63/5 - 21/5 - 73/5 = porfa ayudenme con esto, es mi primera pregunta<3, son restas de racionales, gracias <3

Answer:

30

Step-by-step explanation:

WE use permutation for this question:

since the letters in SQUARE are all distinct, so：

[tex]^{6}P_{2} = 6*5=30[/tex]

The number of ways of arranging 2 letters from the word S Q U A R E is given by A = 15 ways

The number of ways of selecting r objects from n unlike objects is given by combinations

ⁿCₓ = n! / ( ( n - x )! x! )

where

n = total number of objects

x = number of choosing objects from the set

Given data ,

Let the number of ways of arranging 2 letters from the word S Q U A R E be represented as A

Now , to select 2 letters from the 6 letters in the word SQUARE, without regard to order.

This is a combination problem, since the order in which we select the letters does not matter. Therefore, we can use the formula:

6 C 2 = 6! / 2!(6 - 2)!

= 6 x 5 / (2 x 1) x (4 x 3 / (2 x 1))

= 15

Hence , there are 15 ways to arrange 2 letters from the word SQUARE

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Answer:

D

Step-by-step explanation:

Rotating 270 puts you in the 4th quadrant.

Answer:

5%

Step-by-step explanation:

Answer:

1.5

18 and 33

Step-by-step explanation:2.

c

Answer:

14/15

Step-by-step explanation:

9/15+5/15=14/15

3/5+1/3

common denominator is 15 ( just think about the 3 times table and 5 times table )

5*3=15

3*5=15

Multiply the denominator and numerator by 3 for 3/5

Multiply the denominator and numerator by 5 for 1/3

(3)(3)/(5)(3) +(1)(5)/3(5)

9/15+5/15= 14/15

Answer : 14/15

Answer:

Rate per day: 6 rooms

estimate: 6*5 = 30 rooms

Answer:

b) I think. sorry if its wrong.

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

4x2=8

8x5=40

Answer:

Function: c = 2(m) + 5

A: Jason will spend $11 because 2(3) + 5 = (6 + 5) =11

B: No, because 2(7) + 5 = (14 + 5) = 19 and he only has 15 dollars.

Step-by-step explanation:

Cost = $2(the rate per mile) x (M)(miles driven) plus $5 (base cost)

For A and B I solved using the function.

The midpoint of a segment divides the segment into equal halves

The given parameters are:

[tex]\mathbf{R =(24,0)}[/tex]

[tex]\mathbf{N =(12,18)}[/tex]

[tex]\mathbf{T =(12,6)}[/tex]

[tex]\mathbf{E =(18,15)}[/tex]

K is the midpoint of N and T.

So, we have:

[tex]\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}[/tex]

This gives

[tex]\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}[/tex]

[tex]\mathbf{K = (12,12)}[/tex]

E is the midpoint of T and I.

So, we have:

[tex]\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}[/tex]

This gives

[tex]\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}[/tex]

Multiply through by 2

[tex]\mathbf{(36,30) = (I_x + 12,I_y+ 6)}[/tex]

By comparison

[tex]\mathbf{I_x + 12 = 36.\ I_y + 6 =30}[/tex]

So, we have:

[tex]\mathbf{I_x= 24.\ I_y =24}[/tex]

Hence, the coordinates of I are:

[tex]\mathbf{I = (24,24)}[/tex]

I is the midpoint of E and B.

So, we have:

[tex]\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}[/tex]

This gives

[tex]\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}[/tex]

Multiply through by 2

[tex]\mathbf{(48,48) = (18 + B_x,15 + B_y)}[/tex]

By comparison

[tex]\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }[/tex]

So, we have:

[tex]\mathbf{B_x = 30,\ B_y = 33 }[/tex]

Hence, the coordinates of B are:

[tex]\mathbf{B = ( 30,33 )}[/tex]

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Answer: Input values are 8,-2,12,9, and 18, so select 9 and -2.

Answer:

Step-by-step explanation:

Answer:

That depends on how accurate you are with pen and paper.

You can tell it's a growing exponential, so the form is the traditional one. If you are particularly inclined in crunching numbers and working on a grid I would pick 0, 1 and -1, 1/2 and -1/2, a few positive integers, and that's it.

If not, i would be satisfied saying that when x = 0 (ie, the y intercept) y= 3, and that's all. Then, my drawing is made with paint, don't expect a masterpiece.

Answer:

Rounded up percentages:

Corn: 15.65%

Green Beans: 16.52%

Tomatoes: 6.96%

Carrots: 13.04%

For exact percentages divide this with a calculator:

Corn: 360/2300

Green Beans: 380/2300

Tomatoes: 160/2300

Carrots: 300/2300

Answer:

2

Step-by-step explanation:

8*6 = 48 /  6* 4 = 24

So we would get 48/24.

Now we simplify so 48/24 would simplify to 2.

So the answer is 2.

Answer:

40cm :)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

-5(x - 19) ≤ -6 + 2x                           Remove the brackets on the left

-5x +95 ≤ -6 +2x                             Add 5x to both sides.

95 ≤ -6 + 2x +5x                             combine

95 ≤ -6 + 7x                                    Add 6 to both sides

101 ≤ 7x                                           Divide by 7

101 /7 ≤ x                  

What you do next is both tricky and time consuming. You have to get x on the left and the fraction on the right. So subtract x from both sides. And subtract 101/7 from both sides. They both become minus.

101/7 - 101/7 ≤ -101/7 + x

0 ≤ -101/7+ x                                   Now subtract x from both sides

-x ≤ -101/7 + x -x

-x ≤  -101/7

Now comes the really nasty part. You have to get x > 0 and -101/7>0 That's easy enough. You just multiply both sides by -1

x ≤ 101/7

But when you do that (and this where you have to pay attention) the ≤ becomes ≥

x≥ 101/7

Answer:

x=1.5 y=-1/3

Step-by-step explanation:

2x-3y=4

2x+8=11

Let's subtract 8 from both sides of the second equation:

2x=3

x=1.5

Substituting this into the first equation, we get:

2(1.5)-3y=4

3-3y=4

-3y=1

y=-1/3

Answer:

X= 65

Y= 120

Step-by-step explanation:

3y +235 = y-5

2y +235 = - 5

2y = 240

Y = 120

2x - 60 = x-5

X - 60 = - 5

X = 65

Answer:

1

Step-by-step explanation:

Subsitute x and y:

x + y - 4

= 4 + 1 - 4

= 1

The expected number of a dataset is the mean of the dataset

The given parameters are:

[tex]\mathbf{n = 100}[/tex] --- sample size

[tex]\mathbf{r = 3}[/tex] --- selection of 3 people

(a) The expected number of birthdays

The probability of a having a birthday on a certain day is:

[tex]\mathbf{p = \frac{1}{365}}[/tex]

The probability of not having a birthday on the day is:

[tex]\mathbf{q = \frac{364}{365}}[/tex]

For a selection of 3 people in 100, the expected number of selection is:

[tex]\mathbf{E(x) =Days \times ^{100}C_3 \times p^3 \times q^{100 - 3}}[/tex]

So, we have:

[tex]\mathbf{E(x) = Days \times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{100 - 3}}[/tex]

Rewrite as:

[tex]\mathbf{E(x) =Days \times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{97}}[/tex]

There are 365 days in a year.

So, the expression becomes

[tex]\mathbf{E(x) =365\times ^{100}C_3 \times \frac{1}{365}^3 \times \frac{364}{365}^{97}}[/tex]

(b) Expected number of distinct birthdays

The probability that a person from the has his birthday on a certain day is:

[tex]\mathbf{p = 1 - (\frac{364}{365})^{100}}[/tex]

For 365 days, the expected number of distinct birthdays is:

[tex]\mathbf{E(x) = Days \times (1 - (\frac{364}{365})^{100})}[/tex]

There are 365 days in a year.

So, the expression becomes

[tex]\mathbf{E(x) = 365\times (1 - (\frac{364}{365})^{100})}[/tex]

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Pregnancy can be a factor in changing body composition for women between the ages of 20 and 40, with an estimated 40 percent of women gaining excessive weight.

Body composition is affected by all the changes a body undergoes. Some may result in positive, while other in negative as side effects.

