As you stretch the band a distance x, the force you need to exert has a magnitude of (250 N/m) x.
So if 100 N is required to stretch it to maximum length, then this length is x such that
100 N = (250 N/m) x ==> x = (100 N)/(250 N/m) = 0.4 m
Answer:
0.6
Explanation:
I got it right
A bike travels at 3.0 m/s, and then accelerates to a speed of
8.5 m/s in a time of 2.5 seconds. The average acceleration of
the bike is
m/s2
The average acceleration of the bike is 2.2 m/s²
What is average acceleration?Acceleration, rate at which velocity changes with time, in terms of both speed and direction.
A point or an object moving in a straight line is accelerated if it speeds up or slows down.
According to the question,
Given, initial velocity, u=3.0m/s and final velocity v=8.5 m/s
Time = 2.5 seconds
If a be the acceleration.
a = [tex]\frac{v-u}{t}[/tex]
a = [tex]\frac{8.5 - 3.0}{2.5s}[/tex]
⟹ a=2.2 m/s²
So, The average acceleration of the bike is 2.2 m/s²
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1. A bicycle initially moving with a velocity
5.0 m s-1 accelerates for 5 s at a rate of 2 m s? Wh
will be its final velocity ?
Answer:
[tex]\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}[/tex]
Explanation:
We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.
[tex]v_f= v_i+ at[/tex]
In this formula, [tex]v_f[/tex] is the final velocity, [tex]v_i[/tex] is the initial velocity, [tex]a[/tex] is the acceleration, and [tex]t[/tex] is the time.
The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.
[tex]\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)[/tex]
Solve inside the parentheses.
[tex]\frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s[/tex][tex]v_f= 5.0 \ m/s + (10 \ m/s)[/tex]
Add.
[tex]v_f= 15 \ m/s[/tex]
The units can also be written as:
[tex]v_f= 15 \ m*s^{-1}[/tex]
The bicycle's final velocity is 15 meters per second.
5. Which of the following is NOT a course goal?
For students to understand fitness principles
For students to establish a habit of physical activity
For students to do nothing
For students to enhance their level of physical fitness
Answer:
for students to do nothing
Explanation:
because doing nothing is not a course goal
briefly explain what EMF of a cell cell is
Answer:
The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.
Explanation:
pls mark brainliest
Robin fired a bullet of mass 100 gm from a gun of mass 5 kg. The bullet leaves the gun with a speed of 400 m/s. After penetrating 4 cm of a plank of 10 cm, the bullet loses one third of its initial velocity.
a. Calculate the backward velocity of the gun?
b. Can the bullet penetrate the plank of the wood completely? Explain mathematically.
please help
(a) The recoil or backward velocity of the gun is 8 m/s.
(b) The bullet cannot penetrate the plank of the wood completely.
The given parameters include;
mass of the bullet, m₁ = 100 g = 0.1 kgmass of the gun, m₂ = 5 kginitial velocity of the bullet, u₁ = 400 m/sthickness of the plank, x = 10 cm(a) The backward or recoil velocity of the gun is calculated by applying the principle of conservation of linear momentum.
let the backward or recoil velocity of the gun = u₂m₁u₁ + m₂u₂ = 0
m₂u₂ = -m₁u₁
[tex]u_2 = -\frac{m_1u_1}{m_2} \\\\u_2 = - \frac{0.1 \times 400}{5} \\\\u_2 = -8 \ m/s[/tex]
Thus, the recoil or backward velocity of the gun is 8 m/s.
(b) determine if the bullet can penetrate the plank of the wood completely
the bullet traveled 4 cm and lost ¹/₃ of u₁the remaining distance to completely penetrate the plank = 6 cmthe final velocity of the bullet at 4 cm, v = 400 - ¹/₃ x 400 m/s = 266.67 m/sthe acceleration of the bullet is calculated as;
v² = u₁² + 2as
2as = v² - u²
[tex]a = \frac{v^2 -u_1^2}{2s} \\\\a = \frac{(266.67)^2 -(400)^2}{2\times 0.04} = -1.111 \times 10^6 \ m/s^2[/tex]
Finally, determine the distance traveled by the bullet when it comes to a complete stop, that is the final velocity = 0
[tex]v_f^2 = v^2 + 2ad\\\\2ad = v_f^2 - v^2\\\\d = \frac{v_f^2 - v^2}{2a} \\\\d = \frac{(0) - (266.67)^2}{2(-1.111\times 10^6)} \\\\d = 0.032 \ m[/tex]
d = 3.2 cm
The total distance traveled by the bullet inside the plank = 4 cm + 3.2 cm = 7.2 cm
Therefore, the bullet cannot penetrate the plank completely.
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If ∲E.ds=0, inside a surface, that means :-
(a) there is no net charge present inside the surface
(b) uniform electric field inside the surface
(c) discontinues field lines inside the surface
(d) charge present inside the surface
Answer:
(a) there is no net charge present inside the surface
Explanation:
when ∲E.ds=0,
net charge = 0
Therefore no net charge.
pete walks at a rate of 4.0 miles per hour for 30 minutes. How far did he walk?
DOES STONE DISPLACE MORE WATER THAN ITS WEIGHT
Define the term ‘matter’ in physics.
Answer:
Matter is any substance that has mass and takes up space by having volume
You plan to pass alpha particles through a field that contains a consistent type of particle. Which configuration will result in the largest deflection of alpha particles? (1 point)
low-energy alpha particles passing through a field of low mass-number-particles
low-energy alpha particles passing through a field of high mass-number-particles
high-energy alpha particles passing through a field of high mass-number-particles
high-energy alpha particles passing through a field of low mass-number-particles
Answer:
low-energy alpha particles passing through a field of high mass-number-particles
Answer:
low-energy alpha particles passing through a field of high mass-number-particles
Explanation:
Convert 400 mm to m using the method of dimensional analysis
Answer:
To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4
PLEASE MARK AS BRAINLIEST ANSWER
If star A is 20 light years away from earth and star B is 40 light years away from earth,which star appears brighter and by what factor?
Answer:
Because Star A and Star B have identical luminosities, the difference in their apparent brightness is due solely to distance. Star B is twice as far from Earth as Star A.
Explanation:
How can you distinguish wave motion and particle motion?
Answer:
The particle is defined as the small quantity of matter under the consideration. ... The wave is defined as the propagating dynamic distrubance. The energy of the wave is calculated based on the wavelength and velocity
I HOPE THIS WILL HELP YOU IF NOT THEN SORRY :)Explanation:
In Physics, we distinguish between wave motion and particle motion. Wave motion refers to the movement of a wave-like pattern from one location on the medium to another. ... When you observe the motion of these points, you are observing particle motion - the motion of particles of the rope.
I need help with the question asap.
Answer:
whats the question lol
Explanation:
Answer:d
Explanation:
-8. A vessel is filled with a 20cm of water. When an irregular body of mass 800gm is immersed the volume of water is increased to 60cm3. What is the density of irregular shaped body?
Answer:
13.33 g/cm3
Explanation:
density = mass/volume
mass of irregular body = 800 grams
new volume = 60 cube cm
= density = 800/60 = 13.333 g/cm3
the movement of both oxygen and carbon dioxide in the body is accomplished by ___.
a. diffusion
b. endocytosis
c. exocytosis
d. osmosis
Answer: Diffusion
Explanation: Please give brainliest
An observer measures a 100 Hz Doppler shift as an ambulance goes by. At rest, the frequency of the ambulance's siren is 2,000 Hz. What is the speed of the ambulance?
