The shop owner makes total 120 sandwiches with brown bread today.
What is linear equation in one variable?The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
According to the given question.
A sandwich shop owner makes 1 sandwich with brown bread for every 4 sandwiches he makes with white bread.
Let the total number of white bread sandwiches be 4x and white bread sandwiches be 1x.
Since, the shop owner have to make 600 sandwiches.
So, for the given scenario we have a linear equation in one variable.
[tex]\implies 600 = 4x+1x\\\implies 600 = 5x \\\implies x = \frac{600}{5} \\\implies x = 120[/tex]
Hence, the shop owner makes total 120 sandwiches with brown bread today.
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True or False: A line perpendicular to x=7 has a slope of 0
Answer:
True, I believe
Step-by-step explanation:
Answer:
The answer is yes because its horizontal
Find the area of the shaded regions
Sector area
Area of whole = 51.313
Area of unshaded = 9.424
Area of shaded = 41.8886
Answer:
40π/3Step-by-step explanation:
Find the area of the bigger circle:
A = πr² = π(4 + 3)² = 49πFind the area of 120° sector AOC:
A = 120°/360°*A = 1/3*49π = 49π/3Find the area of smaller circle:
A = π(3²) = 9πFind the area of 120° sector of DOB:
A = 120°/360°*9π = 3πNow find the shaded area, the difference of areas of sectors:
49π/3 - 3π = 40π/3What is the best point estimate for the population's standard deviation if the sample standard deviation is 37.3
Answer:
The best point estimate for the population's standard deviation is 37.3.
Step-by-step explanation:
Best point estimate:
The best point estimate for the population mean is the sample mean.
The best point estimate for the population standard deviation is the sample standard deviation.
In this question:
Sample standard deviation of 37.3, and thus, the best point estimate for the population's standard deviation is 37.3.
make m the subject of this eequation please help!! asap
Answer: [tex]M = \pm\sqrt{\frac{3K}{4(5+7NK)}}\\\\[/tex]
======================================
Work Shown:
[tex]\frac{5}{K} = \frac{3}{4M^2} - 7N\\\\\frac{5}{K}+7N = \frac{3}{4M^2}\\\\\frac{5}{K}+7N*\frac{K}{K} = \frac{3}{4M^2}\\\\\frac{5}{K}+\frac{7NK}{K} = \frac{3}{4M^2}\\\\\frac{5+7NK}{K} = \frac{3}{4M^2}\\\\4M^2*(5+7NK) = K*3\\\\M^2 = \frac{3K}{4(5+7NK)}\\\\M = \pm\sqrt{\frac{3K}{4(5+7NK)}}\\\\[/tex]
Other forms are possible, but those forms would be equivalent to what is shown above.
Grams in this equation
30 .650 pounds of gramsin vegetables
whats the value of 5 in the product of 6,541 x 100
Answer:
50,000
Step-by-step explanation:
The product would be 654,100. Replace the other numbers to find the value of 5. The value of 5 is 050,000 or 50,000.
I hope this helps!
Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. A paper gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the postweaning period (P).
Subject
1 2 3 4 5 6 7 8 9 10
L 1928 2549 2825 1924 1628 2175 2114 2621 1843 2541
P 2126 2885 2895 1942 1750 2184 2164 2626 2006 2627
Required:
a. Does data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. [Note: The appropriate normal probability plot shows some curvature but not enough to cast substantial doubt on a normality assumption.]
b. Calculate a lower confidence bound using a 95% confidence level for the true average difference between TBBMC during postweaning and lactation.
Answer:
- 179.981
Step-by-step explanation:
The hypothesis :
H0 : μL - μP ≥ 25
H0 : μL - μP < 25
The sample mean difference ;Xd
d = L - P
Xd = Σd/n
d = -198,-336,-70,-18,-122,-9,-50,-5,-163,-86
Xd = - 1057 / 10
Xd = - 105.7
Using calculator ;
Standard deviation of difference, Sd = 103.845
The test statistic :
T = Xd ÷ (Sd/√n)
T = -105.7 ÷ (103.845/√10)
T = - 3.219
Decision region :
Reject H0 ; If Pvalue < α
The Pvalue : df = n - 1 ; 10 - 1 = 9
Pvalue(-3.219, 9) ; two-tailed = 0.00525
Hence, reject H0
B.) The confidence interval for difference in mean :
Xd ± Tcritical[Sd/√n]
Tcritical at 95%, df = 9
Tcritical = 2.262
C.I = -105.7 ± 2.262[103.845/√10]
C.I = -105.7 ± 74.281076
Lower boundary: - 105.7 - 74.281076 = - 179.9810
The perimeter of the figure below is 107.5 in. Find the length of the missing side
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Answer:
7.3 in
Step-by-step explanation:
The sum of the lengths of the sides shown is 100.2 in, so the missing length is ...
