How many grams of silver sulfide are formed when 0.280 g of hydrogen sulfide reacts with excess silver and oxygen?
Answer:
[tex]2.03~g~Ag_2S[/tex]
Explanation:
For this question we have to start with the reaction:
[tex]Ag~+~H_2S~+~O_2~->~Ag_2S~+~H_2O[/tex]
Now, we can balance the reaction, so:
[tex]4Ag~+~2H_2S~+~O_2~->~2Ag_2S~+~2H_2O[/tex]
With this in mind, we have to start with the amount of [tex]H_2S[/tex]. The first step is to convert from grams to moles. For this, we need to find the molar mass of [tex]H_2S[/tex]. If we check the periodic table we will find the atomic masses for Ag and H; H: 1 g/mol and A: 32 g/mol, so:
(1*2)+ (32*1) = 34 g/mol.
Now we can calculate the moles of [tex]H_2S[/tex]:
[tex]0.280~g~H_2S\frac{34~g~H_2S}{1~mol~H_2S}=0.0082~mol~H_2S[/tex]
With the moles of [tex]H_2S[/tex] we can calculate the moles of [tex]Ag_2S[/tex] if we check the molar ratio in the balanced equation, [tex]2~mol~H_2S=2~mol_Ag_2S[/tex], so:
[tex]0.0082~mol~H_2S\frac{2~mol_Ag_2S}{2~mol~H_2S}=0.0082~mol~H_2S[/tex]
With the molar mass of [tex]Ag_2S[/tex] we can convert from moles to grams (Ag: 107.86 g/mol, S: 32 g/mol), so:
(107.86*1)+(32*2)=247.80 g/mol
[tex]0.0082~mol~H_2S\frac{247.8~g~Ag_2S}{1~mol~H_2S}=2.03~g~Ag_2S[/tex]
I hope it helps!
7. Which molecular solid would have the lowest boiling point?
a. One that has hydrogen bonding
b. One made of molar molecules
c. One with dipole-dipole attractions
d. One with induced dipole attractions
Answer:
The molecular solids would have the lowest boiling point because of WEAK INTERMOLECULAR FORCES.
Explanation:
Answer: One with induced dipole attractions
1.09 grams of H2 to moles
b) How many kilograms of carbon dioxide are formed when 24.42 g of iron is
produced?
Answer:
0.0289 kg of CO2 will be formed
Explanation:
Step 1: Data given
Mass of iron produced = 24.42 grams
Atomic mass iron = 55.845 g/mol
Molar mass CO2 = 44.01 g/mol
Step 2: The balanced equation
Fe2O3 + 3CO → 2Fe + 3CO2
Step 3: Calculate moles iron
Moles iron = mass iron / molar mass iron
Moles iron = 24.42 grams / 55.845 g/mol
Moles iron = 0.437 moles
Step 4: Calculate moles CO2
For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2
For 0.437 moles Fe we'll have 3/2 * 0.437 = 0.6555 moles CO2
Step 5: Calculate mass CO2
Mass CO2 = moles CO2 * molar mass CO2
Mass CO2 = 0.6555 moles * 44.01 g/mol
Mass CO2 = 28.85 grams = 0.0289 kg
0.0289 kg of CO2 will be formed
Explain why airborne and water-borne chemicals are both local and global issues.
Draw a Lewis structure for each covalent molecule. a. CH3F b. N2H4
Answer:
See attached picture.
Explanation:
Hello,
In this case, given the compounds we notice:
a. Since carbon has four valence electrons (group IVA), it has three hydrogen atoms around it as well as a fluorine atom which has seven valence electrons (group VIIA). Moreover, we notice both carbon and fluorine attaining the octet.
b. In this case, two nitrogen atoms which have five valence electrons each (groupVA) are bonded via a single bond and two hydrogen atoms are bonded to each nitrogen atom in order to attain the octet for nitrogen only.
Thus, structures are given on the attached picture.
Regards.
Lewis structure for each covalent molecule CH₃F and N₂H₄ are attached to the image below.
a. CH₃F:
Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Fluorine (F) has 7 valence electrons.
The total number of valence electrons in CH3F can be calculated as follows:
1 carbon atom (C) × 4 valence electrons = 4 valence electrons
3 hydrogen atoms (H) × 1 valence electron = 3 valence electrons
1 fluorine atom (F) × 7 valence electrons = 7 valence electrons
Total valence electrons = 4 + 3 + 7 = 14
b. N₂H₄:
Nitrogen (N) has 5 valence electrons, and Hydrogen (H) has 1 valence electron.
The total number of valence electrons in N2H4 can be calculated as follows:
2 nitrogen atoms (N) × 5 valence electrons = 10 valence electrons
4 hydrogen atoms (H) × 1 valence electron = 4 valence electrons
Total valence electrons = 10 + 4 = 14
To learn more about the Lewis structure, follow the link:
https://brainly.com/question/29603042
#SPJ6
1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.
a. with H_2 O
b. with H_2 SO_4
c. with 1 equiv of KOH
d. with Csl
e. with NaCN
f. with HCl
g. with (CH_3)_2 S
h. with 1 equiv of NH_3
j. with CI_2
k. with KF
Answer:
Explanation:
If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane a primary alkyl-halide.
Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used otherwise it will result to a reactive mechanism if a weak electrophile is used.
However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.
The attached diagrams portraying this notions is shown in the attached file below.
Based on its location on the periodic table, how many electrons does nitrogen have in its outer energy level?
Answer:
its 5 got it right
How many mL of a 0.4 M nitric acid solution are required to neutralize 200 mL of a 0.16 M potassium hydroxide
Answer:
80 ml.
Explanation:
The balanced equation is:
KOH + HNO3 ----> KNO3 + H2O
So 1 mole of KOH reacts with 1 mole of HNO3
200ml of 0.16M KOH contains 0.16 * 200/1000
= 0.16 * 0.2
= 0.032 M KOH.
So we need the volume (V) of 0.4 M HNO3 which contains 0.032 moles.
0.4 * V = 0.032
V = 0.032 / 0.4
V = 0.08 liters
= 80 mls.
In an oven, 7000 kg of limestone are heated to over 900ºC to give lime and carbon dioxide. Assuming all calcium carbonate reacts. How much lime do you get? What volume of CO2 is emitted into the atmosphere? Atomic weights: Ca: 40; C: 12; O: 16.
Answer:
3920kg of lime(CaO) 1568m^3 of CO2
Explanation:
I attached the explanation!
also for calculating the volume I assumed Standard Temperature and Pressure(STP).
Why LDL called "bad" cholesterol?
Answer:
Its called bad cholesterol because a high LDL level leads to buildup of cholesterol in your arteries.
Explanation:
HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
If the value of Kc for this process is 5.2 x 10-5, there is no H3O+ or BrO- initially present, and the initial [HBrO] = 0.749 M, what will be the concentration of BrO- at equilibrium?
HINT: you should not use the quadratic formula for this problem.
7.67 x 10-3 M
9.01 x 10-3 M
5.17 x 10-3 M
4.29 x 10-3 M
6.24 x 10-3 M
Answer:
6.24 x 10-3 M
Explanation:
Hello,
In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:
[tex]Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}[/tex]
Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change [tex]x[/tex], we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:
[tex]5.2x10^{-5}=\frac{x*x}{0.749-x}[/tex]
Thus, we obtain a quadratic equation whose solution is:
[tex]x_1=-0.00627M\\x_2=0.00624M[/tex]
Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.
Best regards.
Answer:
6.24×10¯³ M
Explanation:
Step 1:
The equation for the reaction is given below:
HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
Step 2:
The following data were obtained from the question:
Equilibrium constant, Kc = 5.2x10^-5
Concentration of HBrO, [HBrO] = 0.749 M
Concentration of BrO-, [BrO-] =?
Step 3:
Determination of the concentration of
BrO-.
We can obtain the concentration of BrO- as follow:
Initial concentration:
[HBrO] = 0.749 M
[H3O+] = 0
[BrO-] = 0
During reaction:
[HBrO] = - y
[H3O+] = +y
[BrO-] = +y
After reaction:
[HBrO] = 0.749 - y
[H3O+] = y
[BrO-] = y
Applying the equation constant equation:
Kc = [H3O+] [BrO-] / [HBrO]
5.2x10^-5 = y × y / 0.749
5.2x10^-5 = y² / 0.749
Cross multiply
y² = 5.2x10^-5 x 0.749
Take the square root of both side
y = √(5.2x10^-5 x 0.749)
y = 6.24×10¯³ M
[BrO-] = y = 6.24×10¯³ M
Therefore, the the concentration of BrO- at equilibrium is 6.24×10¯³ M
Which of the following is a characteristic of the lanthanides?
O A. They are silvery metals that conduct electricity.
B. There are no known uses for the metals.
C. They are all radioactive.
D. They are used in making fireworks
Answer:
A
Explanation:
Lanthanides share the following common properties: Silvery-white metals that tarnish when exposed to air, forming their oxides. Relatively soft metals. Hardness increases somewhat with higher atomic number.
Answer:
APEX
Explanation:
A
Identify which subatomic particles match each of these descriptions. One of the descriptions describes two particles. Make sure to include both particles it describes.
Description Particle(s)
have a relative charge of +1
have a relative charge of −1
have no charge
located in the nucleus of an atom
have a much lower mass than the other two types of particles
Explanation:
First off, it's important to know that the three subatomic particles we have are the proton, neutron and electron.
have a relative charge of +1 : This is the proton. It is the postive subatomic particle present in an atom.
have a relative charge of -1 : This is the electron. It is the negative subatomic particle present in an atom.
have no charge : This is the neutron. It is the neutral subatomic particle present in an atom.
located in the nucleus of an atom : Twoo subatomic particles are located in the nucleus, the neutron and proton.
have a much lower mass than the other two types of particles: This is the electron. The proton and neutron are almost similar in mass. The electron is abut 1 / 1840 times the mass of the proton.
A balloon is cooled by removing 0.784 kJ of heat. It shrinks on cooling, and the atmosphere does 655 J of work on the balloon. Calculate the change in internal energy, ∆E, of the system.
Answer:
The correct answer is -0.129 kJ
Explanation:
In the given case, the cooling of the balloon is done by withdrawing 0.784 J of heat, and the work done by the atmosphere on the balloon is 655 J. First, there is a need to transform kJ into J, 1 kJ = 1000 J. So, 0.784 kJ would be 784 J.
The ΔE or the change in the internal energy can be calculated by using the formula, ΔE = q + w ----- (1).
In the given case, q refers to the heat moved out of the system, that is, the value of q would be less than 0 or will be a negative quantity. Therefore, the heat moved out of the system will be -784 J. On the other hand, as the work or w is done on the system, therefore, the value of w would be more than 0 or will be a positive quantity. Thus, the value of w will be +655 J.
Now putting the values in the equation (1) we get,
ΔE = -784 J + 655 J
ΔE = -129 J or -0.129 kJ
As the change in internal energy comes out to be a negative value, therefore, the process is considered exothermic.
Explain why the benzene molecule usually reacts with electrophiles
Answer:
Explanation:Because of the delocalised electrons exposed above and below the plane of the rest of the molecule, benzene is obviously going to be highly attractive to electrophiles - species which seek after electron rich areas in other molecules.
Answer:
Benzene has a pi electron system that is electron rich.
Electrophiles are molecules that are attracted to electron rich molecules as they are electron deficient in order to form a more stable complex.
Hence, as benzene is electron rich, electrophiles will be attracted to it.
As a quality control check, a sample of acetone is taken from a process to determine the concentration of suspended particulate matter. An 850 mL sample was placed in a beaker and evaporated. The remaining suspended solids were determined to have a mass of 0.001 g. The specific gravity of acetone is 0.79 g/cm.
(a) Determine the concentration of the sample as mg/L.
(b) Determine the concentration of the sample as ppm (problem from EPA Air Pollution Training Institute)
Answer:
The volume of the sample given is 850 ml, the density given is 0.79 gram per cm. Now the weight of the sample will be,
Weight = volume × density = 850 × 0.79
= 671.5 grams
Weight of the suspended solids given is 0.001 gram
The concentration of the sample can be determined by using the formula,
Concentration = wt. of sample/volume
= [671.5 - 0.001) 10³ mg / 0.85 L
= 789998.82 mg/L or 789998.82 ppm
Now the concentration of suspended solids is.
Css = 0.001 × 10³ mg / 0.85 L = 1.1764 mg per L or 1.1764 ppm
What is the volume in a 2. 00M solution containing 8.00 moles of solute?
Answer:
4000cm³
Explanation:
2.0moles-1000cm³
8.0moles-?
(8.0×1000)÷2
=4000cm³
A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
significant figures when answering this question.
Answer:
1.3223 acres
Explanation:
a football field's area is 360 feet (120 yards) x 160 feet (53.333 yards) = 57,600 sq. feet
if the area of an acre is 43,560 sq. feet, then a football field in acres = 57,600 sq. feet / 43,560 sq. feet = 1.3223 acres
we can verify our answer by doing the same calculation in sq. yards:
football field = 120 yards x 53.33 yards = 6,400 sq. yards
an acre is 4,840 sq. yards
football field in acres = 6,400 sq. yards / 4,840 sq. yards = 1.3223 acres
The area of the field is 1.3223 acres
From the question given above, the following data were obtained:
Dimension = 120 yard × 53.333 yard
Area =?The area of the field can be obtained as follow:
Area = Dimension
Area = 120 yard × 53.333 yard
Area = 6399.96 yard²Finally, we shall convert 6399.96 yard² to acre. This can be obtained as follow:
4840 yard² = 1 acre
Therefore,
6399.96 yard² = 6399.96 / 4840
6399.96 yard² = 1.3223 acresThus, the area of the field is 1.3223 acres
Learn more: https://brainly.com/question/1406215
What is the Electronegativity difference of F and CI
The element fluorine is more electronegative than the element chlorine. Fluorine has an electronegativity value of 4.0 and Carbon has an electronegativity value of 2.5.
What is electronegativity ?The term electronegativity is defined as a chemical property that describes the capacity of an atom or a functional group to attract electrons toward itself.
Electronegativity is refer to the ability of an atom to attract shared electrons in a covalent bond. The grater the value of the electronegativity, the more strongly that element attracts the shared electrons.
In fluorine electronegativity value is more than carbon. Therefore, it strongly attracts the shared electrons.
Thus, The element fluorine is more electronegative than the element chlorine.
To learn more about an electronegativity, follow the link;
https://brainly.com/question/17762711
#SPJ2
A certain atom has 22 protons and 19 electrons. This atom loses an electron. The net charge on the atom is now ___.If this same
atom with 22 protons and 19 electrons were to gain 3 electrons, the net charge on the atom would be ____
Answer:
I think first one has net charge 4+
second one has earlier 3+ charge after gaining net charge becomes zero
I think this is correct
Explanation:
if wrong means pls correct me bro
An atom has 22 protons and 19 electrons. The net charge on the atom is now elementary, 1e+. If the same atom with 22 electrons and 19 electrons were to gain 3 electrons, the net charge on the atom would be, negative, -3.
What are electrons?Electrons are the positively charged particles that revolve around the negatively charged nucleus. Electrons revolve around the nucleus, and protons and neutrons are also present.
When the electrons gain electron they acquire negative charge and when they donate electrons it acquires positive charge.
It gains 3 electrons that why -3 charge.
Thus, the correct elementary charge, negative, -3.
Learn more about electrons
https://brainly.com/question/1255220
#SPJ2
A gas sample has a pressure of 2.65 atm when the temperature is -18 ∘C. What is the final pressure, in atmospheres, when the temperature is 39 ∘C, with no change in the volume or amount of gas?
Answer:
P₂ = 3.24atm
Explanation:
(a) Give systematic names or the chemical formulas for the following. Remember, names must
be spelled correctly!
1.) [Ni(CO)2C2O4]
2.) K3[Fe(NCO)3(OCN)3]
3.) diammineaquahydroxoplatinum(II) ion
4.) Al[Co(CO3)2(CN)2]
5.) ethylenediaminedinitritozinc(II)
Answer:
[Ni(CO)2C2O4]- Dicarbonyloxalatonickel(0)
K3[Fe(NCO)3(OCN)3-potassiumtricyanatotriisocyanatoferrate II
diammineaquahydroxoplatinum(II) ion- [Pt(NH3)2(H2O)(OH)]^+
Al[Co(CO3)2(CN)2- Aluminiumdicarbonatodicyanocobalt III
ethylenediaminedinitritozinc(II)- Zn(en)(NO2)2
Explanation:
The international Union of Pure and applied chemistry published a set rules for the nomenclature of inorganic compounds in 1985. This set of rules have been consistently revised ever since.
The rules stipulate the order for naming positive ions, negative ions and neutral ligands and the allowed order of preference for naming. It also stipulates the proper endings for ligands which are positive ions, negative ions or neutral ligands as the case may be.
The compounds named above were named in accordance with the revised IUPAC nomenclature for inorganic compounds.
uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 1.83 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 22.08 mL. What volume of base was required for the titration?
Answer:
20.25 mL.
Explanation:
The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.
i.e Final volume - initial volume
= (22.08 - 1.83)mL
= 20.25 mL.
(Repeat and average volume results for accuracy.)
The total enthalpy of the products in a reaction is 0 kJ, and the total enthalpy of the reactants is 100 kJ. What is the ΔH for the reaction? Choose the correct answer.
a.–393.5 kJ
b.–100 kJ
c.0 kJ
d.+100 kJ
Answer: b. -100 kJ
Explanation:
Heat of reaction is the energy released or absorbed during the course of the reaction. It is represented by the symbol [tex]\Delta H[/tex].
[tex]\Delta H=H_{products}-H_{reactants}[/tex]
[tex]\Delta H[/tex] = enthalpy of reaction = ?
[tex]H_{products}[/tex] = enthalpy of products = 0 kJ
[tex]H_{reactants}[/tex] = enthalpy of reactants = 100 kJ
[tex]\Delta H=0kJ-100kJ[/tex]
[tex]\Delta H=-100kJ[/tex]
Thus the ΔH for the reaction is -100kJ
Can you please answer Question 9 please
A certain compound is made up of one carbon (C) atom, two fluorine (F) atoms, and one oxygen (O) atom. What is the chemical formula of this compound?
Answer:
CF₂O
Explanation:
To determine how the molecule will be made think about the valence number of each element in molecule:
F= -1 , O= -2 , C= +4
because the C is positive atom it will be the central atom with a double bond to the O and a single bond to each F.
this way all atoms completed the octet and stability
True or False: reactions in which the oxidation state of an element decreases are reduction processes
Answer:
False; An oxidation-reduction is any chemical process that involves any chemical process in which elements undergo changes in oxidation number. hope that helps love!
moles of Fe in 3.13×1022 atoms of Fe
Answer: 0.05 moles
Explanation:
To convert from atoms to moles, you will need Avogadro's number.
Avogadro's number: 6.022×10²³atoms/moles
(3.13×10²²atoms)×(moles/6.022×10²³ atoms)=0.05 moles
The atoms would cancel out and we will be left with our moles.
how many significant figures are in 11.005 g
Answer:
Number of Significant Figures: 5
The Significant Figures are 1 1 0 0 5
Explanation:
