3. The Protons in the nucleus has relevative
Charge of________
the electrons has relativie
charge of_____​

Answer: The answer is D. The central atoms consist of two carbons.

Explanation:

Answer:

The central atoms consist of two carbons

Explanation:

Took the test! hope this helps!

Answer Copper, copper is a type of metal, so it can form cations

The atoms of element will form cations is Copper as to get the stable electronic configuration.

Cations are those species which carries possitive charge on it and produced by any element by lossing of their outermost electrons.

An atom will form cation to get the stable outermost configuration.

Hence option (C) is correct i.e. Copper.

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Answer:

Element is not present in an atom

Answer:

element

Explanation:

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question

volume = final volume of water - initial volume of water

volume = 18.3 -15 = 3.3 mL

We have

[tex]density = \frac{33.65}{3.3} \\ = 10.19696969...[/tex]

We have the final answer as

Hope this helps you

Answer:

2.88 g

Explanation:

First, let us look at the balanced equation of the reaction:

[tex]CaO(s) + H_2O (l) --> Ca(OH)_2(s)[/tex]

From the equation, 1 mole of CaO reacts with 1 mole of H2O to produce 1 mole of [tex]Ca(OH)_2[/tex].

mole = mass/molar mass

4.50 g of CaO = 4.50/56.08 = 0.08 mole

4.34 g of H2O = 4.34/18.02 = 0.24 mole

The ratio of moles of CaO and H2O should be 1:1, hence, H2O is in excess.

Excess mole of H2O = 0.24 - 0.08 = 0.16 mole

mass of 0.16 mole of H2O = mole x molar mass = 0.16 x 18.02 = 2.88 g

Therefore, 2.88 g of the excess reagent (water) would remain after the reaction is complete.

Answer:

A Weak acid indicator has general formulae HIn- and base has In-.

When constructed a plot determining wavelength equilibrium reached according to the equation HIn(aq) + H2O(l) ↔ In-(aq) + H3O+(aq)

HIn(aq) is the acid, that has a different color from the base In-(aq). When the pH is low, the concentration of the hydronium ion H3O+ is high and equilibrium is toward the left, producing the color A.

At high pH, the concentration of H3O+ is low, so equilibrium tends toward the right side of the equation and color B is displayed

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The system here is chloroplast, so the boundary of the system would be cell cell membrane. Input will be nutrients, output waste and process photosynthesis

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Answer:

X and Z

Explanation:

See attachment for complete question...

Your question illustrates kinetic energy as it relates to height (according to the attachment)

Kinetic energy increases with a decrease in height.

So, from the attachment...

W and Y are at higher heights.

While X and Z are at lowest heights

By the analysis above, kinetic energy would be at highest at X and then Z.

Hence, the answer to the question is X and Z.

Answer:

e. None of these

Explanation:

The oxide of Bromine (BrₐOₓ) produce "a" moles of Br that are equal to "a" moles of AgBr. The moles of AgBr are:

Moles AgBr:

3.188g AgBr * (1mol / 187.78g) = 0.01698 moles of AgBr = Moles of Br

These moles of Br weighs (Molar mass: 79.9g/mol):

0.01698 moles of Br * (79.9g / mol) = 1.36g of Br

Mass of Oxygen must be:

1.90g - 1.36g Br = 0.54g oxygen. In moles:

0.54g O * (1mol / 16g) = 0.03375 moles of O

Empirical formula is the simplest ratio of atoms in the molecule. Dividing in the moles of Br:

Br:  0.01698 moles of Br / 0.01698 moles = 1

O: 0.03375 moles of O / 0.01698 moles = 1.99 ≅ 2

That means empirical formula is:

BrO₂

And right option is:

The empirical formula of the oxide would be [tex]BrO_2[/tex]

1.90 g of the oxide of bromine produces 3.188 g of AgBr

moles of 3.188 g AgBr = 3.188/187.78

                                        = 0.017 moles

AgBr ---> Ag+ + Br-

Thus, mole of Br in AgBr = 0.017 moles

Mass of 0.017 Br = mole x molar mass

                           = 0.017 x 79.904

                              = 1.357 g

Mass of oxygen in the oxide of bromine = 1.90 - 1.357

                                                                    = 0.543 g

mole of 0.543 oxygen = 0.543/16

                                       = 0.0339 moles

mole of 1.357 g Br = 0.017

Dividing by the smallest:

Br = 0.017/0.017 = 1

O = 0.0339/0.017 = 1.99

Empirical formula = BrO2

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Answer:

Taking energy away from a gas cooling it down may cause it to turn into a liquid or condense

Answer:

sold,liquidator gas

Explanation:

pressure| practicelmodel of matter| siyavula

Answer:

[tex]Kp = \frac{P_{NH_{3}} ^{2} }{P_{N_{2}} ^{}P_{H_{2}} ^{3} }[/tex]

Explanation:

For the reaction at equilibrium:

N₂ (g) + 3 H₂(g) ⇄ 2 NH₃ (g)

Since this is an equilibrium in the gas phase, the equilibrium expression is obtained from the partial pressures (P) of the products (NH₃) and reactants (N₂ and H₂) raisen to their stoichiometric coefficients:

[tex]Kp = \frac{P_{NH_{3}} ^{2} }{P_{N_{2}} ^{}P_{H_{2}} ^{3} }[/tex]

Answer:

Explanation:

abything that is both mass and volume

Answer:

anything that has both mass and volume

Answer: 22.78KJ/ mol

Explanation:

The computation of activation energy [tex]E_0[/tex] follows by formula:

[tex]\ln (\dfrac{K_2}{K_1}) = (\dfrac{E_a }{ R}) (\dfrac{1}{T_1} -\dfrac{ 1}{T_2})[/tex]

Given:[tex]T_1 = 376.0^{\circ}C =376+273K= 649 K[/tex]

[tex]K_1 = 4.8 \times10^8[/tex]

[tex]T_2 = 280.0^{\circ}C = 273+280K=553 K ,\ \ \ K_2 = 2.3 \times 10^8[/tex]

[tex]\ln(\dfrac{2.3 \times10^8 }{ 4.8 \times 10^8}) = (\dfrac{E_a }{ 8.314}) (\dfrac{1}{649} - \dfrac{1}{553})\\\\\Rightarrow\ \ln(0.479) = (\dfrac{E_a }{ 8.314}) (-\dfrac{96}{358897})\\\\\Rightarrow\ -0.73605468= (\dfrac{E_a }{ 8.314}) (-\dfrac{96}{358897})\\\\\Rightarrow\E_a=-0.73605468\times 8.314\times\dfrac{-358897}{96}=22878.033\\\\\Rightarrow\E_a=22878.033\ J/mol=22.78 KJ /mol[/tex]

Hence, the activation energy for this reaction =22.78KJ/ mol

Answer:

There are two properties that can be used to identify an element: the atomic number or the number of protons in an atom. The number of neutrons and number of electrons are frequently equal to the number of protons, but can vary depending on the atom in question.

Answer:

the apple changed color

Explanation:

cause when it changes to brown it means the apple is no longer edible

many fruits with just having contact with the air it may change color like apple

Answer: This means that the isotope of silicon with a mass number of 28 is by far the most common of these three isotopes.

Explanation:

The abundance of Si-28 is 92.23%. Si-29 is 4.68% and Si-30 is 3.09%.

Answer:

See explanation

Explanation:

Let us remember that the Iodide ion is a good nucleophile.  SN2 reaction is  promoted in a polar aprotic solvents like  acetone.

Aprotic solvents like acetone do not favor the formation of a carbocation hence the reaction of Sodium iodide in acetone with PhCH2Cl proceeds by SN2 mechanism. This is possible because the compound possesses a halogen atom(Cl) which is easily replaced by I^- from NaI. The corresponding NaCl formed is insoluble in acetone.

Similarly, when AgNO3/ethanol reacts with PhCH2Cl; ethanol which is a polar protic solvent and a poor nucleophile coordinates with the silver ion in the  PhCH2Cl and enhances carbocation formation (SN1 mechanism operates).

The SN2 mechanism is not followed here because there is no good nucleophile present compared to the situation in the reaction of PhCH2Cl with NaI/acetone.

Answer:

Explanation:

From the given information:

We explained the reaction mechanism of 2,4-pentanedione with hydrazine to yield 3,5-dimethylpyrazole as shown below;

At the initial stage, the carbonyl oxygen gains a proton, increasing the carbonyl carbon's electrophilicity. After that, the carbonyl carbon is being attacked by hydrazine. Then, the process proceeds with the species formed where removal of a proton takes place. Similarly, hydroxyl oxygen gains a proton. After that, the water molecule is being removed, and further rearrangement of an electron occurs at the site of nitrogen in hydrazine.

From species formed, the removal of a proton takes place. Finally, all step is being repeated to yield the final product known as 3,5 - dimethylpyrazole.

Answer:

0.0820M H₃PO₄

Explanation:

THe phosphoric acid, H₃PO₄ reacts with sodium hydroxide, NaOH, thus:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

The moles of NaOH used to neutralize the acid are:

Moles NaOH:

20.8mL = 0.0208L * (0.532mol / L) = 0.0111 moles NaOH.

That means moles of phosphoric acid in the solutionare:

0.0111 moles NaOH * (1mole H₃PO₄ / 3 moles NaOH) =

0.00369 moles H₃PO₄

These moles are in 45.0mL = 0.045L. The molar concentration of the solution are:

0.00369 moles H₃PO₄ / 0.045L =

Answer:

V = 83.6 L

Explanation:

Given data:

Number of moles of He = 5.33 mol

Pressure of gas = 1.56 atm

Temperature of gas = 25°C

Volume of sample = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

Now we will put the values in formula.

1.56 atm × V = 5.33 mol ×  0.0821 atm.L/ mol.K  × 298 K

1.56 atm × V = 130.4 atm.L

V = 130.4 atm.L/1.56 atm

V = 83.6 L

According to the Aufbau principle, the 4s orbital is filled first instead of the 3d orbital

Each electron shell and its orbitals have a specific energy level.

The farther the shell is from the atomic nucleus, the higher the energy level.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub shell in the shell of an atom, namely s, p, d and f.

Charging electrons in the subshell uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

According to Aufbau, electrons occupy orbitals of the lowest energy level  

So the 4s orbital has a lower energy level than the 3d orbital, so the electrons fill the 4s orbital first

Answer:

See full explanation.

Explanation:

Hello.

In this case, since we apply the law of mass action in order to write the equilibrium expression for each chemical reaction, we proceed as follows:

a. The reaction is:

[tex]2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)[/tex]

And the equilibrium expression:

[tex]Kc=\frac{[CO_2][CF_4]}{[COF_2]^2}[/tex]

Since all the species are in gaseous phase they are included on the equilibrium expression.

b. The reaction is:

[tex]Cu(s)+Ag^+(aq)\rightleftharpoons Ag(s)+Cu^{2+}(aq)[/tex]

And the equilibrium expression:

[tex]Kc=\frac{Cu^{2+}}{Ag^+}[/tex]

Since only copper (II) ions and silver (I) ions are in aqueous phase.

c. The reaction is redox and it turns out:

[tex](S_2O_8)^{2-}+Fe^{2+}\rightleftharpoons Fe^{3+}+(SO_4)^{2-}\\\\S_2^{7+}+2e^-\rightarrow 2S^{6+}\\\\2\times (Fe^{2+}\rightarrow Fe^{3+}+1e^-)\\\\\\(S_2O_8)^{2-}(aq)+2Fe^{2+}(aq)\rightleftharpoons 2Fe^{3+}(aq)+2(SO_4)^{2-}(aq)[/tex]

And the equilibrium expression:

[tex]Kc=\frac{[Fe^{3+}]^2[(SO_4)^{2-}]^2}{[(S_2O_8)^{2-}][Fe^{2+}]^2}[/tex]

Since all the species are in aqueous phase.

Answer:

Empirical formula: C3H30

Molecular formula: C6H6O2

Explanation:

The empirical formula can be calculated thus:

65.45% C - 65.45g

5.45% H - 5.45g

29.09% O - 29.09g

We convert each mass to mole by dividing by their respective atomic mass:

C = 65.45/12 = 5.45mol

H = 5.45/1 = 5.45mol

O =29.09/16 = 1.82mol

Next, we divide each mole value by the smallest value;

C = 5.45mol/1.82 = 2.99

H = 5.45mol/1.82 = 2.99

O = 1.82mol/1.82 = 1

Approximately, the empirical ratio of C, H and O is 3:3:1 i.e. C3H3O

Molecular formula is calculated thus:

(C3H3O)n = 100g/mol

{12(3) + 1(3) + 16}n = 100

(36+3+16)n = 100

(55)n = 100

n = 100/55

n = 1.82

n = 2

Molecular formula= (C3H3O)2

C6H6O2

Answer:yes,no,no,yes

Answer:

i feel like it will have an acid smell

Answer:

D. It's the only one with C6H14 on the reactant side.

Explanation:

Answer:

Q = 10118.4 j

Explanation:

Given data:

Mass of ice = 30.0 g

Initial temperature of ice = -20°C

Final temperature = 140°C

Energy required = ?

Solution:

The specific heat of ice is 2.108 J/g*°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 140°C -  (-20°C)

ΔT = 160°C

Q = 30.0 g× 2.108 J/g°C ×160°C

Q = 10118.4 j

Answer:

Explanation:

When the primary amine undergoes Hofmann degradation it forms an Alkene

In this case the alkenes have undergone ozonolysis and has formed two products as butanal and 2-methyl propanal

when we revert back from these aldehydes to alkene we observed the alkene formed will be "2-methyl hept-3-ene " this alkene is the Hofmann product of that primary amine

upon addition of this alkene we observe the primary amine formed is

4-amino-2-methylheptane

Answer:

1 mole

The first step is to calculate the molar mass (gram formula weight) of MgCl2. Molar mass = (24.31 + 2 × 35.45) = 95.21 g mol–1 i.e. 95.21 g of MgCl2 is exactly 1 mole