Answer:
8.6 m/s
Explanation:
The observer is stationary
The source is moving
Let v₀ be the speed of sound in the air
Let v be the speed of the ambulance
As the siren approaches
f₁ = 2000(v₀ / (v₀ - v))
As the siren departs
f₁' = 2000(v₀ / (v₀ + v))
f₁ - f₁' = 100
2000(v₀ / (v₀ - v)) - 2000(v₀ / (v₀ + v)) = 100
v₀ / (v₀ - v) - v₀ / (v₀ + v) = 100/2000
v₀(v₀ + v) / (v₀ - v)(v₀ + v) - v₀(v₀ - v) / (v₀ - v)(v₀ + v) = 0.05
(v₀² + vv₀) - (v₀² - vv₀) / (v₀² - v²) = 0.05
2vv₀ / (v₀² - v²) = 0.05
2vv₀ = 0.05 (v₀² - v²)
0.05v² + 2vv₀ - 0.05v₀² = 0
v² + 40vv₀ - v₀² = 0
quadratic formula positive answer
v = (-40v₀ + √((40v₀)² - 4(1)(v₀²))) / 2
v = (-40v₀ + √(1604v₀²)) / 2
v = (0.049968v₀) / 2
v = 0.02498439v₀
If we assume the speed of sound in air is 343 m/s
v = 8.56964... = 8.6 m/s
Approaching frequency heard is 2051 Hz
Departing frequency heard is 1951 Hz
How can you show that an enclosed liquid exerts pressure in all directions equally?
Answer:
Now make holes in all the directions. Now fill with water. The water comes out of the bottle in all the direction. This shows that liquids exert pressure in all direction
How do longshore currents shape the land?
Answer:
Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.
why does balloon pop in the sun?
Answer:
The heat gives atoms/ particles in balloon more kinetic energy so they move further apart, increasing size and eventually popping balloon
^ very simple explanation
Explanation:
A ball is launched from the ground with the horizontal speed of 30 m/s and vertical speed of 30 m/s what angle was the ball launch at?
Answer:
45 degrees
Explanation:
angle of launch=arctan(vertical velocity/ horizontal velocity)
angle = arctan(30/30) = 45 degrees
Brainstorm and write at least 3 potential challenges or important points to consider when conducting the described
data collection.
Plz help me I need to turn this in tomorrow and I’m working on on it at 10:35 pm
Although you did not mention the "described data collection," we can help you answer in the following terms.
The three potential challenges or important points to consider when conducting data collection are:
1.- To correctly establish the specific information needed to get as a result of the research.
2.- The kind of methodology appropriate to get that expected data.
3.- The process needed to analyze and interpret that data.
- As well, it is of the utmost importance that the researcher considers the type of data compared to the budget needed to get it. Here, the budget should consider the cost of the collection process.
- Of course, the result of the process has to result in data that is valid and accurate, because that is the nature of a good research project.
Here we have to stress the relevance of the establishment of a good hypothesis to start the collection process, no matter the data collection methods used to get the data such as interviews, focus groups, observations, and so on.
We can conclude that collection data is a rigorous process that should be strictly followed to really obtain the kind of data needed to support the foundation of any research.
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Evaluate the multi-store model (5 marks)
THIS IS A PSYCHOLOGY QUESTION
Answer:
OK well
Explanation:
where's the question bring it first
Answer:
ExplanationjakkJXJAKGKXAHLKHQHL:
A merry-go-round rotates with a centripetal acceleration of 18 m/s^2. If the outer horses are 9 m from the center of the ride. What is their velocity?
A. 12.7 m/s
B. 14.6 m/s
C. 16.3 m/s
D. 10.4 m/s
Answer:
A
Explanation:
a_c = v^2/r
v = sqrt*a_c × r*
v = sqrt * 18 × 9*
v = 9×sqrt *2*
v = 12. 7 m/s
Una onda se propaga en un medio P, de tal forma que recorre una distancia 8D en un tiempo 4T. La misma onda cuando se propaga por un medio Q recorre una distancia 4D en el mismo tiempo anterior, es decir, en 4T. Respecto a esta onda es correcto afirmar que *
Sabemos todo material tiene asociado un coeficiente de difracción n.
De tal forma que la velocidad de una onda electromagnetica que viaja a travez de dicho material, será:
v = c/n
donde c es la velocidad de la luz.
Con la información dada, podremos concluir que el coeficiente de difracción del medio Q es dos veces el del medio P.
Ahora veamos como llegamos a esto:
Sabemos que en el medio P, la onda recorre una distancia 8*D en un tiempo 4*T
entonces la velocidad de la onda en el medio P es:
[tex]V_p = \frac{8*D}{4*T} = 2*\frac{D}{T}[/tex]
Mientras que en el medio Q, recorre una distancia 4*D en un tiempo 4*T, por lo que la velocidad en el medio Q será:
[tex]V_Q = \frac{4*D}{4*T} = \frac{D}{T}[/tex]
Podemos ver que:
[tex]V_P = 2*V_Q[/tex]
Reescribiendo las velocidades como el cociente entre la velocidad de la luz y el correspondiente coeficiente de difracción obtenemos:
[tex]\frac{c}{n_P} = 2*\frac{c}{n_Q} \\\\n_Q = 2*n_P[/tex]
Es decir, podemos concluir que el coeficiente de difracción del medio Q es dos veces el del medio P.
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Which of the globes in Figure 7.9 will light up?
A ship going from sea water to river water has to displace more water to (a) change the buoyant force (b) decrease the buoyant force in the same buoyant force (d) none of these
Answer:
Change, or increase, the buoyant force.
Explanation:
As the salt water of the sea is denser than the river's fresh water, the boat will rise when entering the sea from the river and sink (to increase the buoyant force) when entering the river from the sea.
someone can help me?
FORMACION DE IMÁGENES EN UN ESPEJO
1. Un objeto es situado frente a un espejo cóncavo, como se muestra en la figura
Con ayuda de los rayos notables, dibuja en donde se forma la imagen y responde
a) ¿Qué tipo de imagen es?:
b) ¿Qué dirección tiene?:
c) ¿Cuál es su tamaño?:
TRANSLATION:
FORMATION OF IMAGES IN A MIRROR
1. An object is placed in front of a concave mirror, as shown in the figure
With the help of the noticeable rays, draw where the image is formed and respond
a) What kind of image is it?:
b) What is your address?:
c) What is its size?:
I hope I helped you^_^
Question 4: Scientists and engineers often plan investigations to see how changing one variable affects the outcome. A variable is any trait, condition or feature of something being tested. Imagine a team is testing the speed of a toy car. In trial 1, they test the car and measure how long it takes it to travel 2 meters. In trial 2, they want to investigate how changing a variable affects the car's speed. Which of the following plans is BEST for trial 2?
A variable, as its name implies, is something that can change, ideally, as the scientists and engineers want to.
Particularly we care for the independent variables, which are the ones we can control and affect the dependent variables, which are the outcomes we study.
For a quick example, think of an experiment where you heat something on an oven. The temperature of the oven can be set by the scientist, so the temperature is an independent variable because they can control it.
Now let's see the given experiment.
The team is testing the speed of the toy car.
remember that:
distance/time = speed.
We know that in the first trial, they test how long takes the car to travel 2 meters.
Now, what we can change for the second trial, knowing that the speed is the output that we are studying?
The answer is trivial, the only thing we can change in the given setup is the distance that the car travels, so in the next trial we should change the variable "distance travelled by the car" and see if it affects the output "speed of the car".
If you want to learn more about variables, you can read:
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What is meant by the term wave front?
Explanation:
Wave front, imaginary surface representing corresponding points of a wave that vibrate in unison. ... Wave fronts for longitudinal and transverse waves may be surfaces of any configuration depending on the source, the medium, and the obstructions encountered.
