gas law:

PV = nRT

(94.0 kPa) (4.0 L) = nRT

nRT = 376 J

At state 2, the volume triples to 12.0 L.  The work done is:

W = nRT ln(Vf / Vi)

W = (376 J) ln(12 / 4)

W = 413 J

The process is isothermal, so ΔE = 0 J.  Therefore, Q = 413 J.

The new pressure is:

P₁ V₁ = P₂ V₂

(94.0 kPa) (4.0 L) = P₂ (12.0 L)

P₂ = 31.3 kPa

At state 3, the volume is constant at 12.0 L, and the pressure rises back to 94.0 kPa.  Since there's no change in volume, W = 0 J.  The heat added is:

Q = (Cᵥ/R) VΔP

Q = (3/2) (12.0 L) (94.0 kPa − 31.3 kPa)

Q = 1130 J

So ΔE = Q − W = 1130 J.

From ideal gas law:

PV = nRT

(94.0 kPa) (12.0 L) = nRT

nRT = 1128 J

At state 4, the volume returns to 4.0 L.  The work done is:

W = nRT ln(Vf / Vi)

W = (1128 J) ln(4 / 12)

W = -1240 J

The process is isothermal, so ΔE = 0 J.  Therefore, Q = -1240 J.

The new pressure is:

P₃ V₃ = P₄ V₄

(94.0 kPa) (12.0 L) = P₄ (3.0 L)

P₄ = 376 kPa

Finally back to state 1, the volume is constant at 4.0 L, and the pressure drops back to 94.0 kPa.  Again, since there's no change in volume, W = 0 J.  The heat added is:

Q = (Cᵥ/R) VΔP

Q = (3/2) (4.0 L) (94.0 kPa − 376 kPa)

Q = -1690 J

So ΔE = Q − W = -1690 J.

For the entire cycle:

Q = 413 J + 1130 J − 1240 J − 1690 J = -1390 J

W = 413 J + 0 J − 1240 J + 0 J = -827 J

ΔE = 0 J + 1130 J + 0 J − 1690 J = -560 J

Solution :

Given :

Length of the propeller rods, L =0.30 m

Mass of each, M = 0.040 kg

Moment of inertia of one propeller rod is given by  

[tex]$I=\frac{1}{3}\times M \times L^2$[/tex]

Therefore, total moment of inertia is

[tex]$I=3 \times \frac{1}{3}\times M \times L^2$[/tex]

[tex]$I=M\times L^2$[/tex]

[tex]$I=0.04\times (0.3)^2$[/tex]

  [tex]$0.0036 \ kg \ m^2$[/tex]

Now energy required is given by

[tex]$E=\frac{1}{2}\times I \times \omega^2 $[/tex]

where, angular speed, ω = 5800 rpm

[tex]$\omega = 5800 \times \frac{2 \pi}{60} $[/tex]

 = 607.4 rad/s

Therefore energy,

[tex]$E=\frac{1}{2}\times 0.0036 \times (607.4)^2 $[/tex]

   = 664.1 J

The moment of inertia of the propeller is 0.0036 kgm² and the energy required is 663.21 J

Given that the mass of the propellers is m = 0.040kg,

and their length is L = 0.30m

The moment of inertia of a rod with the rotation axis at one end is given by :

[tex]I = \frac{1}{3}m L^2[/tex]

so for 3 propellers:

[tex]I=3\times\frac{1}{3}\times(0.04)\times(0.3)^2[/tex]

I = 0.04 × 0.09

I = 0.0036 kgm²

Now, the frequency is given f = 5800 rpm

so anguar speed, ω = 5800×(2π/60)

ω = 607 rad/s

Energy required:

E = ¹/₂Iω²

E = 0.5 × 0.0036 × (607)² J

E = 663.21 J

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its the 3rd one kinetic energy increases as speed increases

Answer:the ballon and the comb have the same electrical charge

Explanation:because I got the answer right

The comb is able to repel the balloon is that the balloon and the comb possess the same electrical charge. Therefore, option (B) is correct.

Electric charge is the physical property of matter that offers it to experience a force when keep in an electric or magnetic field. An electric charge is related to an electric field, and the moving electric charge produced a magnetic field.

The interaction of the charges creates an electromagnetic force and the combination of an electric field and magnetic field is called an electromagnetic field.

When the students rub a balloon and comb against his hair several times static charges are built up on the balloon and the comb.  When the students place the comb near the balloon and the comb repels the balloon means that both the comb and the balloon possess the same type of electrical charges.

Therefore, the balloon and the comb acquired the same electrical charge.

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Answer:

Is that the question?

Explanation:

Answer:

0.5Amperes

Explanation:

Using the conservation of power formula

P = VI

The power we have in this coil is given as

P = 60 watts

Then we have V = 120 watts

Such that when we put these values into the formula above we will get:

60 = 120I

Then when we divide through by 120:

I = 60/120

I = 0.5 amperes

So 0.5 amperes is the rms in the primary coil.

Answer: 6.25 m/s

explanation: remember an easir way to solve problems like this is to have a horizontal side (x) and a vertical side (y) and on each side always set up for initial speed, average speed, final speed, distance, time, and acceleration.

lmk if you need anything else or any more good tips yk

Answer:

B

Explanation:

Examples of ink blots would be Faceless women, Rocket or Tower, Roast chicken which gives more meaning of your personality and you yourself of the picture that is shown.

Answer:

d, magnetic attracting metal, because the force is still going on without the magnet touching metal, and you cant see the force

Explanation:

Hope this helps <33

Answer:

The bullet will lose momentum

Explanation:

mass of the bullet, m₁ = 2.0 g = 0.002 kg

initial velocity of the bullet, u₁ = 700 m/s

mass of the wood block, m₂ = 5 kg

initial velocity of the wood block, u₂ = 0

let the final velocity of the bullet-block system after collision = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(0.002 x 700) + (5 x 0) = v(0.002 + 5)

1.4 = 5.002 v

v = 1.4 / 5.002

v = 0.28 m/s

Change in momentum of the bullet is given by;

ΔP = m₁v - m₁u₁

ΔP = m₁(v - u₁)

ΔP = 0.002( 0.28 - 700)

ΔP = -1.4 kg.m/s

Therefore, the bullet will lose momentum

Answer:

L = 22.97 H

Explanation:

Given that,

Capacitance, [tex]C=0.1\ \mu F=0.1\times 10^{-6}\ F[/tex]

Oscillation frequency, f = 0.5 Hz

The frequency of an AC circuit is given by :

[tex]f=\dfrac{1}{2\pi \sqrt{LC} }[/tex]

Where

L is impedance

[tex]f^2=\dfrac{1}{4\pi ^2LC}\\\\L=\dfrac{1}{4\pi ^2 f^2 C}\\\\\text{Putting all the values}\\\\L=\dfrac{1}{4\pi^2 \times (105)^2\times 0.1\times 10^{-6}}\\\\L=22.97\ H[/tex]

So, the impedance of LC circuit 22.97 H.

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

[tex]Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}[/tex]

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

[tex]e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm[/tex]

Therefore, the extension of the wire is 0.362 mm.

The correct answer B. Not affected by cognition

Explanation:

In the Social Cognitive Theory, the most important aspects are social interaction and cognition that involves mental processes such as comprehension. Indeed, this theory proposes behaviors are the result of observing other people as part of social interaction, understanding this behavior, and then imitating it.

Despite this, many psychologists do not support this theory and the main reason is that they deny the learning of behavior is related to cognition or complex mental processes. Instead, some believe behavior is the result of certain impulses or that is regulated by conditioning such as behaving correctly to avoid negative consequences.

Answer:

B. is correct on Edge 2020

Explanation:

Peace and Love

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC  

Explanation:

a)

       [tex]E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)[/tex]

b)

       [tex]Q = \sigma* A (2)[/tex]

        From (1), we know that V = E*d, but at the same time, applying Gauss'

        Law at a closed surface half within the plate, half outside it , it can be

        showed than E= σ/ε₀, so finally we get:

       [tex]C = \frac{Q}{V} =\frac{\sigma*A}{E*d} = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)[/tex]

c)    

       [tex]Q = C* V = 17.7 nF * 9.0 V = 159.3 nC (4)[/tex]

a) Electric field between the plates, E = 4.5*10⁴ V/m

b) Capacitance of the capacitor, C= 17.7 nF

c) Magnitude of the charge, Q = 159. 3 nC  

It is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

[tex]E=\frac{V}{d} \\\\E=\frac{90V}{2*10^{-4}m} \\\\E=4.5*10e4V/m[/tex]

For a parallel-plate capacitor, It is the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

[tex]Q=\sigma*A[/tex]

On comparing equation 1 and 2:

[tex]C=\frac{Q}{V}\\\\C=\frac{\sigma*A}{E*d}\\\\\\C=\frac{\sigma*A}{\frac{\sigma}{E_0}*d}\\\\C=\frac{8.85e^{-12}F/m-0.4m^2}{2e-4m}\\\\C=17.7nF\\\\[/tex]

From equation 3:

[tex]Q=C*V\\\\Q=17.7*9.0\\\\Q=159.3nC\\[/tex]

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Answer:

it's answer is 1 newton

Answer:

A, C, E

Explanation:

I put this and got it right.

Answer:

Explanation:

i think that the inside and outside of electric wire are make from different material because outdoor electrical wires are always exposed to the fluctuations of temperature and moisture, they are made with more durable insulation. If an indoor electrical wire is used outdoors, it is possible for sunlight to break down the protective layers. Electrical conductors are made up of metals such as, copper, aluminum, etc. These metals are used to make wires. Most wires are made out of copper because it conducts electricity with high flexibility and very little resistance. The first stage in the manufacturing process of a conductor is the wire-drawing

Answer:

The value is  [tex]\rho = 0.0180 97 9 \ \Omega m^{-1}[/tex]

Explanation:

From the question we are told that

   The radius of the conductor is [tex]r = 1.20 \ cm = 0.012 \ m[/tex]

    The current it is carrying is  [tex]I = 3.00 \ A[/tex]

    The electric field is  [tex]E = 120 \ V/m[/tex]

Generally the resistivity of the material is mathematically represented as

        [tex]\rho = \frac{EA}{ I }[/tex]

Here A is the area of the conductor which is mathematically represented as

      [tex]A = \pi r^2[/tex]

=>  [tex]A =3.142 * (0.012)^2[/tex]

=>  [tex]A = 0.000452 \ m^2[/tex]

So

    [tex]\rho = \frac{120 * 0.000452}{ 3 }[/tex]

=> [tex]\rho = 0.0180 97 9 \ \Omega m^{-1}[/tex]

Given values,

Now,

The area of conductor,

→ [tex]A = \pi r^2[/tex]

      [tex]= 3.142\times (0.012)^2[/tex]

      [tex]= 0.000452 \ m^2[/tex]

hence,

The resistivity will be:

→ [tex]\rho = \frac{EA}{I}[/tex]

By substituting the values, we get

     [tex]= \frac{120\times 0.000452}{3}[/tex]

     [tex]= 0.0180979 \ \Omega m^{-1}[/tex]

Thus the above response is right.  

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Explanation:

so sorry

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don't know but please mark me as brainliest please

Answer:

The dog ran a total distance of 45m but he is only 5m away from the starting line

Explanation: When you add 25 to 20 you get 45 for the total distance and if he ran back in the same direction then you would subtract 20 from 25 and get 5m

Answer:

0.817g

Explanation:

Zn2+ + 2e -----> An

Amount of electricity used

Q = It

= 1.6A x 25 x 60 seconds

= 2400 coulomb's

Number of moles of electrons = Q/f

F = 96500 coulomb's

= 2400/96500

= 0.025mol

From the equation above,

We see that the number of Zn moles firmed is equal to half the number of electrons used.

Molecular weight of Zn = 65.38

0.025x65.38/2

= 0.817 grams of zinc

Thank you!

Answer:

B. 100%

Explanation:

When the amplitude of a vibrating membrane increases the loudness of sound increases. Higher amplitude waves will mean more energy and greater intensity which causes the sound to be louder.

Loudness is proportional to the square of the amplitude. This will simply mean when the amplitude of a wave is doubled, the sound will be 4 times louder.

In this case, 50% increase in the amplitude of a vibrating membrane will cause a 100% increase in the loudness of sound.

Answer:

The largest wavelength of light that will produce photoelectrons from this surface is 324.6 nm.

Explanation:

Given;

work function, Ф = 3.82 eV

The work function of the metal is minimum energy required to produce electron from the metal surface.

Ф = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f is the frequency of the photon

f = c / λ

[tex]\phi = \frac{hc}{\lambda}[/tex]

where;

c is speed of light = 2.998 x 10⁸ m/s

λ is the wavelength = ?

[tex]\phi = \frac{hc}{\lambda}\\\\\lambda = \frac{hc}{\phi }\\\\\lambda = \frac{(6.626*10^{-34})(2.998*10^8)}{3.82*1.602*10^{-19}}\\\\\lambda = 3.246*10^{-7} \ m\\\\\lambda = 324.6 *10^{-9} \ m\\\\\lambda = 324.6 \ nm[/tex]

Therefore, the largest wavelength of light that will produce photoelectrons from this surface is 324.6 nm.

Answer:

None, both objects will hit ground at the same time.

Explanation:

        [tex]\Delta h = \frac{1}{2}*g*t^{2} (1)[/tex]