For a women between age group 20 to 40 face weight gaining problem. Generally this is becuse mostly women are pregnant during this age group and due to the biological changes occured during pregnancy may result in weight gain as a side effect to most of them.

Thus, Pregnancy can be a factor in changing body composition for women between the ages of 20 and 40

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if 2+8=10 then 12+8=20 so Asher is 12 years old while His sister is 20 cus we're adding Ash age to his sister which we don't kno what her age is but at the same time we both know that whatever her age is it adds up to 20

Answer:  Option C, neither.

Step-by-step explanation:

Here we have the table:

x: -10    -3    4    11

y:   1      6    30   120

This means that if our function is f(x), then:

f(-10) = 1

f(-3) = 6

f(4) = 30

f(11) = 120

We want to know if this represents a linear equation or an exponential equation or neither.

First, let's try with a linear equation.

We know that a linear equation can be written as:

f(x) = a*x + b

Then let's input the known values and let's see if this equation works.

We can use two of the known points to get:

f(-10) = 1 = a*-10 + b

f(4) = 30 = a*4 + b

With these equations, we can find the value of a and b, once we find these values, we can see if the equation also works for the other two points.

1 = a*-10 + b

30 = a*4 + b

First, we need to isolate one of the variables in one of the equations.

I will isolate b in the first one:

b = 1 + a*10

Now we can replace this in the other one to get:

30 = a*4 + 1 + a*10

30 = 1 + a*14

30 - 1 = a*14

29 = a*14

29/14 = a = 2.07

and using the equation b = 1 + a*10 we can find the value of b:

b = 1 + 2.07*10 = 1 + 20.7 = 21.7

Then the equation we get is:

f(x) = 2.07*x +  21.7

Now we need to see if this works for the other two points:

for x = -3, we need to get: f(-3) = 6

f(-3) = 2.07*-3 + 21.7 = 15.49

We did not get the value we expected, then we already know that the relationship is not linear.

Now let's see if the relationship can be exponential.

An exponential function is written as:

f(x) = A*(r)^x

Let's do the same as above, let's use two of the known points to find the values of A and r

f(-3) = 6 = A*(r)^(-3)

f(4) = 30 = A*(r)^4

Now we have the system of equations:

30 = A*(r)^4

6 = A*(r)^(-3)

If we take the quotient of these two equations, we get:

(30/6) = (A*(r)^4)/( A*(r)^(-3))

5 = (r^4)*r^3 = r^(4 + 3) = r^7

(5)^(1/7) = r = 1.258

And the value of A is given by:

30 = A*(1.258)^4

30/( (1.258)^4 ) = 11.98

Then the exponential equation is something like:

f(x) = 11.98*(1.258)^x

Now let's see if this equation also works for the other two points:

for x = -10, we should get f(-10) = 1

Let's see that:

f(-10) = 11.98*(1.258)^(-10) = 1.2

And for x = 11 we should get f(11) = 120

f(11) =  11.98*(1.258)^(11) = 149.6

So we get values closer to the ones we should get, but not the exact ones, so this is not an exponential relation.

Then the correct option is C, neither.

Answer:

increase

$750

y=750x+1000

Answer:

19.66

Step-by-step explanation:

Let x represent our unknown number

Okay so it's basically saying that 30 is greater than 3x by 89

We would represent that mathematically by:

30 - 89 = 3x

So then we just solve this like we usually would

30 - 89 = -59

-59 [tex]\div[/tex] 3 = 19.666. . .

Hope this helps:)

Answer:  11/6 0r 1 5/6

Step-by-step explanation:

12x = 22

x = 22/12

x = 11/6 or 1 5/6

Answer:

48

11

Step-by-step explanation:

5 glasses  ------  20 sec

12 glasses ------  ?

so 5 * x = 12 * 20

x = 12 * 4

x = 48

12 glasses -------  48 sec

?   glasses -------  44 sec

so 12 * 44 = x * 48

44 = x * 4

x = 44/4 = 11

x = 11

Answer:

12 - 48

11 - 44

Step-by-step explanation:

20 ÷ 5 = 4

12 · 4 = 48

44 ÷ 4 = 11

I hope this helps!

Answer -162

Step-by-step explanation:

Answer:

=−162

Step-by-step explanation: