25 POINTS FIRST CORRECT GET BRAINLIEST!!!!!!!!!!!!!!!!1

Answer:

Momentum is vector quantity and it is defined as the product of mass of the object and velocity of the object.

As it is a vector quantity it has both direction and magnitude, and momentum is written as

p = m × v

p = momentum

m = mass of the object

v = velocity

Two kinds of momentum are there and they are:

Answer:no

Explanation: lol

Answer:

1. Radiation

2. Conduction

3. Conduction

4. Convection

5. Convection

6. Convection

7. Radiation

Answer:120

Vav = S / t = (120 + 45) m / (4 + 60) sec = 2.6 m/s

Answer:

8 M/S

Explanation:

This is because the points match from 4 seconds (X) and it matches up to 8 (Y), therefore it went up 8 M/S in 4 seconds.

Answer:

Four times greater

Explanation:

Drag is comprised of parasite drag and induced drag. The Parasite drag is the drag that acts on an object when the said object happens to be moving through a fluid. Parasite drag is also a combination of two forms of drag. These two forms of drag are called form drag and skin friction drag.

As the speed of an airplane increases, the parasite drag also increases while the induced drag of the airplane decreases. The parasite drag of an airplane in theory becomes four times greater, when it's airspeed is doubled.

Answer: Root mean square speed, Vrms=5,694m/s

Explanation:

Root mean square speed  is defined as the  the square root of the average of the square of the velocity and given as [tex]\sqrt 3RT/M[/tex]

Where R =8.3145J/mol.k

M molar mass of the molecule in kg/mol

Helium= He=4g/mol =  0.004kg/mol

T= Temperature = 5200k

Vrms=  [tex]\sqrt 3RT/M[/tex]

=[tex]\sqrt 3 x 8.3145 x 5200/0.004[/tex]

=[tex]\sqrt32426550[/tex]

Vrms =5,694m/s

Answer:

Monachry

Explanation:

Hope this helped!!!

Answer:

I think it is D

Explanation:

might be wrong

Answer:

Tension ( B )

Explanation:

When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is in TENSION , this is because the force of flow in a stationary object will be in a compressive nature that will in turn cause the force on the coupling to be in a form of a Tension ( i.e. Tensile )

Answer:

h = 52.24 m

Explanation:

Given that,

A penny is dropped from the top of the hotel in New York. It hits a tourist in the head at 32 m/s.

Let it falls at a height of h.

We can find the value of h using the conservation of energy such that,

[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(32)^2}{2\times 9.8}\\\\h=52.24\ m[/tex]

So, it will fall at a distance of 52.24 m.

Answer:

h = 40 m

Explanation:

       [tex]\Delta K = \frac{1}{2} * m* v_{b} ^{2}[/tex]  (2)

       where vb = speed at the bottom = 28 m/s

       [tex]\Delta U = U_{f} - U_{i} = 0- m*g*h = -m*g*h[/tex] (3)

       [tex]\frac{1}{2} * m* v^{2} = m*g*h[/tex]

       [tex]h = \frac{v_{b} ^{2} }{2*g} = \frac{(28m/s)^{2}}{2*9.8m/s2} = 40 m[/tex]

Answer:

15 seconds

Explanation:

We can use this formula to solve this problem:

Velocity = Initial Velocity + Acceleration * Time

We know that initial velocity is 0, the velocity is 147, and acceleration is 9.8(because of earth's gravitational pull), so we can plug those numbers in and solve for time:

147 = 0 + 9.8*t

t = 15

Therefore, it will take 15 seconds for an object that falls from rest to reach 147 m/s.

Answer:

no

Explanation:

Answer: The whale shark is the largest type of fish in the world. Its mass can be as large as 2.00 x 10^4kg, which is the equivalent mass of three average adult elephants. Suppose a crane lifts a net with a 2.00 x 10^4kg whale shark off the ground. The net is steadily accelerated from rest over an interval of 2.5s until the net reaches a speed of 1.0 m/s.

Explanation:

The net force on the boat is the vector

F = (-120 N) i + (-140 N) j

where we take West and South to be the negative directions going left-and-right and up-and-down, respectively.

The magnitude of the net force is

F = √((-120 N)² + (-140 N)²) = 20 √(85) N ≈ 180 N

and its direction is

tan(θ) = (-140 N) / (-120 N)   →   θ ≈ -130°

relative to due East, or approximately 50° South of West.

Answer:

Explanation:

we know that momentum is given as

P=mv

given data

P1=?

mass m1=100kg

velocity v1=7m/s

P2=?

mass m2=120kg

velocity v2=5m/s

the total momentum =P1+P2

total=m1v1+m2v2

total= 100*7+120*5

total=700+600

total= 1300kgm/s

total kinetic energy

KE total= 1/2m1v1^2+1/2m2v2^2

KE total= 1/2*100*(7)^2+1/2*120*(5)^2

KE total= 1/2*100*49+1/2*120*25

KE total= 1/2*4900+1/2*3000

KE total=2450+1500

KEtotal=3950 J

Answer:

The person on the bus will see the balloon hit the bus at a velocity = V - U

Explanation:

There is relative motion between the water balloon and the person sitting in the bus.

Relative motion is the motion of a body with respect to another body (eg. an observer) from the point of reference of the second body (observer).

The person on the bus has a velocity which is the same as that of the moving bus = U

The velocity of the thrown water balloon (greater than U) = V

The relative motion between the person and the water balloon is the difference between their velocities (since they are both moving in the same direction) = V - U

Therefore, the person on the bus will see the balloon hit the bus at a velocity = V - U

Answer:

The velocity of the projectile just prior to the collision is 154.934 meters per second.

Explanation:

Let consider the projectile-pendulum system as our system of study, from statement we know that projectile gives kinetic energy to the pendulum and turns into gravitational potential energy. By Principle of Energy Conservation we construct the following expression:

[tex]U_{g,1}+K_{1} = U_{g,2}+K_{2}[/tex] (Eq. 1)

Where:

[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Initial and final gravitational potential energies, measured in joules.

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies, measured in joules.

By applying definitions of gravitational potential and kinetic energies, we expand and simplify the equation above:

[tex](m+M)\cdot g \cdot (y_{2}-y_{1}) = \frac{1}{2}\cdot (m+M)\cdot (v_{1}^{2}-v_{2}^{2})[/tex]

[tex]g\cdot (y_{2}-y_{1})=\frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2})[/tex]

And we clear the initial velocity of the pendulum-projectile system:

[tex]v_{1}=\sqrt{v_{2}^{2}+2\cdot g\cdot (y_{2}-y_{1})}[/tex] (Eq. 2)

Where:

[tex]m[/tex] - Mass of the projectile, measured in kilograms.

[tex]M[/tex] - Mass of the ballistic pendulum, measured in kilograms.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the pendulum-projectile system, measured in meters per second.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]y_{1}[/tex], [tex]y_{2}[/tex] - Initial and vertical position of the pendulum-projectile system, measured in meters.

Under the consideration of inellastic collision, we find the velocity of the projectile prior to the collision by Principle of Linear Momentum Conservation:

[tex]m\cdot v_{o, P} + M\cdot v_{o,B} = (m+M)\cdot v_{1}[/tex]

[tex]v_{o,P} = \frac{(m+M)\cdot v_{1}-M\cdot v_{o,B}}{m}[/tex] (Eq. 2)

Where:

[tex]v_{o, P}[/tex] - Velocity of the project prior to the collision, measured in meters per second.

[tex]v_{o,B}[/tex] - Velocity of the ballistic pendulum prior to the collision, measured in meters per second.

If we know that [tex]v_{2} = 0\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]y_{2}-y_{1} = 0.12\,m[/tex], [tex]m = 0.025\,kg[/tex], [tex]M = 2.5\,kg[/tex] and [tex]v_{o,B} = 0\,\frac{m}{s}[/tex], then the velocity just prior to the collision is:

By (Eq. 1):

[tex]v_{1} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.12\,m)}[/tex]

[tex]v_{1} \approx 1.534\,\frac{m}{s}[/tex]

By (Eq. 2):

[tex]v_{o,P} = \frac{(0.025\,kg+2.5\,kg)\cdot \left(1.534\,\frac{m}{s} \right)-(2.5\,kg)\cdot \left(0\,\frac{m}{s} \right)}{0.025\,kg}[/tex]

[tex]v_{o,P} = 154.934\,\frac{m}{s}[/tex]

The velocity of the projectile just prior to the collision is 154.934 meters per second.

Answer:

20N to the North

Explanation:

the west and east forces cancel out, that leaves us with 50 to the north, and 30 to the south, the difference would be 20 N to the North

Answer:

Explanation:

Volume of the cone = 1/3πr²h

r is the radius

h is the height

2500 = 1/3πr²h

Criss multiply

r²h = 2500 × 3π

Rewrite the expression

r²h = 50² × 3π

Compare values

r² = 50²

r = √50²

r = 50yd

The radius is 50yards

Also;

h = 3π yards

h = 3(3.14)

h = 9.42yards

Hence the pile is 9.42yards high

Circumference of the pile = 2πr

Given r = 50

Substitute

Circumference = 2π(50)

Circumference = 100π

Circumference = 100(3.14)

Circumference = 314yards

Hence the circumference of the pile at the ground level is 314yards

Answer:

1975 ohm

Explanation:

The maximum current that can pass through the galvanometer is 50.0µA

p.d across the galvanometer at a full scale deflection is given by

V = IR

V = (50.0×10^-6)*25

V1 = 1/800 or 0.00125volts

Since the p.d across the multiplier and galvanometer at full scale deflection is 0.100volts,the p.d across the multiplier alone must be given by

V2 = 0.100-0.00125

= 0.09875volts

Current passing through the multiplier is (50.0×10^-6)A

Hence if R is the resistance of the multiplier, we have that

V2 = (50.0×10^-6)×R

0.09875volts = (50.0×10^-6)×R

Divide both sides by 0.09875volts

R = 0.09875/(50.0×10^-6)

R =( 0.09875) ÷ 1/20000

R = 0.09875×20000

R = 1975 ohms

Answer:

Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. ... Heat is the transfer of thermal energy between objects that have different temperatures.

Answer:

Explanation:

Given

final speed v = 30.0m/s

initial velocity u = 0m/s

Time taken t = 1.00s

Required

constant acceleration of the police car a

Substitute the given parameters into this equation of motion

v = u + at

30 = 0 +1a

30 = a

a = 30.0m/s²

Hence the magnitude of the constant acceleration of the police car is 30.0m/s²

Answer:

[tex]\boxed {\tt Neil's \ journey}[/tex]

Explanation:

We want to find who travelled faster, so we must find the time for each person's journey. Time can be found by dividing distance by speed.

Neil

[tex]t=\frac{d}{s}[/tex]

Neil travelled 36 kilometers at a speed of 8 kilometers per hour.

[tex]d= 36 \ km \\s= 8 \ km/hr[/tex]

[tex]d=\frac{36 \ km}{8 \ km/hr}[/tex]

Divide (the kilometers or "km" will cancel each other out).

[tex]d=4.5 \ hr[/tex]

Grant

[tex]t=\frac{d}{s}[/tex]

Grant travelled 48 kilometers at a speed of 10 kilometers per hour.

[tex]d= 48 \ km \\s= 10 \ km/hr[/tex]

[tex]d=\frac{48 \ km} { 10 \ km/hr}[/tex]

Divide (the kilometers or "km" will cancel each other out).  

[tex]d=4.8 \ hr[/tex]

Neil's journey took 4.5 hours and Grant's took 4.8 hours. We want to find the journey that was quicker and 4.5 is less than 4.8. So Neil's journey was quicker.

Answer:

3.7

Explanation: