Answer:
Friction = 2 N
Explanation:
F = ma
= .4 * 24.5 = 9.8 N net force 10 N by stick means Ffriction = 2 N
The frictional force acting on the shuffleboard puck is 6.08 N.
What is meant by frictional force ?Frictional force is defined as the resistive force that prevents the relative motion between two surfaces that are in contact with each other.
Here,
Horizontal force applied on the shuffleboard puck, F = 10 N
Mass of the shuffleboard puck, m = 400 g = 0.4 kg
Acceleration of the shuffleboard puck, a = 24.5 m/s²
According to Newton's third law,
F - f = ma
where f is the frictional force acting on the shuffleboard puck.
So, the frictional force,
f = F - ma
f = 10 - (0.4 x 9.8)
f = 10 - 3.92
f = 6.08 N
Hence,
The frictional force acting on the shuffleboard puck is 6.08 N.
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The study of properties of matter, energy and of their mutual relationships is called
Explanation:
The study of properties of matter, energy and of their mutual relationships is called physics
bem ²4.23=1.4m/s
3. Use Equations: What is the mean speed in kilometers per minute (km/min)?
Convert the speed from m/s to km/min using the following formula: mean speed
(m/s) x 1km/1000m x 60s/1min=km/min.
Could 2 students do different amounts of work and have the same power, why?
Answer:
Power is defined as Work / Time
P1 = P2 = W1 / T1 = W2 / T2 W1 and W2 are not necessarily the same Power expended depends on both work input over a unit of time
Which of the following statements is UNTRUE? In order for an object to float..
The buoyant force must be stronger than the gravitational force
The density of the object must be less than the surrounding fluid
The object must be equally buoyant with the surrounding fluid
The fluids must be more dense than the object
Answer:
The object must be equally buoyant with the surrounding fluid
is an untrue statement - because the object could not float - it could be anywhere in the fluid
The amount of energy that would be needed to accelerate a large spaceship to half the speed of light is:.
At a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸ x m (J).
Energy neededThe amount of energy that would be needed to accelerate a large spaceship to half the speed of light is calculated as folllows;
E = mc²
where;
m is mass of the spaceshipc is speed of light = 3 x 10⁸ m/shalf the speed of light = 1.5 x 10⁸ m/s
E = 1.5 x 10⁸ x m
Thus, at a known mass of the spaceship, the amount of energy that would be needed to accelerate the spaceship to half the speed of light is 1.5 x 10⁸ x m (J).
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What are two ways an engineer can build a car in order for it to accelerate faster
Explanation:
Take F=ma
a = F/m
For a higher, F higher or m lower
Means higher horse power for engine or lower mass for the car
An engineer can make a car to accelerate faster by having higher horsepower for the engine or less mass for the car.
What is an Acceleration?Acceleration is defined as the rate of change of velocity of an object with respect to time. These are vector quantities because they have both direction and magnitude. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Acceleration in a car has everything to do with the torque and horsepower on the car where these two characteristics essentially determine the speed of the vehicle. The higher the torque and horsepower, the faster we go
Acceleration is expressed in terms of Force which is equals to
F=ma (m=mass, a= accelaration)
So, a = F/m
For a higher, F will be higher or m will be lower
Thus, an engineer can make a car to accelerate faster by having higher horsepower for the engine or less mass for the car.
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An object with a mass of 5.0 kg accelerates 3.0 m/s2 after a force is applied to it. What is the amount
of force acting on the object?
Answer:
Dont
Explanation:
Know
A sailboat is moving at a constant velocity is work being done by a net external force
Answer:
Yes
Explanation:
The wind net force acting on the sail is doing work. (The 'net' force takes into account the force of friction between the boat hull and the water)
What is the mass of a truck if it produces a force of 14,000 n while accelerating at 5 m/s^2?
Answer:
[tex]F=ma \\ 14000 = 5m \\ m = \frac{14000}{5} \\ \therefore \: m = 2800 \: kg[/tex]
The cluster of galaxies that our own galaxy belongs to is called the.
Answer:
The Local Group/ Virgo Cluster
Explanation:
Our solar system is part of a galaxy called the Milky Way galaxy. The Milky Way galaxy is part of a small cluster of just over 30 galaxies known as the "Local Group." This cluster resides in a larger cluster of galaxies called the "Virgo Cluster" (sometimes called the Virgo Supercluster). The Virgo cluster contains just about 2000 galaxies.
Spacesuits have different parts, each of which is important for the astronaut’s survival.
Use the same article and answer the question.
Space Suit
On the back of the spacesuit is a backpack called the Primary Life Support Subsystem. Why is this backpack important?
Answer:
On the back of the spacesuit is a backpack called the Primary Life Support Subsystem. This backpack contains the oxygen that astronauts breathe during a spacewalk. It removes carbon dioxide that astronauts exhale. The backpack also provides electricity for the suit.
Explanation:
got a 100%.
brainliest, please?
Use the table to answer the question.
A
B
formed by oscillating source
formed by vibration of charged particles
requires a medium to transmit energy
can transmit energy through a vacuum
examples include sound waves
examples include light waves
What should column A be titled?
(1 point)
seismic waves
mechanical waves
surface waves
electromagnetic waves
Answer:
Mechanical Waves
Explanation:
I took the practice
Planet A has a mass of 2.25 x 1020 kg, while planet B has a
mass of 6.20 x 1018 kg. What is the gravitational attraction
between two planets if the distance between them is
435,500 km? Estimate G as 6.67 x 10-11 N (m/kg)
Answer:
4905.95 N
Explanation:
F= G m1 m2 / (r^2)
= 6.67 x 10^-11 * 2.25 * 10^20 * 6.2 * 10^10 / ( 435 500 000)^2 =
( be sure to use meters NOT kilometers !)
The gravitational attraction between two planets is 4905.95 N
What is gravitational attraction?When two objects with masses are placed at a distance, there will an attractive force acting between them.
According to the Newton's law of gravitation, gravitational force is
F = Gm₁m₂ /r²
where r is the distance between the masses m₁ and m₂ and G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²
Substitute the values into the expression, we get
F = 6.67 x 10⁻¹¹ x 2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²
F= 4905.95 N
Thus, the gravitational attraction between two planets is 4905.95 N.
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You find 6.21 g of diamonds. You measure that the diamonds have a volume of 1.77 ml. What is the
density of diamonds, and where would the diamonds fit into your density column?
Answer:
3.51 g/mL
Explanation:
Density can be found using the equation: density = mass / volume.
In this case, mass is given in grams (g) and volume is given in milliliters (mL).
You can find the density of the diamonds by plugging the given values into the formula and simplifying.
Density = mass (g) / volume (mL)
Density = 6.21 g / 1.77 mL
Density = 3.51 g/mL
physics 1
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The emf is induced in the wire will be 1.56 ×10 ⁻³ V. The induced emf is the product of the magnetic field,velocity and length of the wire.
What is induced emf?Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.
When the flux coupling with a conductor or coil changes, electromotive Force, or EMF, is said to be induced.
The given data in the problem is;
B is the magnitude of the magnetic field,= 5.0 ×10⁻⁵ T
V(velocity)=125 M/SEC
L(length)=25 cm=0.25 m
The maximum emf is found as;
E=VBLsin90°
E=125 × 5.0 × 10⁻⁵ ×0.25
E=1.56 ×10 ⁻³ V
Hence, the emf is induced in the wire will be 1.56 ×10 ⁻³ V
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What is the missing number in the nuclear reaction shown below? 237 Np 93 - 4 He+ 2 233 ? Pa
actually answer pls
Answer:
91 is the missing number because an alpha particle with a charge of 2 was emitted.
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a wavelength of 5.9 m and the velocity of sound in water is 15 m/s, what is the frequency of the signal?
The frequency of the signal is = 2.5 Hz
Calculation of frequencyThe wavelength of the sonar device = 5.9 m
The velocity of the sound = 15 m/s
The frequency = ?
But the formula for the velocity of sound wave = frequency × wavelength
Male frequency the subject of formula,
f = v/ wavelength
f = 15/5.9
f = 2.5Hz
Therefore, the frequency of the signal is = 2.5Hz
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A sound wave travels at 379 m/sec and has a wavelength of 8 meters. Calculate its frequency and period.
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Wavelength, Wavespeed and frequency depends on each other in the following way :
[tex]\qquad \sf \dashrightarrow \: frequency = \dfrac{wave \: \: velocity}{wavelength} [/tex]
[tex]\qquad \sf \dashrightarrow \: f = \dfrac{389}{8} [/tex]
[tex]\qquad \sf \dashrightarrow \: f \approx 48.62 \: \: hertz[/tex]
And we know the Reciprocal relationship between frequency and period ~
So, let's find it's period •
[tex] \sf{\qquad \sf \dashrightarrow \: t = \dfrac{8}{389}} [/tex]
[tex] \sf{\qquad \sf \dashrightarrow \: t \approx 0.02 sec } [/tex]
Two conducting spheres have net charges of +3.0 uC and -9.0 uC and attract each
other with a force of 0.20 mN. How far apart are the spheres?
The force between the two charges will be 16,000 N. It is the force exerted by one charge on another charge.
What is electric force?The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.
The given data in the problem is;
The magnitude of charge of sphere q₁ = +3.0 μC=-3.0×10⁻⁶ C
The magnitude of charge of sphere q₂ = -9.0 μC=9.0×10⁻⁶ C
k is the proportionality constant = 9 × 10⁹ Nm²
r is the separated distance to be found;
The electric force is F = 0.20 mN = 0.20 ×10⁻³ N
The electric force is found as;
[tex]\rm F = \frac{K q_1q_2}{r^2} \\\\ \rm 0.20 \times 10^{-3} = \frac{9 \times 10^9 \times 3.0 \times 10^{-6}\times 3.0 \times 10^{-6} }{r^2} \\\\\ R^ 2 =4.04\times 10^{-4} \\\\ R= 0.020 \ m[/tex]
Hence, the force between the two charges will be 16,000 N.
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Karyn is a zookeeper who takes care of baboons. Each day, Karyn writes down how the baboons eat, play, sleep, and wash. She reviews her notes every week to see if the animals are healthy and content. Which statement explains why Karyn's approach is an investigation instead of an experiment?
She is measuring variables.
She is testing a specific hypothesis.
She is not following the scientific method.
She is not attempting to change outcomes.
The statement which explains why Karyn's approach is an investigation instead because she is not attempting to change outcomes.
What is Investigation?This is defined as the systematic study of a subject topic and involves various forms of observation.
It however doesn't involve measuring variable as the outcomes aren't changed but only recorded.
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Four different constant forces are exerted on a 2. 0 kg object. The figure represents the magnitude and direction of each force. If the object is initially at rest, how long will it take the object to reach a speed of 2. 0 m/s?.
Based on the mass of the object, and its acceleration, the time taken to reach a speed of 2.0 m/s is 4 seconds.
How many seconds will the object take to reach the required speed?The time can be found as:
= Required speed / Acceletation
Accelaration is:
= Force / Mass
= (0.99iN + 0jN) / 2kg
= 0.5 ms⁻²
Time taken is:
= 2 / 0.5
= 4 seconds
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Since the force that axts on the object is the resultant force, the time taken is 0.8 s.
What is resolution of forces?Since force is a vector, it can be resolved into its components. From the complete question, the componenets of the force are;
Vertical component;
5N sin 373N sin 9017 N-20NTotal = 3 + 3 + 17 - 20 = 3 NHorizontal component;
5N cos 373N cos 90Total = 3.99 + 0 = 4Resultant force = √(3)^2 + (4)^2 = 5N
Now;
F = ma
a = F/m
a = 5N/2. 0 kg
a = 2.5 m/s^2
Given that;
v = u + at
since u = 0 (object started from rest)
2 = 2.5 * t
t = 2/2.5 = 0.8 s
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Write out the solution to the following problem: Find the force of an object with a mass of 5 kg and an acceleration of 3 m/s2.
Answer:
15 N
Explanation:
Force=mass x acceleration
15= 5 x 3
Answer: 15N
Explanation:
If the object has a mass of 5kg and accelerates 5m/s^2, force that is applied to move the object is simply the product of mass and acceleration.
Between 1992 and today, astronomers using large telescopes have discovered many icy pieces that orbit in the same region as the orbit of Pluto. These are believed to be members of the
Icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.
What is the Kuiper belt?The Kuiper belt is a shape-disc formation in the solar system observed from Neptune and more away from our sun.
The Kuiper belt consists of different celestial bodies including among others icy pieces, planets, and comets.
In conclusion, icy pieces that orbit in the same region as the orbit of Pluto are believed to be members of the Kuiper belt.
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Of the following approximate conversions of celsius into fahrenheit, which is most accurate? a. 24°c almost-equals 75.9°f b. 2°c almost-equals 35.8°f c. 34°c almost-equals 92.7°f d. 13°c almost-equals 55.0°f
The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0
Hence, option D) is the most accurate.
What is Scale of Temperature?Scale of temperature is simply a method used in calibrating the physical quantity of temperature in metrology.
Conversion of Celsius into Fahrenheit, Formula is expressed as;
Degree = (0 × 9/5) + 32 = Fahrenheit
First we check each option;
A) 24°c almost-equals 75.9°f
24°C = (24 × 9/5) + 32 = 75.2°F
B) 2°C almost-equals 35.8°f
2°C = (2 × 9/5) + 32 = 35.6°F
C) 34°C almost-equals 92.7°f
34°C = (34 × 9/5) + 32 = 93.2°F
D) 13°c almost-equals 55.0°f
13°C = (13 × 9/5) + 32 = 55.4°F
The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0
Hence, option D) is the most accurate.
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what will be the key difference in the energy of the particles in the iron 250 K and 500 K ?
Answer: the guy is right
Explanation:
:)
The distance between Carol's house and her uncle's house is 24 km. What is her speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle.
Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.
How to calculate average speed?The average speed of a moving body can be calculated by dividing the distance moved by the time taken.
According to this question, the distance between Carol's house and her uncle's house is 24 km. The speed it will take her to get to her uncle's house in 40 minutes by motorcycle is as follows:
Average speed = 24km ÷ 40/60 hour
Average speed = 36km/hr
Therefore, Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.
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If the andromeda galaxy collided with the milky way, what would most likely happen to earth?.
Answer:
the surface of the earth would've already turned into a very hot liquid water to even exist and there would be no existence of humans on earth
How do the amplitudes of a 120 decibel sound and a 100-decibel sound compare?
150N
V
nail
0.50 m
wood
pivot
The man applies a force of 150 N at a distance of 0.50m from the pivot.
Calculate the moment of this force about the pivot. Include a unit.
physics 4
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The value of the peak power will be 50 W. The peak power is found as two times of the average power. Option C is correct.
What is average power?Average power is a ratio of total work done by the body to the total time. Its unit is the watt. It is also defined as the rate of total work done by the body.
The given data in the problem is;
Average power = 25 W
Peak power = ?
The peak power is found as;
Peak power = 2 × average power
Peak power=2×25
Peak power = 50 W
Hence, the value of the peak power will be 50 W.
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