107.5 -100.2 = 7.3 . . . inches
A manufacturing process produces bags of cookies. The distribution of content weights of these bags is Normal with mean 15.0 oz and standard deviation 1.0 oz. We will randomly select n bags of cookies and weigh the contents of each bag selected. How many bags should be selected so that the standard deviation of the sample mean is 0.1 ounces?
a. 8 bags
b. 10 bags
c. 64 bags
d. 100 bags
Answer:
100 bags
Step-by-step explanation:
S.E = σ/ √n
0.1 = 1 / √n
Square both sides
0.1² = 1² / n
0.01 = 1 / n
0.01n = 1
n = 1 / 0.01
n = 100
What is the volume of the pyramid shown below?
Answer:
B is the answer of this question
Step-by-step explanation:
144 cu. units
Alan's aunt gave him $95 to spend on clothes at the mall. He bought 5 shirts that cost $6 each and a pair of pants that cost $17. How much money does Alan have left to buy more clothes? (one more)
Answer:
he has 48 dollars left to spend on clothes
Last week, you spoke with 800 customers in 40 hours."
Employee: "That is an average of __________ customers every 30 minutes."
Answer:
10 customers
Step-by-step explanation:
Hi!
Each hour has 60 minutes, so two half hour (30 minute) blocks. Thus, 1 hour = 2 half hours, so 40 hours = 80 half hours.
800 customers in 80 half hours, divide that:
800 customers / 80 half hours = 10 customers / half hour
So, your answer is 10 customers every half hour, or 10 customers every 30 minutes.
Average is [tex]10[/tex] customers per hour
Average is a single number taken as representative of a list of numbers, usually the sum of the numbers divided by how many numbers are in the list.
Total number of customers [tex]=800[/tex]
Total number of hours [tex]=40[/tex]
[tex]=40\times 60[/tex]
[tex]=2400[/tex] minutes
Average (in every [tex]30[/tex] minutes) [tex]=[/tex] Total number of customers [tex]\div[/tex] Total number of hours
[tex]=\frac{800}{2400 \div 30}[/tex]
[tex]=10[/tex] customers per hour
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Determine the remaining sides and angles of the triangle ABC.
c=6 mi, B = 38.71°, C = 32.51°
Find the measure of angle A.
A=°
(Type an integer or a decimal.)
Find the length of side a.
а:
mi
(Round to the nearest mile as needed.)
Find the length of side b.
b=mi
(Round to the nearest mile as needed.)
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Answer:
A = 108.78°
a = 11 mi
b = 7 mi
Step-by-step explanation:
The sum of angles in a triangle is 180°, so the third angle is ...
A = 180° -38.71° -32.51°
A = 108.78°
__
The remaining sides can be found from the law of sines.
a/sin(A) = c/sin(C)
a = sin(A)·c/sin(C) ≈ 0.946762 × 11.163896
a ≈ 11 mi
b = sin(B)·11.163896 ≈ 0.625379 × 11.163896
b ≈ 7 mi
Which of the following is a polynomial?
A. X4- 2
B. 1/x+ 2
c. x-2-1
D.(x - 4)/(x + 1)
Answer:
ok um last person was rude but your answer is A
Step-by-step explanation:
If it takes sally 45 minutes to walk 1 mile how long will it take sally to walk 1,954 miles?
Answer:
87,930 Minutes
Step-by-step explanation:
Let us use unit rates for this question. Let's first draw a table.
Minutes Mile
45 1
This table represents the relation of Sally walking 1 mile in 45 minutes. Let's put the other data we know of in the table.
Minutes Mile
45 1
1954
To find the number of minutes, we must know that if 1 mile takes 45 minutes, we must multiply the number of minutes, which is 45, by 1954 to get the result desired. Let us do that.
1954*45 = 87,930
Minutes Miles
45 1
87,930 1954
Therefore it will take Sally 87,930 minutes to walk 1,954 Miles.
I Hope This Helps!
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I need help answering this question thank guys
Answer:
b
Step-by-step explanation:
the square root of 8 is 2 and the square root of 18 is 4.5 and both simplified is 4/9.
Aslo did this last week.
A student decides she wants to save money to buy a used car, which costs $2600. She comes up with what she thinks is a very modest savings plan. She decides to save 2 cents the first day and double the amount she saves each day thereafter. On the second day she plans to save 4 cents, on the third day, 8 cents, and so on. Determine how long it will take her to save enough money to buy the car ?
Answer:
17 days
Step-by-step explanation:
as you see, 4=2^2
and 8=2^3
so we have a number sequence:
2+2^2+2^3+...+2^n=260000 (1)
multiply (1) by 2 we have:
2^2+2^4 +...+2^(n+1)=520000 (2)
(2) minus (1) we have:
2^(n+1)-2=260000
2^n*2=260002
2^n=130001
and we have 2^17=131072 >130001
so it will take her at least 17 days to buy the car
It will take her about 17 days to buy the car worth 260000 cents
If a student decides she wants to save money to buy a used car that cost $2600 (260,000 cents)
If she saves 2 cents the first day and doubles the amount thereafter, the sequence of savings will be:
2, 4, 8...
This sequence is geometric in nature
In order to determine how long it will take her to save 260,000, we will use the sum of a GP formula expressed as:
[tex]S_n = \frac{a(r^n-1)}{r-1}[/tex]
Given the folowing
a = 2
r = 4/2 = 8/4 = 2
Sn = 260,000
Substitute into the formula the given parameters
[tex]260000= \frac{2(2^n-1)}{2-1}\\260000/2=2^n-1\\130000 = 2^n - 1\\2^n = 130000 + 1\\2^n = 130001\\nlog 2=log130001\\n = \frac{log130001}{log2} \\n \approx 17[/tex]
This shows that it will take her about 17 days to buy the car worth 260000 cents
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5x + 2y + 19 = 0 3x + 4y + 17 = 0
Answer:
x = -3; y = 2
Step-by-step explanation:
5x + 2y + 19 = 0
3x + 4y + 17 = 0
-10x - 4y - 38 = 0
3x + 4y + 17 = 0
-7x - 21 = 0
x = -3
5(-3) + 2y = -19
2y = -4
y = -2
Answer: x = -3; y = 2
A duck has 1,100 feathers. It went for a swim in a pond and lost 2/100 of its feathers. How many feathers did it lose?
Answer:
It lost 22 feathers.
Step-by-step explanation:
To complete this problem, this expression will be used: 2x/100.
2(1100)/100 {Multiply 2 by 1100}
2200/100 {Simplify by cancelling out 100}
22/1 {Divide}
22 feathers were lost.
35 POINTS HELP in the figure above the circle has center O and radius 6 what is the length of arc acb
Answer:
9.425 or 3π
Step-by-step explanation:
arc length = 2πr(θ/360)
The angle is 90˚ as indicated by the square symbol.
ABC = 2π6(90/360) = 9.425 or 3π
Angles CED and CBD subtend the same arc. Determine the measure of ∠CED.
Question options:
1)
100°
2)
150°
3)
310°
4)
50°
Answer:
[tex]50^{\circ}[/tex]
Step-by-step explanation:
Inscribed angles that form the same arc have the same angle measure, no matter where they lie on the circle. Since the measure of angle CBD forms the same arc as angle CED, the measure of angle CBD must be equal to the measure of angle CED, hence [tex]m\angle CED=\boxed{50^{\circ}}[/tex]
Answer:
the answer is 4)50°
Step-by-step explanation:
because it is same
Find the length of the third side?
Answer:
2
Step-by-step explanation:
let x be the third side
Using Pythagoras' identity in the right triangle
x² + 5² = ([tex]\sqrt{29}[/tex] )²
x² + 25 = 29 ( subtract 25 from both sides )
x² = 4 ( take the square root of both sides )
x = [tex]\sqrt{4}[/tex] = 2
60kg of rice must be put into three equal bags. what weight of rice must be put into each bag?
Answer:
20kg of rice in each bag
Step-by-step explanation:
we have 60kg of rice and 3 bags. we know that we need to have an eqal amount of rice in each bag so we can divide the 60kgs of rice by 3.
60÷3=20
Checking our Answer:
we can check our work by doing the opposite of division which is multiplication. to check our work we'd have to multiply the dividend (in our case 3) and our quotient (in our case 20) to see if we get the larger dividend (in our case 60) as our answer.
3×20=60
The length of a rectangle is 10 yd less than three times the width, and the area of the rectangle is 77 yd^2. Find the dimensions of the rectangle.
Answer:
W=7 and L=11
Step-by-step explanation:
We have two unknowns so we must create two equations.
First the problem states that length of a rectangle is 10 yd less than three times the width so: L= 3w-10
Next we are given the area so: L X W = 77
Then solve for the variable algebraically. It is just a system of equations.
3W^2 - 10W - 77 = 0
(3W + 11)(W - 7) = 0
W = -11/3 and/or W=7
Discard the negative solution as the width of the rectangle cannot be less then 0.
So W=7
Plug that into the first equation.
3(7)-10= 11 so L=11
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.
The Total mileage is "400" and the further solution can be defined as follows:
Let t become the time he spent commuting on the first day of his vacation.
It is then calculated as [tex]t + 2[/tex].
[tex]\to 40\times(t+2) = 60(t) + 20 \\\\\to 40t+80 = 60t + 20 \\\\\to 80-20 = 60t + 40t \\\\\to 60 = 20t \\\\\to t=\frac{60}{20} \\\\\to t=\frac{6}{2} \\\\\to t= 3\\\\[/tex]
It traveled [tex]40\times (3 + 2) + 20 = 40\times 5 + 20 = 200+20=220[/tex] miles on its first day of operation.
The car traveled [tex]180\ miles[/tex] on the second day, which was [tex]60 \ miles \times 3[/tex].
So,
Total mileage= first day traveled + second day traveled [tex]= 220+ 180= 400 \miles[/tex]
Learn more:
Total distance traveled: brainly.com/question/20670144
Suppose the discrete random variable X has the probability distribution below:
X 0 1 2 3 4
P(X) 0.11 0.52 0.19 0.12 0.06
1pt a right parenthesis space F i n d space P left parenthesis X less than 3 right parenthesis
2pt b right parenthesis space F i n d space P left parenthesis X greater or equal than 1 right parenthesis
2pt c right parenthesis space F i n d space mu subscript X
2pt, 1pt d right parenthesis space F i n d space sigma subscript X squared space a n d space sigma subscript X
(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82
(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89
(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5
(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07
σ = √(σ²) ≈ 1.03
Convert 110101 in base 2 to base 10
Answer:
base-2 base-10
110011 = 51
110100 = 52
110101 = 53
110110 = 54
21 more rows
P over 8 4
The solution is ___.
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Answer:
1680
Step-by-step explanation:
nPk = n!/(n-k)!
8P4 = 8!/(8-4)! = 8·7·6·5 = 1680
Data was collected on reaction time of both hands for an experiment. 14 out of 27 students had a faster reaction time with their right hand than with their left hand. Using this information, we wish to construct a confidence interval for the proportion of all WCU students that have a faster reaction time with their right hand than with their left hand.
Calculate the lower boundary of a 99% confidence interval.
Give your answer as a decimal rounded to 3 places after the decimal.
Answer:
0.3902
Step-by-step explanation:
The question meets the criteria for the calculation of the confidence interval of a one sample proportion ;
Sample size, n = 27
Number of students with faster reaction time = 14
Phat = x / n = 14 / 27 = 0.6296
The confidence interval is calculated thus :
C. I = Phat ± Zcritical * √[p(1 - p)/n]
Zcritical at 99% = 2.576
C. I = 0.6296 ± 2.576 * √[0.6296(0.3704)/27]
C.I = 0.6296 ± 0.2394042
The lower boundary of C.I = 0.6296 - 0.2394042
Lower boundary = 0.3902
(3x - 2)^5 =(3x - 2)^2
Answer:
x=3/2,1
Step-by-step explanation:Given
(3x-2)ˆ5-(3x-2)ˆ2=0
(3x-2)ˆ3(3x-2)ˆ2-(3x-2)ˆ2=0
(3x-2)ˆ2{(3x-2)ˆ3-1}=0
(3x-2)ˆ2=0 Or (3x-2)ˆ3-1=0
3x-2=0 Or(3x-2)ˆ3=1
x=3/2 Or 3x-2=1, x=1
