3 and 4 are complementary

Answer:

The AP is 1, 11/2, 10, 29/2, 19, ....

Step-by-step explanation:

Let the first term be a and d be the common difference of the arithmetic progression.

ATQ, a+2d+a+6d=38, 2a+8d=38 and a+8d=37. Solving this, we will get a=1 and d=9/2. The AP is 1, 11/2, 10, 29/2, 19, ....

Find the intersection of the two planes. Do this by solving for z in terms of x and y ; then solve for y in terms of x ; then again for z but only in terms of x.

-4x + 2y - z = 1   ==>   z = -4x + 2y - 1

3x - 2y + 2z = 1   ==>   z = (1 - 3x + 2y)/2

==>   -4x + 2y - 1 = (1 - 3x + 2y)/2

==>   -8x + 4y - 2 = 1 - 3x + 2y

==>   -5x + 2y = 3

==>   y = (3 + 5x)/2

==>   z = -4x + 2 (3 + 5x)/2 - 1 = x + 2

So if we take x = t, the line of intersection is parameterized by

r(t) = ⟨t, (3 + 5t )/2, 2 + t⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

(a) The tangent vector to r(t) is parallel to this line, so you can use

v = dr/dt = d/dt ⟨2t, 3 + 5t, 4 + 2t⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in x = -1, y = 1, and z = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

Answer:

I believe it is A

Step-by-step explanation:

Answer:

Option 4) The area of the flower bed is smaller than 4 square feet.

Step-by-step explanation:

Let’s solve for the area of the flower bed.

Consider that the flower bed is a rectangle.

The area of a recrangle is given by the formula:

A = length x width

The area of the flower bed is:

4 ft x 4/6 ft = 2 2/3 ft^2

2 2/3 ft ^2 < 4 ft^2

Therefore option 4 is the correct answer.

Answer:

Divide. Write the quotient in lowest terms.

4\dfrac{4}{5} \div 1\dfrac12 =4  

5

4

​

÷1  

2

Step-by-step explanation:

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

Answer:

167.64 cm

Step-by-step explanation:

I dont kno how to work it out

Answer:

56

Step-by-step explanation:

A=(3*4)+(4*(4+3+4))=56

Answer:

65 m

Step-by-step explanation:

u = 6 m/s

v = 20 m/s

t = 5 s

[tex]s=\frac{1}{2} (6+20)5[/tex]

[tex]s=\frac{1}{2} (26)5[/tex]

[tex]s=(13)5[/tex]

[tex]s=65[/tex]

Hey there!

1/2(6 + 20)(5)

= 1/2 (26)(5)

1/2(26) = 13

= 13(5)

= 65

Therefore, your answer is most likely: 65m

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that  I can think of.

Answer:

5,20,80,320

Step-by-step explanation:

a1 = 5

an = 4 an-1

Let n = 2

a2 = 4 * a1 = 4*5 = 20

Let n = 3

a3 = 4 * a2 = 4*20 = 80

Let n = 4

a4 = 4 * a3 = 4*80 = 320

Answer: sqrt 3V/pih = r

Step-by-step explanation:

3V = (pi r^2h)3

3V = pi r^2 h

3V/pih = r^2

Sqrt (3V/pi h) = r

Answer:

Step-by-step explanation:

BULBS PRODUCED PER DAY:-

[tex]\\ \sf\longmapsto \dfrac{1188440}{365}[/tex]

[tex]\\ \sf\longmapsto 3256[/tex]

Total bulbs

[tex]\\ \sf\longmapsto 31(3256)[/tex]

[tex]\\ \sf\longmapsto 100936[/tex]

Answer:

554.7

Step-by-step explanation:

The pay=25.8*14+(25.8)*5*1.5=554.7

Answer:

[tex] 16 {x}^{4} {y}^{6} [/tex]

Step-by-step explanation:

[tex](4 {x}^{2} {y}^{3} {)}^{2} [/tex]

➡️ [tex] {4}^{2} \times ( {x}^{2} {)}^{2} \times ( {y}^{3} {)}^{2} [/tex]

➡️ [tex] = 16 {x}^{4} {y}^{6} [/tex] ✅

Answer:

y = 6

Step-by-step explanation:

I'm assuming you are trying to say slope "0".

If the slope is 0, it means that the general equation Y = mX + c equals to Y = 0x + c and finally Y = c. Since the line is horizontal because it is 0 slope, Y = 6

The equation of the line with slope 0 passing through the point (-3, 6) will be y = 6.

A line section that can connect two places is referred to as a segment.

In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.

The equation of the line passing through (x₁, y₁ ) is  given by

y - y₁ = m(x - x₁)

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

Given that

The line has points ( -3, 6 )

Slope(m) = 0

The equation of the line passing through (x₁, y₁ ) is  given by

y - y₁ = m(x - x₁)

so,

y - 6 = 0 (x + 3)

y - 6 = 0

y = 6

Hence, the line which is passing through the point ( -3, 6 ) will be y = 6.

For more about line segment

https://brainly.com/question/25727583

#SPJ2

Answer:

A. [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is [tex]\frac{opposite}{hypotenuse}[/tex]

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be [tex]\frac{PR}{PQ}[/tex]

Substituting the values of PR and PQ gives sin(Q) as [tex]\frac{5}{13}[/tex], which is A

Hope this helps!

5 pencils = 15 dollors

1 pencil = 15/5 dollors

therefore 1 pencil = 3 dollors...

Answer:

Each pencil would cost $3.00

Step-by-step explanation:

If 5 costs $15, to find the cost of one you divide 15 by 5

15 ÷ 5 = 3

Step-by-step explanation:

x=72

63+45+x=180

[tex]108 + x = 180[/tex]

[tex]x = 72[/tex]

Answer:

Point has co-ordinates, (0, 5)

Step-by-step explanation:

If they cut y-axis, then x = 0

[tex]2y - x = 10 \\ 2y - 0 = 10 \\ 2y = 10 \\ y = 5[/tex]

Answer:

Step-by-step explanation:

Mean: sum of terms/ number of terms

4 + 2 + 3 + 1 + 1 + 5  = 16

Numbr of terms = 6

16/6 = 2.66

Answered by g a u t h m a th

Answer:

2 2/3

Step-by-step explanation:

The mean is the average of the values

The values on the graph are 4, 2, 3, 1, 1, and 5

Average is sum/number of values

4+2+3+1+1+5=16

16/6=2 2/3

[tex] \begin{cases} \\ \large\bf{\green{ \implies}} \tt \: - \: \frac{1}{2} \: m \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{1 \: m}{2} \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 9 \: \times \: 2 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 18 \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{ \cancel- 18}{ \cancel - 1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{18}{1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: 18 \: \\ \end{cases}[/tex]

Answer:

Line A does not intersect line B.

Step-by-step explanation:

line A comes close, but does not touch, intersect, or overlap line A. hope this helps, please correct me if i am wrong.

Answer:

6 or 5 or 4...........

Step-by-step explanation:

Answer:

x=N :x<7

Step-by-step explanation:

123456

hope it's helpful

Answer:

8 of the 11

Step-by-step explanation:

4+4=8 of the 11

Part of oranges usef from the orange packet used on 1st day = 4/11

Part of oranges used from the orange packet used on 2nd day = 4/11

Total part of oranges used from the orange packet

= (4/11) + (4/11)

= 8/11

So, Sipho's dad used 8 elevenths of the oranges.

Answer:

2x-1=3

2x=3+1

2x=4

x=2

[tex]\huge\boxed{\underline{\bf \: Answer}}[/tex]

(a) Let's try with x = - 1

[tex] \sf \: 2x - 1 = 3 \\\sf 2( - 1) - 1 = 3 \\ \sf- 2 - 1 = 3 \\ \\ \boxed{\bf- 3 \: \bcancel= \: 3}[/tex]

So, x = - 1 is not the solution to the given equation.

______________

(b) Now, try with x = 2

[tex]\sf2x - 1 = 3 \\ \sf2(2) - 1 = 3 \\ \sf4 - 1 = 3 \\ \\ \boxed{\bf3 = 3}[/tex]

Yes, we can see that x = 2 is the correct solution for the equation.

______________

Hope it helps.

RainbowSalt2222