5. Ms. Lee has 220 students in all her classes. If her classes collected 2860 pounds of food, how many meals did each student provide? Round UP to the nearest number.
Note: 1.2 pounds of food equals one meal
Note:1 kilogram is 2.2 pounds

Answers

Answer 1

Answer:

Each students provides 13 pounds of meal

Step-by-step explanation:

Total students in Ms. Lee class = 220

Total pounds of food collected = 2,860

how many meals did each student provide?

Meals provided by each student = Total pounds of food collected / total number of students

= 2,860 / 220

= 13 pounds

Each students provides 13 pounds of meal

Note: 1.2 pounds of food equals one meal

1.2 pounds : 1 meal = 13 pounds : x meals

1.2/1 = 13/x

1.2 * x = 1 * 13

1.2x = 13

x = 13 / 1.2

= 10.83 meals

Approximately 11 meals to the nearest number

Note:1 kilogram is 2.2 pounds

1 kg : 2.2 pounds = x kg : 13 pounds

1/2.2 = x / 13

1 * 13 = 2.2 * x

13 = 2.2x

x = 13/2.2

= 5.91 kilogram

Approximately x = 6 kilograms


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Answers

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(a)w = 0

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During week 0 the old factory produced 33 more items than at the new factory.

The weekly number of specialty items produced at the new factory exceed the weekly number of specialty items produced at the old factory at week 4.

What is a function?

A function is defined as a relation between a set of inputs having one output each. A function is a relationship between inputs where each input is related to exactly one output. Every function has a domain or range.

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Specialty items produced at the old factory at week 0,

Given function = [tex]223(1.09)^{x}[/tex]

When x = 0,

f(x) = [tex]223(1.09)^{0}[/tex]

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Old factory exceeded the production by:

⇒ ( 223 -  190 )

= 33 specialty items.

Comparing the growth rates of weekly number of specialty items at each factory,

For week 0,

Old factory = 223

New factory = 190

Growth rate = [tex]\frac{223-190}{190}*100[/tex]

                    ≈ 17%

For week 1,

Old factory = 243

New factory = 220

Growth rate = [tex]\frac{243.07-220}{220}*100[/tex]

                    ≈ 10%

For week 2,

Old factory = 265

New factory = 252

Growth rate = [tex]\frac{264.95-252}{252}*100[/tex]

                    ≈ 5%

For week 3,

Old factory = 289

New factory = 290

Growth rate = [tex]\frac{290 -288.79}{288,79}*100[/tex]

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For week 4,

Old factory = 325

New factory = 337

Growth rate = [tex]\frac{337-324.78}{324.78}*100[/tex]

                    ≈ 3%

For week 5,

Old factory = 343

New factory = 380

Growth rate = [tex]\frac{380-343.11}{343.11} *100[/tex]

                    ≈ 13%

For week 6,

Old factory = 374

New factory = 440

Growth rate = [tex]\frac{440-374}{374} *100[/tex]

                    ≈ 18%

For week 7,

Old factory = 408

New factory = 505

Growth rate = [tex]\frac{505-408}{408} *100[/tex]

                   ≈ 23%

At week 3, the production at new factory exceeds the production of the old factory.

For old factory,

⇒ f(x) = [tex]223(1.09)^{x}[/tex]

          = [tex]223(1.09)^{3}[/tex]

          = 289

For new factory at week 3,

Production = 290 items.

Hence, we can conclude, during week 0 the old factory produced 33 more items than at the new factory and the weekly number of specialty items produced at the new factory exceed the weekly number of specialty items produced at the old factory at week 4.

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