9 and -9 are examples of

A. absolute values
B.oposite integers
C. products
D. Quotients

Answer:

9

Step-by-step explanation:

use Tangent-chord formula for finding the arc knowing E

x=1/2n

4x+19=1/2n

n=8x+38

both arcs = 360

28x-2+8x+38=360

x=9

Answer:

9z-2y-3x

Step-by-step explanation:

(6z-4y+2x)+(3z-5x+2y)

Combine like terms

6z+3z-4y+2y+2x-5x

9z-2y-3x

Answer:

-3x - 2y + 9z

Step-by-step explanation:

Since you are adding two polynomials, the parentheses are unnecessary, so you can just drop them. Then combine like terms. Like terms are terms that have the same variable part such as 6z and 3z.

(6z - 4y + 2x) + (3z - 5x + 2y) =             Original problem.

= 6z - 4y + 2x + 3z - 5x + 2y                 Drop unnecessary parentheses.

= 2x - 5x - 4y + 2y + 6z + 3z                 Rearrange terms to group like terms.

= -3x - 2y + 9z                                        Combine each set of like terms.

Answer: -3x - 2y + 9z

9514 1404 393

Answer:

  2^6 = 64

Step-by-step explanation:

Each hour the initial value (1) is multiplied by 2 (again). So the number of times 2 multiplies the initial value is the number of passing hours (t).

The number of cells after t hours is ...

  c(t) = 1×2^t = 2^t

After 6 hours, this is

  c(6) = 2^6 = 64 . . . . cells after 6 hours

_____

Additional comment

As you know, multiplication simplifies repeated addition.

  x + x + x = 3x

In a similar way, exponentiation simplifies repeated multiplication.

 x·x·x = x³ . . . . (written as x^3 in plain text)

In this problem, we're repeatedly multiplying by 2. After we do that t times, the initial value is multiplied by 2^t.

Step-by-step explanation: Let's begin by finding the

greatest common factor for the numbers 65 and 39.

I would make a factor tree and break up 65 and 39.

So 65 is 13 x 5 and 39 is 13 x 3.

Since the 13's match up, the greatest

common factor between 65 and 39 is 13.

For the variables, we use the smallest power on each of them.

So we use a^3 and b^4 to get 13a^3b^4 as our GCF.

Answer:

D.

Step-by-step explanation:

D. This contains an x^2 and is called a parabola ( curved line like a U).

Answer:D

Step-by-step explanation: d is the correct answer

Answer:

74

Step-by-step explanation:

for this question you have to use the formula of the nth term which is Tn=a+(n-1)d,

T21=-6+(21-1)4

=-6+(20)4

=-6+80

=74

I hope this helps

Answer: 1,526.04 yd³ (this is what i got on my calculator others may vary use any rounding you need)

VOLUME of CONE is: V= Pir² h / 3

Pi= 3.14

r= 9

h= 18

V= (3.14) x (9)² x (18)

9²= 81

3.14 x 81= 254.34 x 18= 4,578.12

4,578.12 / 3= 1,526.04 <-- answer

Step-by-step explanation:

check it out.

Hope it helps.

Answer:

first choice..

first choice

Answer:

FIRST CHOISE FIRST CHOISE

Step-by-step explanation:

Answer:

2) - 12

3) - 1

4)y = 8

5)r = 4

6)x= -7/29

Hope it helps you

Answer:

B

Step-by-step explanation:

[tex]\\ \sf\longmapsto 10x=\dfrac{1}{0.001}[/tex]

[tex]\\ \sf\longmapsto 10x=\dfrac{1}{\dfrac{1}{1000}}[/tex]

[tex]\\ \sf\longmapsto 10x=1000[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1000}{10}[/tex]

[tex]\\ \sf\longmapsto x=100[/tex]

Answer:

y = 6x ^2 - 6x + 9

Step-by-step explanation:

hopefully it's visible

:)

Answer:

A square is a retangle

Step-by-step explanation:

Because a squre is a rectangle

Let y = x + 22 and dy = dx, so the integral becomes

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{25}^{31} \frac{\mathrm dy}{(y-1)\sqrt{y}}[/tex]

Now let z = √y, so that z ² = y. Then 2z dz = dy, and the integral becomes

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_{\sqrt{25}}^{\sqrt{31}} \frac{2z}{(z^2-1)z} \\\\ = \int_5^{\sqrt{31}} \frac{2}{z^2-1}\,\mathrm dz[/tex]

Expand the integrand into partial fractions:

[tex]\dfrac{2}{z^2-1} = \dfrac1{z-1}-\dfrac1{z+1}[/tex]

Then we have

[tex]\displaystyle \int_3^9 \frac{\mathrm dx}{(x+21)\sqrt{x+22}} = \int_5^{\sqrt{31}}\left(\frac1{z-1}-\frac1{z+1}\right)\,\mathrm dz \\\\ = \left(\ln|z-1|-\ln|z+1|\right)\bigg|_5^{\sqrt{31}} \\\\ =\left[\ln\left|\frac{z-1}{z+1}\right|\right]\bigg|_5^{\sqrt{31}} \\\\ =\ln\left(\frac{\sqrt{31}-1}{\sqrt{31}+1}\right) - \ln\left(\frac{4}{6}\right) \\\\ =\ln\left(32-2\sqrt{31}\right) - \ln\left(\frac23\right) \\\\ =\boxed{\ln\left(48-3\sqrt{31}\right)}[/tex]

Answer: $ 39.60

Step-by-step explanation:

36 + (36*0.10) = 39.60

Answer:

volume of hemisphere =1912.26cm^3

Step-by-step explanation:

Answer:

x^4

Step-by-step explanation:

x^(2/5) ^10

We know that a^b^c = a^(b*c)

x^(2/5*10)

x^4

Answer:

[tex]{x}^{4} [/tex]

Step-by-step explanation:

[tex] ({x}^{ \frac{2}{5} } ) ^{10} \\ {x}^{ \frac{2}{5} \times 10} \\ {x}^{ \frac{20}{5} } \\ {x}^{4} [/tex]

Step-by-step explanation:

Any number that can be divided by 2 without having remainder is considered an even number.

I hope it helped U

stay safe stay happy

Answer:

x = 50

Step-by-step explanation:

When two secants intersect in the interior of a circle, the angles formed are the average of the arc an angle and its vertical intercept. In this case, our angle, 73, should be the average of x and 96. We can translate this to an equation and solve:

[tex]\frac{x+96}{2} = 73[/tex]

x + 96 = 146

x = 50

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Just a correction, the characteristic roots of the equation are [tex]y = 7[/tex] and [tex]y = -\frac{1}{2}[/tex], thus, we should test for:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

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Question a:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]

[tex]y^{\prime\prime} = 49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}[/tex]

[tex]2y^{\prime\prime} - 13y^{\prime} - 7y = 0[/tex]

[tex]2(49Ae^{-7x} + \frac{1}{4}Be^{-\frac{x}{2}}) - 13(7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}) - 7(Ae^{7x} + Be^{-\frac{x}{2}}) = 0[/tex]

[tex]98Ae^{-7x} + \frac{1}{2}Be^{\frac{x}{2}} - 91Ae^{-7x} + \frac{13}{2}e^{-\frac{x}{2}} - 7Ae^{7x} - 7Be^{-\frac{x}{2}} = 0[/tex]

[tex]98Ae^{-7x} - 91Ae^{-7x} - 7Be^{-\frac{x}{2}} + \frac{1}{2}Be^{\frac{x}{2}}  + \frac{13}{2}e^{-\frac{x}{2}} - 7Be^{-\frac{x}{2}} = 0[/tex]

[tex]0A + 0B = 0[/tex]

[tex]0 = 0[/tex], thus, we found the identity, and for each constant A and B, the following is a solution.

--------------------------------------------------

Question b:

[tex]y = Ae^{7x} + Be^{-\frac{x}{2}}[/tex]

[tex]A + B = 3 \rightarrow B = 3 - A[/tex]

--------------------------------------------------

[tex]y^{\prime} = 7Ae^{-7x} - \frac{1}{2}Be^{-\frac{x}{2}}[/tex]

[tex]7A - \frac{1}{2}B = -5[/tex]

Using [tex]B = 3 - A[/tex]

[tex]7A - \frac{3}{2} + \frac{A}{2} = -5[/tex]

[tex]\frac{14A}{2} + \frac{A}{2} = -\frac{10}{2} + \frac{3}{2}[/tex]

[tex]\frac{15A}{2} = -\frac{7}{2}[/tex]

[tex]15A = -7[/tex]

[tex]A = -\frac{7}{15}[/tex]

--------------------------------------------------

Then, B is given by:

[tex]B = 3 - A = 3 - (-\frac{7}{15}) = \frac{45}{15} + \frac{7}{15} = \frac{52}{15}[/tex]

Thus, the values are: [tex]A = -\frac{7}{15}, B = \frac{52}{15}[/tex]

A similar problem is given at https://brainly.com/question/2456414

Answer:

16 once is the better one.

Answer: 12-ounce bag is better by $0.02 per ounce

Concept:

When coming across questions that ask for a comparison between prices, we should make the final unit [price per object].

In finding [price per object], simply do [Total price / number of objects].

Solve:

A 12-ounce bag of rice costs $4.08

Total price / number of objects = 4.08 / 12 = $0.34 per ounce

A 16-ounce bag of rice costs $5.76

Total price / number of objects = 5.76 / 16 = $0.36 per ounce

$0.36 - $0.34 = $0.02

$0.34 < $0.36, therefore, 12-ounce bag is better by $0.02 per ounce.

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Step-by-step explanation:

Answer:

The correct choice is option B. y+1/y-1

Step-by-step explanation:

Answer:

question is not proper

Step-by-step explanation:

question is

Answer: Volume is 4.19

Step-by-step explanation:

The equation for the volume of a cone is πr^2(h/3)

r = 1

h = 4

Fill in values into the equation

π(1)^2(4/3) = 4.19

Answer:

∠ A ≈ 79.0°

Step-by-step explanation:

Using the Cosine rule to find the angle

cosA = [tex]\frac{b^2+c^2-a^2}{2bc}[/tex]

        = [tex]\frac{15^2+29^2-30^2}{2(15)(29)}[/tex]

        = [tex]\frac{225+841-900}{870}[/tex]

        = [tex]\frac{166}{870}[/tex] , then

A = [tex]cos^{-1}[/tex] ([tex]\frac{166}{870}[/tex] ) ≈ 79.0° ( to the nearest tenth )

Answer:

totally 16 numbers can be formed

It is hard and the condition of repeat of number should be clear if you have formula ( it is obvious to have) you can use that.