Answer:
Step-by-step explanation:
The mean, [tex]\bar{x}[/tex], is 90 and the standard deviation, [tex]\sigma[/tex], is 12. We are looking for the probability that the variable X will fall between 57 and 105. We use the z-score table for this, AFTER we find the z scores. The formula to find the z-scores for us is:
[tex]P(\frac{57-\bar{x}}{\sigma}\leq z\leq \frac{105-\bar{x}}{\sigma})[/tex] and we fill in accordingly:
[tex]P(\frac{57-90}{12}\leq z\leq \frac{105-90}{12})[/tex] which simplifies to
[tex]P(-2.75\leq z\leq 1.25)[/tex] and we will break them up into 2 different sets as follows:
P(-2.75 ≤ z ≤ 0) + P(0 ≤ z ≤ 1.25)
and based on the fact that z scores are given from 0 on up, we are going to convert the first one by using the logic that if z is greater than -2.75 but less than 0, by symmetry, z is greater than 0 but less than 2.75:
P(0 ≤ z ≤ 2.75) + P(0 ≤ z ≤ 1.25) and we go to the z-score table.
Locate 2.7 down along the left side and move over til you're under the .05; that gives us the z-score for 2.75 which is .4970. Do the same for 1.25 to get a z-score of .3944. Add them together to get a final z-score that covers the range of values for X:
.4970 + .3944 = 0.8914
a taxi rider must pay 15000 VND for 1km in the first 10km, when exceeding 10km, they will pay them 14000 VND for each subsequent kilometer.Please write the expression to that the user number must be pay on x km (x>10)
Answer:
Số tien:S =150000+(x-10)14000
Step-by-step explanation:
In a large midwestern university (the class of entering freshmen being on the order of 6000 or more students), an SRS of 100 entering freshmen in 1999 found that 20 finished in the bottom third of their high school class. Admission standards at the university were tightened in 1995. In 2001 an SRS of 100 entering freshmen found that 10 finished in the bottom third of their high school class. The proportion of all entering freshmen in 1999 and 2001, who graduated in the bottom third of their high school class, are p1 and p2, respectively.Is there evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced, as a result of the tougher admission standards adopted in 2000, compared to the proportion in 1999? To determine this, you test the hypothesesH0 : p1 = p2 , Ha : p1 > p2.The P-value of your test isA. 0.976.B. 0.024.C. 0.048.D. 0.001.
Answer:
B. 0.024
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
1999:
Of 100, 20 were in the bottom thid. So
[tex]p_B = \frac{20}{100} = 0.2[/tex]
[tex]s_B = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]
2001:
Of 100, 10 were in the bottom third, so:
[tex]p_A = \frac{10}{100} = 0.1[/tex]
[tex]s_A = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]
To determine this, you test the hypotheses H0 : p1 = p2 , Ha : p1 > p2.
Can also be rewritten as:
[tex]H_0: p_B - p_A = 0[/tex]
[tex]H_1: p_B - p_A > 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the sample:
[tex]X = p_B - p_A = 0.2 - 0.1 = 0.1[/tex]
[tex]s_A = \sqrt{s_A^2+s_B^2} = \sqrt{0.03^2+0.04^2} = 0.05[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.1 - 0}{0.05}[/tex]
[tex]z = 2[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a difference of proportions of at least 0.1, which is 1 subtracted by the p-value of z = 2.
Looking at the z-table, z = 2 has a p-value of 0.976.
1 - 0.976 = 0.024, so the p-value is given by option B.
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
Likes s and t are perpendicular if the slope of line s is 5 what is the slope of line t?
Answer:
Gradient of line t is -1/5
Step-by-step explanation:
[tex]{ \sf{m _{s} \times m _{t} = - 1}} \\ { \sf{5 \times m _{t} = - 1 }} \\ { \sf{m _{t} = - \frac{1}{5} }}[/tex]
factorise the given number
12
hope it helps you............
A phone company charges each customer a monthly fee of $11.25. In addition, it charges $0.03 per minute for in-state calls and $0.11 per minute for out-of-state calls. What is the total monthly charge for a customer who made 340 minutes of in-state calls and 84 minutes of out-of-state calls?
340 x 0.03 = 10.2 (in state)
84 x 0.11 = 9.24 (out of state)
10.2 + 9.24 + 11.25
= $30.69 monthly charge
hope it helps :)
The total monthly charge for a customer is given as $30.69.
What is simplification?Simplifying allows us to test each process and strategy to determine which is the most efficient and best suited for its specific goal.
here,
A phone provider costs each customer $11.25 per month. Furthermore, it charges $0.03 per minute for in-state calls and $0.11 for out-of-state calls.
Charge within the boundary of state for 340 minutes = 340 x 0.03 = 10.2
Charge beyond the boundary of state for 84 minutes = 84 x 0.11 = 9.24
Total monthly charge = 10.2 + 9.24 + 11.25
= $30.69 monthly charge
Thus, A customer's total monthly price is shown as $30.69.
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The current temperature of 8"F below zero is 21°F below the high temperature of the day. What is the high temperature for the day
Answer:
24°c
Step-by-step explanation:
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Find the product (x - 10) ( x - 5)
꙰ Hello there mohammedsaquibali45 ! My Name is ⚝Tobie⚝ and I'm glad you asked! Let me walk you step by step in order to comprehend the question better! ꙰
i
{x}^{2}-5x-10x+50
x
2
−5x−10x+50
ii Collect like terms.
{x}^{2}+(-5x-10x)+50
x
2
+(−5x−10x)+50
iii Simplify.
{x}^{2}-15x+50
x
2
−15x+50
(x - 10)(x - 5) = ...
= x^2 + (-10 + (-5))x + (-10•(-5))
= x^2 - 15x + 50
A car travels 52/5 kilometers in 23/4 minutes. What is the unit rate in kilometers per minute?
The unit rate of the car that travels 5 2/5 km in 2 3/4 mins is: 1.96 km/min.
What is Unit Rate?Unit rate can be defined as the ratio of one quantity in comparison to another.
Distance travelled by a car = 5 2/5 km = 5.4 km
Time travelled = 2 3/4 mins = 2.75 mins
Unit rate in km/min = 5.4/2.75
Unit rate in km/min = 1.96 km/min.
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There is a line whose slope is 0 and whose y-intercept is 7. What is its equation in slope-intercept form?
Step-by-step explanation:
To evaluate such, the following must be comprehended, on the behalf of linear data:
Slope: Rise/Run.
Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.
X-intercept: The peculiar point in which the observed linear data intersects the x-axis.
Recall:
Slope-Intercept Form is acknowledged and defined as the integration of the intersection point, in relation or in proportion to the distance between two points within the linear data presented on the Cartesian Plane.
Slope-Intercept Form:
Y = mx + b
Y = The line.
M = Slope.
B = y-intercept.
The following may be equated, as stated:
- Slope = 0
Y = b
- Y-intercept = 7
Y = 7
Thus, on the Cartesian Plane is identified as a horizontal line positioned within quadrants I and II, intersection (0, 7).
[tex]\sqrt{x^2 +7x+1} =2x+1[/tex]
Step 1: Subtract 3 from both sides of the inequality. Step 2: __________ Step 3: Divide both sides of the inequality by the coefficient of x.
Answer:
Hence the correct answer is Add 8x to both sides of the inequality.
Step-by-step explanation:
Step 1: Subtract 3 from both sides of the inequality.
Step 2: Add 8x to both sides of the inequality.
Step 3: Divide both sides of the inequality by the coefficient of x.
The inequality
5 - 8x < 2x + 3.
I need help I don't understand this.
Answer:
x=5
Step-by-step explanation:
(5x+2)/3 = 9
Multiply each side by 3
(5x+2)/3 *3 = 9*3
5x+2 = 27
Subtract 2 from each side
5x+2-2 = 27-2
5x = 25
Divide by 5
5x/5 = 25/5
x =
In order to make a profit, a retailer will mark up the cost of an item. If the cost of the item is $42 but it is sold for
$89, what is the mark up rate for the item?
Round your answer to the whole percent.
Rachel has 37 videos and decides to purchase 2 more each week. Write an equation describing this situation.
Use the drop-down menus to identify the values of the
parabola.
Vertex = (-3, -5), (-2, 0),
(0, 4), or (2, 0)
Domain = x < 0, x > 0, y > 0, or x is a real number
Range = {y| y < 0, 2, 4, or 6}
Answer:
Vertex= (0,4)
Domain= x: all real number
Range: ( - ∞, 4] or y ≤ 4
OAmalOHopeO
help me with this question of O math
Answer:
domain is { - 1, 0, 1 }
Step-by-step explanation:
The domain are the values of the input x
Substitute the value from the range y into the equation and solve for x
y = 1
2x + 3 = 1 ( subtract 3 from both sides )
2x = - 2 ( divide both sides by 2 )
x = - 1
-------------------------------
y = 3
2x + 3 = 3 ( subtract 3 from both sides )
2x = 0 , then
x = 0
-------------------------------
y = 5
2x + 3 = 5 ( subtract 3 from both sides )
2x = 2 ( divide both sides by 2 )
x = 1
Then the domain is { - 1, 0, 1 }
Rectangle KLMN has vertices K(-5,6), L(-2,9), M(6, 1), and N(3,-2). Determine and state the coordinates of the point of intersection of the diagonals.
Answer:
(0.5,3.5)
Step-by-step explanation:
First, we can draw the image, as shown. The diagonals in the rectangle are the following lines:
from (-2,9) to (3,-2)
from (-5, 6) to (6,1)
To find where they intersect, we can start by making an equation for the lines. For an equation y=mx+b, m represents the slope and b represents the y intercept, or when x=0
For the first line, from (-2,9) to (3,-2), we can calculate the slope by calculating the change in y/change in x = (y₂-y₁)/(x₂-x₁). If (3,-2) is (x₂,y₂) and (-2,9) is (x₁,y₁), our slope is
(-2-9)/(3-(-2)) = -11/5
Therefore, our equation is
y= (-11/5)x + b
To solve for b, we can plug a point in, like (3,-2). Therefore,
-2=(-11/5)*3+b
-2=-33/5+b
-10/5=-33/5+b
add 33/5 to both sides to isolate b
23/5=b
Our equation for one diagonal is therefore y=(-11/5)x+23/5
For the second line, from (-5, 6) to (6,1), if (6,1) is (x₁,y₁) and (-5,6) is (x₂,y₂), the slope is (1-6)/(6-(-5)) = -5/11 . Plugging (6,1) into the equation y=(-5/11)x+b, we have
1=(-5/11)*6+b
11/11 = -30/11 + b
add 30/11 to both sides to isolate b
41/11 = b
our equation is
y = (-5/11) x + 41/11
Our two equations are thus
y = (-5/11) x + 41/11
y=(-11/5)x+23/5
To find where they intersect, we can set them equal to each other
(-11/5)x+23/5 = y = (-5/11) x + 41/11
(-11/5)x + 23/5 = (-5/11)x + 41/11
subtract 23/5 from both sides as well as add 5/11 to both sides to make one side have only x values and their coefficients
(-11/5)x + (5/11)x = 41/11-23/5
11*5 = 55, so 55 is one value we can use to make the denominators equal.
(-11*11/5*11)x+(5*5/11*5)x=(41*5/11*5)-(23*11/5*11)
(-121/55)x+(25/55)x = (205/55) - (253/55)
(-96/55)x = (-48/55)
multiply both sides by 55 to remove the denominators
-96x=-48
divide both sides by -96 to isolate x
x=-48/-96=0.5
plug x=0.5 into a diagonal to see the y value of the intersection
(-11/5)x + 23/5 = y = (-11/5)* 0.5 + 23/5 = 3.5
D
20 B
A
250
E
G
NOTE: Angles not necessarily drawn to scale.
o
-
Answer:
x=45°
Does the answer help you?
Given that h(x) = - (x - 1)^2 - 1, write an expression for f(x) in terms of x.
f(x) =
Answer: f(x) = -(x-1)^2+5
Explanation:
f(x) = h(x) + 6
f(x) = -(x-1)^2 - 1 + 6
f(x) = -(x-1)^2+5
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Based only on the information given in the diagram, which congruence
theorems or postulates could be given as reasons why AABC= ALMN?
Check all that apply
O A. LL
O B. ASA
I C. LA
D. HL
E AAS
3 Answers:
Choice A. LLChoice D. HLChoice F. SAS==========================================================
Explanation:
Let's go through the answer choices one by one.
A) This can be used because LL = leg leg, and this means we have two pairs of congruent legs. Those pairs are AC = LN and CB = NM. The LL theorem only applies to right triangles.B) This cannot be used. We don't have info about two pairs of angles. We only know that one pair of angles are the same (those 90 degree angles). So we can't form the second "A" in "ASA". This idea will come up again in choice C and choice E.C) This cannot be used. Why not? Because the "A" of "LA" refers to "acute angle". But unfortunately we don't know anything about the acute angles (whether they are congruent or not). The LA theorem can only be applied to right triangles.D) This can be used. We can use the HL (hypotenuse leg) theorem because we see that AB = LM are the pair of congruent hypotenuses, and you can use any of the congruent leg pairs to form the L of HL. Similar to LL and LA, the HL theorem only works for right triangles.E) This cannot be used. Like with choice B, we can't form the second "A" of "AAS".F) This can be used because we have two pairs of congruent sides, with a pair of congruent angles between those sides. Those angles being the marked 90 degree angles. It turns out that LL theorem is a special case of the SAS theorem.In short, we can use choice A, choice D, choice F. We can't use the other three choices because we lack the info about any other pairs of angles.
The congruence theorem or postulate that we can use to show that triangle ABC is congruent to triangle LMN is LL (Side-Side-Side), the correct option is A.
What are congruent triangles?Suppose it is given that two triangles ΔABC ≅ ΔDEF
Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.
The order in which the congruency is written matters.
For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.
Thus, we get:
[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]
(|AB| denotes length of line segment AB, and so on for others).
We are given that;
Sides are equal
Now,
Based only on the information given in the diagram, we can use the following congruence theorems or postulates to show that triangle ABC is congruent to triangle LMN:
A. LL (Side-Side-Side): This theorem states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent. In this case, we know that AB = LM, AC = LN, and BC = MN, so we can use LL to show that triangle ABC is congruent to triangle LMN.
B. ASA (Angle-Side-Angle): This theorem states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. In this case, we do not know any angle measures, so we cannot use ASA to show that the triangles are congruent.
Therefore, by the congruent triangles the answer will be LL (Side-Side-Side).
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ASAP PLEASE HELP MEEEEEEEEEEEEEEEEE
Step-by-step explanation:
the radius of a circle is 17m. find its area in terms of pi
Answer:
[tex]289\pi {m}^{2} [/tex]Step-by-step explanation:
Given,
Radius of a circle = 17m
Therefore,
Area in terms of pi
[tex] = \pi {r}^{2} [/tex]
[tex] = \pi \times 17m \times 17m[/tex]
[tex] = 289\pi {m}^{2} (ans)[/tex]
Answer:
A = 289π m²
Step-by-step explanation:
The area (A) of a circle is calculated as
A = πr² ( r is the radius ) , then
A = π × 17² = 289π m²
someone please help me I really need help on this or ill fail
Answer:
a. Smart Dot Company: C = 12 + 0.5·t
Communications Plus: C = 2.5·t
b. Please find attached the required tables created using MS Excel cell function tool
c. Please find attached the graph of both relationship created on the same grid with
Step-by-step explanation:
a. The monthly cost of the Smart Dot Company = $12
The hourly cost for internet use on Smart Dot Company = $0.50
The hourly cost of using the Communications Plus = $2.50
Therefore, the total monthly cost, C, for the duration of hours used, t, is given as follows;
Smart Dot Company: C = 12 + 0.5·t
Communication Plus: C = 2.5·t
b. The table of values are created using MS Excel as follows;
[tex]\begin{array}{ll}Smart \ Dot \ Company&\\Time \ (hours)&Cost \ (dollars)\\0&12\\2&13\\4&14\\6&15\\8&16\\10&17\end{array}[/tex] [tex]\begin{array}{ll}Communications\ \ Plus&\\Time \ (hours)&Cost \ (dollars)\\0&0\\2&5\\4&10\\6&15\\8&20\\10&25\end{array}[/tex]
c. Please find attached the graph of both relationship created on the same grid with MS Excel
Asha found that a vertical line intersects the graph of x = StartAbsoluteValue y EndAbsoluteValue at two points. What can Asha conclude about x = StartAbsoluteValue y EndAbsoluteValue?
It is a function of x but not a relation.
It is a relation but not a function of x.
It is both a function of x and a relation.
It is neither a function of x nor a relation.
Answer:
B
Step-by-step explanation:
Answer:
B) It is a relation but not a function of X
Explanation:
What Asha did was the vertical line test. This is a test to see if something is a function or not. Since a function can only have one output per input, if the vertical line intersects twice, it is not a function. However it is still a relation. A relation doesn't have to fit the rule that one output only has one input.
Please do this ASAP, it’s due in 30 minutes!
Thank you!
No links<3
Answer:
I think it is -24t+20 if you want to simplify
Step-by-step explanation:
Answer:
-24t + 20
Step-by-step explanation:
First, remove the parentheses
Then, multiply 6 by 5
Then expand 3(2t+4) - 30t + 8
Finally simplify 6t + 12 - 30t + 8
-24t + 20
Hope this helps!
Set up the appropriate trigonometric ratio to determine the value of the safety angle.
Step-by-step explanation:
sin/cos=tan theta.It is the value of the safety angle
MNOP is a trapezoid with median QR. Find x
[tex]\bf \large \rightarrow \: \:2x \: + \: 8 \: = \: 0[/tex]
[tex]\bf \large \rightarrow \: \:x \: = \: \frac{8}{2} \\ [/tex]
[tex]\bf \large \rightarrow \: \:x \: = \: \cancel\frac{ 8}{ 2} \: \: ^{4} \\ [/tex]
[tex]\bf \large \rightarrow \: \:x \: = \: 4[/tex]
Option ( A ) is the correct answer.
i have a few questions! what is the gcf for
(21 and 54)
(55 and 90)
(16 and 30)
(42 and 91)
(66 and 121)
Answer:
(21 and 54): 3
(55 and 90): 5
(16 and 30): 2
(42 and 91): 7
(66 and 121): 11
Step-by-step explanation:
What is the slope of a line that is perpendicular to the line whose equation is
y= 4x – 3?
Answer:
-1/ 4
Step-by-step explanation:
y = 4x-3 has a slope of 4 because the equation is in slope intercept form
y = mx+b where the slope is m
Perpendicular lines have slopes that are negative reciprocals
-1/ 4 is the slope of a line that is perpendicular to y = 4x-3
q divided by 6 + p; use p = 10, and q = 12
Answer: =12
Step-by-step explanation:
12 divided by 6=2+10=12
q/6+p = 12/6+10 = 12/16 = 0.75
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