14 of 14
A1 Math gr7 20-21 Form D Online
Full Screen
Screen
Kenwyn is making flower arrangements for an event. The table shows the number of flower arrangements, f, she can make in m minutes.

Answer:

center of mass

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = [tex]\frac{152}{3}[/tex]б

Mx =  [tex]\frac{6976}{15}[/tex]б

My = [tex]\frac{224}{3}[/tex]б

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

Answer:

15

Step-by-step explanation:

The range of a group of numbers is the highest number in the sequence minus the lowest number.

Which in this case was 51 - 36 = 15.

Hope this Helps!

:D

This question is missing some parts. Here is the complete question.

Consider the oriented path which is a straight line segment L running from (0,0) to (16,16).

(a) Calculate the line inetrgal of the vector field F = (3x-y)i + xj along line L using the parameterization B(t) = (2t,2t), 0 ≤ t ≤ 8.

Enter an exact answer.

[tex]\int\limits_L {F} .\, dr =[/tex]

(b) Consider the line integral of the vector field F = (3x-y)i + xj along L using the parameterization C(t) = [tex](\frac{t^{2}-256}{48} ,\frac{t^{2}-256}{48} )[/tex], 16 ≤ t ≤ 32.

The line integral calculated in (a) is ____________ the line integral of the parameterization given in (b).

Answer: (a) [tex]\int\limits_L {F} .\, dr =[/tex] 384

              (b) the same as

Step-by-step explanation: Line Integral is the integral of a function along a curve. It has many applications in Engineering and Physics.

It is calculated as the following:

[tex]\int\limits_C {F}. \, dr = \int\limits^a_b {F(r(t)) . r'(t)} \, dt[/tex]

in which (.) is the dot product and r(t) is the given line.

In this question:

(a) F = (3x-y)i + xj

r(t) = B(t) = (2t,2t)

interval [0,8] are the limits of the integral

To calculate the line integral, first substitute the values of x and y for 2t and 2t, respectively or

F(B(t)) = 3(2t)-2ti + 2tj

F(B(t)) = 4ti + 2tj

Second, first derivative of B(t):

B'(t) = (2,2)

Then, dot product between F(B(t)) and B'(t):

F(B(t))·B'(t) = 4t(2) + 8t(2)

F(B(t))·B'(t) = 12t

Now, line integral will be:

[tex]\int\limits_C {F}. \, dr = \int\limits^8_0 {12t} \, dt[/tex]

[tex]\int\limits_L {F}. \, dr = 6t^{2}[/tex]

[tex]\int\limits_L {F.} \, dr = 6(8)^{2} - 0[/tex]

[tex]\int\limits_L {F}. \, dr = 384[/tex]

Line integral for the conditions in (a) is 384

(b) same function but parameterization is C(t) = [tex](\frac{t^{2}-256}{48}, \frac{t^{2}-256}{48} )[/tex]:

F(C(t)) = [tex]\frac{t^{2}-256}{16}-\frac{t^{2}-256}{48}i+ \frac{t^{2}-256}{48}j[/tex]

F(C(t)) = [tex]\frac{2t^{2}-512}{48}i+ \frac{t^{2}-256}{48} j[/tex]

C'(t) = [tex](\frac{t}{24}, \frac{t}{24} )[/tex]

[tex]\int\limits_L {F}. \, dr = \int\limits {(\frac{t}{24})(\frac{2t^{2}-512}{48})+ (\frac{t}{24} )(\frac{t^{2}-256}{48}) } \, dt[/tex]

[tex]\int\limits_L {F} .\, dr = \int\limits^a_b {\frac{t^{3}}{384}- \frac{768t}{1152} } \, dt[/tex]

[tex]\int\limits_L {F}. \, dr = \frac{t^{4}}{1536} - \frac{768t^{2}}{2304}[/tex]

Limits are 16 and 32, so line integral will be:

[tex]\int\limits_L {F} \, dr = 384[/tex]

With the same function but different parameterization, line integral is the same.

Answer:

3x=60

4x=80

Step-by-step explanation:

I think you've typed it wrong it must be 140 packets. All you need to do is assume 3:4 as 3x and 4x and add it

so 7x=140

x=20

3x=60

4x=80

The base of the model merry-go-round is 450in², and the actual merry-go-round's base is 400 times larger.

Therefore the base of the actual merry-go-round is 180,000in². However, the question asks for the answer in square feet.

180,000in² in squared feet is:

1,250ft² (your final answer)

Answer:

The answer is x= 3

Step-by-step explanation:

hope this helps

Answer:

i think 48

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

1. y= -5x + 12

  y= -5x – 7

2. -5x + 12

   -(-5x – 7)

3. -5x + 12

    5x + 7

    0   +19

4. 19

Answer: -2

Step-by-step explanation: from the equation, -4m +6 = 14, you subtract 6 from both sides and get -4m=8, and the last step is to divide both sides by -4 and you get m=-2.

Answer:

So now D would be at (-4 , 2)

Step-by-step explanation:

From D, you can calculate every other letter’s location. Yeah.

Answer:

Please mark me as brainliest!

Step-by-step explanation:

The coordinates:

D: ( 2,6 )

A: ( 2, 1 )

B: ( 5, 1 )

C: ( 5, 6 )

You want to translate this down 4 units and left 6 units.

So what you would do is this:

Formula = ( x - 6 , y - 4 )

D: ( -4, 2 )

A: ( -4, -3 )

B: ( -1, -3 )

C: ( -1, 2 )

Answer:

/_FCB

Step-by-step explanation:

As, supplementry means they add up to 180°

So a straight angle = /_DCB = 180°

So /_DCF + /_x = /_DCB

So, /_x = /_FCB

So answer = /_FCB

Total weight, w = 10 lbs.

Height of the bucket, h = 2 feet.

Distance walked, d = 100 ft.

Now, work done in moving the bucket at a height of 2 feet.

W = mgh

W = 2× 32.17×100

W = 6434  lbs ft²/s²

Work done in moving bucket in horizontal direction is zero because it is perpendicular to the force.

Therefore, work done is 6434  lbs ft²/s² .

Hence, this is the required solution.

Answer:

0

Step-by-step explanation:

the answer is step by step CFE

Answer:

a) linear pair angles: 1&2, 2&3, 3&4, 1&4... etc (any angles that are adjacent, or right next, to each other that add up to be 180 degrees)

b) All linear pair angles are adjacent angles but not all adjacent angles are linear pairs. So pick any linear pair angle you got because they will always be adjacent. (1&2, 2&3, 3&4, 1&4... etc)

c) vertically opposite angles: 1&3, 2&4, 5&7, 6&8, 9&11, 10&12

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

Step-by-step explanation:

u = 2v

(2v)² = v² + 3

4v² - v² = 3

3v² = 3 ⇒ v = 1 and u = 2

Answer:

5x

Step-by-step explanation:

mutuply and remeber a letter by it self has a one infront

Answer:

Step-by-step explanation:

3/8=0.375

11/16=0.6875

0.375+0.6875=1.0625

Answer:is there a picture I can refer to?

Step-by-step explanation:

Answer:

X=58/3=19 1/3

Step-by-step explanation:

32-x=0.4(2x-7)

32-x=0.8x-2.8

32-x-0.8=-2.8

32-.18x=-2.8

-1.8x=-2.8

-1.8x=-34.8

x=58/3

Answer:

Horizontal component = 9.6

Step-by-step explanation:

Recall that the horizontal component is given by the cosine projection;

[tex]v_x=|v_0| * cos(\theta)[/tex]

which in our case (using the fact that in each degree of angle one has 60 minutes of angle, and therefore 30 minutes of angles is the same as 0.5 degrees) becomes:

[tex]v_x=12.6 * cos(40.5^o)=9.5811[/tex]

And rounding to the nearest tenth as requested, we have:

[tex]v_x=9.6[/tex]

Answer:

12x +4y + 3z=36

Step-by-step explanation:

The equation of plane is given by

z-zo = a(x-xo) + b(y-yo)

pass through (1,3,4)

Z -4 = a(x -1) +b(y-3)

The question is asking us to optimize a and b. To minimize the volume V both a and b should be negative as the normal vector should be towards the negative x and y direction so that a finite tetrahedron can be formed in the first octant.

we need x , y and z intercepts o define volume

x intercept( y, z =0) = [tex]\frac{a+3b-4}{a}[/tex]

y intercept (x, z =0) = [tex]\frac{a+3b-4}{b}[/tex]

z intercept ( x, y =0) = -(a+3b-4)

Base = [tex]\frac{(a+3b-4)^2}{2ab}[/tex]

Volume = [tex]\frac{1}{3}*base*height[/tex]

Volume(a, b) = [tex]\frac{-(a+3b-4)^3}{6ab}[/tex]

now we differentiate partially in terms to a and b the volume to minimize and get a and b.

ΔV(a, b) = [tex]\frac{-1}{6}(\frac{3(a+3b-4)^2ab-b(a+3b-4)^3}{a^2b^2}[/tex] ,[tex]\frac{-1}{6}(\frac{9(a+3b-4)^2ab-a(a+3b-4)^3}{a^2b^2}[/tex]  = 0

Taking the first part of differential it will give

b(a+3b-4) [3a -(a+3b -4)] =0

(a+3b-4) [tex]\neq 0[/tex] because the volume will become zero if this becomes true

2a -3b = -4  ..................(1)

similarly the second part of the differential will give

a-6b=4 ................(2)

on solving 1 and 2 we get

a = -4 and b = -4/3

so the equation will be

Z -4 = -4(x -1) - 4/3*(y-3)

final equation

12x +4y + 3z=36

Answer:

dont get it

Step-by-step explanation:

The question is specific enough for an answer.

Answer:

90

Step-by-step explanation:

Step-by-step explanation:

if the line equation is in the form

y = ...

the slope is always the factor of x.

x + y = 4

y = -x + 4

so, the slope is -1.

a parallel line has the same slope.

when having a surviving point we can use the point-slope form as equation :

y - y1 = m(x - x1)

with m being the slope, and (x1, y1) being a point on the line.

so,

y - 3 = -1(x - 2)

simplified we get

y - 3 = -x + 2

y = -x + 5

that would be the slope-intercept form (+5 being the interception point on the y-axis).

Answer:

C

Step-by-step explanation:

She spent $80

Answer:

8 w

Step-by-step explanation:

yes

Answer:

4 w

Step-by-step explanation:

So first, let's check,

Substitute 4(w=4) for each expression and then evaluate

3(4)=12

4+8=12

4(4)=16

16-4=12

16 is not equal to 12, so the answer is 4 w

Answer:

The answer is B

Step-by-step explanation:

If the students are asked to plant 1/4 of the packet, and they planted six seeds, you would have to multiply 4 x 6 to get a product of 24.

Answer:

The slope is -3

Step-by-step explanation: